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Boats And Streams- 1 - CUET Commerce Free MCQ Test with solutions


MCQ Practice Test & Solutions: Test: Boats And Streams- 1 (10 Questions)

You can prepare effectively for CUET Commerce General Test Preparation for CUET UG with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Boats And Streams- 1". These 10 questions have been designed by the experts with the latest curriculum of CUET Commerce 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Boats And Streams- 1 - Question 1

Q. A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:

Detailed Solution: Question 1

Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.

Man's rate against the current = (12.5 - 2.5) km/hr = 10 km/hr.

Test: Boats And Streams- 1 - Question 2

A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
 

Detailed Solution: Question 2

Let the speed of the stream be x km/hr. Then,

Speed downstream = (15 + x) km/hr,

Speed upstream = (15 - x) km/hr.

⇒  9x2 = 225

⇒  x2 = 25

⇒  x = 5 km/hr.

Test: Boats And Streams- 1 - Question 3

In one hour, a boat goes 14 km/hr along the stream and 8 km/hr against the stream. The speed of the boat in still water (in km/hr) is:

Detailed Solution: Question 3

Test: Boats And Streams- 1 - Question 4

A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:
 

Detailed Solution: Question 4

Suppose he move 4 km downstream in x hours. Then,

Speed downstream = 

Speed upstream = 

So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.

Test: Boats And Streams- 1 - Question 5

A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water?

Detailed Solution: Question 5

Rate downstream = 

Rate upstream = 2 km/hr.

Speed in still water = 

 Required time = 

Test: Boats And Streams- 1 - Question 6

Speed of a boat in standing water is 14 kmph and the speed of the stream is 1.2 kmph. A man rows to a place at a distance of 4864 km and comes back to the starting point. The total time taken by him is:
 

Detailed Solution: Question 6

Speed downstream = (14 + 1.2)
= 15.2kmph
Speed upstream = (14-1.2)
= 12.8kmph
Total time taken = 4864/15.2 + 4864/12.8
= 320 + 380
= 700hrs

Test: Boats And Streams- 1 - Question 7

The speed of a boat in still water in 22 km/hr and the rate of current is 4 km/hr. The distance travelled downstream in 24 minutes is:
 

Detailed Solution: Question 7

Speed downstream = (22 + 4) kmph = 26 kmph.

Distance travelled = 26 x 24/60

Distance travelled = 10.4 km

Test: Boats And Streams- 1 - Question 8

A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while it takes 4 hours to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively?

Detailed Solution: Question 8

Let the man's rate upstream be x kmph and that downstream be y kmph.

Then, distance covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.

Test: Boats And Streams- 1 - Question 9

A boat can travel with a speed of 22 km/hr in still water. If the speed of the stream is 5 km/hr, find the time taken by the boat to go 54 km downstream.

Detailed Solution: Question 9

Speed downstream = (22 + 5) km/hr = 27 km/hr.

Time taken to travel 54 km downstream = (54/27) hours

= 2 hours 

Test: Boats And Streams- 1 - Question 10

A boat can travel 20 km downstream in 24 min. The ratio of the speed of the boat in still water to the speed of the stream is 4 : 1. How much time will the boat take to cover 15 km upstream?

Detailed Solution: Question 10

Down speed =20/24*60 = 50km/hr
4:1 = 4x:x
Downstream speed = 4x+x = 5x
Upstream speed = 4x-x=3x 5x = 50; x =10
So upstream speed = 3*10 = 30
Time = 15/30*60 = 30 mins

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