Examples: Volume Video Lecture - CTET & State TET

hello friends this video on mensuration
part 15 is brought to you by example
comm Nomos your prom exam with an
cylinder
let us try out a few questions question
number one find the item per cuboid
whose day area is 180 centimeter square
and volume is 900 centimeter - so what
is the day failure this is the base aja
of a cuboid and this base area is given
as 180 centimeter square and the entire
volume is also given now the green media
and it gets added as many times as the
eyes then we get the volume so basically
need volume of a cuboid is equal to
length into breadth into height and
length into breadth is nothing but the
base area so the page area multiplied to
height gives the volume so therefore
height is equal to volume divided by
base area so this can be written as
volume is 900 centimeter cube by base
area which is 180 centimeters cubed so
this would be 5 so that is 5 centimeters
would be the height of the cuboid
question number 2 a minute sand is in
the form of cylinders whose radius is
1.5 meters and length is 7 meters so you
have a little stamp in this shape where
the radius is 1.5 meters and the length
is 7 needles so the length is seventy
the length or the height whatever you
call it find the quantity of milk in
details that can be stored in the tank
so how much milk can it hold so it's
basically talking about this capacity to
hold milk so let's find out the volume
of the cylinder which is given by PI R
square H so 5 is 22 by 7 R is given as 1
point 5 so 1 point 5 into 1 point 5 into
H is 7/7/11 will get cancelled so this
is equal to 49 point 5 meter cube
because here all are in meters so the
volume is in meter view now we have to
find out the quantity of
in details now is there any relationship
between leader Antony - - yes there is
now we know that one centimeter cube is
equal to 1 B region so this is the
standard relation that we know now 1
centimeter cube is actually equal to 10
to the power minus 6 meter - right
because 1 meter is equal to 100
centimeters therefore 1 meter cube is
equal to 10 to the power 6 centimeter
cube therefore 1 centimeter cube is
equal to 10 to the power minus 6 meter
cube so 10 to the power minus 6 meter
cube will be equal to 10 to the power
minus 6 religious now we have to
establish a relationship between medium
and detail now 1 millimeter is equal to
10 to the power minus 3 meters
so therefore 10 to the power minus 6
millimeters is equal to 10 to the power
minus 3 meters right so therefore 1
meter cube will be equal to 10 to the
power minus 3 by 10 to the power minus 6
meters which is equal to 10 to the power
3 DS if so we can take 1 meter cube is
equal to thousand liters so knowing this
relation we can convert this into region
so this would be equal to 49 point 5
into 1000 which is equal to 4 9 5 0 0
liters so this much milk get the stamp
stamped or question number 3 if each
edge of a few is double how many times
with its surface area increase okay now
let us support now initially next
suppose so case 1 let's say that each
side of the cube is a this is the
segment so in this case what is the
total surface area of the tube so in
this case the total surface area is 6 a
square now later in case to the edge is
so right now the edge is 2a so in this
case what would be the total surface
area total surface area would be 6 into
2 a whole square so this is equal to 6
into 4 a square which is equal to 24 a
square now if you compare 24 a square
this fixed a square how many times
because become so to find out how many
times it has become just divide 24 a
square by 3 a square so this is 4 so
that means the total surface area has
become 4 times so this is the solution
for first part of the question
second father how many times will is
volume in T let's see that maintains 1
then each side of the cube is a that
kind the volume is equal to a 2 now in
case 2 then each side is doubled that is
2 H to sign the volume would be equal to
2 a whole cube which is equal to 8 a
cube so now if you compare 8 a cube with
hu what do you see you see that the
volume has become a time so when H is
double if the central area becomes 4
times and the volume becomes a 10
question number 4 water is pouring into
a cuboidal little boil at a rate of 60
liters per minute if the volume of the
reservoir is 108 meter cube find the
number of hours it will take to fill the
reservoir now first of all let's
calculate how many details of water is
present in the reserved oil that is the
volume of parasitoid so in this case the
volume of the reservoir is given as 100
8 meter cube and we know that 1 meter
cube is equal to thousand liters we have
deduced it some time back so therefore
this hundred eight into 1,000 liters so
this is 1 0 8 0 0 0
so this much is the volume of the
reservoir now what is the date of water
beanpole that is 60 liters in one minute
that means for 60 liters of water to be
poured how much time it takes it takes 1
minute 1 minute is 1 by 60 hours so in 1
by 60 hours 60 liters of water is poured
so how much time the entire water of the
reservoir in case so entire water is
actually 1 0 8 0 0 0 liters now let's
use the unit ring later
so for 60 liters 1 by 60 hours soup on
one liter how much time it will take it
will take 1 by 60 divided by 60 so
therefore for one zero eight zero zero
zero meters it will take 1 960 divided
by 60 which is 1 minus P 1 by 16 to 16
into one zero eight zero zero zero say
it will take these many hours so let's
calculate this does this becomes 6 1 is
6 6 8 so 48 0 again 6
Fiza 18 0 so that is it would take some
30 hours to fill the reservoir so I hope
you understood the concept the volume of
the reservoir is these mini leaders and
this is the total amount of water that
can be presented in the oil so for 60
liters of water it takes 1 by 60 hours
therefore 40 milliliters of water it
would be be many hours that is 50 hours
so if this we have reached towards the
end of this lesson and I hope that this
lesson would have helped you so next
creation is on about knowing about the
different shapes either 2 dimensional or
three dimensional and dealing with all
the measurements related to Boucher's so
this lesson is really interesting and
you can actually get a huge variety of
problems for verses to solve solve the
questions and gain more confidence on
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