Table of contents | |
Logical Reasoning | |
Mathematical Reasoning | |
Everyday Mathematics | |
Achievers Section |
Note: The questions provided in this document are similar to the questions that were asked in the actual Olympiad exam. So, we recommend you study these for your Olympiad preparation
Q1: Find the word that can be made from the letters of the given word.
DESTINATION
(a) INCITE
(b) MOTION
(c) ACTION
(d) TENTION
Ans: (d)
TENTION can be formed from the letters of the given word.
Q2: Isha spent 25 minutes on her homework last night? She started at 8:10 p.m. What time did she finish her work?
(a) 8:35 a.m.
(b) 8:25 a.m.
(c) 8:45 p.m.
(d) 8:35 p.m.
Ans: (d)
8 : 10 + 25 minutes = 8 : 35 p.m.
Q3: There are 25 boats. If each boat can hold 30 people. How many people in total do all the boats hold?
(a) 750
(b) 700
(c) 850
(d) 800
Ans: (a)
Number of boats = 25
Number of people held by 1 boat = 30
Total people in all boats = 25 × 30 = 750 people.
Q4: Some numbers are given which are numbered 1, 2, 3, 4, 5, and 6. Find the combination of numbers so that the letters are arranged accordingly to form a meaningful English word.
(a) 3, 1, 5, 2, 4, 6
(b) 3, 1, 5, 2, 6, 5
(c) 2, 4, 6, 1, 3, 5
(d) 3, 2, 1, 5, 4, 6
Ans: (a)
Q5: Ritesh was born on July 10th, Naman was born on September 10th of the same year. How many months older is Ritesh?
(a) 3 months
(b) 5 months
(c) 4 months
(d) 2 months
Ans: (d)
Ritesh is 2 months older than Naman.
Q6: Form the word using given letters and find the category in which they belong?
L A I P R
(a) Name of Bird
(b) Name of Month
(c) Name of an Animal
(d) Name of Day
Ans: (b)
Word formed is APRIL.
Q7: Keshav saw 2 cows and 2 horses outside. How many legs did he see?
(a) 12
(b) 14
(c) 16
(d) 20
Ans: (c)
A cow has 4 legs and a horse has also 4 legs.
Number of cows = 2
Number of legs of 2 cows = 4 + 4 = 8
Number of horses = 2
Number of legs of 2 horses = 4 + 4 = 8
Total number of legs = 8 + 8 = 16
Q8: How many circles are there in the given diagram?
(a) 6
(b) 5
(c) 8
(d) 10
Ans: (b)
There are total 5 circles in the given diagram.
Q9: How many triangles are there in the figure given below?
(a) 6
(b) 9
(c) 10
(d) 12
Ans: (d)
The figure has 12 triangles.
Q10: In the given picture, A is the ............ of the circle:
(a) radius
(b) circumference
(c) diameter
(d) centre
Ans: (d)
A is the centre of the circle.
Q11: Roman numeral for 18 is:
(a) XVII
(b) XVIII
(c) XIX
(d) XV
Ans: (b)
18 = 10 + 8
= X + VIII
∴ 18 = XVIII
Q12: Which of the following has the greatest number of factors?
(a) 12
(b) 24
(c) 48
(d) 36
Ans: (c)
Q13: Find the Roman number equivalent to the difference of 500 and 200.
(a) C
(b) CCC
(c) MMM
(d) D
Ans: (b)
500 – 200 = 300 = 100 + 100 + 100 = CCC
Q14: Which of the following is arranged in increasing order?
(a) CXLVI, CLXXXIX, DLXVIII, CMLXXVII
(b) CXLVI, CMLXXVII, CLXXXIX, DLXVIII
(c) CMLXXVII, DLXVIII, CLXXXIX, CXLVI
(d) CMLXXVII, CLXXXIX, DLXVIII, CXLVI
Ans: (a)
Q15: What is the place value of 5 in the number 45,321?
(a) 50
(b) 5000
(c) 500
(d) 50000
Ans: (b)
Place value of digit 5 in the number 45321 = 5 × 1000 = 5000.
Q16: How many times does the place value of 8 in the numeral 2583219705 is greater than the face value of 8?
(a) 10000000
(b) 1000000
(c) 100000
(d) 1000
Ans: (a)
In number 2583219705
Face value of 8 = 8
Place value of 8 = 8 × 1,00,00,000
= 8,00,00,000
So, place value of 8 is 10000000 times of face value of 8.
Q17: Use 1, 0, 4, 1, 6 to build the smallest 5-digit number:
(a) 10,461
(b) 10,146
(c) 10,641
(d) 11,640
Ans: (b)
Given digits 1, 0, 4, 1, 6 Smallest 5-digit number = 10,146
Q18: 4,156 rounded off is to nearest thousand:
(a) 4,000
(b) 5,000
(c) 1,000
(d) 6,000
Ans: (a)
Round off 4156 is 4000.
Q19: For the annual examination 1176 children were made to sit in 21 rooms. If every room had equal number of children, find the number of children sitting in one room.
(a) 60
(b) 56
(c) 54
(d) 42
Ans: (b)
Number of children sitting in one room = 1176 ÷ 21 = 56
Q20: Find the number of buses required to carry 20,625 passengers waiting at the bus stand for Haridwar, if each bus carries 165 passengers?
(a) 105
(b) 115
(c) 120
(d) 125
Ans: (d)
Required number of buses = 20,625 ÷ 165 = 125
Q21: A rectangular playground measures 120 m in length and 80 m in width. What is the total distance Avantika covered by walking around this field 4 times?
(a) 400 m
(b) 1600 m
(c) 800 m
(d) 3200 m
Ans: (b)
Q22: Anjana has to cover 20 km 560 m distance. She walked 1 km 200 m. She covered 10 km 150 m by an auto and the rest of the distance by car. How much distance did she cover by car?
(a) 9 km 21 m
(b) 9 km 210 m
(c) 7 km 350 m
(d) 7 km 300 m
Ans: (b)
Q23: Arjun’s weight is 34 kg 375 g. Kapil’s weight is two times Arjun’s weight. What is the total weight of both of them?
(a) 103 kg 125 g
(b) 103 kg 375 g
(c) 68 kg 750 g
(d) 98 kg 250 g
Ans: (a)
Q24: Deepak filled 17 L 450 mL of water in a tank each day. What is the total amount of water he filled over 7 days?
(a) 110 L 120 mL
(b) 102 L 150 mL
(c) 150 L
(d) 122 L 150 mL
Ans: (d)
Q25: Manoj has read 8/9 of a book. The book contains a total of 1431 pages. How many pages does he still need to read?
(a) 140
(b) 113
(c) 159
(d) 195
Ans: (c)
Q26: Aman is XXI years old. Raghav is XV years older than Aman. The sum of their ages (in years) is ________.
(a) 57
(b) 52
(c) 29
(d) 38
Ans: (a)
Q27: 20 chairs and 15 tables were bought for a hotel. If the price of each chair is ₹110 and each table is ₹235, what is the total cost to be paid?
(a) ₹5725
(b) ₹5000
(c) ₹8250
(d) ₹7359
Ans: (a)
Q28: The XYZ company estimated the cost to build a new baseball stadium which is Rupees ninety-four thousand. What is this number in numeral form?
(a) ₹90400
(b) ₹94000
(c) ₹90004
(d) ₹90040
Ans: (b)
Q29: 950 nuts are produced in a factory each day. What is the total number of nuts that can be produced in 60 days?
(a) 57000
(b) 58000
(c) 60000
(d) 62000
Ans: (a)
Q30: When X is divided by 16, the quotient is 256 and the remainder is 14, find the value of X.
(a) 4110
(b) 4010
(c) 3910
(d) 3810
Ans: (a)
Here, X is dividend.
Since, Dividend = Quotient × Divisor + Remainder
So, X = 256 × 16 + 14 = 4096 + 14 = 4110
31. In a zoo, there were 15 lions and peacocks altogether. The number of heads was 25 less than the number of legs. How many more peacocks were there?
(a) 20
(b) 15
(c) 10
(d) 5
Ans: (d)
Heads of lions + heads of peacocks = 15
Number of heads (lions + peacocks) = Number of legs (lions + peacocks) – 25
So, number of legs (lions + peacocks) = Number of heads (lions + peacocks) + 25 = 15 + 25 = 40
Since, total number of legs was 40, then number of lions has to be less than 10 (because 10 × 4 = 40, which means zero peacock, which is not possible).
So, if we take 5 lions and 10 peacocks, then Total number of legs = 5 × 4 + 10 × 2 = 20 + 20 = 40
Thus, number of peacocks = 10 More peacocks than lions = 10 – 5 = 5
Q32: What is the sum of the first and second common multiples of 4 and 6?
(a) 36
(b) 144
(c) 72
(d) 288
Ans: (a)
Multiples of 4 = 4, 8, 12, 16, 20, 24, 28....
Multiples of 6 = 6, 12, 18, 24, 30, 36….
First multiple of 4 and 6 = 12,
Second multiple of 4 and 6 = 24
So, sum = 12 + 24 = 36.
Q33: A number is greater than 50 but smaller than 59. It has only two factors. What is the number?
(a) 51
(b) 55
(c) 53
(d) 57
Ans: (c)
The required number is the prime number between 50 and 59 because prime number has only two factors 1 and the number itself.
So, prime number between 50 and 59 is 53.
Q34: Find the difference between the numbers of right angles in the following figures:
(a) 4
(b) 3
(c) 5
(d) 6
Ans: (a)
Q35: Total weight of 3 bags of rice is 8 kg 950 g. Weight of bag A is 2 kg 950 g. If weight of Bag B is 900 g more than the weight of bag C, then find the difference between the weight of bag A and bag B.
(a) 500 g
(b) 600 g
(c) 3 kg 400 g
(d) 540 g
Ans: (a)
Weight of Bag A + Weight of Bag B + Weight of Bag C = 8 kg 950 g = 8950 g
Given, weight of bag A = 2 kg 950 g = 2950 g Let Weight of bag C = x g
Then, Weight of bag B = (900 + x) g
Therefore,
2950 g + (900 + x) g + x g = 8950 g 2x = 5100 g x = 2550 g (weight of bag C)
Thus, weight of bag B = (900 + 2550) g = 3450 g
Difference between weight of Bag A and Bag B = (3450 – 2950) g = 500 g
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