To solve number series questions efficiently, follow these steps:
Check Differences: Calculate the difference between consecutive terms to identify arithmetic or step-up patterns.
Test Ratios: Divide consecutive terms to check for geometric or ratio series.
Look for Squares/Cubes: Verify if terms are perfect squares (1, 4, 9, …) or cubes (1, 8, 27, …).
Examine Prime Numbers: Check if terms follow prime numbers (2, 3, 5, …) or their squares.
Consider Mixed Patterns: Look for alternating operations (e.g., add then multiply) in complex series.
Use Visual Aids: Plot terms on a number line or graph to visualise trends.
Example: 100,121,144,__, 196
Sol: This series consists of a perfect square of consecutive numbers 10, 11, 12, 13
Hence 169 will come in the blank.
Example: 9,64, 125, __, 343
Sol: This series consists of a series of numbers with perfect cubes that is (3 x 3 x 3), (4 x 4 x 4), (5 x 5 x 5), (6 x 6 x 6), (7 x 7 x 7)
Hence, 216 will be coming in the blank, as the series is following a trend of cubes of numbers in sequential order.
Example: 3, 6, 9, 12, __, 18, 21
Sol: Here the series is following an increasing trend in which three is added to each number of the series.
3
6 (3+3)
9 (6+3)
12 (9+3)
15 (12+3)
18 (15+3)
21 (18+3)
Example: 3, 6, 9 , 12
Sol: Here a = 3(first term of the series)
d = 3
Hence we get:
3 + 3 = 6
6 + 3 = 9
9 + 3 = 12
12 + 3 = 15
In sequences of this type, each number is obtained by multiplying or dividing each term by a constant number.
The formula for a geometric sequence (GS) is represented as {a, ar, ar2, ar3, ...}, where:
Example: 1, 2, 4, 8, 16, 32
Sol: Here a = 1 (first term of the series)
r = 2 (a standard number that is multiplied with the consecutive number of the series)
Hence, we get:
1
1 x 2
1 x 22
1 x 23, ….)
Example:
(a) 26/5
(b) 24/5
(c) 21/5
(d) 5
Sol: Here we’ve to observe the trend that this series is following, as each term is divided by a specific number, i.e., 1 then 2 then3 then 4 and so on. Hence, we can make out that the denominator must be 5.
Now comes the numerator, where the 1’st number is 1.
Then comes 5, now how can we get 5 from the term number 2. It can come by
Next comes![]()
Q1: 1, 9, 25, 49, ?
A: 81
B: 64
C: 100
D: 36
Ans: A
Sol:
Here the series is squares of odd numbers i.e., 1², 3², 5², 7² and so on.
∴ The next term will be 9² = 81.
Hence, option (a).
Q2: 0, 1, 1, 2, 3, 5, 8, ?
A: 16
B: 13
C: 25
D: 20
Ans: B
Sol:
Here each term is the sum of preceding two terms.
∴ The next term will be = 5 + 8 = 13.
Hence, option (b).
Q3: 17, 29, 53, 89, 137, ?
A: 197
B: 209
C: 185
D: 180
Ans: A
Sol:
Here each subsequent term increases by consecutive multiples of 12 i.e., +12, +24, +36, +48 and so on.
∴ The next term will be = 137 + 60 = 197.
Hence, option (a).
Q4: 13, 26, 23, 46, 43, 86, ?
A: 242
B: 269
C: 253
D: 287
Ans: A
Sol:
Here the pattern is × 2, - 3, × 2, - 3, × 2, - 3 and so on.
∴ The next term will be = 86 – 3 = 83.
Hence, option (a).
Q5: 14, 31, 65, 133, ?
A: 242
B: 269
C: 253
D: 287
Ans: B
Sol:
Here each term of the series is the preceding number multiplied by 2 and then increased by 3 i.e.,
31 = 2 × 14 + 3,
65 = 2 × 31 + 3,
133 = 2 × 65 + 3 and so on.
∴ The next term will be = 133 × 2 + 3 = 269.
Hence, option (b).
Q6: 6, 18, 55, 167, 504, ?
A: 1581
B: 1585
C: 1556
D: 1516
Ans: D
Sol:
Here the series is: 18 = 6 × 3 + 0, 55 = 18 × 3 + 1, 167 = 55 × 3 + 2, 504 = 167 × 3 + 3… and so on. ∴ The next term will be = 504 × 3 + 4 = 1516. Hence, option (d).
Q7: 1200, 240, 60, 20, ?
A: 14
B: 10
C: 12
D: 2
Ans: B
Sol:
Here the series is:
1200 ÷ 5 = 240,
240 ÷ 4 = 60,
60 ÷ 3 = 20, and so on.
∴ The next term will be = 20 ÷ 2 = 10.
Hence, option (b).
Misidentifying Series Type: Assuming an arithmetic series when ratios indicate a geometric series (e.g., 2, 4, 8 is geometric, not arithmetic).
Ignoring Mixed Patterns: Overlooking alternating operations in mixed series (e.g., 1, 2, 6, 24 requires multiplying by increasing numbers).
Calculation Errors: Miscomputing differences or ratios due to haste (e.g., 3, 6, 9 has a difference of 3, not 2).
Forgetting Formulas: Not applying arithmetic or geometric formulas for nth term or sum, leading to manual errors.
Overcomplicating Simple Series: Treating a perfect square series as a complex pattern (e.g., 1, 4, 9 is simply n²).
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