Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE) PDF Download

BIASING FET:-

        For the proper functioning of a linear FET amplifier, it is necessary to maintain the operating point Q stable in the central portion of the pinch off region. The Q point should be independent of device parameter variations and ambient temperature variations.

This can be achieved by suitably selecting the gate to source voltage Vgs and drain current Id which is referred to as biasing.

 JFET biasing circuits are very similar to BJT biasing circuits. The main difference between JFET circuits and BJT circuits is the operation of the active components themselves.

There are mainly two types of Biasing circuits

  1. Self bias
  2. Voltage divider bias.

 

6.9.1 SELF BIAS

Self bias is a JFET biasing circuit that uses a source resistor to help reverse bias the JFET gate. A  self bias circuit is shown in the fig. Self bias is the most common type of JFET bias. This JFET must be operated such that gate source junction is always reverse biased. This condition requires a negative Vgs for an N-channel JFET and a positive Vgs for P-channel JFET. This can be achieved using the self bias arrangement as shown in Fig. The gate resistor RG doesn’t affect the bias because it has essentially no voltage drop across it, and the gate remains at 0 V. RG is necessary only to isolate an ac signal from ground in amplifier applications. The voltage drop across resistor RS makes gate source junction reverse biased.

                         Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)       

For the dc analysis, coupling capacitors are open circuits.

For the N channel FET in Fig (a)

IS produces a voltage drop across RS and makes the source positive w.r.t ground. In any JFET circuit all the source current passes through the device to the drain circuit. This is due to the fact that there is no significant gate current.

We can define source current as  IS = ID

(VG =0 because there is no gate current flowing in RG. So, VG across RG is zero)

VG =0 then VS= ISRS =ID RS

VGS = VG-VS =0-ID RS=- ID RS

DC analysis of self Bias:-

In the following DC analysis, the N-channel JFET shown in the fig. is used for illustration.

For DC analysis we can replace coupling capacitors by open circuits and we can also replace the resistor RG by a short circuit equivalent.:. IG = 0.The relation between ID and VGS is given by-

Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)

 

             Id=Idss   Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)                                 Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)


VGS for N-channel JFET is =-Id Rs

Substuting this value in the above equation,

          Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)


For the N-chanel FET in the above figure

Is produces a voltage drop across Rs and makes the source positive w.r.t ground in any JFET circuit, all the source current passes through the device to drain circuit this is due to the fact that there is no significant gate current. Therefore, we can define source current as Is=Id and Vg=0 then

Vs= IRs =IdRs

Vgs=Vg-Vs=0-IdRs=-IdRs

Drawing the self bias line:-

Typical transfer characteristics for a self biased JFET are shown in the fig.

The maximum drain current is 6mA and the gate source cut off voltage is -3V. This means the gate voltage has to be between 0 and -3V.

Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)

Now using the equation Vgs= -IDRS and assuming RS of any suitable value we can draw the self bias line.

Let us assume RS = 500Ω

 With this Rs , we can plot two points corresponding to ID = 0 and ID = IDSS

      for ID = 0

VGS = -ID RS

VGS = 0 x (500.Ω) = 0V

So the first point is (0 ,0)

                                      ( ID, VGS)

For ID= IDSS=6mA

VGS = (-6mA) (500 Ω) = -3V

So the 2nd  Point will be (6mA,-3V)

By plotting these two points, we can draw the straight line through the points. This line will intersect the transconductance curve and it is known as self bias line.The intersection point gives the operating point of the self bias JFET for the circuit.

At Q point , the ID is slightly  > than 2mA and VGS is slightly > -1V. The Q point for the self bias JFET depends on the value of RS. If RS is large, Q point is far down on the transconductance curve, ID is small, when RS is small Q point is far up on the curve , ID is large.

6.9.2 VOLTAGE DIVIDER BIAS:-

Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)

The fig. shows N channel JFET with voltage divider bias. The voltage at the source of JFET must be more positive than the voltage at the gate in order to keep the gate to source junction reverse biased. The source voltage is

VS = IDRS

The gate voltage is set by resistors R1 and R2 as expressed by the following equation using the voltage divider formula.

Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)


For dc analysis:

Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)            

Applying KVL to the input circuit

VG-VGS-VS =0

:: VGS = VG-Vs=VG-ISRS

VGS = VG-IDRS       :: IS = ID

Applying KVL to the input circuit we get

VDS+IDRD+VS-VDD =0

::VDS = VDD-IDRD-IDRS

VDS = VDD-ID ( RD +RS )

The Q point of a JFET amplifier , using the voltage divider bias is 

IDQ  = IDSS [1-VGS/VP]2

VDSQ = VDD-ID ( RD+RS )

 

COMPARISON OF MOSFET WITH JFET

  1. In enhancement and depletion types of MOSFET, the transverse electric field induced across an insulating layer deposited on  the semiconductor material controls the conductivity of the channel.
  2. In the JFET, the transverse electric field across the reverse biased PN junction controls the conductivity of the channel.
  3. The gate leakage current in a MOSFET is of the order of 10-12A. Hence the input resistance of a MOSFET is very high in the order of 1010  to  1015 Ω.  The gate leakage current of a JFET  is of the order of 10-9A., and its input resistance is of the order of 108Ω.
  4. The output characteristics of the JFET are flatter than those of the MOSFET, and hence the drain resistance of a JFET (0.1 to 1MΩ)  is  much higher than that of a MOSFET (1 to 50kΩ).
  5. JFETs are operated only in the depletion mode. The depletion type MOSFET may be operated in both depletion and enhancement mode.
  6. Comparing to JFET, MOSFETs  are easier to fabricate.
  7. Special digital CMOS circuits are available which involve near zero power dissipation and very low voltage and current requirements. This makes them suitable for portable systems.    
The document Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE) is a part of the Electrical Engineering (EE) Course Analog and Digital Electronics.
All you need of Electrical Engineering (EE) at this link: Electrical Engineering (EE)
137 videos|143 docs|71 tests

Top Courses for Electrical Engineering (EE)

FAQs on Biasing FET - Analog and Digital Electronics - Electrical Engineering (EE)

1. What is FET biasing in electrical engineering?
Ans. FET biasing refers to the process of applying a DC voltage or current to a field-effect transistor (FET) in order to establish a specific operating point, or bias point. This ensures that the FET operates in its desired region and provides the desired performance characteristics.
2. Why is biasing important in FET circuits?
Ans. Biasing is important in FET circuits because it sets the operating point of the transistor, which directly affects its performance. By properly biasing the FET, we can ensure that it operates within its linear range, provides the desired gain, and minimizes distortion.
3. What are the different methods of biasing a FET?
Ans. There are three commonly used methods for biasing a FET: fixed bias, self-bias, and voltage divider bias. Fixed bias involves using a resistor and a biasing voltage source, self-bias relies on negative feedback to stabilize the operating point, and voltage divider bias uses resistors to establish the bias voltage.
4. How does FET biasing affect the amplifier's gain?
Ans. FET biasing directly affects the amplifier's gain by determining the operating point of the transistor. If the bias point is too low, the FET may not be able to amplify the input signal effectively, leading to a lower gain. On the other hand, if the bias point is too high, the FET may enter saturation, causing distortion and also reducing the gain.
5. What are the advantages and disadvantages of different FET biasing methods?
Ans. The fixed bias method provides a stable bias point but lacks flexibility in accommodating variations in transistor parameters. Self-bias offers better stability but may be sensitive to temperature changes. Voltage divider bias provides good stability and flexibility but requires careful selection of resistor values to ensure proper biasing. Additionally, voltage divider bias may introduce noise due to the resistor network.
137 videos|143 docs|71 tests
Download as PDF
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)

,

Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)

,

Sample Paper

,

pdf

,

Biasing FET | Analog and Digital Electronics - Electrical Engineering (EE)

,

Previous Year Questions with Solutions

,

study material

,

Extra Questions

,

Semester Notes

,

MCQs

,

video lectures

,

mock tests for examination

,

shortcuts and tricks

,

Exam

,

Summary

,

Important questions

,

Objective type Questions

,

Free

,

practice quizzes

,

past year papers

,

Viva Questions

,

ppt

;