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Mathematics Olympiad Previous Year Paper - 2 | Mathematics Olympiad for Class 3 PDF Download

Note: The questions provided in this document are similar to the questions that were asked in the actual Olympiad exam. So, we recommend you study these for your Olympiad preparation.

Logical Reasoning

Q1: Which of the following letters is not hidden in the given figure?
(a) D
(b) T
(c) R
(d) L

Mathematics Olympiad Previous Year Paper - 2 | Mathematics Olympiad for Class 3

View Answer

Ans: (c)

Mathematics Olympiad Previous Year Paper - 2 | Mathematics Olympiad for Class 3

Alphabet R is not present in the figure.

Q2: Find the odd one out.
(a) Train
(b) Motor car
(c) Motor bike
(d) Aeroplane

View Answer

Ams: (d)
Aeroplane is the odd one out as it is the air based means of transport whereas others are land based means of transport.

Q3: If 'Cat' is called Watch, 'Watch' is called 'Dog', 'Dog' is called 'Tea' and 'Tea' is called 'Drink', then what will Yuri will use ____ to see the time.
(a) Dog
(b) Watch
(c) Cat
(d) Tea

View Answer

Ans: (a)
Yuri will use a Watch to see the time but Watch is called Dog.

Q4: In a queue of men, whose strength is 19, Ram is standing in the middle. What will be his place if we start to count from the left hand side of that line?
(a) 8^th
(b) 9^th
(c) 10^th
(d) 11^th

View Answer

Ans: (b)

Mathematics Olympiad Previous Year Paper - 2 | Mathematics Olympiad for Class 3

Ram is on the 9th position when we count from the left side of the queue.

Q5: If Hari does not go to play cricket on 5thof July and goes only on odd number of days in July 2000, then find out for how many days does he go to play cricket? (Assume that Sunday is not counted in between.)

(a) 14
(b) 13
(c) 12
(d) 11

View Answer

Ans: (b)
Hari goes on 1, 3, 7, 11, 13, 15, 17, 19, 21, 25, 27, 29 and 31 of July.
Therefore, 13 number of days.

Q6: Look at the given pattern and answer the following question.
27, 35, 43, 51, __
What will come in place of the blank?
(a) 56
(b) 57
(c) 58
(d) 59

View Answer

Ans: (d)
27 + 8 = 35
35 + 8 = 43
43 + 8 = 51
51 + 8 = 59
So, 59 is the missing number.

Q7: There is a certain relationship between the pair of numbers on either side of '::'. Identify the relationship of given pair and find the missing number.2 : 8 :: 3 : ?
(a) 3
(b) 9
(c) 27
(d) 2

View Answer

Ans: (c)
As, 2 x 2 x 2 = 8
Similarly,
3 x 3 x 3 = 27

Q8: Samaira is playing a word puzzle game as shown in the figure. Which letter from the given options will replace the question mark (?) to form name of a animal and name of a metal?

(a) I
(b) M
(c) O
(d) U

View Answer

Ans: (c)
Name of the animal is frog and name of the metal is bronze as shown in the given figure.

Mathematics Olympiad Previous Year Paper - 2 | Mathematics Olympiad for Class 3

Therefore, O will replace the question mark '?'.

Q9: Identify the category to which the word belongs after arranging it in meaningful order.
OTREMH
(a) Fruit
(b) Bird
(c) Parent
(d) Vegetable

View Answer

Ans: (c)
Word formed by OTREMH is MOTHER, and MOTHER is a parent.

Q10: If R is removed from the given arrangement, then A is at which place from right?
(a) Sixth
(b) Fifth
(c) Fourth
(d) Third

View Answer

Ans: (b)
If R is removed from the given arrangement then, A will be fifth from the right as shown below.
C A R O T S
6 5 4 3 2 1

Mathematical Reasoning

Q11: For a christmas party, a person bought 529 candies. Find the cost of all the candies if 1 candy costs Rs. 12.
(a) Rs. 6348
(b) Rs. 6338
(c) Rs. 541
(d) Rs. 517

View Answer

Ans: (a)
Cost of 1 candy = Rs. 12
Total number of candies = 529
Cost of 529 candies = 529 × 12 = Rs. 6348

Q12: John had Rs. 5450 in his pocket. How much money would one needy person get if John distributed the money equally among 5 needy people?
(a) Rs. 1090
(b) Rs. 1190
(c) Rs. 746
(d) Rs. 109

View Answer

Ans: (a)
Total amount with John = Rs. 5450
Number of needy people = 5
Amount that each needy person will get = Rs. = Rs. 1090

Q13: The product of 7 and a number is 1071. Find the number.
(a) 7497
(b) 1064
(c) 153
(d) 121

View Answer

Ans: (c)
Let the number be X.
Then, X × 7 = 1071
So, X = 1071/7 = 153

Q14: Vidyut was watching a football match on the T.V. and the match started at 3:00 pm. After 50 minutes, the electricity went off, but actual time for the football match to be end was 4:35 pm. For how many minutes is the match missed by Vidyut?
(a) 35 minutes
(b) 39 minutes
(c) 41 minutes
(d) 45 minutes

View Answer

Ans: (d)
Starting time of the match = 3:00 pm
Ending time of the match = 4:35 pm
Total duration of the match = 1 hour and 35 minutes or 95 minutes (1 hour = 60 minutes)
Duration for which Vidyut watched the match = 50 minutes
Total duration of the match missed by Vidyut = (95 - 50) minutes = 45 minutes

Q15: What number will come in place of the question mark '?' in the following equation?
56 ÷ 7 = 10 - ?
(a) 1
(b) 2
(c) 3
(d) 40

View Answer

Ans: (b)
Let the missing number be 'X'.
56 ÷ 7 = 10 - X
8 = 10 - X
X = 2
So, the missing number is 2.

Q16: Which of the following has the same weight as 1.36 kg of potatoes?
(a) A greeting card that weighs 100 g
(b) A pack of pens that weighs 1,360 g
(c) A box of raisins that weighs 1,000 g
(d) A bundle of text books that weighs 1,500 g

View Answer

Ans: (b)
1 kg = 1,000 gm
1.36 kg = 1,360 gm
So, a package of pens that weighs 1,360 gm has the same weight as 1.36 kg of potatoes.

Q17: If Amy saves Rs. 20 per day, how much will she save in a week?
(a) Rs. 160
(b) Rs. 150
(c) Rs. 140
(d) Rs. 100

View Answer

Ans: (c)
Money saved in 1 day = Rs. 20
Money saved in a week (7 days) = Rs. 20 × 7 = Rs. 140

Q18: Ajay bought 48 jigsaw puzzles. Each puzzle had 24 pieces. How many jigsaw puzzle pieces did Ajay get in all?
(a) 72
(b) 258
(c) 1125
(d) 1152

View Answer

Ans: (d)
Number of pieces in each puzzle = 24
Number of puzzles = 48
Total number of pieces = 24 × 48 = 1152

Q19: Amit rides 48 m in a ground on his bicycle. How much distance does he cover in 'mm'?
(a) 48,000 mm
(b) 4800 mm
(c) 480 mm
(d) 4.8 mm

View Answer

Ans: (a)
Distance covered by Amit = 48 m
1 m = 1000 mm
So, distance covered in mm = 48 × 1000 mm = 48,000 mm

Q20: Shakira has 50 chocolates. She needs to divide chocolates among 10 friends. How many chocolates will each friend get?
(a) 5
(b) 10
(c) 15
(d) 20

View Answer

Ans: (a)
Total number of chocolates = 50
Number of friends = 10
So, number of chocolates each friend gets = 50/10 = 5

Q21: Sherry went on a 52 km journey. She divided the distance travelled evenly over 4 days. How many metres did Sherry walk each day?
(a) 0.013 m
(b) 5200 m
(c) 1300 m
(d) 13,000 m

View Answer

Ans: (d)
Total distance covered in 4 days = 52 km
Distance covered in 1 day = km = 13 km
Distance covered (in metres) = 13,000 m [As 1 km = 1000 m]

Q22: If a bag weighs 96 kg, how much does it weigh in grams?
(a) 9600 g
(b) 96,000 g
(c) 9.60 g
(d) 0.096 g

View Answer

Ans: (b)
Volume of bag = 96 kg
As 1 kg = 1000 g
96 kg = 96 × 1000 g = 96,000 g
So, volume of bag (in grams) = 96,000 g

Q23: Rahul's birthday is 15 days before the last day of February month of a leap year. When is Rahul's birthday?
(a) 16^thFebruary
(b) 15^th February
(c) 14^th February
(d) 13^th Fenruary

View Answer

Ans: (c)
An extra day is added in a leap year—February 29—which is called an intercalary day or a leap day.
So, last day of February month of a leap year = 29^th
Rahul's birthday = 29 - 15 = 14^th February

Q24: Find the value of:
A + B + C × D
(a) 84(b) 48(c) 67
(d) 10

View Answer

Ans: (c)
Mathematics Olympiad Previous Year Paper - 2 | Mathematics Olympiad for Class 3 The value of A = 0, B = 4, C = 7 and D = 9.So, A + B + C × D = 0 + 4 + 7 × 9
Using BODMAS,
A + B + C × D = 0 + 4 + 7 x 9 = 67

Q25: Two kids, Rahul and Manish, weigh 32 kg and 24 kg, respectively. Find who is heavier and by how much.
(a) Rahul, 32 kg
(b) Manish, 24 kg
(c) Rahul, 8 kg
(d) Manish, 8 kg

View Answer

Ans: (c)
Weight of Rahul = 32 kg
Weight of Manish = 24 kg
Weight of Rahul > Weight of Manish
Required difference = (32 – 24) kg = 8 kg

Q26: Arpit travelled from point A to point B and covered 1750 km. While returning, he took a shortcut, in which he just travelled 1250 km. What is the difference between the two distances travelled?
(a) 400 km
(b) 450 km
(c) 500 km
(d) 550 km

View Answer

Ans: (c)
Distance travelled while returning = 1250 km
Distance travelled from point A to point B = 1750 km
So, required difference = (1750 – 1250) km = 500 km

Q27: Rahul makes 32 cookies. If he shares this equally among his four friends, how many cookies will each friend receive?
(a) 8
(b) 6
(c) 4
(d) 1

View Answer

Ans: (a)
Number of cookies = 32
Number of friends = 4
Number of cookies with each friend = 32 ÷ 4 = 8

Q28: Ravneet goes to buy a model of a house. She observes the prices of the models of two houses as Rs. 8299 and Rs. 8999. If she buys both the models, then how much money does she need to pay to the shopkeeper?
(a) Rs. 17,298
(b) Rs. 17,198
(c) Rs. 17,098
(d) Rs. 16,998

View Answer

Ans: (a)
Total money needs to be paid to the shopkeeper = 8299 + 8999 = Rs. 17,298

Q29: I am greater than 360 and less than 390. If you add my first and third digits, you will get 9. What am I?
(a) 356
(b) 376
(c) 396
(d) 369

View Answer

Ans: (b)
The number lies between 360 and 390, so it is a three-digit number whose hundreds digit is 3.
Also, the sum of the first and third digits is 9. So, ones digit is 6.
So, numbers can be 366, 376, or 386.
Hence, 376 is the required answer.

Q30: Which number am I? There is 6 at my hundreds place. There is 2 at my ones place. There is 4 at my thousands place. There is 7 at my tens place.
(a) 4627
(b) 4672
(c) 4762
(d) 6247

View Answer

Ans: (b)
There is 2 at my ones place.
There is 7 at my tens place.
There is 6 at my hundreds place.
There is 4 at my thousands place.
So, I am '4672'.

Achievers Section

Q31: Look at the number bond below and then find the answer for 2A.

(a) 20
(b) 15
(c) 10
(d) 5

View Answer

Ans: (a)
According to the question,
25 + 6A + 2A = 105
8A = 80
A = 10
So, 2A = 20

Q32: Mr. Kumar wrote 3 digit number on his notebook. Three students Ria, Sumit and Falak gave the following statements about the numbers.
Ria - It is the 3 digit number but not the least.
Sumit - The first digit is smaller than 1.
Falak - Last two digits can be divided by 2.
If only two out of three students said the truth, who is definitely lying?
(a) Ria
(b) Sumit
(c) Falak
(d) Both Sumit and Falak

View Answer

Ans: (b)
Sumit said the first digit is smaller than 1 is 0. Therefore, if the number will start from 0, it will make a two digit number.

Q33: This is the calendar for September 2015. If Rajesh is starting his training for shooting on day 5th of the month and his training will be every 6th day, which will be the last date of his training of the month?
(a) 29^thSeptember
(b) 26^th September
(c) 30^th September
(d) None of these

View Answer

Ans: (a)
Rajesh is starting his training from 5^th September, so his training days will be as follows:
11, 17, 23, 29
So, 29th September will be the last day of his training.

Q34: Bag 1 contains 60 kg of rice and bag 2 weighs 15 kg less than the weight of bag 1. Find the total quantity of rice in both the bags in grams.
(a) 1,35,000
(b) 1,00,000
(c) 1,05,000
(d) 10,500

View Answer

Ans: (c)
Weight of bag 1 = 60 kg
Weight of bag 2 = 60 kg - 15 kg = 45 kg
Total weight = 60 kg + 45 kg = 105 kg
As, 1 kg = 1000 g
So, 105 kg = 105 × 1000 g = 1,05,000 g

Q35: A music academy has five rooms and in each room there are 32 students. Chahat wants to distribute 640 candies fairly between all the students of the academy. How many candies will each student get?
(a) 3
(b) 4
(c) 5
(d) 6

View Answer

Ans: (b)
Number of rooms = 5
Number of students in each room = 32
Total number of students = 32 × 5 = 160
Chahat wants to distribute 640 candies fairly between all the students of the academy.
Thus, each student will get 640 ÷ 160 candies.
640 ÷ 160 = 4 candies

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FAQs on Mathematics Olympiad Previous Year Paper - 2 - Mathematics Olympiad for Class 3

1. What is the format of the Mathematics Olympiad for Class 3?

Ans. The Mathematics Olympiad for Class 3 typically consists of multiple-choice questions that assess various mathematical concepts, logical reasoning, and problem-solving skills. The exam usually includes questions from topics such as addition, subtraction, multiplication, division, patterns, and basic geometry.

2. How can students prepare for the Mathematics Olympiad?

Ans. Students can prepare for the Mathematics Olympiad by practicing sample papers from previous years, solving math puzzles, and engaging in group study sessions. It is also helpful to understand the concepts thoroughly and clarify any doubts with teachers or peers.

3. What topics are usually covered in the Class 3 Mathematics Olympiad?

Ans. The Class 3 Mathematics Olympiad generally covers topics such as basic arithmetic (addition, subtraction, multiplication, and division), patterns, fractions, measurement (length, weight, volume), and introductory geometry (shapes and their properties).

4. Are there any specific resources recommended for Olympiad preparation for Class 3?

Ans. Yes, recommended resources include Olympiad preparation books, online practice tests, and worksheets specifically designed for Class 3 students. Websites that offer math games and interactive quizzes can also be beneficial for engaging practice.

5. What are the benefits of participating in the Mathematics Olympiad for Class 3 students?

Ans. Participating in the Mathematics Olympiad helps students enhance their problem-solving skills, boosts their confidence in mathematics, and provides a competitive platform to evaluate their understanding of mathematical concepts. It also encourages a love for math and critical thinking from an early age.

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