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| Factors Affecting Acidity (Organic Compounds) | |
| Basic Strength (General Principles) | |
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According to the Arrhenius concept:

Weak electrolytes (weak acids and weak bases) ionise only to a small extent in water. Most solute molecules remain undissociated and ionic concentrations are relatively low. The extent of dissociation is described by the degree of ionisation (α) or by equilibrium (ionisation) constants.
For a weak monoprotic acid:
HA + H2O ⇌ H3O+ + A-
For a weak base:
B + H2O ⇌ BH+ + OH-
The acid ionisation constant, Ka, for HA ⇌ H+ + A- is defined as:
Ka = [H+][A-] / [HA]
The base ionisation constant, Kb, for B + H2O ⇌ BH+ + OH- is defined as:
Kb = [BH+][OH-] / [B]
For conjugate acid-base pairs in water, the relation holds:
Ka × Kb = Kw where Kw is the ionic product of water (≈ 1.0 × 10-14 at 298 K).
Use of logarithmic scale: pKa = -log Ka. A smaller pKa (or larger Ka) indicates a stronger acid.






Some common Lewis acids that can accept electron pairs include:

Examples include:

Key factors that influence acidity of an organic acid (ability to donate H+) are:
Ex.1 Compare the acidic strength of the following acids.
(a) C - C - C - COOH (b) C = C - C - COOH (c) C≡C-C-COOH
Sol. The acid whose conjugate base is most stable will be more acidic.
After forming conjugate base from the above acids.
(a)
(b)
(c)
Explanation: An sp-hybridised carbon adjacent to the carboxylate stabilises the negative charge most effectively due to higher s-character and greater electronegativity. Hence acidity order:
c > b > a
Ex.2 Which is more acidic between the two:
(a) CHF3 (b) CHCl3
Sol. CHF3 > CHCl3
After removal of proton:
Note: In haloforms, inductive and other stabilising effects can be complex. The input comment about vacant d-orbitals and pπ-dπ bonding is not generally applicable to carbon; for halogens such as Cl and Br, pπ-dπ interactions are not a primary stabilising factor for conjugate bases of haloforms. The important point is the relative -I effect and polarisation stabilising the negative charge. Thus CHF3 is generally more acidic than CHCl3.
Ex.3 Compare the acidic strength of the following:
(a) CHF3 (b) CHCl3 (c) CHBr3
Sol. CHCl3 > CHBr3 > CHF3
Explanation: Although F is more electronegative than Cl or Br, other factors such as polarisation and inductive stabilisation, and the overall ability to stabilise the conjugate base result in this order. For haloforms, CHCl3 is often more acidic than CHBr3, and CHF3 is least acidic among these in many comparisons.
Ex.4 Compare the acidic strength of the following
(a) CH(CN)3 (b) CH(NO2)3 (c) CHCl3
Sol. After removing H+
(Resonance) In its resonating structure, negative charge will be on N)
(Resonance) Negative charge will reside on O (more effective resonance)
→ more effective resonance stabilisation in nitro derivative than cyano derivative.
(pπ-dπ interaction in CHCl3 is weaker)
Therefore: b > a > c
Reason: Negative charge on O is stabilised better than on N because O is more electronegative; nitro groups withdraw by powerful -I and -M effects giving strong stabilisation.
Ex.5 Compare the acidic strength of the following:
(a) CH≡CH (b) CH2=CH2 (c) CH3-CH3
Sol.
(Stability of the conjugate base)
Order: a > b > c (acidic strength)
Explanation: The conjugate base of alkyne has negative charge on an sp carbon (50% s-character) and is most stabilised, then sp2, then sp3.
Ex.6 Compare the acidic strength of the following :

Sol. d > c > b > a
Ex.7 Compare the acidic strength of the following :
(a) H2O (b) H2S (c) H2Se (d) H2Te
Sol. Conjugate base stability order:
Therefore: H2O < H2S < H2Se < H2Te (acidic strength)
Explanation: Down the group, larger size and greater polarizability stabilise the negative charge better, increasing acidity.
Ex.8 Compare the acidic strength of the following compound:
(a)
(b)
(c)
(d)
Sol. After forming conjugate bases:
Order: c > d > b > a
Ex.9 Compare the reactivity of the following compounds with 1 mole of AgNO3
(a)
(b)
(c)
(d)
Sol. After removing Cl-:
(Negative charge not stabilised by resonance - least stable)
(Most stable as lone pair of Cl coordinates to positive charge completing octet and stabilising carbocation)
Extent of positive charge decreases as stability increases.
Ex.10 Compare the acidic strength:
(a)
(b)
(c)
(d)
Sol. After making conjugate base:
Order: c > b > a > d
Basic strength depends directly on the availability of the lone pair for bonding with H+ (protonation). Factors affecting basicity include:
Ex.11 Compare the basic strength of following:
Sol.
Ex.12 Compare the basic strength of the following
(a)
(b)
(c)
(d)
Sol.
Note: The acidity order given in input: CH4 < NH3 < H2O < HF (acidic strength). From conjugate acid viewpoint, HF is strongest acid among these; hence F- is weakest base among them.
* Strong acids have weak conjugate bases.
* For atoms in the same period, lower electronegativity implies greater nucleophilicity (greater tendency to donate electron pair).
Ex.13 Which is more basic
or
Sol.
>
Which is more basic: NH3 or ? (forming conjugate acid)
Ex.14 Compare the basic strength of NH3, CH3NH2, (CH3)2NH, (CH3)3N
Factors: (1) Steric effect (2) Inductive effect (3) Solvation effect.
The base whose conjugate acid is more stable will be more basic (in that phase/medium).
Stability order of conjugate acids (gas phase):
Therefore basic strength in gas phase or non-polar solvent:
(CH3)3N > (CH3)2NH > CH3NH2 > NH3
In aqueous solution (polar solvent), due to solvation and hydrogen bonding of the conjugate acids, the order changes:
(CH3)2NH > CH3NH2 > (CH3)3N > NH3
Explanation: Conjugate acids of 1° amines form more H-bonds with water (more N-H available for hydrogen bonding), so 1° amine conjugate acid is more stabilised in water. Steric hindrance in 3° amine reduces solvation of conjugate acid and lone pair accessibility, lowering basicity in aqueous medium.
Aromatic amines are least basic as the lone pair on N is delocalised into the aromatic ring and less available for protonation.
Combined effects typically yield: 2° > 1° > 3° > NH3 in aqueous solution.
Ex.15 Compare the basic strength of the following:
(a)
(b)
(c)
(If lone pair participates in resonance, the molecule becomes aromatic.)
Hence lone pair participates in resonance and is less available for H+; this compound will be least basic.
Ex.16 Compare the basic strength of the following:
Sol. sp hybridised carbon being most electronegative attracts electron density from nitrogen, making lone pair less available for protonation. Hence basicity decreases.
Order: c > b > a
Ex.17 Compare the basic strength:
(a)
(b)
Answer: a < b
Ex.18 Compare the basicity of the following compounds:
(a) CH3-CH2-CH = CH -
(b)
(c)
(d)
Sol. In part (a) the lone pair of nitrogen is in resonance, therefore less available for protonation, making it least basic among all; follow trend based on hybridisation of carbon atoms attached to N.
Order: b > c > d > a
Ex.19 Compare the basicity of the numbered nitrogen atoms.
Sol. The planarity of the ring will be destroyed if lone pair takes part in resonance. Basicity order of nitrogen follows:
N(sp3) > N(sp2) > N(sp)
(In this example, the sp2 nitrogen lone pair is in resonance with the ring and thus is least available for protonation - least basic.)
Ex.20 Compare the basic strength of the following:
(a)
(b)
(c)
Sol. In (a) nitro group at para position withdraws electron density by both -M and -I effects, reducing availability of lone pair on N most. In (b) nitro at meta position withdraws by -I only. In (c) there is no such effect.
Order: c > b > a
Ortho-substituted anilines are less basic than aniline, and ortho-substituted benzoic acids are more acidic than benzoic acid. The ortho effect arises from both steric hindrance and intramolecular interactions; it is particularly significant for benzoic acids and anilines.
Examples:
Ex.21 Compare the basic strength of the following :
(a)
(b)
(c)
(d)
Sol. a > b > d > c
* Due to ortho effect d > c
If c is less basic than d then it will be certainly less basic than b as b is more basic than d.
Ex.22 Compare the basic strength of the following :
(a)
(b)
(c)
(d)
Sol. Do yourselves.
S.I.P - Steric inhibition of Protonation (ortho effect)
Bulky ortho substituents hinder protonation; after protonation, steric repulsion increases and the ortho-substituted aniline is less basic than aniline.
S.I.R - Steric inhibition of Resonance
Bulky ortho substituents can also prevent effective resonance by twisting rings or substituents out of conjugation. Examples:
(a)
(b)
This chapter covered three classical definitions of acids and bases (Arrhenius, Brønsted-Lowry and Lewis), dissociation and ionisation constants (Ka, Kb, pKa), and the principal structural and electronic factors that determine acidity and basicity in organic compounds: electronegativity, inductive and resonance effects, hybridisation, size and polarizability, solvation and steric effects. Worked examples illustrate how to compare acids and bases using these principles. Use conjugate base stability and lone-pair availability as guiding rules when comparing acidity and basicity respectively.
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| 1. What is the Arrhenius theory of acids and bases? | ![]() |
| 2. What is the Bronsted-Lowry theory of acids and bases? | ![]() |
| 3. What is the Lewis theory of acids and bases? | ![]() |
| 4. What is a Lewis base? | ![]() |
| 5. Can you provide examples of Lewis bases? | ![]() |
| 6. How does the basicity of ammonia compare to alkyl amines? | ![]() |