Class 7 Maths Chapter 7 HOTS Questions - Comparing Quantities

Let us assume that
Meeta’s salary be ₹ x,
Now,
10% of ₹ x = ₹ 4000
(10/100) × (x) = 4000
X = 4000 × (100/10)
X = 4000 × 10
X = ₹ 40000
Hence Meeta’s salary is ₹ 40000.

From the above question, it is given that
The cost price of the gardening shears = ₹ 250
The selling price of the gardening shears = ₹ 325
Since (SP) > (CP), hence there is a profit.
Profit is = (SP) – (CP)
= ₹ (325 – 250)
= ₹ 75
Profit % = {(Profit/CP) × 100}
= {(75/250) × 100}
= {7500/250}
= 750/25
= 30%

From the above question, it is given that the
The cost price of the refrigerator is = ₹ 12000
The selling price of the refrigerator is = ₹ 13500
Since (SP) > (CP), hence there is a profit
Profit = (SP) – (CP)
= ₹ (13500 – 12000)
= ₹ 1500
Profit % = {(Profit/CP) × 100}
= {(1500/12000) × 100}
= {150000/12000}
= 150/12
= 12.5%

From the above question, it is given that
The cost price of the cupboard is = ₹ 2500
The selling price of the cupboard is = ₹ 3000
Since (SP) > (CP), hence there is a profit.
Profit = (SP) – (CP)
= ₹ (3000 – 2500)
= ₹ 500
Profit % = {(Profit/CP) × 100}
= {(500/2500) × 100}
= {50000/2500}
= 500/25
= 20%

Since (SP) < (CP), hence there is a loss.
Loss is = (CP) – (SP)
= ₹ (250 – 150)
= ₹ 100
Loss % = {(Loss/CP) × 100}
= {(100/250) × 100}
= {10000/250}
= 40%

From the above question, it is given that.
The Initial population of the city is = 25000
The final population of the city is = 24500
Population decrease is equal to = Initial population – Final population
= 25000 – 24500
= 500
Now,
Percentage decrease in the population = (population decrease/Initial population) × 100
= (500/25000) × 100
= (50000/25000)
= 50/25
= 2%

From the above question, it is given that.
The selling price of the washing machine is = ₹ 13500
Percentage of loss is = 20%
Now, we have to find the initial cost of price washing machine.
By using the given formula, we have:
CP = ₹ {(100/ (100 – loss %)) × SP}
= {(100/ (100 – 20)) × 13500}
= {(100/ 80) × 13500}
= {1350000/80}
= {135000/8}
= ₹ 16875

From the above question, it is given that
The cost price of the book = ₹ 275
Percentage of loss of the book = 15%
Now, we have to find the selling price of a book,
By using the below formula, we have:
SP = {((100 – loss %) /100) × CP)}
= {((100 – 15) /100) × 275)}
= {(85 /100) × 275}
= 23375/100
= ₹ 233.75

Given:
P(principal) = ₹ 56000, SI = ₹ 280, t = 2 years.
We know the formula,
R (rate) = (100 × SI) / (P × T)
= (100 × 280)/ (56000 × 2)
= (1 × 28) / (56 × 2)
= (1 × 14) / (56 × 1)
= (1 × 1) / (4 × 1)
= (1/ 4)
= 0.25%

From the above question, it is given that the
Total matches played by the local team = 20
Percentage of matches won by these local teams = 25%
Now,
The number of matches won by the team is = 25% of the 20
= (25/100) × 20
= 25/5
= 5 matches.
Hence, The local team won 5 matches out of 20 matches.

We have to find the total parts by adding the given ratio = 3 + 1 = 4
1st part = ¾ = (¾) × 100 %
= 3 × 25%
= 75%
2nd part = ¼ = (¼) × 100%
= 1 × 25
= 25%

We have to find the total parts by adding the given ratio as = 2 + 3 + 5 = 10
1st part = 2/10 = (2/10) × 100 %
= 2 × 10%
= 20%
2nd part = 3/10 = (3/10) × 100%
= 3 × 10
= 30%
3rd part = 5/10 = (5/10) × 100%
= 5 × 10
= 50%

We have to find the total parts by adding the given ratio = 1 + 4 = 5
1st part = (1/5) = (1/5) × 100 %
= 1 × 20%
= 20%
2nd part = (4/5) = (4/5) × 100%
= 4 × 20
= 80%

We have to find the total parts by adding the given ratio as = 1 + 2 + 5 = 8
1st part = 1/8 = (1/8) × 100 %
= (100/8) %
= 12.5%
2nd part = 2/8 = (2/8) × 100%
= (200/8)
= 25%
3rd part = 5/8 = (5/8) × 100%
= (500/8)
= 62.5%

From the above question, it is given that.
The cost price of the T.V. is = ₹ 10000
Percentage of profit is = 20%
Profit = (20/100) × 10000
= ₹ 2000
Then,
The selling price of the T.V. is = cost price + profit
= 10000 + 2000
= ₹ 12000
Hence Ishan will get it for ₹ 12000.

From the above question, it is given that,
The ratio of calcium, carbon and oxygen in chalk is = 10: 3: 12
So, total part = 10 + 3 + 12 = 25
In that, the total part amount of carbon = 3/25
Then,
Percentage of carbon is = (3/25) × 100
= 3 × 4
= 12 %

From the above question, it is given that,
The Weight of carbon in the chalk is = 3g
Let us assume that the weight of the stick is x
Then,
12% of x = 3
(12/100) × (x) = 3
X = 3 × (100/12)
X = 1 × (100/4)
X = 25g
∴The weight of the stick is 25g.

Given in the above question.
P (Principal) = ₹ 1200, Rate (R) = 12% p.a. and T (time) = 3years.

If the interest is calculated uniformly on an original principal throughout the loan period, then it is called Simple interest (SI).
SI = (P × R × T)/100
= (1200 × 12 × 3)/ 100
= (12 × 12 × 3)/ 1
= ₹432
Amount = (principal + SI)
= (1200 + 432)
= ₹ 1632

Given in the question: –
Principal (P) = ₹ 7500, Rate (R) = 5% p.a. and Time (T) = 3years.
If the interest is calculated uniformly on an original principal throughout the loan period, then it is called Simple interest (SI).
SI = (P × R × T)/100
= (7500 × 5 × 3)/ 100
= (75 × 5 × 3)/ 1
= ₹ 1125
Amount = (principal + SI)
= (7500 + 1125)
= ₹ 8625

Ans:
From the above question, it is given that the SI = ₹ 45, R = 9%, T = 1 year, P =?
SI = (P × R × T)/100
45 = (P × 9 × 1)/ 100
P = (45 ×100)/ 9
= 5 × 100
= ₹ 500
Hence, she borrowed ₹ 500.