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Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC PDF Download

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Q1. What is the least possible number of cuts required to cut a cube into 64 identical pieces?    (2024)
(a) 8 
(b) 9 
(c) 12 
(d) 16

Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSCView Answer  Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC

Ans: (b)
Let n be the number of cubes on each edge of the cube. n3 = 64
or n = 4
So, there are 4 cubes on each edge of the cube. 
For this to happen we need to cut each edge 3 times.
Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSCThis can be achieved by cutting the cube 3 times along each of the three axes – x, y and z. 
So, the total number of minimum possible cuts required = 3 + 3 + 3 = 9

Q2. 125 identical cubes are arranged in the form of cubical block. How many cubes are surrounded by other cubes from each side?     (2023)
(a) 27 
(b) 25 
(c) 21 
(d) 18

Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSCView Answer  Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC

Ans: (a)
We have to find the number of internal cubes, i.e. the number of cubes that are not exposed
There are 125 cubes. Now, 53 = 125. So, n = 5 
Number of internal cubes = (n - 2)3 = (5 - 2)3 = 33 = 27 
Hence, option (a) is correct.

Q3. What is the unit digit in the expansion of (57242)9 × 7 × 5 × 3 × 1?     (2023)
(a) 2 
(b) 4 
(c) 6 
(d) 8

Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSCView Answer  Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC

Ans: (a)
(57242)9 × 7 × 5 × 3 × 1 = (57242)945
The unit digit of the resultant number only depends on the unit digit of the given number 57242, i.e. 2. 
Now, we know that:
21 = 2
22 = 4
23 = 8
24 = 16 (unit digit 6)
25 = 32 (unit digit 2)
.
.
.
And so on.
So, 2 has a cyclicity of 4. Exponent of any number ending in 2 will produce a number that will end in 2, 4, 8, or 6.
Now, 945 = 944 + 1
944 is divisible by 4. So, the last digit of (57242)945 will be the same as that of (57242)1, which is 2. 
Hence, option (a) is correct.

Q4. Consider the following statements in respect of a rectangular sheet of length 20 cm and breadth 8 cm:   (2022)
1. It is possible to cut the sheet exactly into 4 square sheets. 
2. It is possible to cut the sheet into 10 triangular sheets of equal area. 
Which of the above statements is are correct? 
(a) 1 only 
(b) 2 only 
(c) Both 1 and 2 
(d) Neither 1 nor 2

Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSCView Answer  Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC

Ans: (c)
The rectangle is of dimensions 20 cm × 8 cm. 
Statement I: You may think that as the area of rectangle is not a perfect square, it is not possible to cut it into exactly 4 square sheets. 
But there’s a catch. The statement never says that the 4 squares have to be equal in area. 
We can do so as follows:
Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSCStatement II: You may think that we can cut the rectangle into 8 triangles of equal area (as shown below), but not in 10.
Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC

But again, this can be done. It has been shown below:
Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC

Hence, both statements 1 and 2 are correct.

Q5. A cubical vessel of side 1 m is filled completely with water. How many millilitres of water is contained in it (neglect thickness of the vessel)?  (2021)
(a) 1000 
(b) 10000 
(c) 100000 
(d) 1000000

Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSCView Answer  Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC

Ans: (d)
Volume of the cube = Side × Side × Side = 1 × 1 × 1 = 1 cubic meter
Now, 1 cubic meter = 1000000 mililiters

The document Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures | CSAT Preparation - UPSC is a part of the UPSC Course CSAT Preparation.
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FAQs on Previous Year Topic Wise Questions With Solutions: Mensuration-Volume, Surface Area & Solid Figures - CSAT Preparation - UPSC

1. What is the formula for calculating the volume of a cylinder?
Ans. The volume V of a cylinder can be calculated using the formula V = πr²h, where r is the radius of the base and h is the height of the cylinder.
2. How do you find the surface area of a sphere?
Ans. The surface area A of a sphere is given by the formula A = 4πr², where r is the radius of the sphere.
3. What is the difference between the volume and surface area of a cube?
Ans. The volume V of a cube is calculated using the formula V = a³, where a is the length of one side. The surface area A of a cube is given by A = 6a². Thus, volume measures the space within the cube, while surface area measures the total area of its six faces.
4. How can the volume of a cone be determined?
Ans. The volume V of a cone can be calculated using the formula V = (1/3)πr²h, where r is the radius of the base and h is the height of the cone.
5. What is the formula for the surface area of a rectangular prism?
Ans. The surface area A of a rectangular prism can be calculated using the formula A = 2(lw + lh + wh), where l is the length, w is the width, and h is the height of the prism.
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