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Introduction

The particle in a box problem is a common application of a quantum mechanical model to a simplified system consisting of a particle moving horizontally within an infinitely deep well from which it cannot escape. The solutions to the problem give possible values of E and ψ that the particle can possess. E represents allowed energy values and ψ(x) is a wavefunction, which when squared gives us the probability of locating the particle at a certain position within the box at a given energy level.

Step 1: Define the Potential Energy V

The potential energy is 0 inside the box (V = 0 for 0 < x < L) and goes to infinity at the walls of the box (V = ∞ for x < 0 or x > L). We assume the walls have infinite potential energy to ensure that the particle has zero probability of being at the walls or outside the box. Doing so significantly simplifies our later mathematical calculations as we employ these boundary conditions when solving the Schrödinger Equation.

Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC

Step 2: Solve the Schrödinger Equation

The time-independent Schrödinger equation for a particle of mass m moving in one direction with energy E is
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC(4.8.1)

with

  • ℏ is the reduced Planck constant where  ℏ = h/2π
  • m is the mass of the particle
  • ψ(x) is the stationary time-independent wavefunction
  • V(x) is the potential energy as a function of position
  • E is the energy, a real number

This equation can be modified for a particle of mass  m free to move parallel to the x-axis with zero potential energy (V = 0 everywhere) resulting in the quantum mechanical description of free motion in one dimension:

Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.2)
This equation has been well studied and gives a general solution of:
ψ(x) = Asin (kx) + Bcos (kx) (4.8.3)
where A, B, and k are constants.

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Step 3: Define the Wavefunction

The solution to the Schrödinger equation we found above is the general solution for a 1-dimensional system. We now need to apply our boundary conditions to find the solution to our particular system. According to our boundary conditions, the probability of finding the particle at x = 0 or x = L is zero. When x = 0, then sin(0) = 0 and cos(0) = 1; therefore, B must equal 0 to fulfill this boundary condition giving:
ψ(x) = Asin (kx) (4.8.4)
We can now solve for our constants (A and k) systematically to define the wave function.

Solving for k
Differentiate the wavefunction concerning x:
dψ/dx = kA cos (kx) (4.8.5)
Differentiate the wavefunction again concerning x:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.6)
Since ψ(x) = A sin (kx), then
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.7)
If we then solve for k by comparing with the Schrödinger equation above, we find:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC(4.8.9)

Solving for A
To determine A, we have to apply the boundary conditions again. Recall that the probability of finding a particle at x = 0 or x = L is zero.
When x = L:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.10)
This is only true when
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.11)

where n = 1,2,3,…
Plugging this back in gives us:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.12)

To determine A, recall that the total probability of finding the particle inside the box is 1, meaning there is no probability of it being outside the box. When we find the probability and set it equal to 1, we are normalizing the wavefunction.
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.13)
For our system, the normalization looks like:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.14)
Using the solution for this integral from an integral table, we find our normalization constant,  A:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC(4.8.15)
Which results in the normalized wavefunctions for a particle in a 1-dimensional box:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC(4.8.16)
where  n=1,2,3,…

Step 4: Determine the Allowed Energies

Solving for the energy of each ψ requires substituting Equation  4.8.16 into Equation 4.8.2 to get the allowed energies for a particle in a box:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC (4.8.17)
Equation  4.8.17  is a very important result and tells us that:

  • The energy of a particle is quantized.
  • The lowest possible energy of a particle is NOT zero. This is called the zero-point energy and means the particle can never be at rest because it always has some kinetic energy.

This is also consistent with the Heisenberg Uncertainty Principle: if the particle had zero energy, we would know where it was in both space and time.

What does all this mean?

The wavefunction for a particle in a box at the n = 1 and n = 2 energy levels look like this:

Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC
The probability of finding a particle a certain spot in the box is determined by squaring ψ. The probability distribution for a particle in a box at the n = 1 and n = 2 energy levels looks like this:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSCNotice that the number of nodes (places where the particle has zero probability of being located) increases with increasing energy n. Also note that as the energy of the particle becomes greater, the quantum mechanical model breaks down as the energy levels get closer together and overlap, forming a continuum. This continuum means the particle is free and can have any energy value. At such high energies, the classical mechanical model is applied as the particle behaves more like a continuous wave. Therefore, the particle in a box problem is an example of Wave-Particle Duality.

Solved Example

Example: What is the  ΔE between the  n = 4 and n = 5 states for an F2 molecule trapped within in a one-dimension well of length 3.0 cm? At what value of  n does the energy of the molecule reach  ¼kBT at 450 K, and what is the separation between this energy level and the one immediately above it?
Ans:
Since this is a one-dimensional particle in a box problem, the particle has only kinetic energy (V = 0), so the permitted energies are:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC
with  n = 1,2,... The energy difference between n = 4 and  n = 5 is then
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC
Using Equation  4.8.17 with the mass of  F2 (37.93 amu =  6.3 × 10−26kg) and the length of the box (L = 3 × 3.0 × 10−2m2:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC
The n value for which the energy reaches 1/4kBT:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC
The separation between n + 1 and  n:
Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC

Important Facts to Learn from the Particle in the Box

  • The energy of a particle is quantized. This means it can only take on discreet energy values.
  • The lowest possible energy for a particle is NOT zero (even at 0 K). This means the particle always has some kinetic energy.
  • The square of the wavefunction is related to the probability of finding the particle in a specific position for a given energy level.
  • The probability changes with increasing energy of the particle and depends on the position in the box you are attempting to define the energy for
  • In classical physics, the probability of finding the particle is independent of the energy and the same at all points in the box.

The document Particle in a One-Dimensional Box | Chemistry Optional Notes for UPSC is a part of the UPSC Course Chemistry Optional Notes for UPSC.
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FAQs on Particle in a One-Dimensional Box - Chemistry Optional Notes for UPSC

1. What is a particle in a one-dimensional box?
Ans. A particle in a one-dimensional box refers to a theoretical concept in quantum mechanics where a particle is confined within a narrow one-dimensional region. This region is often represented as a box with infinite potential walls at its boundaries.
2. What is the significance of a particle in a one-dimensional box?
Ans. The concept of a particle in a one-dimensional box is important in quantum mechanics as it provides a simplified model to understand the behavior of particles in confined spaces. It helps in studying quantum phenomena such as energy quantization and wave-particle duality.
3. How is the energy of a particle in a one-dimensional box determined?
Ans. The energy of a particle in a one-dimensional box is determined by solving the Schrödinger equation for the corresponding system. The allowed energy states or eigenvalues are quantized and depend on the size of the box and the boundary conditions.
4. What are the boundary conditions for a particle in a one-dimensional box?
Ans. The boundary conditions for a particle in a one-dimensional box typically include the requirement that the wavefunction of the particle must be zero at the boundaries of the box. This ensures that the particle is confined within the box and does not escape.
5. What are some real-life applications of the concept of a particle in a one-dimensional box?
Ans. The concept of a particle in a one-dimensional box has applications in various fields such as solid-state physics, nanotechnology, and quantum computing. It helps in understanding the behavior of electrons in nanostructures, the formation of energy bands in solids, and the design of quantum devices.
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