JEE Exam  >  JEE Notes  >  Physics for JEE Main & Advanced  >  Important Formulas: Dual Nature of Matter & Radiation

Important Dual Nature of Matter & Radiation Formulas for JEE and NEET

Important Dual Nature of Matter & Radiation Formulas for JEE and NEET1. Energy of a photon

  • Formula: E = hν
  • Explanation: This formula expresses the energy of a photon in terms of its frequency. Here, E is the energy, h is Planck's constant (6.626 × 10-34 Js), and ν is the frequency of the photon. The energy of a photon is directly proportional to its frequency.

2. Number of photons emitted per second

  • Formula: N = P / E
  • Explanation: This formula calculates the number of photons emitted per second. Here, P is the power (energy emitted per second), and E is the energy of a single photon. It shows that the number of photons is inversely proportional to the energy of each photon.

3. Momentum of a photon

  • Formula: P = E / c = h / λ
  • Explanation: The momentum of a photon is calculated using this formula. P is the momentum, E is the energy of the photon, and c is the speed of light. Alternatively, using the relation E = hν, we can express momentum as P = h / λ where λ is the wavelength of the photon.

4. Equivalent mass of a photon

  • Formula: m = E / c2 = h / λc
  • Explanation: A photon, although massless in the classical sense, has equivalent mass derived from its energy. Using Einstein's mass-energy equivalence E = mc2, we can derive the mass of a photon in terms of its energy and wavelength.

5. Work function

  • Formula: W0 = hν0
  • Explanation: The work function is the minimum energy required to remove an electron from a material (typically a metal). Here, W0 is the work function, and ν₀ is the threshold frequency required to emit an electron.

6. Kinetic energy of photoelectron (Einstein's photoelectric equation)

  • Formula: Kmax = 1/2 mv2 = h(ν - ν0)
  • Explanation: This equation describes the maximum kinetic energy (Kmax) of the photoelectron emitted when a photon hits a material. m is the mass of the emitted electron, v is its velocity, h is Planck's constant, and ν0 is the threshold frequency. The kinetic energy is proportional to the difference between the frequency of the incident light and the threshold frequency.

7. Kinetic energy if V0 is the stopping potential

  • Formula: K = 1/2 m vmax2 = - eV0
  • Explanation: The stopping potential V0 is the potential required to stop the most energetic photoelectron. The kinetic energy of the emitted electron is directly related to the stopping potential.

8. Kinetic energy of De-Broglie Waves

  • Formula: K = 1/2 mv2 = p2 / 2m
  • Explanation: The De-Broglie wave theory postulates that particles, like electrons, have a wavelength associated with them. The kinetic energy of the particle can be expressed in terms of its momentum (p) and mass m.

9. Momentum of De-Broglie Waves

  • Formula: P = √(2mK)
  • Explanation: This formula relates the momentum of a particle to its kinetic energy K and mass m. It shows that the momentum is proportional to the square root of the product of mass and kinetic energy.

10. Wavelength of De-Broglie Waves

  • Formula: λ = h / p = h / √(2mK)
  • Explanation: The wavelength λ associated with a particle's De-Broglie wave is inversely proportional to its momentum P. Here, h is Planck’s constant, and m is the mass of the particle, while K is its kinetic energy.

11. De-Broglie wavelength of an electron beam

  • Formula: λ = h / √(2meV)
  • Explanation: The De-Broglie wavelength of an electron accelerated through a potential difference V is given by this formula. e is the charge of the electron, and m is its mass. This formula shows that higher the potential difference, the smaller the De-Broglie wavelength.

12. De-Broglie wavelength associated with gas molecules

  • Formula: λ = h / √(2mkT)
  • Explanation: This formula describes the De-Broglie wavelength of gas molecules, where m is the mass of the molecules, k is Boltzmann’s constant, and T is the temperature in Kelvin. It shows the relationship between the wavelength and the temperature of the gas.

13. The value of h/c in eV ⋅ m

  • Formula: h / c = 1240 × 10-9 eV ⋅ m
  • Explanation: This value is a constant used for converting photon energy from wavelength to eV. It is a useful conversion factor when dealing with electromagnetic waves.

14. The value of h/c in eV ⋅ m

  • Formula: h / c = 1240 × 10-9 eV ⋅ m
  • Explanation: This is another form of the constant used in calculating energy of a photon with given wavelength in eV. The same value as above is used in solving problems involving photon energy.
The document Important Dual Nature of Matter & Radiation Formulas for JEE and NEET is a part of the JEE Course Physics for JEE Main & Advanced.
All you need of JEE at this link: JEE
293 videos|654 docs|184 tests

FAQs on Important Dual Nature of Matter & Radiation Formulas for JEE and NEET

1. What is the dual nature of matter and radiation?
Ans.The dual nature of matter and radiation refers to the concept that all particles exhibit both wave-like and particle-like properties. This principle is central to quantum mechanics and was highlighted by experiments such as the double-slit experiment, where electrons and photons display interference patterns typical of waves, but also can be detected as individual particles.
2. How does the dual nature of light manifest in experiments?
Ans.Light demonstrates its dual nature through various experiments. For example, in the double-slit experiment, light creates an interference pattern when not observed, suggesting it behaves like a wave. However, when observed, it appears to act as particles (photons), confirming its particle-like properties. This duality is crucial in understanding phenomena such as the photoelectric effect.
3. What are some key experiments that support the dual nature of matter?
Ans.Key experiments include the double-slit experiment, which shows light and electrons can create interference patterns, and the photoelectric effect, which demonstrates that light can cause electrons to be emitted from metal surfaces, behaving as particles. Additionally, de Broglie's hypothesis introduced the concept that all matter has a wavelength associated with it, further supporting this duality.
4. How does the concept of wave-particle duality affect modern technology?
Ans.Wave-particle duality influences many modern technologies, including semiconductors, lasers, and quantum computing. Understanding both wave and particle behaviors allows for the development of devices such as transistors and photodetectors, which harness these principles for efficient functioning in electronics and communication technologies.
5. What is the significance of the de Broglie wavelength in the dual nature of matter?
Ans.The de Broglie wavelength is significant as it provides a way to calculate the wavelength associated with a moving particle, reflecting its wave nature. This concept bridges classical and quantum mechanics, allowing for the analysis of particles like electrons in terms of their wave properties, crucial for understanding atomic and subatomic behavior.
Related Searches

Sample Paper

,

video lectures

,

Previous Year Questions with Solutions

,

Objective type Questions

,

practice quizzes

,

Extra Questions

,

Viva Questions

,

Important Dual Nature of Matter & Radiation Formulas for JEE and NEET

,

Exam

,

Summary

,

Semester Notes

,

pdf

,

past year papers

,

Important questions

,

Free

,

Important Dual Nature of Matter & Radiation Formulas for JEE and NEET

,

shortcuts and tricks

,

mock tests for examination

,

ppt

,

Important Dual Nature of Matter & Radiation Formulas for JEE and NEET

,

study material

,

MCQs

;