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Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - NEET MCQ


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10 Questions MCQ Test - Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4)

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) for NEET 2024 is part of NEET preparation. The Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) questions and answers have been prepared according to the NEET exam syllabus.The Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) below.
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Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 1

Capacitive reactance of the capacitor depends upon

Detailed Solution for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 1

Capacitive reactance (symbol XC) is a measure of a capacitor’s opposition to AC (alternating current). Like resistance it is measured in ohms, but reactance is more complex than resistance because its value depends on the frequency (f) of the signal passing through the capacitor. Reactance is also inversely proportional to the value of capacitance (C), i.e. the value of XC at any frequency will be less in larger capacitors than in smaller ones. All capacitors have infinitely high values of reactance at 0Hz, but in large capacitors, the reactance falls to a low level at much lower frequencies than in smaller capacitors. Hence, larger capacitors are preferred in low frequency applications.

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 2

The average power dissipation in pure inductance is:

Detailed Solution for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 2

In pure inductance circuit, R=0
Thus power factor of pure inductance circuit cosϕ=R/Z​=0
Average power dissipation Pav​=Vrms​Irms​cosϕ
⟹ Pav​=0

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Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 3

An a.c. voltage source E= 200 √2 sin 100t is connected across a circuit containing an a.c ammeter and a capacitor of capacitance 1μF. The reading of the ammeter is:​

Detailed Solution for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 3

equation of alternating voltage , E = 200√2sin(100t)
compare this equation with E0sin(ωt)
so,  E0=200√2 volts
ω= 100 rad/s
now, Erms=E0/√2
= 200√2/√2 = 200 volts .
given, capacitance of capacitor, C = 10-6 F
so, reactance of capacitor,  XC=1/ωC
=1/(10-6x100)
=104
so, the reading of Ammeter, I=Erms/XC
= 200/104 A = 20 × 10-3 A = 20mA
hence, option (b) is correct.

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 4

In a ac circuit with capacitance, the current

Detailed Solution for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 4

Voltage lags current by 90° in a pure capacitive circuit. In a pure capacitive circuit, the instantaneous power may be positive or negative. As with the simple inductor circuit, the 90-degree phase shift between voltage and current results in a power wave that alternates equally between positive and negative.

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 5

What is the capacitive reactance of 6 x 10-6 F capacitor for frequency of 106 Hz?​

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 6

Q factor is

Detailed Solution for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 6

Q-factor: In LCR Circuit, the ratio of resonance frequency to the difference of its neighbouring frequencies so that their corresponding current is 1/√2​ times of the peak value, is called Q-factor of the circuit.
Formula: Q=(1/R)​ √(L/C)​​
So, Q ∝1/R
Conditions for the large value of Q factor:
(i) Value of CL​ should be large.
(ii) Value of R should be less.
 

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 7

In purely inductive circuits, the current:

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 8

If a resistor is connected across the voltage source and the frequency of voltage and current wave form is 50Hz, then what is frequency of instantaneous power

Detailed Solution for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 8

P(t)=VmImSin2ωt
P(t)=0.5VmIm(2sin2ωt)
P(t)= 0.5VmIm(1-cos2ωt)
Therefore, frequency is doubled for the instantaneous power so, frequency of instantaneous power is 100Hz.
 

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 9

The average power dissipation in pure capacitive circuit is:

Detailed Solution for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 9

As we know,
Average power in ac circuit is given by P=Vrms​irms​cosϕ 
For pure capacitive circuit ϕ=90o so P=0

Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 10

When a fluorescent tube is used in A.C. circuit:

Detailed Solution for Test: AC Voltage Applied to an Inductor, Capacitor & Series LCR Circuit (February 4) - Question 10

In a.c. circuits, a choke coil is used to control the current in place of a resistance. If a resistance is used to control the current, the electrical energy will be wasted in the form of heat. Due to its inductive reactance, a choke coil decreases the current without wasting electrical energy in the form of heat.

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