Note: The questions provided in this document are similar to the questions that were asked in the actual Olympiad exam. So, we recommend you study these for your Olympiad preparation.
Ans: (c)
Alphabet R is not present in the figure.
Q2: Find the odd one out.
(a) Train
(b) Motor car
(c) Motor bike
(d) Aeroplane
Ams: (d)
Aeroplane is the odd one out as it is the air based means of transport whereas others are land based means of transport.
Q3: If 'Cat' is called Watch, 'Watch' is called 'Dog', 'Dog' is called 'Tea' and 'Tea' is called 'Drink', then what will Yuri will use ____ to see the time.
(a) Dog
(b) Watch
(c) Cat
(d) Tea
Ans: (a)
Yuri will use a Watch to see the time but Watch is called Dog.
Q4: In a queue of men, whose strength is 19, Ram is standing in the middle. What will be his place if we start to count from the left hand side of that line?
(a) 8th
(b) 9th
(c) 10th
(d) 11th
Ans: (b)
Ram is on the 9th position when we count from the left side of the queue.
Q5: If Hari does not go to play cricket on 5thof July and goes only on odd number of days in July 2000, then find out for how many days does he go to play cricket? (Assume that Sunday is not counted in between.)
(a) 14
(b) 13
(c) 12
(d) 11
Ans: (b)
Hari goes on 1, 3, 7, 11, 13, 15, 17, 19, 21, 25, 27, 29 and 31 of July.
Therefore, 13 number of days.
Q6: Look at the given pattern and answer the following question.
27, 35, 43, 51, __
What will come in place of the blank?
(a) 56
(b) 57
(c) 58
(d) 59
Ans: (d)
27 + 8 = 35
35 + 8 = 43
43 + 8 = 51
51 + 8 = 59
So, 59 is the missing number.
Q7: There is a certain relationship between the pair of numbers on either side of '::'. Identify the relationship of given pair and find the missing number.2 : 8 :: 3 : ?
(a) 3
(b) 9
(c) 27
(d) 2
Ans: (c)
As, 2 x 2 x 2 = 8
Similarly,
3 x 3 x 3 = 27
Q8: Samaira is playing a word puzzle game as shown in the figure. Which letter from the given options will replace the question mark (?) to form name of a animal and name of a metal?
(a) I
(b) M
(c) O
(d) U
Ans: (c)
Name of the animal is frog and name of the metal is bronze as shown in the given figure.
Therefore, O will replace the question mark '?'.
Q9: Identify the category to which the word belongs after arranging it in meaningful order.
OTREMH
(a) Fruit
(b) Bird
(c) Parent
(d) Vegetable
Ans: (c)
Word formed by OTREMH is MOTHER, and MOTHER is a parent.
Q10: If R is removed from the given arrangement, then A is at which place from right?
(a) Sixth
(b) Fifth
(c) Fourth
(d) Third
Ans: (b)
If R is removed from the given arrangement then, A will be fifth from the right as shown below.
C A R O T S
6 5 4 3 2 1
Ans: (a)
Cost of 1 candy = Rs. 12
Total number of candies = 529
Cost of 529 candies = 529 × 12 = Rs. 6348
Q12: John had Rs. 5450 in his pocket. How much money would one needy person get if John distributed the money equally among 5 needy people?
(a) Rs. 1090
(b) Rs. 1190
(c) Rs. 746
(d) Rs. 109
Ans: (a)
Total amount with John = Rs. 5450
Number of needy people = 5
Amount that each needy person will get = Rs. = Rs. 1090
Q13: The product of 7 and a number is 1071. Find the number.
(a) 7497
(b) 1064
(c) 153
(d) 121
Ans: (c)
Let the number be X.
Then, X × 7 = 1071
So, X = 1071/7 = 153
Q14: Vidyut was watching a football match on the T.V. and the match started at 3:00 pm. After 50 minutes, the electricity went off, but actual time for the football match to be end was 4:35 pm. For how many minutes is the match missed by Vidyut?
(a) 35 minutes
(b) 39 minutes
(c) 41 minutes
(d) 45 minutes
Ans: (d)
Starting time of the match = 3:00 pm
Ending time of the match = 4:35 pm
Total duration of the match = 1 hour and 35 minutes or 95 minutes (1 hour = 60 minutes)
Duration for which Vidyut watched the match = 50 minutes
Total duration of the match missed by Vidyut = (95 - 50) minutes = 45 minutes
Q15: What number will come in place of the question mark '?' in the following equation?
56 ÷ 7 = 10 - ?
(a) 1
(b) 2
(c) 3
(d) 40
Ans: (b)
Let the missing number be 'X'.
56 ÷ 7 = 10 - X
8 = 10 - X
X = 2
So, the missing number is 2.
Q16: Which of the following has the same weight as 1.36 kg of potatoes?
(a) A greeting card that weighs 100 g
(b) A pack of pens that weighs 1,360 g
(c) A box of raisins that weighs 1,000 g
(d) A bundle of text books that weighs 1,500 g
Ans: (b)
1 kg = 1,000 gm
1.36 kg = 1,360 gm
So, a package of pens that weighs 1,360 gm has the same weight as 1.36 kg of potatoes.
Q17: If Amy saves Rs. 20 per day, how much will she save in a week?
(a) Rs. 160
(b) Rs. 150
(c) Rs. 140
(d) Rs. 100
Ans: (c)
Money saved in 1 day = Rs. 20
Money saved in a week (7 days) = Rs. 20 × 7 = Rs. 140
Q18: Ajay bought 48 jigsaw puzzles. Each puzzle had 24 pieces. How many jigsaw puzzle pieces did Ajay get in all?
(a) 72
(b) 258
(c) 1125
(d) 1152
Ans: (d)
Number of pieces in each puzzle = 24
Number of puzzles = 48
Total number of pieces = 24 × 48 = 1152
Q19: Amit rides 48 m in a ground on his bicycle. How much distance does he cover in 'mm'?
(a) 48,000 mm
(b) 4800 mm
(c) 480 mm
(d) 4.8 mm
Ans: (a)
Distance covered by Amit = 48 m
1 m = 1000 mm
So, distance covered in mm = 48 × 1000 mm = 48,000 mm
Q20: Shakira has 50 chocolates. She needs to divide chocolates among 10 friends. How many chocolates will each friend get?
(a) 5
(b) 10
(c) 15
(d) 20
Ans: (a)
Total number of chocolates = 50
Number of friends = 10
So, number of chocolates each friend gets = 50/10 = 5
Q21: Sherry went on a 52 km journey. She divided the distance travelled evenly over 4 days. How many metres did Sherry walk each day?
(a) 0.013 m
(b) 5200 m
(c) 1300 m
(d) 13,000 m
Ans: (d)
Total distance covered in 4 days = 52 km
Distance covered in 1 day = km = 13 km
Distance covered (in metres) = 13,000 m [As 1 km = 1000 m]
Q22: If a bag weighs 96 kg, how much does it weigh in grams?
(a) 9600 g
(b) 96,000 g
(c) 9.60 g
(d) 0.096 g
Ans: (b)
Volume of bag = 96 kg
As 1 kg = 1000 g
96 kg = 96 × 1000 g = 96,000 g
So, volume of bag (in grams) = 96,000 g
Q23: Rahul's birthday is 15 days before the last day of February month of a leap year. When is Rahul's birthday?
(a) 16th February
(b) 15th February
(c) 14th February
(d) 13th Fenruary
Ans: (c)
An extra day is added in a leap year—February 29—which is called an intercalary day or a leap day.
So, last day of February month of a leap year = 29th
Rahul's birthday = 29 - 15 = 14th February
Q24: Find the value of:
A + B + C × D
(a) 84(b) 48(c) 67
(d) 10
Ans: (c)
The value of A = 0, B = 4, C = 7 and D = 9.So, A + B + C × D = 0 + 4 + 7 × 9
Using BODMAS,
A + B + C × D = 0 + 4 + 7 x 9 = 67
Q25: Two kids, Rahul and Manish, weigh 32 kg and 24 kg, respectively. Find who is heavier and by how much.
(a) Rahul, 32 kg
(b) Manish, 24 kg
(c) Rahul, 8 kg
(d) Manish, 8 kg
Ans: (c)
Weight of Rahul = 32 kg
Weight of Manish = 24 kg
Weight of Rahul > Weight of Manish
Required difference = (32 – 24) kg = 8 kg
Q26: Arpit travelled from point A to point B and covered 1750 km. While returning, he took a shortcut, in which he just travelled 1250 km. What is the difference between the two distances travelled?
(a) 400 km
(b) 450 km
(c) 500 km
(d) 550 km
Ans: (c)
Distance travelled while returning = 1250 km
Distance travelled from point A to point B = 1750 km
So, required difference = (1750 – 1250) km = 500 km
Q27: Rahul makes 32 cookies. If he shares this equally among his four friends, how many cookies will each friend receive?
(a) 8
(b) 6
(c) 4
(d) 1
Ans: (a)
Number of cookies = 32
Number of friends = 4
Number of cookies with each friend = 32 ÷ 4 = 8
Q28: Ravneet goes to buy a model of a house. She observes the prices of the models of two houses as Rs. 8299 and Rs. 8999. If she buys both the models, then how much money does she need to pay to the shopkeeper?
(a) Rs. 17,298
(b) Rs. 17,198
(c) Rs. 17,098
(d) Rs. 16,998
Ans: (a)
Total money needs to be paid to the shopkeeper = 8299 + 8999 = Rs. 17,298
Q29: I am greater than 360 and less than 390. If you add my first and third digits, you will get 9. What am I?
(a) 356
(b) 376
(c) 396
(d) 369
Ans: (b)
The number lies between 360 and 390, so it is a three-digit number whose hundreds digit is 3.
Also, the sum of the first and third digits is 9. So, ones digit is 6.
So, numbers can be 366, 376, or 386.
Hence, 376 is the required answer.
Q30: Which number am I? There is 6 at my hundreds place. There is 2 at my ones place. There is 4 at my thousands place. There is 7 at my tens place.
(a) 4627
(b) 4672
(c) 4762
(d) 6247
Ans: (b)
There is 2 at my ones place.
There is 7 at my tens place.
There is 6 at my hundreds place.
There is 4 at my thousands place.
So, I am '4672'.
(a) 20
(b) 15
(c) 10
(d) 5
Ans: (a)
According to the question,
25 + 6A + 2A = 105
8A = 80
A = 10
So, 2A = 20
Q32: Mr. Kumar wrote 3 digit number on his notebook. Three students Ria, Sumit and Falak gave the following statements about the numbers.
Ria - It is the 3 digit number but not the least.
Sumit - The first digit is smaller than 1.
Falak - Last two digits can be divided by 2.
If only two out of three students said the truth, who is definitely lying?
(a) Ria
(b) Sumit
(c) Falak
(d) Both Sumit and Falak
Ans: (b)
Sumit said the first digit is smaller than 1 is 0. Therefore, if the number will start from 0, it will make a two digit number.
Q33: This is the calendar for September 2015. If Rajesh is starting his training for shooting on day 5th of the month and his training will be every 6th day, which will be the last date of his training of the month?
(a) 29th September
(b) 26th September
(c) 30th September
(d) None of these
Ans: (a)
Rajesh is starting his training from 5th September, so his training days will be as follows:
11, 17, 23, 29
So, 29th September will be the last day of his training.
Q34: Bag 1 contains 60 kg of rice and bag 2 weighs 15 kg less than the weight of bag 1. Find the total quantity of rice in both the bags in grams.
(a) 1,35,000
(b) 1,00,000
(c) 1,05,000
(d) 10,500
Ans: (c)
Weight of bag 1 = 60 kg
Weight of bag 2 = 60 kg - 15 kg = 45 kg
Total weight = 60 kg + 45 kg = 105 kg
As, 1 kg = 1000 g
So, 105 kg = 105 × 1000 g = 1,05,000 g
Q35: A music academy has five rooms and in each room there are 32 students. Chahat wants to distribute 640 candies fairly between all the students of the academy. How many candies will each student get?
(a) 3
(b) 4
(c) 5
(d) 6
Ans: (b)
Number of rooms = 5
Number of students in each room = 32
Total number of students = 32 × 5 = 160
Chahat wants to distribute 640 candies fairly between all the students of the academy.
Thus, each student will get 640 ÷ 160 candies.
640 ÷ 160 = 4 candies
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