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JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced PDF Download

Q.1. Which one of them is the weakest?
(a) Ionic bond
(b) Covalent bond
(c) Metallic Bond
(d) van der Waals force

Correct Answer is option (d)
Among them van der Waals force is the weakest force.


Q.2. In the resonating structures of benzene, the number of sigma and pi bonds are
(a) 3π and 12σ
(b) 3σ and 3π
(c) 6σ and 6π
(d) 12σ and 12π

Correct Answer is option (a)
In Benzene (C6H6) ring contain 3 alternative double bond = 3π bonds and (six C-C sigma bond + six C-H sigma bond) = 12 σ bonds


Q.3. The ion which is iso-electronic with CO is______
(a) CN
(b) O2
(c) N2+
(d) O2+

Correct Answer is option (a)
Both CO (6 + 8=14) and CN– (6 + 7 + 1 = 14) have the same electrons. so they are iso-electronic with each other.


Q.4. Which of the following molecules have trigonal planar geometry?
(a) BF3
(b) NH3
(c) PCl3
(d) IF3

Correct Answer is option (a)
BF3 has trigonal planar geometry. The hybridization of BF3 is sp2 hybridization.


Q.5. In which of the following pairs, the two molecules have identical bond orders:
(a) N2 , O22+
(b) N2 , O2
(c) N2 , O2
(d) O22- , N2

Correct Answer is option (a)
Both N2 and O22+ have bond order equal to 3.0.


Q.6. The bond angle around atom which uses sp2 hybridization is ———–
(a) 1200
(b) 1800
(c) 1070
(d) 1090. 28’

Correct Answer is option (a)
The bond angle around an atom which uses sp2 hybridization is 1200.


Q.7. Which of the following substances has a dipole moment more than zero?
(a) Water
(b) Methane
(c) Carbon dioxide
(d) Nitrogen

Correct Answer is option (a)
The dipole moment (μ) of H2O = 1.84 D


Q.8. The correct bond order in the following species is —————.
(a) O2+ < O2 < O22+
(b) O2 < O2+ < O22+
(c) O22+ < O2+ < O2
(d) O22+ < O2 < O2+

Correct Answer is option (b)
The correct one is O2 < O2+ < O22+ , bond order is 1.5 < 2.5 < 3.0 respectively.


Q.9. During change of O2 to O22- ion, the electron adds on which of the following orbitals?
(a) σ* orbital
(b) π orbital
(c) σ orbital
(d) π* orbital

Correct Answer is option (d)
The incoming electrons added to π* orbital in the change of O2 to O22- ion.


Q.10. Ionic bonds will be formed more easily between elements with comparatively:
(a) low ionization enthalpy and high electron affinity
(b) high ionization enthalpy and high electron affinity
(c) low ionization enthalpy and low electron affinity
(d) high ionization enthalpy and low electron affinity

Correct Answer is option (a)
Ionic bonds will be formed more easily between elements with low ionization enthalpy and high electron affinity.


Q.11. The bond angle is minimum in  
(a) NH+4
(b) NOCl
(c) H2Se
(d) SO3 

Correct Answer is option (c) 
JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced hybridisation – 109°28'.
NOCl → sp2 hybridisation - 120°
H2Se  → sp3 hybridisation because of lone pair bond angle gets minimized.
SO3 → sp2 hybridisation 120°.


Q.12. The observed dipole moment of HCl molecule is 1.03 D. If H–Cl bond distance is 1.275 Å and electronic charge is 4.8 × 10–10 e.s.u. The % polarity in HCl will be
(a) 1.275 × 1.03 %
(b) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
(c) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
(d) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced

Correct Answer is option (c)
Percentage polarity
JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
Here observed dipole moment of HCl = 1.03 D
Calculated dipole moment of HCl = 4.8 × 10-10 × 1.275 × 10-8
= 4.8 × 1.275 D
Therefore,  % polarity
JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced


Q.13. Which of the following has same bond order as NO+ has?  
(a) CN 
(b) O2 
(c) CN+ 
(d) none of them

Correct Answer is option  (a)
NO+ and CN- both have 14 electrons and also both will have the following configuration.
JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
∴ Bond order of NO+ = Bond order of CN- = 3.


Q.14. The correct order of increasing bond angles is  
(a) PF3 < PCl3 < PBr3 < PI3 
(b) PI3 < PCl3 < PBr3 < PF3 
(c) PI3 < PBr3 < PCl3 < PF3 
(d) PCl3 < PBr3 < PI3 < PF3 

Correct Answer is option (a)
As the size of surrounding atom increases the electronic repulsion increases bond angle increases.  


Q.15. Which of the following is planar?  
(a) XeO4 
(b) XeO2F2 
(c) XeO3F2 
(d) XeF
4

Correct Answer is option (d)
XeO- tetrahedral
XeO3F- trigonal bipyramidal
XeO2F- trigonal bipyramidal
XeF4 - square planar.


Q.16. Which of the following does not contain coordinate bond?
(a) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
(b) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
(c) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
(d) H3O
+

Correct Answer is option (c)
JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced


Q.17. The correct order in which the O–O bond length increases in the following is  
(a) O2 < O3 < H2O2
(b) H2O2 < O3 < O2
(c) O3 < O2 < H2O2
(d) O2 < H2O2 < O3

Correct Answer is option (a)
JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
Due to resonance in O3, O–O bond length will be in between O=O and O–O.


Q.18. Which species has the maximum number of lone pair of electrons on the central atom?
(a) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced
(b) XeF4
(c) SF4
(d) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced     

Correct Answer is option (d)
InJEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced central atom has 3 lone pair and two bond pair.


Q.19. Which of the following compound has highest covalent character?  
(a) NaCl
(b) KCl
(c) MgCl2
(d) LiCl

Correct Answer is option (c) 
More is the charge on cation, more is the polarisation of anion by cation. Hence, more is the covalent character.


Q.20. Which one of the following species is paramagnetic?
(a) JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced

(b) CN 
(c) CO
(d) NO+

Correct Answer is option (a) 
Only JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced has unpaired electrons in molecular orbital.

The document JEE Advanced (Single Correct Type): Chemical Bonding & Molecular Structure | Chapter-wise Tests for JEE Main & Advanced is a part of the JEE Course Chapter-wise Tests for JEE Main & Advanced.
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