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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Test  >  Analog and Digital Electronics  >  Test: Voltage Regulation Using Zener Diode - Electrical Engineering (EE) MCQ

Voltage Regulation Using Zener Diode - GATE EE Analog and Digital Electronics


MCQ Practice Test & Solutions: Test: Voltage Regulation Using Zener Diode (10 Questions)

You can prepare effectively for Electrical Engineering (EE) Analog and Digital Electronics with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Voltage Regulation Using Zener Diode". These 10 questions have been designed by the experts with the latest curriculum of Electrical Engineering (EE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Voltage Regulation Using Zener Diode - Question 1
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The percentage voltage regulation (VL) is given by_________

Detailed Solution: Question 1

The change in the output voltage from no load to full load condition is called as voltage regulation, where VNL is the voltage at no load condition. It is used to maintain a nearly constant output voltage. If the regulation is high, the output voltage is stable.

Test: Voltage Regulation Using Zener Diode - Question 2
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The limiting value of the current resistor used in a Zener diode (when used as a regulator)

Detailed Solution: Question 2

When the input voltage is maximum, the load current is minimum, the Zener current should not increase the maximum rated value. Therefore there should be a minimum value of resistor.

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Test: Voltage Regulation Using Zener Diode - Question 3
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When the regulation by a Zener diode is with a varying input voltage, what happens to the voltage drop across the resistance?

Detailed Solution: Question 3

 When the input voltage varies, the input current also varies. This makes more current to flow in the diode. This increase in the current should balance a change in the load current. Hence the voltage drop increases across the resistor.

Test: Voltage Regulation Using Zener Diode - Question 4
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In the given limiter circuit, an input voltage Vi=10sin100πt is applied. Assume that the diode drop is 0.7V when it’s forward biased. The zener breakdown voltage is 6.8V.The maximum and minimum values of outputs voltage are _______

Detailed Solution: Question 4

With VI= 10V when maximum, D1 is forward biased, D2 is reverse biased. Zener is in breakdown region. VOMAX=sum of breakdown voltage and diode drop=6.8+0.7=7.5V. VOMIN=negative of voltage drop=-0.7V. There will be no breakdown voltage here.

Test: Voltage Regulation Using Zener Diode - Question 5
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Determine the maximum and minimum values of load current for which the Zener diode shunt regulator will maintain regulation when VIN=24V and R=500Ω. The Zener diode has a VZ=12V and (IZ)MAX=90mA (Iz)min = 3 mA

Detailed Solution: Question 5

The current through the resistance R is given by, I=(VIN-VZ)/R= (24-12)/500=24mA. (IL)MAX=I-(IZ)MIN=24-3=21mA .This current is less than (IZ)MAX. So, we assume that all the input current flows through the Zener diode. Under this condition, (IL)MINis 0mA.

Test: Voltage Regulation Using Zener Diode - Question 6
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Determine the minimum value of load resistance that can be used in the circuit with (IZ)Min=3mA. The input voltage is 10V and the resistance R is 500Ω. The Zener diode has a VZ=6V 0and (IZ)MAX=90mA.

Detailed Solution: Question 6

The I=(VIN-VZ)/R=(10-6)/500=8mA. (IL)MAX=I-(IZ)MIN=8-3=5mA. (RL)MIN=VZ/(IL)MAX=6/5m=1.2KΩ.

Test: Voltage Regulation Using Zener Diode - Question 7
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A Zener regulator has to handle supply voltage variation from 19.5V to 22.5V. Find the magnitude of regulating resistance, if the load resistance is 6KΩ. The Zener diode has the following specifications: breakdown voltage =18V, (IZ)Min=2µA, maximum power dissipation=60mW and Zener resistance =20Ω.

Detailed Solution: Question 7

(PZ)MAX/rZ=(IZ)MAX2 . So, (IZ)MAX =60m/20=54.8µA. IL=VO/RL=18/6000=3mA.
RMAX=(VMin-VZ)/[( IZ)Min+( IL)MAX]=(19.5-18)/(2µ+3m)=500Ω.
RMin=(VMAX-VZ)/[( IZ)MAX+( IL)Min]=(22.5-18)/(54.8m+3m)=77.8Ω.

Test: Voltage Regulation Using Zener Diode - Question 8
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A transistor series regulator has the following specifications: VIN=15V, VZ=8.3V, β=100, R=1.8KΩ, RL=2KΩ. What will be the Zener current in the regulator circuit?

Detailed Solution: Question 8

We know, VO=VZ-VBE=8.3-0.7=7.6V. VCE=VIN-V0=15-7.6=7.4V. So, IR=(VIN-VZ)/R=(15-8.3)/1.8m=3.72mA. IL=VO/RL=7.6/2000=3.8mA. IB=IL/ β=3.8mA/100=0.038mA. Finally, IZ=IR-IB=3.72-0.038=3.682mA.

Test: Voltage Regulation Using Zener Diode - Question 9
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When is a regulator used?

Detailed Solution: Question 9

The regulator has following limitations: 1.It has low efficiency for heavy load currents 2. The output voltage changes slightly due to Zener impedance. Hence, it is used when there are small variations in load current and input voltage.

Test: Voltage Regulation Using Zener Diode - Question 10
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 A transistor in a series voltage regulator acts like a variable resistor. The value of its resistance is determined by _______

Detailed Solution: Question 10

The principle is based on the fact that a large fraction of the increase in input voltage appears across the transistor so that the output voltage remains to be constant. When input voltage is increased, the output voltage also increases which biases the transistor towards less current.

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About this Electrical Engineering (EE) Practice Test

This test contains 10 MCQs on Voltage Regulation Using Zener Diode with detailed solutions for each question. It is part of the Analog and Digital Electronics course on EduRev, designed to align with the current Electrical Engineering (EE) syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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