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30 Questions MCQ Test - Full Test 4 - EKT EEE

Full Test 4 - EKT EEE for AFCAT 2024 is part of AFCAT preparation. The Full Test 4 - EKT EEE questions and answers have been prepared according to the AFCAT exam syllabus.The Full Test 4 - EKT EEE MCQs are made for AFCAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Full Test 4 - EKT EEE below.
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Full Test 4 - EKT EEE - Question 1

If rank of   is 2 then λ is

Detailed Solution for Full Test 4 - EKT EEE - Question 1

The given matrix is 

 

The determinant is given as |A| = λ3 – 1               

If ⍴(A) is given as 2, then the determinant of A should be zero

⇒ |A| = 0 ⇒ λ3 – 1 = 0;

We get λ = 1  at which there are more than one 22 sub-matrices having non zero determinant

∴ value of λ is 1 for which rank of A is 2

Full Test 4 - EKT EEE - Question 2

If  then angle between 

Detailed Solution for Full Test 4 - EKT EEE - Question 2

Given that 
Squaring the above equation, we get 
Putting the values, the equation becomes 
Thus we get 
∴ a ⊥ b
∴ Angle between 

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Full Test 4 - EKT EEE - Question 3

The value of 

Detailed Solution for Full Test 4 - EKT EEE - Question 3

The given integral is of the beta function. Hence it can be written as

Here n = 4, therefore the integral becomes

Full Test 4 - EKT EEE - Question 4

Find the value of L{a.cosat}

Detailed Solution for Full Test 4 - EKT EEE - Question 4

L{a.cosat}
=a.L{.cosat}

Full Test 4 - EKT EEE - Question 5

If X and Y are two independent events with P(X∪Y) = 0.8 and P(Y) = 0.5 then P(X) =

Detailed Solution for Full Test 4 - EKT EEE - Question 5

We know that P(X∪Y)=P(X)+P(Y)−P(X∩Y)
Given that both X and Y are independent hence P(X∩Y)=P(X).P(Y)
So 0.8=P(X)+0.5−0.5×P(X)
0.3=0.5P(X)

Full Test 4 - EKT EEE - Question 6

If two equal forces of magnitude P acts at an angle θ, their resultant will be

Detailed Solution for Full Test 4 - EKT EEE - Question 6

Magnitude of resultant Forces F1 and F2 is:

F1 and F2 = P

Full Test 4 - EKT EEE - Question 7

Dimensional representation of thermal resistance is equal to

Detailed Solution for Full Test 4 - EKT EEE - Question 7

The unit of thermal resistance is kelvin per watt. So the dimension for it will be [power]-1[K]. The dimension will thus be [M-1L-2T3K].

Full Test 4 - EKT EEE - Question 8

The dimension of RC is

Detailed Solution for Full Test 4 - EKT EEE - Question 8

RC is the time constant of a series resistance capacitance DC voltage circuit. The dimension of RC is same as that of time.

Full Test 4 - EKT EEE - Question 9

The colors on a soap bubble is due to

Detailed Solution for Full Test 4 - EKT EEE - Question 9

Color in soap bubble is due to phenomenon of thin film interference. There is a thin film like structure formed between the outer and inner surface of the bubble, which reflects a spectrum of beautiful colors from its surface.

Full Test 4 - EKT EEE - Question 10

The physical properties of electromagnetic waves are determined by their

Detailed Solution for Full Test 4 - EKT EEE - Question 10

The physical properties of electromagnetic waves can be determined from the spectroscopy experiment which detects the wavelengths of objects emitting these.

Full Test 4 - EKT EEE - Question 11

The velocity of sound will be least in

Detailed Solution for Full Test 4 - EKT EEE - Question 11

Greater the stiffness of the material, more is the speed. Speed of sound in metallic solid will be higher than in a gas or liquid. Hence the velocity of sound will be least in distilled water.

Full Test 4 - EKT EEE - Question 12

A line AB is parallel to both HP and VP. Its side view will be ______

Detailed Solution for Full Test 4 - EKT EEE - Question 12

A line AB is parallel to both HP and VP. Its side view will be a point.

Or it can be viewed as:

Full Test 4 - EKT EEE - Question 13

The total current flow in an ECL circuit remains relatively constant

Detailed Solution for Full Test 4 - EKT EEE - Question 13

ECL - Emitter Coupled Logic circuit uses differential pair of transistors biased by constant current source coupled to emitter.

Depending on the logic the current flows from one transistor or the other, the total current drawn by the circuit remains same regardless of logic.

Since the current is constant during switching , hence unlike in CMOS or TTL no noise spikes occur during switching.

Full Test 4 - EKT EEE - Question 14

Which of the following characteristics are possessed by a transformer coupled class B push pull power amplifier?

1. It eliminates even harmonic distortion

2. It suffers from cross over distortion

3. Its device ratings are higher than those of class A power amplifier

4. Its collector circuit efficiency is more than that of class C power amplifier

Select the correct answer using the code given below:

Detailed Solution for Full Test 4 - EKT EEE - Question 14

Transformer coupled class B push pull amplifiers:

1. It suffers from cross over distortions

2. It eliminates even harmonic distortion

3. Its device ratings lower than class A power amplifiers

4. Theoretical efficiency is 78%

Full Test 4 - EKT EEE - Question 15

An Op-Amp comparator circuit employs

Detailed Solution for Full Test 4 - EKT EEE - Question 15

Op-Amp comparator circuit is used to compare the difference between voltage level of two inputs (inverting and non-inverting) and also determines which one is greater. It requires no feedback circuit.

Full Test 4 - EKT EEE - Question 16

A quartz crystal oscillator consists of

Detailed Solution for Full Test 4 - EKT EEE - Question 16

Crystal Oscillator has two closely spaced resonant frequency. In crystal oscillator, series resonant frequency occurs when reactance of the capacitor is equal to the reactance of the inductor (low impedance). Parallel resonant frequency occurs when reactance of the capacitor C2 is equal to the reactance of RLC1 branch (High impedance).

Full Test 4 - EKT EEE - Question 17

What is dual of A+[B+(AC)]+D

Detailed Solution for Full Test 4 - EKT EEE - Question 17

To get the dual of the given expression change OR to AND operator and AND to OR operator.
A+[B+(AC)]+D=A[B(A+C)]D

Full Test 4 - EKT EEE - Question 18

The hexadecimal representation of (657)8 is

Detailed Solution for Full Test 4 - EKT EEE - Question 18

(657)8=(110101111)2=(1AF)16=1AFH

Full Test 4 - EKT EEE - Question 19

The full scale output of a 10 – bit DAC is 5V. the resolution is

Detailed Solution for Full Test 4 - EKT EEE - Question 19

DAC has 10 bits, that means the total number of steps =210−1=1023
Resolution = 

Full Test 4 - EKT EEE - Question 20

Which of the following circuits come under the class of combinational logic circuits?

1. Full adder

2. Full subtractor

3. Half adder

4. J – K flop – flop

5. Counter

Select the correct answer from the codes given below – 

Detailed Solution for Full Test 4 - EKT EEE - Question 20

Full adder, full subtractor and half adder are combinational circuits.

JK flip flop and counter are sequential circuits.

Full Test 4 - EKT EEE - Question 21

Merz-price protection is generally used in

Detailed Solution for Full Test 4 - EKT EEE - Question 21

Differential circulating current protection scheme or merz-price protection scheme is a popular method of alternator stator protection.

Full Test 4 - EKT EEE - Question 22

The core of any transformer is laminated so as to

Detailed Solution for Full Test 4 - EKT EEE - Question 22
  • Transformer cores are laminated in order to minimize eddy current loss.
  • By providing laminations, the area of each part gets reduced and hence resistance will get very high which limits the eddy current to a minimum value and hence eddy current losses gets reduced
  • The laminations provide small gaps between the plates. As it is easier for magnetic flux to flow through iron than air or coil, the stray flux or leakage flux that can cause core losses is minimized.
Full Test 4 - EKT EEE - Question 23

In a dc machine, the laminated parts are the armature core and

Detailed Solution for Full Test 4 - EKT EEE - Question 23

Apart from the armature core, the pole core and pole shoes are also laminated. They are made of thin laminations of annealed steel which are riveted together.

Full Test 4 - EKT EEE - Question 24

An ideal transformer is one which

Detailed Solution for Full Test 4 - EKT EEE - Question 24

In an ideal transformer, there are no no-load losses and magnetic leakage losses. Rest other things can be used in practical transformers also.

Full Test 4 - EKT EEE - Question 25

In a dc generator, sparking at brushes results due to 

Detailed Solution for Full Test 4 - EKT EEE - Question 25

In commutation, if reversal of current is completed during the short circuit time then the coil develops reactance voltage due to which sparking occurs at the brushes.

Full Test 4 - EKT EEE - Question 26

The depletion capacitance CJ of an abrupt P - N junction is related to the reverse bias voltage by

Detailed Solution for Full Test 4 - EKT EEE - Question 26

The value of Junction depletion capacitance is given by

Where A = Area of junction
W = width of Depletion region = 

Full Test 4 - EKT EEE - Question 27

Avalanche photodiodes are preferred over PIN diodes in optical communication systems because of

Detailed Solution for Full Test 4 - EKT EEE - Question 27

P-i-N photodiodes contain layer of intrinsic semiconductor sandwiched between, P and N type semiconductors. The depletion region is contained entirely in the i-region.The thickness of intrinsic region can be adjusted to produce device with optimum sensitivity and frequency response.

Avalanche photo diodes arc reverse-biased p-n junction diodes that arc operated at voltages above breakdown voltage. They have higher power handling capacity.

Full Test 4 - EKT EEE - Question 28

The energy band diagram of a semiconductor material is as shown in figure below, the type of semi-conductor is

Where EC is conduction band energy, EV is valence band energy. EI is impurity energy level.

Detailed Solution for Full Test 4 - EKT EEE - Question 28

When impurities are added to other wise perfect crystals of semiconductors additional energy levels are created. In P-type semiconductor accepted impurities have one covalent bond empty which will easily accept a free electron from valence band due to thermal or optical excitation. The energy level is closer to valence band in P-type semiconductor.

Full Test 4 - EKT EEE - Question 29

The threshold voltage of an n-channel enhancement MOSFET can be increased by _____.

Detailed Solution for Full Test 4 - EKT EEE - Question 29

In an n-channel enhancement MOSFET, the drain current flows through the narrow channel of electrons produced in the p-type substrate due to applied minimum VGS known as the threshold voltage.

With the increase in the number of minority charge carriers in the substrate (in this case electrons) less gate-source voltage is needed to start drain-current. So to increase threshold voltage minority charge carriers need to be reduced, hence channel doping should be increased

Hence threshold voltage of an n-channel MOSFET can be increased by increasing the channel(substrate) doping concentration.

Full Test 4 - EKT EEE - Question 30

Which of the following is the name given to resistance of thin films that are uniform in thickness?

Detailed Solution for Full Test 4 - EKT EEE - Question 30

Sheet resistance is a measure of resistance of thin films that are nominally uniform in thickness. It is commonly used to characterize materials made by semiconductor doping, metal deposition, resistive paste printing, and glass coating.

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