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Short Notes: Areas Related to Circles

  1. Circumference of a circle = 2πr
  2. Area of a circle = πr2 ...[where r is the radius of a circle]
  3. Area of a semi-circle =πr2/2
  4. Area of a circular path or ring: 
    Important Formulas related to CircleLet 'R' and 'r' he radii of two circles 
    Then area of shaded part = πR2 - πr2 = π(R2 - r2) = π(R + r)(R - r) 

Minor Arc and Major Arc

An arc length is called a major arc if the arc length enclosed by the two radii is greater than a semi-circle.

Minor Arc and Major Arc
If the arc subtends angle 'θ' at the centre, then the 
Length of minor arc = Minor Arc and Major Arc
Length of major arc = Minor Arc and Major Arc

Sector of a Circle and its Area

A region of a circle is enclosed by any two radii and the arc intercepted between two radii is called the sector of a circle.

Minor Sector

A sector is called a minor sector if the minor arc of the circle is part of its boundary.
OAPB is minor sector.

Minor SectorArea of minor sector = Minor Sector
Perimeter of minor sector = Minor Sector

Major Sector

A sector is called a major sector if the major arc of the circle is part of its boundary. 
OAQB is major sector
Area of major sector = Major Sector
Perimeter of major sector = Major Sector

MULTIPLE CHOICE QUESTION

Try yourself: An arc length is called a major arc if:

A

The arc length is equal to half the circumference of the circle.

B

The arc length is greater than the circumference of the circle.

C

The arc length is greater than the area of the circle.

D

The arc length is greater than a semi-circle.

Segment of a Circle and its Area

Minor Segment

The region enclosed by an arc and a chord is called a segment of the circle. The region enclosed by the chord AB & minor arc ACB is called the minor segment. 

Minor Segment
Area of Minor segment = Area of the corresponding sector - Area of the corresponding triangle
Minor Segment

Major Segment

The region enclosed by the chord AB & major arc ADB is called the major segment. Area of major segment = Area of a circle - Area of the minor segment
Area of major sector + Area of triangle
Major Segment

Example: A chord of a circle of radius 12 cm subtends an angle of 120° at the centre. Find the area of the corresponding segment of the circle. (Use π = 3.14 and √3 = 1.73).

Sol:

We use the concept of areas of sectors of circles to solve the question.

In a circle with radius r and the angle at the centre with degree measure θ:

(i) Area of the sector = θ/360 πr2

(ii) Area of the segment = Area of the sector - Area of the corresponding triangle

Let's draw a figure to visualize the given question.

Major Segment

Here, radius, r = 12 cm, ∠AOB = θ = 120°

Visually it's clear from the figure that AB is the chord that subtends 120° angle at the centre.

To find the area of the segment AYB, we have to find the area of the sector OAYB and the area of the ΔAOB

(i) Area of sector OAYB = θ/360° πr2

(ii) Area of ΔAOB = 1/2 × base × height

For finding the area of ΔAOB, draw OM ⊥ AB then find base AB and height OM using the figure as shown above.

Area of sector OAYB = 120°/360° × πr2

= 1/3 × 3.14 × (12 cm)2

= 150.72 cm2

Draw a perpendicular OM from O to chord AB

In ΔAOM and ΔBOM

AO = BO = r (radii of circle)

OM = OM (common side)

∠OMA = ∠OMB = 90° (perpendicular OM drawn)

∴ ΔAOM ≅ ΔBOM (By RHS Congruency)

⇒ ∠AOM = ∠BOM (By CPCT)

Therefore, ∠AOM = ∠BOM = 1/2 ∠AOB = 60°

In ΔAOM,

AM/OA = sin 60° and OM/OA = cos 60°

AM/12 cm = √3/2 and OM/12 cm = 1/2

AM = √3/2 × 12 cm and OM = 1/2 × 12 cm

AM = 6√3 cm and OM = 6 cm

⇒ AB = 2 AM

= 2 × 6√3 cm

= 12√3 cm

Area of ΔAOB = 1/2 × AB × OM

= 1/2 × 12√3 cm × 6 cm

= 36 × 1.73 cm2

= 62.28 cm2

Area of segment AYB = Area of sector OAYB - Area of ΔAOB

= 150.72 cm2 - 62.28 cm2

= 88.44 cm2

MULTIPLE CHOICE QUESTION

Try yourself: What is the area of the region enclosed by a chord AB and the minor arc ACB of a circle called?

 

Major Segment

A

Minor sector

B

Major segment

C

Minor segment

D

Circular region

Table for Area and Perimeter of Circle

The document Short Notes: Areas Related to Circles is a part of the Class 10 Course Mathematics (Maths) Class 10.
All you need of Class 10 at this link: Class 10

FAQs on Short Notes: Areas Related to Circles

1. What are the formulas for calculating the circumference and area of a circle?
Ans. The formula for the circumference of a circle is given by \( C = 2\pi r \), where \( r \) is the radius of the circle. The formula for the area of a circle is \( A = \pi r^2 \).
2. How do you differentiate between a minor arc and a major arc in a circle?
Ans. A minor arc is the shorter arc connecting two points on a circle, while a major arc is the longer arc connecting the same two points. The total measure of the arcs is \( 360^\circ \), so the minor arc measures less than \( 180^\circ \) and the major arc measures more than \( 180^\circ \).
3. What is a sector of a circle and how can we calculate its area?
Ans. A sector of a circle is a portion of the circle enclosed by two radii and the arc between them. The area of a sector can be calculated using the formula \( \text{Area} = \frac{\theta}{360} \times \pi r^2 \), where \( \theta \) is the angle in degrees and \( r \) is the radius.
4. What is the difference between a segment of a circle and a sector?
Ans. A segment of a circle is the area enclosed by a chord and the arc connecting the endpoints of the chord, while a sector is the area enclosed by two radii and the arc between them. The segment does not include the triangular area formed by the radii and the chord.
5. How do you find the area of a segment of a circle?
Ans. The area of a segment can be calculated using the formula: \( \text{Area of Segment} = \text{Area of Sector} - \text{Area of Triangle} \). The area of the sector can be found using \( \frac{\theta}{360} \times \pi r^2 \) and the area of the triangle can be calculated using \( \frac{1}{2} r^2 \sin(\theta) \), where \( \theta \) is the angle in radians.
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