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NCERT Solutions for Class 7 Maths - Rational Numbers

Exercise 8.1

Q1: List five rational numbers between:
(i) -1 and 0
Ans: Let us write -1 and 0 as rational numbers with denominator 6.

NCERT Solutions for Class 7 Maths - Rational Numbers
Therefore, five rational numbers between -1 and 0 would be
NCERT Solutions for Class 7 Maths - Rational Numbers

(ii) -2 and -1
Ans: Let us write -2 and -1 as rational numbers with denominator 6.

NCERT Solutions for Class 7 Maths - Rational Numbers
Therefore, Five rational numbers between -2 and -1 would be
NCERT Solutions for Class 7 Maths - Rational Numbers

(iii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: Let us write NCERT Solutions for Class 7 Maths - Rational Numbers as rational numbers with the same denominators.

NCERT Solutions for Class 7 Maths - Rational Numbers
Therefore, five rational numbers between NCERT Solutions for Class 7 Maths - Rational Numbers would beNCERT Solutions for Class 7 Maths - Rational Numbers

(iv) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: Let us write NCERT Solutions for Class 7 Maths - Rational Numbersas rational numbers with the same denominators.

NCERT Solutions for Class 7 Maths - Rational Numbers
Therefore, five rational numbers between NCERT Solutions for Class 7 Maths - Rational Numbers would be  NCERT Solutions for Class 7 Maths - Rational Numbers


Q2: Write four more rational numbers in each of the following patterns: 
(i) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans:

NCERT Solutions for Class 7 Maths - Rational Numbers
Therefore, the next four rational numbers of this pattern would be
NCERT Solutions for Class 7 Maths - Rational Numbers

(ii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans:
NCERT Solutions for Class 7 Maths - Rational Numbers
Therefore, the next four rational numbers of this pattern would be

NCERT Solutions for Class 7 Maths - Rational Numbers

(iii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans:

NCERT Solutions for Class 7 Maths - Rational Numbers
Therefore, the next four rational numbers of this pattern would be
NCERT Solutions for Class 7 Maths - Rational Numbers

(iv) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans:
NCERT Solutions for Class 7 Maths - Rational Numbers
Therefore, the next four rational numbers of tins pattern would be
NCERT Solutions for Class 7 Maths - Rational Numbers


Q3: Give four rational numbers equivalent to:
(i) -2/7
Ans: The four rational numbers equivalent to -2/7 are,
NCERT Solutions for Class 7 Maths - Rational Numbers

Therefore, four equivalent rational numbers are NCERT Solutions for Class 7 Maths - Rational Numbers

(ii) 5/-3
Ans: The four rational numbers equivalent to 5/-3 are,
NCERT Solutions for Class 7 Maths - Rational Numbers

Therefore, four equivalent rational numbers are  NCERT Solutions for Class 7 Maths - Rational Numbers

(iii) 4/9
Ans: The four rational numbers equivalent to 5/-3 are,
NCERT Solutions for Class 7 Maths - Rational Numbers

Therefore, four equivalent rational numbers are  NCERT Solutions for Class 7 Maths - Rational Numbers


Q4: Draw the number line and represent the following rational numbers on it: 
(i) 3/4
Ans: We know that 3/4 is greater than 0 and less than 1.
∴ it lies between 0 and 1. It can be represented on number line as,

NCERT Solutions for Class 7 Maths - Rational Numbers

(ii) -5/8
Ans: We know that -5/8 is less than 0 and greater than -1.
∴ it lies between 0 and -1. It can be represented on number line as,

  NCERT Solutions for Class 7 Maths - Rational Numbers

(iii)  -7/4
Ans: 
Now above question can be written as,
= (-7/4) = NCERT Solutions for Class 7 Maths - Rational Numbers
We know that (-7/4) is Less than -1 and greater than -2.
∴ it lies between -1 and -2. It can be represented on number line as,

NCERT Solutions for Class 7 Maths - Rational Numbers

(iv) 7/8
Ans: 
We know that 7/8 is greater than 0 and less than 1.
∴ it lies between 0 and 1. It can be represented on number line as,

NCERT Solutions for Class 7 Maths - Rational Numbers

Q5: The points P, Q, R, S, T, U, A and B on the number line are such that, TR = RS = SU and AP = PQ = QB. Name the rational numbers represented by P, Q, R and S. 
NCERT Solutions for Class 7 Maths - Rational Numbers

Ans:
Therefore, NCERT Solutions for Class 7 Maths - Rational Numbers
Similarly NCERT Solutions for Class 7 Maths - Rational Numbers
Thus, the rational numbers represented P, Q, R, and S are NCERT Solutions for Class 7 Maths - Rational Numbers respectively.


Q6: Which of the following pairs represent the same rational numbers: 
(i) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: 
We have to check the given pair represents the same rational number.
Then,
NCERT Solutions for Class 7 Maths - Rational Numbers [Converting into lowest term]
NCERT Solutions for Class 7 Maths - Rational Numbers
So, the given pair is not represents the same rational number.

(ii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: 
We have to check the given pair represents the same rational number.
Then,

NCERT Solutions for Class 7 Maths - Rational Numbers [Converting into lowest term]

NCERT Solutions for Class 7 Maths - Rational Numbers
So, the given pair is represents the same rational number.

(iii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: 
We have to check the given pair represents the same rational number.
Then,

NCERT Solutions for Class 7 Maths - Rational Numbers [Converting into lowest term]

NCERT Solutions for Class 7 Maths - Rational Numbers
So, the given pair is represents the same rational number.

(iv)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: 
We have to check the given pair represents the same rational number.
Then,

NCERT Solutions for Class 7 Maths - Rational Numbers  [Converting into lowest term]

NCERT Solutions for Class 7 Maths - Rational Numbers
So, the given pair is represents the same rational number.

(v)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: 
We have to check the given pair represents the same rational number.
Then,

NCERT Solutions for Class 7 Maths - Rational Numbers   [Converting into lowest term]

NCERT Solutions for Class 7 Maths - Rational Numbers
So, the given pair is represents the same rational number.

(vi)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: 
We have to check the given pair represents the same rational number.
Then,

NCERT Solutions for Class 7 Maths - Rational Numbers   [Converting into lowest term]

NCERT Solutions for Class 7 Maths - Rational Numbers
So, the given pair does not represent the same rational number.

(vii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: 
We have to check the given pair represents the same rational number.
Then,
NCERT Solutions for Class 7 Maths - Rational Numbers [Converting into lowest terra]
NCERT Solutions for Class 7 Maths - Rational Numbers
So, the given pair does not represent the same rational number.


Q7: Rewrite the following rational numbers in the simplest form:
(i) -8/6 
Ans: 
The given rational numbers can be simplified further,
Then,
= -4/3 … [∵ Divide both numerator and denominator by 2]

(ii) 25/45
Ans: 
The given rational numbers can be simplified further,
Then,
= 5/9 … [∵ Divide both numerator and denominator by 5]

(iii) -44/72
Ans: 
The given rational numbers can be simplified further,
Then,
= -11/18 … [∵ Divide both numerator and denominator by 4]

(iv) -8/10
Ans: 
The given rational numbers can be simplified further,
Then,
= -4/5 … [∵ Divide both numerator and denominator by 2]


Q8: Fill in the boxes with the correct symbol out of <, > and =:
(i) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: The LCM of the denominators 7 and 3 is 21
∴ (-5/7) = [(-5 × 3)/ (7 × 3)] = (-15/21)
And (2/3) = [(2 × 7)/ (3 × 7)] = (14/21)
Now, -15 < 14
So,
(-15/21) < (14/21)
Hence, -5/7 [<] 2/3

(ii) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: The LCM of the denominators 5 and 7 is 35
∴ (-4/5) = [(-4 × 7)/ (5 × 7)] = (-28/35)
And (-5/7) = [(-5 × 5)/ (7 × 5)] = (-25/35)
Now, -28 < -25
So,
(-28/35) < (- 25/35)
Hence, -4/5 [<] -5/7

(iii) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: 14/-16 can be simplified further,
Then,
7/-8 … [∵ Divide both numerator and denominator by 2]
So,
(-7/8) = (-7/8)
Hence, -7/8 [=] 14/-16

(iv)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: The LCM of the denominators 5 and 4 is 20
∴ (-8/5) = [(-8 × 4)/ (5 × 4)] = (-32/20)
And (-7/4) = [(-7 × 5)/ (4 × 5)] = (-35/20)
Now, -32 > – 35
So,
(-32/20) > (- 35/20)
Hence, -8/5 [>] -7/4

(v) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: The LCM of the denominators 3 and 4 is 12
∴ (-1/3) = [(-1 × 4)/ (3 × 4)] = (-4/12)
And (-1/4) = [(-1 × 3)/ (4 × 3)] = (-3/12)
Now, -4 < – 3
So,
(-4/12) < (- 3/12)
Hence, 1/-3 [<] -1/4

(vi)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: Since, (-5/11) = (-5/11)
Hence, 5/-11 [=] -5/11

(vii) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: Since every negative rational number is less than 0.
We have:
= 0 [>] -7/6


Q9: Which is greater in each of the following: 
(i) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: The LCM of the denominators 3 and 2 is 6
(2/3) = [(2 × 2)/ (3 × 2)] = (4/6)
And (5/2) = [(5 × 3)/ (2 × 3)] = (15/6)
Now, 4 < 15
So, (4/6) < (15/6)
∴ 2/3 < 5/2
Hence, 5/2 is greater.

(ii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: The LCM of the denominators 6 and 3 is 6
∴ (-5/6) = [(-5 × 1)/ (6 × 1)] = (-5/6)
And (-4/3) = [(-4 × 2)/ (3 × 2)] = (-12/6)
Now, -5 > -12
So, (-5/6) > (- 12/6)
∴ -5/6 > -12/6
Hence, – 5/6 is greater.

(iii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: The LCM of the denominators 4 and 3 is 12
∴ (-3/4) = [(-3 × 3)/ (4 × 3)] = (-9/12)
And (-2/3) = [(-2 × 4)/ (3 × 4)] = (-8/12)
Now, -9 < -8 So, (-9/12) < (- 8/12)
∴ -3/4 < 2/-3
Hence, 2/-3 is greater.

(iv)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: The given fraction is like friction,
So, -¼ < ¼
Hence ¼ is greater,

(v)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: First we have to convert mixed fractions into improper fractions,
NCERT Solutions for Class 7 Maths - Rational Numbers= -23/7
NCERT Solutions for Class 7 Maths - Rational Numbers= -19/5
Then, The LCM of the denominators 7 and 5 is 35
∴ (-23/7) = [(-23 × 5)/ (7 × 5)] = (-115/35)
And (-19/5) = [(-19 × 7)/ (5 × 7)] = (-133/35)
Now, -115 > -133 So, (-115/35) > (- 133/35)
NCERT Solutions for Class 7 Maths - Rational Numbers> NCERT Solutions for Class 7 Maths - Rational Numbers
Hence, NCERT Solutions for Class 7 Maths - Rational Numbersis greater.


Q10: Write the following rational numbers in ascending order: 
(i)  -3/5, -2/5, -1/5
Ans: 
The given rational numbers are in form of like fractions,
Hence, (-3/5)< (-2/5) < (-1/5)

(ii) -1/3, -2/9, -4/3
Ans:
To convert the given rational numbers into like fractions we have to find LCM,
LCM of 3, 9, and 3 is 9
Now,
(-1/3)= [(-1 × 3)/ (3 × 9)] = (-3/9)
(-2/9)= [(-2 × 1)/ (9 × 1)] = (-2/9)
(-4/3)= [(-4 × 3)/ (3 × 3)] = (-12/9)
Clearly, (-12/9) < (-3/9) < (-2/9)
Hence, (-4/3) < (-1/3) < (-2/9)

(iii) -3/7, -3/2, -3/4
Ans: 
To convert the given rational numbers into like fractions we have to find LCM,
LCM of 7, 2, and 4 is 28
Now, (-3/7)= [(-3 × 4)/ (7 × 4)] = (-12/28)
(-3/2)= [(-3 × 14)/ (2 × 14)] = (-42/28)
(-3/4)= [(-3 × 7)/ (4 × 7)] = (-21/28)
Clearly, (-42/28) < (-21/28) < (-12/28)
Hence, (-3/2) < (-3/4) < (-3/7)

Exercise 8.2 

Q1: Find the sum: 
(i) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: We have:
= (5/4) – (11/4) = [(5 – 11)/4] … [∵ denominator is same in both the rational numbers]
= (-6/4)
= -3/2 … [∵ Divide both numerator and denominator by 3]

(ii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: Take the LCM of the denominators of the given rational numbers.
LCM of 3 and 5 is 15 Express each of the given rational numbers with the above LCM as the common denominator.
Now, (5/3) = [(5 × 5)/ (3 × 5)] = (25/15)
(3/5) = [(3 × 3)/ (5 × 3)] = (9/15)
Then,
= (25/15) + (9/15) … [∵ denominator is same in both the rational numbers]
= (25 + 9)/15 = 34/15

(iii)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: Take the LCM of the denominators of the given rational numbers.
LCM of 10 and 15 is 30 Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-9/10)= [(-9 × 3)/ (10 × 3)] = (-27/30)
(22/15)= [(22 × 2) / (15 × 2)] = (44/30)
Then, = (-27/30) + (44/30) … [∵ denominator is same in both the rational numbers]
= (-27 + 44)/30
= (17/30)

(iv)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: We have, = 3/11 + 5/9
Take the LCM of the denominators of the given rational numbers.
LCM of 11 and 9 is 99
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(3/11) = [(3 × 9)/ (11 × 9)] = (27/99)
(5/9) = [(5 × 11)/ (9 × 11)] = (55/99)
Then,
= (27/99) + (55/99) … [∵ denominator is same in both the rational numbers]
= (27 + 55)/99
= (82/99)

(v)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: We have = -8/19 – 2/57
Take the LCM of the denominators of the given rational numbers.
LCM of 19 and 57 is 57
Express each rational number with the above LCM as the common denominator.
Now,
(-8/19)= [(-8 × 3)/ (19 × 3)] = (-24/57) (-2/57)= [(-2 × 1)/ (57 × 1)] = (-2/57)
Then,
= (-24/57) – (2/57) … [∵ denominator is same in both the rational numbers]
= (-24 – 2)/57 = (-26/57)

(vi) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: We know that any number or fraction is added to zero the answer will be the same number or fraction.
Hence,
= -2/3 + 0
= -2/3

(vii) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans:
NCERT Solutions for Class 7 Maths - Rational Numbers [L.C.M. of 3 and 5 is 15]
NCERT Solutions for Class 7 Maths - Rational Numbers


Q2: Find: 
(i)  NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: Take the LCM of the denominators of the given rational numbers.
LCM of 24 and 36 is 72
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(7/24)= [(7 × 3)/ (24 × 3)] = (21/72)
(17/36)= [(17 × 2)/ (36 × 2)] = (34/72)
Then,
= (21/72) – (34/72) … [∵ denominator is same in both the rational numbers]
= (21 – 34)/72 = (-13/72)

(ii)NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: We can also write -6/21 = -2/7
= 5/63 – (-2/7)
We have, = 5/63 + 2/7
Take the LCM of the denominators of the given rational numbers.
LCM of 63 and 7 is 63
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(5/63)= [(5 × 1)/ (63 × 1)] = (5/63)
(2/7)= [(2 × 9)/ (7 × 9)] = (18/63)
Then, = (5/63) + (18/63) … [∵ denominator is same in both the rational numbers]
= (5 + 18)/63 = 23/63

(iii)NCERT Solutions for Class 7 Maths - Rational Numbers
Ans: We have, = -6/13 + 7/15
LCM of 13 and 15 is 195
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-6/13)= [(-6 × 15)/ (13 × 15)] = (-90/195)
(7/15)= [(7 × 13)/ (15 × 13)] = (91/195)
Then, = (-90/195) + (91/195) … [∵ denominator is same in both the rational numbers]
= (-90 + 91)/195
= (1/195)

(iv) NCERT Solutions for Class 7 Maths - Rational Numbers 
Ans: Take the LCM of the denominators of the given rational numbers.
LCM of 8 and 11 is 88
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-3/8)= [(-3 × 11)/ (8 × 11)] = (-33/88)
(7/11)= [(7 × 8)/ (11 × 8)] = (56/88)
Then, = (-33/88) – (56/88) … [∵ denominator is same in both the rational numbers]
= (-33 – 56)/88
= (-89/88)

(v) NCERT Solutions for Class 7 Maths - Rational Numbers
Ans:
First we have to convert the mixed fraction into improper fraction,
NCERT Solutions for Class 7 Maths - Rational Numbers= -19/9
We have, -19/9 – 6
Take the LCM of the denominators of the given rational numbers.
LCM of 9 and 1 is 9
Express each of the given rational numbers with the above LCM as the common denominator.
Now,
(-19/9)= [(-19 × 1)/ (9 × 1)] = (-19/9)
(6/1)= [(6 × 9)/ (1 × 9)] = (54/9)
Then, = (-19/9) – (54/9) … [∵ denominator is same in both the rational numbers]
= (-19 – 54)/9
= (-73/9)


Q3: Find the product: 
(i) (9/2) × (-7/4)
Ans: 
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
The above question can be written as
(9/2) × (-7/4)
We have,
= (9 × -7) / (2 × 4)
= -63/8 

(ii) (3/10) × (-9)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
The above question can be written as
(3/10) × (-9/1)
We have,
= (3 × -9)/ (10×1)
= -27/10

(iii) (-6/5) × (9/11)
Ans: 
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
We have,
= (-6 × 9) / (5 × 11)
= -54/55

(iv) (3/7) × (-2/5)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
We have,
= (3 × -2) / (7 × 5)
= -6/35

(v) (3/11) × (2/5)
Ans: 
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
We have,
= (3 × 2) / (11 × 5)
= 6/55

(vi) (3/-5) × (-5/3)
Ans:
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
We have,
= (3 × -5) / (-5 × 3)
On simplifying, = (1 × -1)/ (-1 × 1)
= -1/-1 = 1


Q4: Find the value of: 
(i) (-4) ÷ (2/3)
Ans:
We have,
= (-4/1) × (3/2) … [∵ reciprocal of (2/3) is (3/2)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-4 × 3) / (1 × 2) = (-2 × 3) / (1 × 1) = -6

(ii) (-3/5) ÷ 2
Ans: 
We have,
= (-3/5) × (1/2) … [∵ reciprocal of (2/1) is (1/2)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-3 × 1) / (5 × 2)
= -3/10

(iii) (-4/5) ÷ (-3)
Ans:
We have,
= (-4/5) × (1/-3) … [∵ reciprocal of (-3) is (1/-3)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-4× (1)) / (5× (-3))
= -4/-15 = 4/15

(iv) (-1/8) ÷ 3/4
Ans: 
We have,
= (-1/8) × (4/3) … [∵ reciprocal of (3/4) is (4/3)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-1 × 4) / (8 × 3)
= (-1 × 1) / (2 × 3) = -1/6

(v) (-2/13) ÷ 1/7
Ans: 
We have,
= (-2/13) × (7/1) … [∵ reciprocal of (1/7) is (7/1)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-2 × 7) / (13 × 1)
= -14/13

(vi) (-7/12) ÷ (-2/13)
Ans:
We have, = (-7/12) × (13/-2) … [∵ reciprocal of (-2/13) is (13/-2)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (-7× 13) / (12× (-2))
= -91/-24 = 91/24

(vii) (3/13) ÷ (-4/65)
Ans:
We have, = (3/13) × (65/-4) … [∵ reciprocal of (-4/65) is (65/-4)]
The product of two rational numbers = (product of their numerator)/ (product of their denominator)
= (3 × 65) / (13 × (-4))
= 195/-52 = -15/4

The document NCERT Solutions for Class 7 Maths - Rational Numbers is a part of the Class 7 Course Mathematics (Maths) Class 7.
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FAQs on NCERT Solutions for Class 7 Maths - Rational Numbers

1. What are rational numbers and how are they represented?
Ans. Rational numbers are numbers that can be expressed in the form of a fraction \( \frac{p}{q} \), where \( p \) and \( q \) are integers and \( q \neq 0 \). They can also be represented on a number line, where the distances between rational numbers are consistent.
2. How do you add and subtract rational numbers?
Ans. To add or subtract rational numbers, first ensure they have a common denominator. Then, add or subtract the numerators while keeping the denominator the same. Simplify the resulting fraction if possible.
3. Can you provide an example of multiplying rational numbers?
Ans. Yes! To multiply rational numbers, simply multiply the numerators together and the denominators together. For example, \( \frac{2}{3} \times \frac{4}{5} = \frac{2 \times 4}{3 \times 5} = \frac{8}{15} \).
4. What is the process for dividing rational numbers?
Ans. To divide rational numbers, multiply the first rational number by the reciprocal of the second. For example, to divide \( \frac{3}{4} \) by \( \frac{2}{5} \), you would calculate \( \frac{3}{4} \times \frac{5}{2} = \frac{15}{8} \).
5. How do you convert a decimal to a rational number?
Ans. To convert a decimal to a rational number, write the decimal as a fraction with a denominator of 1, then multiply the numerator and denominator by 10 for each digit after the decimal point. For example, \( 0.75 = \frac{75}{100} = \frac{3}{4} \) when simplified.
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