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Circles and its Properties | The Complete SAT Course - Class 10 PDF Download

Definition of a Circle

  • When a set of all points that are at a fixed distance from a fixed point are joined then the geometrical figure obtained is called circle.

Circles and its Properties | The Complete SAT Course - Class 10

Terms related to Circles

Circles and its Properties | The Complete SAT Course - Class 10Center

The fixed point in the circle is called the center.

  • So, the set of points are at a fixed distance from the center of the circle.

Radius

  • Radius is the fixed distance between the center and the set of points. It is denoted by “R”.

Diameter

  • Diameter is a line segment, having boundary points of circles as the endpoints and passing through the center.
    • So, logically a diameter can be broken into two parts:
    • One part from one boundary point of the circle to the center
    • And, the other part from the center to another boundary point.
    • Hence, Diameter = Twice the length of the radius or “D = 2R”

Circumference

  • It is the measure of the outside boundary of the circle.
  • So, the length of the circle or the perimeter of the circle is called Circumference.

Circles and its Properties | The Complete SAT Course - Class 10

Arc of a circle

  • The arc of a circle is a portion of the circumference.
  • From any two-points that lie on the boundary of the circle, two arcs can be created: A Minor and a Major Arc.
    • Minor arc: The shorter arc created by two points.
    • Major Arc: The longer arc created by two points.

Circles and its Properties | The Complete SAT Course - Class 10Sector of a circle:

  • A Sector is formed by joining the endpoints of an arc with the center.
    • On joining the endpoints with the center, two sectors will be obtained: Minor and Major.
    • By default, we only consider the Minor sector unless it is mentioned otherwise.

Circles and its Properties | The Complete SAT Course - Class 10

Semi-circle

  • A semi-circle is half part of the circle or,
  • A semi-circle is obtained when a circle is divided into two equal parts.

Circles and its Properties | The Complete SAT Course - Class 10

Important Properties of Circle – Lines

Circles and its Properties | The Complete SAT Course - Class 10Properties related to Lines in a Circle

Chord

  • A chord is a line segment whose endpoints lie on the boundary of the circle.

Circles and its Properties | The Complete SAT Course - Class 10

Properties of Chord

  • Perpendicular dropped from the center divides a chord into two equal parts.

Circles and its Properties | The Complete SAT Course - Class 10Tangent

  • Tangent is a line that touches the circle at any point.

Properties of Tangent

  • Radius is always perpendicular to the tangent at the point where it touches the circle.

Circles and its Properties | The Complete SAT Course - Class 10

Important Properties of Circle – Related to Angles

Circles and its Properties | The Complete SAT Course - Class 10Properties related to Angles in a circle

Inscribed Angle

  • An inscribed angle is the angle formed between two chords when they meet on the boundary of the circle.

Circles and its Properties | The Complete SAT Course - Class 10

Properties of Inscribed Angles

  • Angles formed by the same arc on the circumference of the circle is always equal.
  • Circles and its Properties | The Complete SAT Course - Class 10The angle in a semi-circle is always 90°.

Circles and its Properties | The Complete SAT Course - Class 10

Central Angle 

  • A central angle is the angle formed when two-line segments meet such that one of the endpoints of both the line segment is at the center and another is at the boundary of the circle.

Circles and its Properties | The Complete SAT Course - Class 10Property of Central Angles

  • An angle formed by an arc at the center is twice the inscribed angle formed by the same arc.

Circles and its Properties | The Complete SAT Course - Class 10

Important Circle Formulas: Area and Perimeter

The following are some mathematical formulae that will help you calculate the area and perimeter/circumference of a circle.

Perimeter:

  • Perimeter or the Circumference of the circle = 2 × π × R.
  • Length of an Arc = (Central angle made by the arc/360°) × 2 × π × R.

Area:

  • Area of the circle = π × R²
  • Area of the sector =(Central angle made by the sector/360°) × π × R².

Example of Application of the properties

Example 1: The lengths of two sides in a right-angle triangle other than hypotenuse are 6 cm and 8 cm. If this right-angle triangle is inscribed in a circle, then what is the area of the circle?

(a) 5 π

(b) 10 π

(c) 15 π

(d) 20 π

(e) 25 π

Correct answer is option (e)
Step 1: Given

  • The lengths of two sides other than hypotenuse of a right triangle are 6 cm and 8 cm.
  • This triangle is inscribed in a circle.

Step 2: To find

  • Area of the circle.

Step 3: Approach and Working out

  • Let us draw the diagrammatic representation.

Circles and its Properties | The Complete SAT Course - Class 10

By applying the property that the angle in a semi-circle is 90º, we can say that AB is the diameter of the circle.

  • And, once we find the length of the diameter, we can find the radius, and then we can find the area of the circle as well.

Applying Pythagoras theorem in △ ABC,

  • AB² = AC² + BC²
    • AB² = 6² + 8² = 36 +64 = 100
    • AB = 10 cm

Since AB is the diameter, AB = 2R = 10

  • Hence, R = 5 cm.

Area of the circle = π × R²= π × 5² = 25 π.
Hence, the correct answer is option E.

Example 2: In the diagram given below, O is the center of the circle. If OB = 5 cm and ∠ABC = 300 then what the length of the arc AC?

Circles and its Properties | The Complete SAT Course - Class 10

(a) 5π/6

(b) 5π/3

(c) 5π/2

(d) 

(e) 10π

Correct answer is option (b)

Step 1: Given

  • OB = 5 cm
  • ∠ABC = 30°

Step 2: To find

  • Length of the arc

Step 3: Approach and Working out

  • Length of the arc =  (Central angle made by the arc/360°) × 2 × π × R.

To find the length of the arc, we need the value of two variable, the center angle made by the arc and the radius.

  • We are already given radius as OB = 5cm
  • We need to find the ∠AOC

On visualizing the diagram, the inscribed angle by the arc AC is ∠ABC, and the center angle by arc AC is ∠AOC.

  • Hence, we can apply the property that the angle made at the center by an arc is twice the inscribed angle formed by the same arc.
  • Thus, ∠AOC = 2 × ∠ABC = 2 × 30° = 60°

Now, we know the central angle formed by the arc as well.

  • Hence, length of the arc AC =(Central angle made by the arc/360°) × 2 × π × R.
    • =(60°/360°) × 2 × π × 5.
    • =(1/6) × 2 × π × 5.
    • =(5π/3) cm

Thus, the correct answer is option B.

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