Arithmetic Progressions Class 10 Notes Maths Chapter 5

What is a Sequence ?

A sequence is an arrangement of numbers in a definite order and according to some rule.
Example: 

•  2, 4, 6, 8, 10, … is a sequence where each successive item is 2 greater than the preceding term.

• 1, 4, 9, 16, 25, … is a sequence where each term is the square of successive natural numbers.

Terms 

The various numbers occurring in a sequence are called ‘terms’. Since the order of a sequence is fixed, therefore the terms are known by the position they occupy in the sequence.
Example: If the sequence is defined as

Arithmetic Progression (A.P.)

An Arithmetic progression is a special case of a sequence, where the difference between a term and its preceding term is always constant, known as common difference, i.e., d. The arithmetic progression is abbreviated as A.P.

General form of an A.P.

The general form of an A.P. is
∴ a, a + d, a + 2d,… For example, 1, 9, 11, 13.., Here the common difference is 2. Hence it is an A.P.

nth term of an A.P.

In an A.P. with first term a and common difference d, the nth term (or the general term) is given by .

a_n = a + (n – 1)d.

where [a = first term, d = common difference, n = term number

For Example,

To find seventh term put n = 7
∴ a₇ = a + (7 – 1)d or a₇ = a + 6d 

Solved Examples

Example 1: Find the value of n, if a = 10, d = 5, an = 95.

Sol: Given, a = 10, d = 5, an = 95

From the formula of general term, we have:

a_n = a + (n − 1) × d

95 = 10 + (n − 1) × 5

(n − 1) × 5 = 95 – 10 = 85

(n − 1) = 85/ 5

(n − 1) = 17

n = 17 + 1

n = 18

Example 2: Find the 20th term for the given AP:3, 5, 7, 9, ……

Sol: Given, 

3, 5, 7, 9, ……

a = 3, d = 5 – 3 = 2, n = 20

a_n = a + (n − 1) × d

a₂₀ = 3 + (20 − 1) × 2

a₂₀ = 3 + 38

⇒a₂₀ = 41

Sum of n terms of an A.P.

The sum of the first n terms of an A.P. is given by

where [a = first term, d = common difference, n = term number

Example: Find the sum of the first 30 multiples of 4.

Sol: The first 30 multiples of 4 are: 4, 8, 12, ….., 120

Here, a = 4, n = 30, d = 4

We know,

S30 = n/2 [2a + (n − 1) × d]

S30 = 30/2[2 (4) + (30 − 1) × 4]

S30 = 15[8 + 116]

S30 = 1860

Note: If a, b, c are in A.P. then b =  and b is called the arithmetic mean of a and c.