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JEE Main Mock Test - 8 - JEE MCQ


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30 Questions MCQ Test - JEE Main Mock Test - 8

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JEE Main Mock Test - 8 - Question 1

In thermodynamics, heat and work are:

Detailed Solution for JEE Main Mock Test - 8 - Question 1

Heat and work are treated as path functions in thermodynamics.
ΔQ = ΔU + ΔW
Since work done by gas depends on the type of process, i.e. path, and ΔU depends just on the initial and final states, ΔQ, i.e. heat, also has to depend on path.

JEE Main Mock Test - 8 - Question 2

Two gases A and B have equal pressure P, temperature T, and volume V. The two gases are mixed together and the resulting mixture has the same temperature T and volume V as before. The ratio of pressure exerted by the mixture to either of the two gases is:

Detailed Solution for JEE Main Mock Test - 8 - Question 2

Let P1 and P2 be the partial pressures of gases A and B, respectively. Under equal conditions of temperature and volume, P1 = P2
Let P be the total pressure exerted by the mixture of two gases A and B. Using Dalton's law of partial pressures, P = P1 + P2
⇒ P = 2P1 ⇒ P/P1 = 2/1 ⇒ P : P1 = 2 : 1

JEE Main Mock Test - 8 - Question 3

In an adiabatic process, the density of a diatomic gas becomes 32 times its initial value. The final pressure of the gas is found to be n times the initial pressure. The value of n is

Detailed Solution for JEE Main Mock Test - 8 - Question 3

JEE Main Mock Test - 8 - Question 4

A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by 20.0°C will be:
(Given: gas constant R = 8.3 JK-1 mol-1)

Detailed Solution for JEE Main Mock Test - 8 - Question 4

No. of moles = 44.8/22.4 = 2
The gas is monatomic, so CV = 3/2 R.
ΔQ = nCvΔT
= 2 × 3/2 R × 20
= 60R
= 60 × 8.3
= 498 J

JEE Main Mock Test - 8 - Question 5

A sample of an ideal gas is taken through the cyclic process ABCA as shown in figure. It absorbs 40 J of heat during the part AB, no heat during BC and rejects 60 J of heat during CA. A work of 50 J is done on the gas during the part BC. The internal energy of the gas at A is 1560 J. The work done by the gas during the part CA is:

Detailed Solution for JEE Main Mock Test - 8 - Question 5


ΔQcycle = 40 - 60 = ΔW
⇒ ΔW = -20J = WBC + WCA
⇒ WCA = -20J - WBC
= -20 - (-50)
= 30 J

JEE Main Mock Test - 8 - Question 6

A bag is gently dropped on a conveyor belt moving at a speed of 2 m/s. The coefficient of friction between the conveyor belt and bag is 0.4. Initially, the bag slips on the belt before it stops due to friction. The distance travelled by the bag on the belt during slipping motion is:
[Take g = 10 ms-2]

Detailed Solution for JEE Main Mock Test - 8 - Question 6


μ = 0.4
Velocity of the conveyor belt = 2 m/s
Initially, when the bag is dropped on the conveyor belt, it starts slipping.
So, kinetic friction acts on it, due to which it finally stops after some time.
Motion with respect to belt:

JEE Main Mock Test - 8 - Question 7

Two balls A and B are placed at the top of 180 m tall tower. Ball A is released from the top at t = 0 s. Ball B is thrown vertically down with an initial velocity 'u' at t = 2 s. After a certain time, both balls meet 100 m above the ground. Find the value of 'u' in ms-1. [Use g = 10 ms-2]

Detailed Solution for JEE Main Mock Test - 8 - Question 7

Let us assume that both the balls meet at time t.

= 4 sec
Time taken by ball B to meet A = 2 sec
Using, S = ut + 1/2 at2
-80 = -u × 2 + 1/2(-10)(2)2
u = 30 ms-1

JEE Main Mock Test - 8 - Question 8

A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms-1. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is [use g = 9.8 ms-2]

Detailed Solution for JEE Main Mock Test - 8 - Question 8

JEE Main Mock Test - 8 - Question 9

A person can throw a ball up to a maximum range of 100 m. How high above the ground can he throw the same ball?

Detailed Solution for JEE Main Mock Test - 8 - Question 9

JEE Main Mock Test - 8 - Question 10

A 100 g of iron nail is hit by a 1.5 kg hammer striking at a velocity of 60 ms-1. What will be the rise in the temperature of the nail if one fourth of energy of the hammer goes into heating the nail?
[Specific heat capacity of iron = 0.42 Jg-1 °C-1]

Detailed Solution for JEE Main Mock Test - 8 - Question 10

JEE Main Mock Test - 8 - Question 11

When a ball is dropped into a lake from a height 4.9 m above the water level, it hits the water with a velocity v and then sinks to the bottom with the constant velocity v. It reaches the bottom of the lake 4.0 s after it is dropped. The approximate depth of the lake is:

Detailed Solution for JEE Main Mock Test - 8 - Question 11

JEE Main Mock Test - 8 - Question 12

A clock has a continuously moving second's hand of 0.1 m length. The average acceleration of the tip of the hand (in units of ms-2) is of the order of

Detailed Solution for JEE Main Mock Test - 8 - Question 12

JEE Main Mock Test - 8 - Question 13

Detailed Solution for JEE Main Mock Test - 8 - Question 13

JEE Main Mock Test - 8 - Question 14

A radar sends an electromagnetic signal of electric filed (E0) = 2.25 V/m and magnetic field (B0) = 1.5 × 10-8 T which strikes a target on the line of sight at a distance of 3 km in a medium. After that, a part of signal (echo) reflects back towards the radar with the same velocity and by the same path. If the signal was transmitted at time t = 0 from the radar, then after how much time echo will reach to the radar?

Detailed Solution for JEE Main Mock Test - 8 - Question 14

E= 2.25V/m
B= 1.5× 10-8 T

JEE Main Mock Test - 8 - Question 15

In AM modulation, a signal is modulated on a carrier wave such that maximum and minimum amplitudes are found to be 6 V and 2 V, respectively. The modulation index is

Detailed Solution for JEE Main Mock Test - 8 - Question 15

JEE Main Mock Test - 8 - Question 16

Detailed Solution for JEE Main Mock Test - 8 - Question 16

JEE Main Mock Test - 8 - Question 17

Only 2% of the optical source frequency is the available channel bandwidth for an optical communicating system operating at 1000 nm. If an audio signal requires a bandwidth of 8 kHz, how many channels can be accommodated for transmission?

Detailed Solution for JEE Main Mock Test - 8 - Question 17

JEE Main Mock Test - 8 - Question 18

Which one of the following will be the output of the given circuit?

Detailed Solution for JEE Main Mock Test - 8 - Question 18

*Answer can only contain numeric values
JEE Main Mock Test - 8 - Question 19

A block of ice of mass 120 g at temperature 0°C is put in 300 gm of water at 25°C. The x g of ice melts as the temperature of the water reaches 0°C. The value of x is (in integers)
[Use: Specific heat capacity of water = 4,200 Jkg-1K-1, Latent heat of ice = 3.5 × 105 Jkg-1]


Detailed Solution for JEE Main Mock Test - 8 - Question 19

Energy released by water = 0.3 × 25 × 4,200 = 31,500 J
Suppose m kg of ice melts.
m × 3.5 × 105 = 31,500

m = 0.09 kg = 90 gm
x = 90

*Answer can only contain numeric values
JEE Main Mock Test - 8 - Question 20

A closed vessel contains 0.1 mole of a monatomic ideal gas at 200 K. If 0.05 mole of the same gas at 400 K is added to it, the final equilibrium temperature (in K) of the gas in the vessel will be close to _________.
(Answer up to two decimal places)


Detailed Solution for JEE Main Mock Test - 8 - Question 20

As the work done on the gas and the heat supplied to the gas are zero, total internal energy of gas remains same.
u1 + u2 = u1' + u2'
(0.1) CV (200) + (0.05) CV (400) = (0.15) CV T
T = 800/3 K = 266.67 K

*Answer can only contain numeric values
JEE Main Mock Test - 8 - Question 21

A diatomic gas (γ = 1.4) does 400 J of work when it is expanded isobarically. The heat given to the gas in the process is ________ J. (in integers)


Detailed Solution for JEE Main Mock Test - 8 - Question 21

*Answer can only contain numeric values
JEE Main Mock Test - 8 - Question 22

If 2.5 × 10-6 N average force is exerted by a light wave on a non-reflecting surface of 30 cm2 area during 40 minutes of time span, the energy flux of light just before it falls on the surface is _____ W/cm2.
(Round off to the nearest integer)
(Assume complete absorption and normal incidence conditions)


Detailed Solution for JEE Main Mock Test - 8 - Question 22

*Answer can only contain numeric values
JEE Main Mock Test - 8 - Question 23

When light of frequency twice the threshold frequency is incident on the metal plate, the maximum velocity of emitted electron is v1. When the frequency of incident radiation is increased to five times the threshold value, the maximum velocity of emitted electron becomes v2. If v2 = xv1, the value of x will be ________. (In Integers)


Detailed Solution for JEE Main Mock Test - 8 - Question 23

JEE Main Mock Test - 8 - Question 24

The coordination numbers of Co and Al, in [Co(Cl)(en)2]Cl and K3[Al(C2O4)3], respectively are
(en = ethane-1, 2-diamine)

Detailed Solution for JEE Main Mock Test - 8 - Question 24

[CoCl(en)2]Cl
en is a bidentate ligand.
Cl- is a monodentate ligand.
Since the central metal ion(Co+3) is involved in 5 coordination bonds, the co-ordination number of Co is 5.
K3[Al(C2O4)3]
C2O42- is a bidentate ligand.
Since the central metal ion(Al+3) is involved in 6 coordination bonds, the co-ordination number of Al is 6.

JEE Main Mock Test - 8 - Question 25

Which one of the following reactions will not yield propionic acid?

Detailed Solution for JEE Main Mock Test - 8 - Question 25

All except option 1 give propionic acid as the product, but option 1 yields butanoic as the product.

JEE Main Mock Test - 8 - Question 26

Given below are two statements:

Statement I: Potassium permanganate on heating at 573 K forms potassium manganate.
Statement II: Both potassium permanganate and potassium manganate are tetrahedral and paramagnetic in nature.

In the light of the above statements, choose the most appropriate answer from the options given below:

Detailed Solution for JEE Main Mock Test - 8 - Question 26

JEE Main Mock Test - 8 - Question 27

The number of isomers possible for [Pt(en)(NO2)2] is

Detailed Solution for JEE Main Mock Test - 8 - Question 27

When two compounds have the same molecular formula and the same structural formula but differ in the spatial arrangement of atoms or group of atoms due to the restricted rotation of double bonds (about single bond in the case of cyclic compounds), they are said to exhibit geometrical isomerism.
Optical isomers are two compounds which contain the same number and kinds of atoms, and bonds (i.e., the connectivity between atoms is the same), and different spatial arrangements of the atoms, but which have non-superimposable mirror images. Each non-superimposable mirror image structure is called an enantiomer.

[Pt(en)(NO2)2]:
It does not show G.I. as well as optical isomerism.



This complex will have three linkage isomers as follows:
[Pt(en)(NO2)2] I
[Pt(en)(NO2)(ONO)] II
[Pt(en)(ONO)2] III

JEE Main Mock Test - 8 - Question 28

The pair in which both the species have the same magnetic moment (spin only) is:

Detailed Solution for JEE Main Mock Test - 8 - Question 28


Thus, the complexes [Cr(H2O)6]2+ and [Fe(H2O)6]2+ have same number of unpaired electrons and hence same magnetic moment (spin only).

JEE Main Mock Test - 8 - Question 29

The values of the crystal field stabilization energies for a high spin d6 metal ion in octahedral and tetrahedral fields, respectively, are

Detailed Solution for JEE Main Mock Test - 8 - Question 29

For high spin octahedral field,



CFSE = (4)(-0.4Δ0) + 2(0.6Δ0) = -0.4Δ0

For high spin tetrahedral field,



CFSE = 3(-0.6Δt) + 3 (0.4Δt) = -0.6Δt

JEE Main Mock Test - 8 - Question 30

The theory that can completely/properly explain the nature of bonding in [Ni(CO)4] is:

Detailed Solution for JEE Main Mock Test - 8 - Question 30

The synergic bonding between the central metal atom and the carbonyl ligand is best explained by the molecular orbital theory.
The metal-carbonyl σ formed is formed by the donation of a pair of electrons from a bonding molecular orbital of carbon monoxide into the vacant d-orbital of the metal atom.
The metal-carbonyl π is formed by the donation of a pair of electrons from a filled d-orbital of metal into the vacant antibonding π* orbital of carbon monoxide.
Therefore, option (1) is correct.

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