Class 7 Exam  >  Class 7 Notes  >  Mathematics (Maths) Class 7  >  Practice Questions: Integers

Class 7 Maths Chapter 1 Practice Question Answers - Integers

Q1. The value of 52−27 is
(a) 24
(b) 25
(c) 26
(d) −24

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: 52−27=25


Q2. (−60×−72) by (36×(−15))
(a) -8
(b) -16
(c) 8
(d) 16

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol:  Given,  
Class 7 Maths Chapter 1 Practice Question Answers - Integers

As there are 2 negative numbers in the numerator and 1 in the denominator, the answer will be negative.
Cancelling out the common factors and simplifying we get
Class 7 Maths Chapter 1 Practice Question Answers - Integers

= -4 x 2
= -8


Q3. Solve (−87)+(−35)=
(a) -122
(b) -65
(c) -35
(d) 87

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: (−87)+(−35)
Two different signs (+ and − in either order) ( + and − in either order ) become a negative sign (−)
(−87−35)
Two of the same signs (+ and + or − and −) ( + and + or − and − ) become a positive sign (+) but the sign remains the original one
=−122


Q4. Divide 96×(−25) by (−75)×(−16)
(a) -2
(b) 2
(c) -5
(d) 5

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: 96×(−25)÷(−75)×(−16)
The rule for multiplying positive and negative numbers with the same sign (two positive or two negative) is that the product will always be positive.
When multiplying a positive and a negative, the product will always be negative. It doesn't matter what order the signs are in.
=−2400÷1200
=−2


Q5. Multiply: (−5)×8 and 3×(−2)
(a) 240
(b) 420
(c) -240
(d) -420

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: When multiplying a positive and a negative, the product will always be negative. It doesn't matter what order the signs are in.
(−5) × 8 = −40
3 × (−2) = −6
The rule for multiplying positive and negative numbers with the same sign (two positive or two negative) is that the product will always be positive.
Hence, ((−5) × 8) × (3 × (−2)) = −40 × − 6
= 240


Q6. Multiply 4×(−3)×(−2) and 6×(−5)
(a) -720
(b) -70
(c) -270
(d) 720

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: When multiplying a positive and a negative, the product will always be negative. It doesn't matter what order the signs are in.
4 × (−3) × (−2) × 6 × (−5)
= 24 × −30
= −720


Q7. What value should come in place of question mark (?) in the questions given below ?
29 + 729 = ?

(a) 758
(b) 763
(c) 741
(d) 751

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: 29 + 729 = 758


Q8. Evaluate Class 7 Maths Chapter 1 Practice Question Answers - Integers
(a) −18
(b) 18
(c) 16
(d) −16

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol:  Given,
Class 7 Maths Chapter 1 Practice Question Answers - Integers
As there are 3 negative numbers in the numerator and 1 in the denominator, the answer will be positive.
Canceling out the common factors and simplifying we get:

Class 7 Maths Chapter 1 Practice Question Answers - Integers
 = 18


Q9. Multiplication of a negative integer for even times gives a _____result 
(a) negative
(b) 0
(c) positive
(d) none

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol:  Multiplication 2 times: (−2) × (−2)=4
Multiplication 4 times: (−3) × (−3) × (−3) × (−3) = 9 × 9 = 81
Multiplication 6 times: (−1) × (−1) × (−1) × (−1) × (−1) × (−1) = 1 × 1 × 1 = 1
Hence, when a negative integer is multiplied even number of times, the result is a positive integer.


Q10. If 27 × 3 = 243 and 5 × 4 = 80
Then the value of 3×7 is ___.
(a) 84
(b) 147
(c) 63
(d) 23

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: We can observe that,
27 × 3 = 81 and 81 × 3 = 243
Similarly,
5 × 4 = 20 and 20 × 4 = 80
Hence,
3 × 7 = 3 × 7 × 7 = 147


Q11. 42(4 + 2) = (42 × 4) + (42 × 2) is an example of
(a) closure property
(b) commutative property
(c) associative property
(d) distributive property

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: 42(4 + 2) = (42 × 4) + (42 × 2) is an example of distributive property.
a(b + c) = (a × b) + (a × c) is the basic form of distributive property.


Q12. Sign of the product of 231 negative integers and 9 positive integers is 
(a) negative
(b) positive
(c) 0
(d) none

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: Since 231 is an odd number, the product of 231 negative integers will be negative. The product of all positive integers is a positive number. Hence, the product of 9 positive integers will be a positive integer.
Therefore, the product of the two integers (231 negative and 9 positive) of unlike signs will be negative.


Q13. Multiplication of a negative integer for even number of times gives a _________ number.
(a) negative
(b) 0
(c) positive
(d) none of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: Observe −1×−1=1
Product of a pair of negative numbers is positive.
When even number of negative numbers are multiplied, the result is a positive number because every pair of negative terms will give a positive number.


Q14. Evaluate   Class 7 Maths Chapter 1 Practice Question Answers - Integers
(a) 9/4
(b) 9/8
(c) 9/2
(d) −9/2

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: As there are 2 negative numbers in the numerator and 2 in the denominator, the answer will be positive.
Canceling out the common factors and simplifying we get
Class 7 Maths Chapter 1 Practice Question Answers - Integers


Q15. Choose the correct statement from following:
(a) 8,58,68,788>8,58,78,688>8,58,88,687
(b) 8,58,78,688>8,58,68,788>8,58,88,687
(c) 8,58,68,788>8,58,88,687>8,58,78,688
(d) 8,58,88,687>8,58,78,688>8,58,68,788

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: Clearly the first 3−digits of each number are same.
So, let us compare rest of the remaining 5−digits of each number.
For option A, we have
68788,78688,88687
Clearly, 88687>78688>68788
So, option A is wrong.
Now, check for option D
We have, 88687,78688,68788
Clearly, 88687>78688>68788$$
So, option D is correct.


Q16. Suppose we represent the distance above the ground by a positive integer and that below the ground by a negative integer, then answer the following:
An elevator descends into a mine shaft at the rate of 5 m/min. What will be its position after one hour? 

(a) 250
(b) 200
(c) 100
(d) None of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: Since, the elevator going down, so the distance covered by it will be represented by a negative integer.
Change in position of elevator in one minute = −5 m
Position of the elevator after 60 minutes
= (−5) × 60

= −300  m
That means the position of the elevator will be 300 m below ground level.


Q17. Which of the following options shows the given number sentence?
-13 + (-3) = -16

(a) When two positive integers are added, we get a positive integer.
(b) When two negative integers are added, we get a negative integer.
(c) The subtraction of an integer is the same as the addition of its additive inverse.
(d) All of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: We are given that −13+(−3)=−16.
The LHS is the sum of the negative integers and the RHS is a negative integer. Thus, the correct answer is option B


Q18. The value of −5×−2×−2×−3  is
(a) 80
(b) 65
(c) 60
(d) -60

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: As there are 4 negative numbers, which is an even number, the product will be positive.
So, −5×− 2×− 2×− 3
= 60


Q19. Divide 96×(−25) by (−75)×(−16)
(a) -2
(b) 2
(c) -5
(d) 5

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: 96 × (−25) ÷ (−75) × (−16)
The rule for multiplying positive and negative numbers with the same sign (two positive or two negative) is that the product will always be positive.
When multiplying a positive and a negative, the product will always be negative. It doesn't matter what order the signs are in.
The answer will be positive if the product or quotient is positive (two positives or two negatives in the equation) or negative (one positive and one negative in the equation).
= −2400 ÷ 1200
= −2


Q20. The value of −5×−12 × 2×−3 is
(a) -360
(b) -380
(c) -400
(d) 360

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: As there are 3 negative numbers, which is an odd number, the product will be negative.
So, −5×−12 × 2×−3
=−360


Q21. Divide (−54)×(64) by (−27)×(−128)
(a) -1
(b) 1
(c) 5
(d) -4

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: (−54) × (64) ÷ (−27) × (−128)
The rule for multiplying positive and negative numbers with the same sign (two positive or two negative) is that the product will always be positive.
When multiplying a positive and a negative, the product will always be negative. It doesn't matter what order the signs are in.
The answer will be positive if the product or quotient is positive (two positives or two negatives in the equation) or negative (one positive and one negative in the equation).
= −3456 ÷ 3456
= −1


Q22. Evaluate:(+48)+(−53)
(a) +5
(b) -5
(c) 5
(d) none of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: (+48)+(−53)
Two different signs (+ and − in either order) ( + and − in either order ) become a negative sign (−) 
=53−48
=−5


Q23. Fill in the blank:68 × ____ = −68
(a) 0
(b) 1
(c) -1
(d) None of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)=
Sol: 68×(−1)=−68


Q24. (-12) × (-3) × (+4) × (-6) =
(a) -144
(b) -908
(c) +864
(d) -864

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: Multiplying them in pairs.
There are 3 negative signs. So, the resultant of 3 multiplications would be negative.
Consider,
(−12) × (−3) × (+4) × (−6) = (−12×−3) × (4×−6)
=36×(−24)
=−864
Hence, Option D is correct.


Q25. Fill in the blank:−112 × _______ = +112
(a) +1
(b) 0
(c) -1
(d) +112

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (c)
Sol: −112×(−1)
= +112


Q26. (+13)+(−12) is equal to
(a) +1
(b) + 13
(c) - 1
(d) None of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: (+13) + (−12)
Two different signs (+ and − in either order) ( + and − in either order ) become a negative sign (−) 
= +1


Q27. (+132) ÷ (−12)
(a) +101
(b) −101
(c) +11
(d) −11

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (d)
Sol: (132) ÷ (−12)
The answer will be positive if the product or quotient is positive (two positives or two negatives in the equation) or negative (one positive and one negative in the equation).
= 132 / -12
= 12 x 11 / -12
=  -1 x 11
= - 11
Option D is correct.


Q28. If the dividend and divisor have like signs then the quotient will be_____.
(a) Positive
(b) Negative
(c) Zero
(d) none of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: If the dividend and divisor have same  signs then the quotient will be positive.
For eg. 132/12 = 11
and -132/-12 = 11


Q29. Positive of a negative integer is____.
(a) Negative
(b) Positive
(c) Zero
(d) None of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (a)
Sol: Positive of a negative integer is negative.
Example: +(−40) = −40


Q30. The product of any number and "0" is ___
(a) 1
(b) 0
(c) number itself
(d) none of these

Class 7 Maths Chapter 1 Practice Question Answers - Integers  View Answer

Ans: (b)
Sol: The product of any number and zero is zero.
Theorem: 0 × a = 0 for any integer a.
So option B is the correct answer.

The document Class 7 Maths Chapter 1 Practice Question Answers - Integers is a part of the Class 7 Course Mathematics (Maths) Class 7.
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FAQs on Class 7 Maths Chapter 1 Practice Question Answers - Integers

1. What are integers?
Ans. Integers are whole numbers that can be positive, negative, or zero. They do not have any fractional or decimal parts.
2. How do you compare integers?
Ans. Integers can be compared by looking at their numerical value on the number line. The integer with the greater numerical value is considered larger.
3. Can integers be added and subtracted?
Ans. Yes, integers can be added and subtracted. When adding integers with the same sign, you add their absolute values and keep the sign. When adding integers with different signs, you subtract their absolute values and keep the sign of the integer with the greater absolute value.
4. What is the difference between positive and negative integers?
Ans. Positive integers are greater than zero, while negative integers are less than zero. Positive integers are usually denoted with a plus sign (+), while negative integers are denoted with a minus sign (-).
5. How are integers used in real-life situations?
Ans. Integers are used in various real-life situations such as calculating temperatures (positive and negative values), keeping track of money (positive and negative values for income and expenses), and determining directions (positive and negative values for east and west).
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