Test: Simple Interest- 2

Take P=x
given T=25/8
& I=1/4x
w.k.t I=PTR/100
1/4x =x*25/8*R/100
R = 8%

Amount borrowed = Rs.10
Let rate of interest = R%
Simple Interest for Rs.10 for 6 months at R% =

Payment after 1st month = Rs.3
Interest for this Rs.3 for the remaining 4 months =

Payment after 5th month = Rs.3
Interest for this Rs.3 for the remaining 1 month   = 

Payment after 6th month = Rs.3 and this closes the loan

Hence the rate of interest is 640%
 

We have to find the annual payment that will discharge a debt of Rs. 6450 in 4 years at a 5% per annum interest rate. We can solve this problem using the annuity formula.

The annuity formula is given by:

P = (R * (1 - (1 + r)^(-n))) / r

Where P is the present value (amount of the debt), R is the annual payment, r is the interest rate per period, and n is the number of periods.

In this problem, P = 6450, r = 5% = 0.05, and n = 4.

We need to find R.

6450 = (R * (1 - (1 + 0.05)^(-4))) / 0.05

Now, let's solve for R.

6450 = (R * (1 - (1.05)^(-4))) / 0.05

6450 = (R * (1 - 0.822702)) / 0.05

6450 = (R * 0.177298) / 0.05

Now, multiply both sides by 0.05.

6450 * 0.05 = R * 0.177298

Now, divide both sides by 0.177298.

(6450 * 0.05) / 0.177298 = R

R ≈ 1816.61

Since we need to find the closest integer value for the annual payment, we can round it to Rs. 1800.

So, the correct answer is Rs. 1800

B is the correct option. Solution
6 months interest will be 5%
next 6 months interest will be 5%
percentage effect = 5 + 5 +25/100
= 10.25 Ans
 

The correct answer is D  as
let assume 3 parts of amount are x,y,z
x+y+z=2379
SI for x= x*5*2/100⇒ x/10
Total amount after 2 years - x+(x/10)= 11x/10 ------------(1)
SI for y= y*5*3/100=> 15y/100
Total amount after 3 years - y+(15y/100) = 115y/100 -------(2)
SI for z= z*5*4/100=> z/5
Total amount after 4 years - z+(z/5) = 6z/5 ---------------(3)

As per the conditions "3 parts amounts after 2, 3 and 4 years respectively may be equal" (1) = (2) = (3)
based on the above condition and x+y+z=2379, we can get x= 828, y= 792 and z= 759
So answer is Rs.828

Let's try to understand the problem step by step.

A sum of Rs. 9 is lent to be paid back in 10 equal monthly installments of Re. 1 each.

This means that the borrower is paying back Re. 1 per month for 10 months.

Now, let's calculate the interest paid in each installment.

1. In the first month, the borrower still owes Rs. 9, so no interest is paid.
2. In the second month, the borrower has already paid Re. 1, so he now owes Rs. 8. The interest paid would be on Rs. 8.
3. In the third month, the borrower has paid Rs. 2, so he now owes Rs. 7. The interest paid would be on Rs. 7.
4. This continues until the 10th month when the borrower has paid Rs. 9 and owes nothing.

Now let's calculate the total interest paid over the 10 months.

Total Interest Paid = (Interest on Rs. 8) + (Interest on Rs. 7) + ... + (Interest on Re. 1)

Let's assume the rate of interest is "R" percent per month.

Total Interest Paid = (8 * R) + (7 * R) + ... + (1 * R)

Now, we know that the total amount paid is Rs. 10 (10 installments of Re. 1 each), and the total amount lent is Rs. 9. So, the total interest paid is Rs. 1.

1 = (8 * R) + (7 * R) + ... + (1 * R)

Now we can simplify the equation:

1 = R * (8 + 7 + 6 + 5 + 4 + 3 + 2 + 1)

1 = R * 36

Now, let's find the value of R (the rate of interest per month):

R = 1/36

Since we need to calculate the rate of interest in percentage, we multiply R by 100:

R (%) = (1/36) * 100 = 2.78%

Now, we have the monthly rate of interest. To find the annual rate of interest, we multiply the monthly rate by 12:

Annual Rate of Interest = 2.78% * 12 = 33.33%

A is the correct option.
Simple interest on the total money lent at 
8% FOR 4 YEARS = 1400
Total money lent
= 100/8 × 1400/4 =4375
Therefore, money lent to C
= 4375- 1400 = 2875

Amount = 22400, P = 14000, T = 12yrs
SI = 22400 - 14000
= 8400
Rate = (8400*100)/(12*14000)
= 5%