Table of contents | |
Ratios | |
Proportions | |
Introduction to Direct and Inverse Proportions | |
Variations | |
Direct Proportion | |
Methods to solve Direct Proportion Problems | |
Inverse Proportion |
Ratio and proportion are fundamental concepts in mathematics that help compare quantities and understand relationships between different values. They are crucial for the CTET (Central Teacher Eligibility Test) and other educational exams. Here’s a detailed overview:
When the given ratios are equal, then these ratios are called as equivalent ratios.
The method in which first we find the value of one unit and then the value of required number of units is known as Unitary Method.
Example: Cost of two shirts in a shop is Rs.200. What will be the cost of 5 shirts in the shop?
Solution : Cost of 2 shirts = Rs.200
⇒ Cost of 1 shirt = 200/2 = 100
⇒ Cost of 5 shirts = (200/2) ∗ 5 = 100 ∗ 5
= Rs.500
There are so many situations in our life where we see some direct or indirect relationship between two things. Like
If the number of things purchased is increasing then the amount to pay will also increase.
If the speeds of the car will increase then the time to reach the destination will decreases.
If the value of two objects depends upon each other in such a way that the increase or decrease in the value of one object affects the value of another object then these two objects are said to be in variation.
Two quantities a and b are said to be in direct proportion if
Increase in a increases the b
Decrease in a decreases the b
But the ratio of their respective values must be the same.
a and b will be in direct proportion if a/b = k(k is constant) or a = kb.
In such a case if b1, b2 are the values of b corresponding to the values a1, a2 of a respectively then, a1/b2 = a2/b1
This shows that as the no. of hours worked will increase the amount of salary will also increase with the constant ratio.
When two quantities a and b are in proportion then they are written as a ∝ b where ∝ represents “is proportion to”.
There are two methods to solve the problems related to direct proportion-
As we know that,
so, if one ratio is given then we can find the other values also. (The ratio remains the constant in the direct proportion).
Example: The cost of 4-litre milk is 200 Rs. Tabulate the cost of 2, 3, 5, 8 litres of milk of same quality.
Solution:
Let X litre of milk is of cost Y Rs.
We know that as the litre will increase the cost will also increase and if the litre will decrease then the cost will also decrease.
Given,
So the cost of 2 ltr milk is 100 Rs.
So the cost of 3 ltr milk is 150 Rs.
So the cost of 5 ltr milk is 250 Rs.
So the cost of 8 ltr milk is 400 Rs.
If two quantities a and b are in direct proportion then the relation will be
k = a/b or a = kb
We can use this relation in solving the problem.
Example: If a worker gets 2000 Rs. to work for 4 hours then how much time will they work to get 60000 Rs.?
Solution:
Here,
By using this relation a = kb we can find
Hence, they have to work for 12 hours to get 60000 Rs.
Two quantities a and b are said to be in Inverse proportion if
Increase in a decreases the b
Decrease in a increases the b
But the ratio of their respective values must be the same.
a and b will be in inverse proportion if k= ab
In such a case if b1, b2 are the values of b corresponding to the values a1, a2 of a respectively then, a1b1 = a2b2 = k,
When two quantities a and b are in inverse proportion then they are written as a ∝ 1/b
This shows that as the distance of the figure from light increases then the brightness to the figure decreases.
Example: If 15 artists can make a statue in 48 hours then how many artists will be required to do the same work in 30 hours?
Solution:
Let the number of artists required to make a statue in 30 hours be y.
We know that as the no. of artists will increase the time to complete the work will reduce. So, the number of hours and number of artists are in inverse proportion.
So 48 × 15 = 30 × y (a1b1 = a2b2)
Therefore,
So, 24 artists will be required to make the statue in 30 hours.
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