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Monthly Mock Test (April 30) - NEET MCQ


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30 Questions MCQ Test - Monthly Mock Test (April 30)

Monthly Mock Test (April 30) for NEET 2024 is part of NEET preparation. The Monthly Mock Test (April 30) questions and answers have been prepared according to the NEET exam syllabus.The Monthly Mock Test (April 30) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Monthly Mock Test (April 30) below.
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Monthly Mock Test (April 30) - Question 1

An organic compound contains 80% (by wt.) carbon and the remaining percentage of hydrogen. The right option for the empirical formula of this compound is: [Atomic wt. of C is 12, H is 1]     (2021)

Detailed Solution for Monthly Mock Test (April 30) - Question 1

Hence empirical formula =CH3

Additional Information: An empirical formula represents the simplest whole-number ratio of various atoms present in a compound, whereas, the molecular formula shows the exact number of different types of atoms present in a molecule of a compound.

Monthly Mock Test (April 30) - Question 2

The dimensions of   are    [2011]

Detailed Solution for Monthly Mock Test (April 30) - Question 2

, so, dimensions are [LTT–1].

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Monthly Mock Test (April 30) - Question 3

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be: 

Detailed Solution for Monthly Mock Test (April 30) - Question 3

2H​+ O2​ → 2H2​O

10 g of hydrogen (molar mass 2 g/mol) = 2 g/mol  10 g ​= 5 mol 

64 of oxygen  (molar mass 32 g/mol) = 32 g/mol  64 g ​= 2 mol 

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent.

Hence the amount of H2O produced depends on the amount of Otaken
0.5 mole of O2 gives H2O = 1 mol
∴ 2 mole of O2 gives H2O = 4 mol

Monthly Mock Test (April 30) - Question 4

What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 1L of propane gas (C3H8) measured under the same conditions? [2008]

Detailed Solution for Monthly Mock Test (April 30) - Question 4

Writing the equation of  combustion of propane (C3H8), we get

From the above equation we find that we need 5 L of oxygen at NTP to completely burn 1 L of propane at N.T.P.
If we change the conditions for both the gases from N.T.P. to same conditions of temperature and pressure. The same results are obtained. i.e. 5 L is the correct answer.

Monthly Mock Test (April 30) - Question 5

Selaginella and Salvinia are considered to represent a significant step toward evolution of seed habit because: [2011M]

Detailed Solution for Monthly Mock Test (April 30) - Question 5

Genera like Selaginella and Salvinia which produce two kind of spores, macro (large) and small (micro) spores are known as heterosporous. Microspore and macrospore germinate and gives rise to male and female gametophyte respectively. The female gametophytes in these plants are retained on the parent sporophyte for variable period. The development of zygote into young embryo takes place within the female gametophytes. This event is a precursor to the seed habits considered as an important step in evolution.
So, the correct answer is 'Embryo develops in female gametophyte which is retained on parent sporophyte'

Monthly Mock Test (April 30) - Question 6

The dimensions of universal gravitational constant are [1992, 2004]

Detailed Solution for Monthly Mock Test (April 30) - Question 6

∴  dimension of G is  

= M–1L3T–2

Monthly Mock Test (April 30) - Question 7

The percentage errors in the measurement of mass and speed are 2% and 3% respectively.The error in kinetic energy obtained by measuring mass and speed will be [1995]

Detailed Solution for Monthly Mock Test (April 30) - Question 7

Percentage error in mass 

percentage error in speed 

Kinetic energy 

∴ Error in measurement of kinetic energy

By Binomial Function ,

 Reqd. error

∴ %age error = 8%.

Monthly Mock Test (April 30) - Question 8

Archegoniophore is present in : [2011]

Detailed Solution for Monthly Mock Test (April 30) - Question 8

Archegoniophore is the female sex organ of bryophytes (Marchantia) and pteridophytes. Its neck region is made up of 4-6 vertical rows of cells.

Monthly Mock Test (April 30) - Question 9

Which one of the following aspects is an exclusive characteristic of living things? [2011M]

Detailed Solution for Monthly Mock Test (April 30) - Question 9
  • Metabolism is the process by which all living things assimilate energy and use it for various purposes such as growth, movement, locomotion etc. This mechanism of metabolism is not shown by nonliving objects. However, some of the metabolic reactions can be carried out in a cell-free system or outside the cells. Isolated metabolic reactions in vitro are not living things but are living reactions. Hence, statement A is incorrect.
  • All living organisms show growth either by multiplication or by an increase in size. It is an irreversible increase in the mass of individual from inside. Two types of substances are produced by the cells, apoplastic and protoplastic. Apoplastic substances are nonliving materials formed by the cells which become components of tissues. For example, cell wall, the matrix of bone etc. Protoplastic substances are the components of living matter like cytoplasm and nucleus.
  • Although some nonliving things like mountains, sand mounds, crystals also grow, their growth is due to the addition of matter from outside.

Hence, statements B and D are incorrect.

  • All organisms respond to external stimuli which can be physical, chemical or biological. This is called irritability. Stimuli are perceived by sense organs in animals but plants can respond to external factors like water, temperature, light etc. All organisms from prokaryote to the most complex eukaryotes can sense and respond to environmental events.

Hence, statement C is correct.

So, the correct answer is 'Perception of events happening in the environment and their memory'.

Monthly Mock Test (April 30) - Question 10

In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine): [NEET Kar. 2013]

Detailed Solution for Monthly Mock Test (April 30) - Question 10

Millimoles of solution of chloride = 0.05 × 10 = 0.5
Millimoles of AgNO3 solution = 10 × 0.1 = 1
So, the millimoles of AgNO3 are double than the chloride solution

Monthly Mock Test (April 30) - Question 11

The number of moles of KMnO4 that will be needed to react with one mole of sulphite ion in acidic solution is [2007]

Detailed Solution for Monthly Mock Test (April 30) - Question 11

The balanced chemical equation is:

 

From the equation, it is clear that 2 moles of MnO4  are required to oxidize 5 moles of SO3–2  

2/5 mole of MnO4 is required to oxidize 1 mole of SO3–2 

Monthly Mock Test (April 30) - Question 12

Nomenclature is governed by certain universal rules. Which one of the following is contrary to the rules of nomenclature?     [NEET 2016]

Detailed Solution for Monthly Mock Test (April 30) - Question 12
  • Binomial nomenclature (also called binomial nomenclature or binary nomenclature) is a formal system of naming species of living things by giving each a name composed of two parts, both of which use Latin grammatical forms, although they can be based on words from other languages.

Monthly Mock Test (April 30) - Question 13

In which one of the following sets of animals do all the four give birth to young ones? [2006]

Detailed Solution for Monthly Mock Test (April 30) - Question 13

Penguin, Kiwi & Ostrich all belong to class Aves of chordata (i.e. birds) and they do not give birth to their young ones, they are oviparous while Kangaroo, Hedgehog, Dolphin, Loris all belong to class mammalia and are viviparous.

Monthly Mock Test (April 30) - Question 14

Which one of the following is true for fungi? [NEET Kar. 2013]

Detailed Solution for Monthly Mock Test (April 30) - Question 14

Fungi lack chlorophyll, hence, they do not prepare their food by photosynthesis. They can grow where organic material is available. So, they are heterotrophs that acquire their nutrient by absorption and store in the form of glycogen.

Monthly Mock Test (April 30) - Question 15

The mass of carbon anode consumed (givin g only carbondioxide) in the production of 270 kg of aluminium metal from bauxite by the Hall process is  (Atomic mass: Al = 27) [2005]

Detailed Solution for Monthly Mock Test (April 30) - Question 15

2Al2O3 + 3C → Al3CO2

Gram equivalent  of Al2O3 = Gram equivalent of C

Equivalent weight of Al 

Equivalent weight of C

No. of gram equivalent of Al  = = 30 × 103
Hence, No. of gram equivalent of C = 30 × 103

Again, No. of gram equivalent of C
⇒  mass = 90 × 10g = 90 kg

Monthly Mock Test (April 30) - Question 16

Cycas have two cotyledons but not included in angiosperms because of [2001]

Detailed Solution for Monthly Mock Test (April 30) - Question 16

In Cycas (gymnosperm) the seed does not occur inside a fruit but lies naked  or exposed on the surface of megasporophyll.

Monthly Mock Test (April 30) - Question 17

Virus envelope is known as: [2010]

Detailed Solution for Monthly Mock Test (April 30) - Question 17

Virus envelope is known as capsid. The capsid is composed of protein subunits called capsomere.

Monthly Mock Test (April 30) - Question 18

The dimensional formula of pressure is [1990]

Detailed Solution for Monthly Mock Test (April 30) - Question 18

[Pressure] = [Force] / [Area]

= ML–1T–2

Monthly Mock Test (April 30) - Question 19

Biosystematics aims at: [2003]

Detailed Solution for Monthly Mock Test (April 30) - Question 19
  • Biosystematics is the study of biological diversity and its origins. It focuses on understanding evolutionary relationships among organisms, species, higher taxa or other biological entities, such as genes and the evolution of the properties of taxa including intrinsic traits, ecological interactions, and geographic distributions.
  • An important part of systematics is the development of methods for various aspects of phylogenetic inference and biological nomenclature.
  • Whereas morphological characteristics ( physical appearance) and cytological characteristics ( size of cell and nucleus) are not used for systematics.
Monthly Mock Test (April 30) - Question 20

An element , X has the following isotopic composition :
200X:90 %
199X : 8.0%
202X ; 2.0 %
The weighted average atomic mass of the naturally occuring element X is closest to

Detailed Solution for Monthly Mock Test (April 30) - Question 20

Average isotopic mass of,

= 199.96 amu ≈200 amu

Monthly Mock Test (April 30) - Question 21

Columella is a specialised structure found in the  sporangium of [1999]

Detailed Solution for Monthly Mock Test (April 30) - Question 21

Ulothrix is a green alga. Spirogyra is a filamentous green alga. In Rhizopus the columella bears the spores for asexual reproduction

Monthly Mock Test (April 30) - Question 22

The animals with bilateral symmetry in young stage, and radial pentamerous symmetry in the adult stage, belong to the phylum [2004]

Detailed Solution for Monthly Mock Test (April 30) - Question 22

Echinoderms show bilateral  symmetry  in their larval stage and pentamerous radial symmetry in the adult stage. Annelids are bilaterally symmetrical, coelenterates show radial symmetry.  Molluscs are also bilaterally symmetrical.

Monthly Mock Test (April 30) - Question 23

The unit of permittivity of free space, εo is  [2004]

Detailed Solution for Monthly Mock Test (April 30) - Question 23

⇒ unit of εo is (coulomb)2/ newton -metre2

Monthly Mock Test (April 30) - Question 24

In Ferns meiosis occurs when [2000]

Detailed Solution for Monthly Mock Test (April 30) - Question 24

Gametic meiosis is found in all animals.  In sporic meiosis the sporophyte produces sporangia where meiosis occurs producing haploid spores.

Monthly Mock Test (April 30) - Question 25

The number of moles of KMnO4 reduced by one mole of KI in alkaline medium is:   [2005]

Detailed Solution for Monthly Mock Test (April 30) - Question 25

Monthly Mock Test (April 30) - Question 26

The velocity v of a particle at time t is given by where a, b and c are constant.The dimensions of a, b and c are respectively [2006]

Detailed Solution for Monthly Mock Test (April 30) - Question 26

Dimension of  a. t = dimension of velocity a . t = LT-1 ⇒ a = LT-2
Dimension of c = dimension of t (two physical quantity of same dimension can only be added)

So, dimension of c = T

Dimension of   = Dimension of v

  

So, answer is LT–2, L & T

Monthly Mock Test (April 30) - Question 27

Which of the following pairs are correctly matched ? [2007]

Animals            -      Morphological features
(i) Crocodile - 4-chambered heart
(ii) Sea urchin - Parapodia
(iii) Obelia - Thecodont
(iv) Lemur - Thecodont

Detailed Solution for Monthly Mock Test (April 30) - Question 27

Crocodile belongs to reptilia class which has four chambered heart. Lemur teeth are combedded in the sockets of two which is known as thecodont.

Monthly Mock Test (April 30) - Question 28

The number of atoms in 0.1 mole of a triatomic gas is: [2010] (NA = 6.02 ×1023 mol–1)

Detailed Solution for Monthly Mock Test (April 30) - Question 28

1 mol of triatomic gas has 3 ×6.02×1023 atoms

Therefore, no. of atoms in 0.1 mol =0.1×  3 ×6.02×1023 = 1.806×1023

Monthly Mock Test (April 30) - Question 29

The time dependence of a physical quantity p is given by p = p0 exp (– αt2), where α is a constant and t is the time. The constant α [1993]

Detailed Solution for Monthly Mock Test (April 30) - Question 29

In p = p0 exp (–αt2), αt2 dimension less

Monthly Mock Test (April 30) - Question 30

Which one of the following pairs of animals comprises ‘jawless fishes’? [2009]

Detailed Solution for Monthly Mock Test (April 30) - Question 30

Lampreys and hagfishes are unusual, jawless fish that comprise the order Cyclostomata, so named because of the circular shape of the mouth. The brains of lampreys and hagfishes differ a lot, but they also show a large number of similarities, as do all craniate brains.

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