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Mensuration: Shortcuts & Tricks | Quantitative Techniques for CLAT PDF Download

Types of questions are given where this trick can be applied.

Mensuration: Shortcuts & Tricks | Quantitative Techniques for CLAT


Mensuration: Shortcuts & Tricks | Quantitative Techniques for CLAT

Mensuration: Shortcuts & Tricks | Quantitative Techniques for CLAT

Use these Tricks

Direction: Check whether π=22/7 has been used in the formula for finding out the Particular Area, Curved Surface Area, Total Area, Volume, etc. If it is so, then
Q1: Find the surface area of a sphere whose volume is 4851 cubic meters.
(a) 1380 m2
(b) 1360 m2
(c) 1368 m2
(d) 1386 m2
Ans:
d
Sol:
Using the Trick: We know that surface area of a sphere = 4πr2
It means ‘π’ has been used in finding out the surface area of the sphere.
We can easily see that only ‘1386’ from the given options is divisible by ‘11’
Hence, surface area of the sphere = 1386 m2

Q2: The radius and height of a right circular cylinder are 14 cm & 21 cm respectively. Find its volume.
(a) 12836 cm3
(b) 12736 cm3
(c) 12936 cm3
(d) 12837 cm3

Ans: c
Sol:

Using the Trick: The know that volume of Cylinder = πr2h
We must check divisibility by ‘11’. Here, both ‘12936’ and ‘12837’ are divisible by 11. But you also notice that radius (14 cm) & height (21 cm) are both multiples of 7. So the option divisible by ‘7’ is your answer.
Hence, volume of a right circular cylinder = 12936 cm3 (since this is the only option divisible by 7)
We can test this as follows:
Volume of the given cylinder
= (22/7) × 14 × 14 × 14 × 21 cm3
= 22 × 14 × 14 × 3 cm3
⇒ Volume must be divisible by ‘7’.

Q3: The radius and height of a right circular cone are 7 cm & 18 cm respectively. Find its volume.
(a) 814 cm3
(b) 624 cm3
(c) 825 cm3
(d) 924 cm3

Ans: d
Sol: 
Using the Trick:

The option should be divisible by ‘11’ because ‘π’ has been used in finding its volume. One of the parameters is a multiple of 7 without being a higher power. So we must go through fundamentals.

Now, volume of a right circular cone = (1/3)πr2h
= (1/3) × (22/7) × 7 × 7 × 18 cm3
= 22 × 7 × 6
Clearly, we need an answer that is a multiple of 11, 7 as well as 3.
Among the given options, 814, 825 and 924 are all multiples of 11. However, we see that only one option is divisible by 7. So this is the correct answer.
Hence, volume of the given cone = 924 cm3

The document Mensuration: Shortcuts & Tricks | Quantitative Techniques for CLAT is a part of the CLAT Course Quantitative Techniques for CLAT.
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FAQs on Mensuration: Shortcuts & Tricks - Quantitative Techniques for CLAT

1. What are some shortcuts and tricks for solving mensuration problems?
Ans. Some shortcuts and tricks for solving mensuration problems include memorizing formulas for different shapes, using symmetry to simplify calculations, breaking complex shapes into simpler ones, and using the concept of similarity to solve proportion problems.
2. How can I quickly calculate the area of a circle?
Ans. To quickly calculate the area of a circle, you can use the formula A = πr^2, where A represents the area and r represents the radius of the circle. Simply square the radius and multiply it by π to find the area.
3. What is the trick to finding the surface area of a cube?
Ans. The trick to finding the surface area of a cube is to realize that all six faces are identical squares. So, instead of calculating each face individually, you can multiply the area of one face by six to find the total surface area of the cube.
4. How can I find the volume of a cylinder quickly?
Ans. To find the volume of a cylinder quickly, you can use the formula V = πr^2h, where V represents the volume, r represents the radius of the base, and h represents the height of the cylinder. Multiply the area of the base (πr^2) by the height to find the volume.
5. Are there any shortcuts for finding the volume of irregular shapes?
Ans. Unfortunately, there are no specific shortcuts for finding the volume of irregular shapes. However, you can break down the irregular shape into simpler shapes, calculate their volumes separately, and then add them up to find the total volume. This method may require more steps, but it will give an accurate result.
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