Table of contents | |
Scheduling | |
Types of Scheduling | |
Sequencing | |
Johnson’s Rule |
Sequencing refers to the order in which tasks are performed, where each task begins only after the previous one is completed. Scheduling, however, involves assigning specific times for people to accomplish various tasks. Scheduling improves delivery performance and reduces manufacturing time and cost.
Operations scheduling is crucial for an organization's success, although it can be complex. Effective schedules help meet customer delivery dates and inventory targets. It involves:
Forward Operations Scheduling:
Backward Operations Scheduling:
Other Sequencing Rules:
Job Shop:
Flow Shop:
CR = [(Due date) – (Today’s date)]/Total shop time remaining
The job with the lowest S/RO is scheduled next
S/RO = [(Due date –Today’s date)–Total shop time remaining] / Number of operations remaining
Johnson’s Rules a technique that can be used to minimize the completion time for a group of jobs that are to be processed on two machines or at two successive work centers.
The Objectives of Johnson’s Rule are:
In order for the technique to be used, several conditions must be satisfied:
Minimizes makespan when scheduling a group of jobs on two workstations
Step 1: Scan the processing time at each workstation and find the shortest processing time among the jobs not yet scheduled. If two or more jobs are tied, choose one job arbitrarily.
Step 2: If the shortest processing time is on workstation 1, schedule the corresponding job as early as possible. If the shortest processing time is on workstation 2, schedule the corresponding job as late as possible.
Step 3: Eliminate the last job scheduled for further consideration. Repeat steps 1 and 2 until all jobs have been scheduled
Solved Example:
Sol:
The smallest time is 1 for Machine 1, process it first.
Next, the smallest time is 2 for Machine 2, process it last
The next smallest time is 3 of job 5 but Job 5 is already being processed by Machine 2. Discard it.
Next, the smallest time is 4 for Machine 2, process it last just before J5.
The next smallest time is 5 for job 2 but job 2 is already being processed by Machine 2. Discard it.
Next, the smallest value is 7 for Machine 2, process it last just before J2.
Next, the smallest value is for Machine 1 & Machine 2, J1 of Machine 1 is already being processed on Machine 2 . So, take J3 of Machine 2 and process it last just before J3.
So, the final sequence of processing the jobs is J4, J3, J1, J2, and J5.
Total Elapsed Time = 28
Idle time of Machine 1 = 0
Idle time of Machine 2 = 1 (Machine 2 has to wait for Machine 1 for 1 unit during the execution of Job 4.
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1. What are the different types of scheduling methods used in mechanical engineering? |
2. How does sequencing play a role in scheduling in mechanical engineering? |
3. What is Johnson's Rule and how is it used in scheduling? |
4. How can mechanical engineers benefit from implementing effective scheduling techniques? |
5. What are some common challenges faced when it comes to sequencing and scheduling in mechanical engineering projects? |
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