All Courses
Get the App Signup / Login
Sign in Open App

Sravya Mehta

EduRev Chemistry

Sravya Mehta
EduRev Chemistry
  • Followers 39 |
  • Following 101
39
Followers 		101
Following
Join EduRev Infinity
Premium plans starting at /month
View Plans
View Plans
Content, tests & courses saved by you for accessing later. (visible to you only)

Currently preparing for

Rated 5 by Sravya
Tangent Lines and Rates of Change- 1
Video | 19:41 min
Operations on Sets
Video | 09:25 min
Differential Equation First Order and Degree
Video | 22:33 min
Venn Diagrams
Video | 05:51 min
Sequence: Definition & Examples
Video | 09:39 min
Introduction to Relations
Video | 07:39 min
Indefinite Integral
Video | 29:00 min
Properties Of Cyclic Group
Video | 24:24 min
Multiplication of Matrices- 2
Video | 05:19 min
Properties of Scalar Multiplication
Video | 12:52 min
Basics of Complex Numbers
Video | 03:36 min
Polar Form of Complex Number
Video | 25:50 min
Multiplication of Matrices Property- 3
Video | 08:54 min
Transpose Property- 4
Video | 11:02 min
Matrices - Scalar Multiplication
Video | 03:34 min
Modulus and Conjugate of a Complex Number
Video | 02:04 min
Argand Plane
Video | 07:28 min
Problems for Practice - Complex Numbers
Video | 12:55 min
Remainder Theorem
Video | 25:14 min
Degree of Polynomial
Video | 04:05 min
Multiplication of Matrices Property- 2
Video | 11:39 min
Power Series And Functions
Video | 08:30 min
Maclaurin Theorem- 1
Video | 18:55 min
Transpose Property- 3
Video | 04:15 min
Introduction to Series
Video | 16:18 min
Ideals of Ring- Theorems
Video | 18:46 min
Concept of Subgroup
Video | 30:22 min
Value of Polynomial and Division Algorithm
Video | 11:00 min
Exact Differential Equations
Video | 31:36 min
Introduction - Continuity
Video | 13:31 min
Infinite Limits
Video | 09:12 min
Examples of Limit- 3
Video | 09:58 min
Power Series
Video | 06:48 min
Taylor Theorem- 1
Video | 17:56 min
Binomial Series
Video | 45:13 min
Introduction to Functions
Video | 11:34 min
Introduction to Limits- 1
Video | 11:32 min
Examples of Limit- 1
Video | 08:58 min
Limits to Define Continuity
Video | 11:14 min
Examples of Limit- 2
Video | 06:58 min
Permutation Group
Video | 34:00 min
Concept of Homomorphism
Video | 25:48 min
Transpose Property- 1
Video | 04:42 min
Multiplication of Matrices Property- 1
Video | 04:31 min
Convergence/Divergence Of Series
Video | 28:17 min
Reduction of Order
Video | 18:39 min
Substitutions, First Order Differential Equations- 2
Video | 11:23 min
Bernoulli Differential Equations
Video | 20:03 min
Limits At Infinity
Video | 13:14 min
Cayley’s Theorem
Video | 23:30 min
Discussed Questions
Sravya Mehta upvoted   •  3 weeks ago

Which of the following compounds cannot give E1CB reaction?
  • a)
    CF3 – CHCl2
  • b)
    C6h5 – CH2 – CH2F
  • c)
    CH3 – CH2 – CH2Br
  • d)
Correct answer is option 'D'. Can you explain this answer?

Asf Institute answered

Compound d will give E2 reaction, Br is a better leaving group so formation of carboanion and removal of leaving group occurs simultaneously. But E1CB reaction is shown by poor leaving group like in compounds a, b and c.

Sravya Mehta upvoted   •  Feb 12, 2025

Choose the correct answer from the following four choices.
Statement: Pyridine is more basic than pyrrole.
Reason: The nitrogen in pyrrole carries a proton while the nitrogen in pyridine does not.
Assertion: Nitrogen in trigonal geometry are generally more basic than nitrogens in a tetrahedral geometry. 
a)Both Reason and Assertion are correct.
b)Both Reason and Assertion are wrong.
c)Reason is correct and Assertion is wrong.
d)Reason is wrong and Assertion is correct.
The correct answer is option 'B'. Can you explain this answer?

Asf Institute answered
  • Pyridine is more basic than pyrrole because lone pair of electrons on N in pyridine and pyrrole are different in nature. These form a part of aromatic sextet in pyrrole, while not in pyridine.
  • Pyrrole, C4H4NH (in which N contributes a lone pair) has a pKa−3.8 but pyridine (where N is part of the ring's double bond)... more
  • In pyrrole, the lone pair electrons of the nitrogen atom gets involved with the 2 carbon-carbon double bonds in the 5-member ring to form a conjugated system of pi electrons, leading to greater stability of the molecule.
  • Pyridine, on the other hand, already has a stable conjugated system of 3 double bonds in the aromatic hexagonal ring, like benzene. Hence, the lone pair electrons on the N atom in pyridine can be easily donated to a H+ ion or a Lewis acid.

Sravya Mehta upvoted   •  Feb 07, 2025

The structure of hyponitrous acid molecule (H2N2O2) is:
  • a)
    Linear (A –B–C–D type) 
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?

Dronacharya Institute answered
Correct Answer :- C
Explanation : Trans and cis are the two possible structures of hyponitrous acid. White crystals are obtained from trans-hyponitrous which are explosive when dry and it is a weak acid which decomposes to nitrous oxide when in aqueous solution. Sodium salt can be obtained from cis acid.

Sravya Mehta upvoted   •  Feb 01, 2025

Hybridizat ion of Ni(II) in K2[NiBr4] is:
  • a)
    dsp2
  • b)
    sp3
  • c)
    sp2d
  • d)
    d3s
Correct answer is option 'B'. Can you explain this answer?

Asf Institute answered
- In K2[NiBr4], the nickel ion is surrounded by four bromide ions.
- The electronic configuration of Ni(II) is 3d8 4s2.
- To form the complex, the nickel ion utilizes one 4s and three 4p orbitals to hybridize into four sp3 hybrid orbitals.
- The hybrid orbitals are then used to form sigma bonds with the four bromide ions.
- Therefore, the hybridization of Ni(II) in K2[NiBr4] is sp3.

Sravya Mehta upvoted   •  Jan 29, 2025

The correct order of stability for the given canonical structures is:
  • a)
    I > III > II
  • b)
    III > I > II
  • c)
    II > III > I
  • d)
    II > I > III
Correct answer is option 'B'. Can you explain this answer?

Veda Institute answered
There are a certain set of rules that must be followed in order to check the stability of resonating structures.
These rules have a preference so we have to follow the order:
  • Uncharged species is more stable than charged species.
  • Charged species having more number of covalent bond are more stable.
  • The species in which the octet rule is followed by every atom is more stable than the species in which the octet rule is violated.
  • Species in which opposite charges are closer are more stable than species having same charges closer.
  • Species with negative charge on more electronegative atom while positive charge on more electropositive atom is more stable.
According to above discussion, B is the correct answer.

BF3 is hydrolyzed by H2O, then how many type of acids are expected as products:
    Correct answer is '3'. Can you explain this answer?

    Sravya Mehta answered  •  Jan 25, 2025
    Understanding BF3 Hydrolysis
    When boron trifluoride (BF3) undergoes hydrolysis, it reacts with water (H2O) resulting in the formation of various products. This process involves the interaction of BF3 with water molecules, leading to the generation of acids.
    Types of Acids Produced
    The hydrolysis of BF3 can typically yield three different types of acids:
    • ... more
    • 2. Hydrofluoric Acid (HF): During the hydrolysis, hydrofluoric acid is also produced as a byproduct. This acid is known for its strong reactivity and can cause severe burns. The reaction yields HF alongside boric acid:
      • BF3 + 3 H2O → H3BO3 + 3 HF

    • 3. Bifluoride Ion (HF2-): Under certain conditions, additional hydrolysis can lead to the formation of the bifluoride ion. This ion can be considered as a weak acid, contributing to the overall acidity of the solution:
      • HF + F- → HF2-


    Conclusion
    In summary, the hydrolysis of BF3 produces three types of acids: boric acid, hydrofluoric acid, and the bifluoride ion. Each of these contributes to the overall acidity of the solution formed during the hydrolysis process. Thus, the answer to how many types of acids are expected as products is indeed '3'.

    Radioactive decay is not affected by           
    • a)
      Pressure                           
    • b)
      Temp                         
    • c)
      Gravity                   
    • d)
      Composition
    Correct answer is option 'A,B,C,D'. Can you explain this answer?

    Sravya Mehta answered  •  Dec 11, 2024
    Understanding Radioactive Decay
    Radioactive decay is a fundamental process whereby unstable atomic nuclei lose energy by emitting radiation. This process is intrinsic to the nature of the atoms and is governed by the laws of quantum mechanics.
    Factors Unaffected by Radioactive Decay
    The correct answer indicates that radioactive decay is not influenced by the following    ... more

    The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.?

    Sravya Mehta answered  •  Oct 22, 2024
    Analyzing the Reaction Order
    To determine the order of the reaction, we can use the concentration data provided at various time intervals. The concentrations of the reactant are:
    - At 1.0 hr: 0.1 mol/L
    - At 2.0 hr: 0.08 mol/L
    - At 3.0 hr: 0.067 mol/L
    Calculating the Change in Concentration
    - From 1.0 hr to 2.0 hr:
    - Change = 0.1 - 0.08 = 0.02 mol/    ... more

    Gibberellins promote
    • a)
      Seed dormancy
    • b)
      Seed germination
    • c)
      Root elongation
    • d)
      Fruit ripening
    Correct answer is option 'B'. Can you explain this answer?

    Sravya Mehta answered  •  Aug 22, 2024
    Gibberellins promote seed germination:
    Gibberellins are plant hormones that play a crucial role in promoting seed germination. They help to break seed dormancy and initiate the growth process of the seed. Here's how gibberellins promote seed germination:

    1. Breaking seed dormancy:
    - Gibberellins stimulate the production of enzymes that break down the inhibitors o    ... more

    CO forms metal complex but isoelectronic N2 cannot do so?

    Sravya Mehta answered  •  Jul 16, 2024



    Complex Formation of CO vs N2

    Electronic Configuration
    - CO has a lone pair of electrons on the carbon atom which can be donated to form a coordinate bond with a metal ion.
    - N2, on the other hand, is a homonuclear diatomic molecule with a triple bond between the nitrogen atoms, making it difficult to donate electrons to form a metal    ... more

    Discuss the role of magnesium in phosphorylation (bioprocess) reaction?

    Sravya Mehta answered  •  Jun 19, 2024
    Role of Magnesium in Phosphorylation Reaction
    Phosphorylation is a key bioprocess that involves the addition of a phosphate group to a molecule, typically a protein, by enzymes known as kinases. This process plays a crucial role in various cellular functions such as signal transduction, energy metabolism, and gene expression.

    Magnesium as a Cofactor
    - Magnesium s    ... more

    The molar heat capacity at constant volume of a colourless gas is found to be 25 J mol–1 K–1 at room temperature. The gas must be:
     
    • a)
      N2
    • b)
      O2
    • c)
      CO2
    • d)
      SO2
    Correct answer is option 'D'. Can you explain this answer?

    Sravya Mehta answered  •  May 08, 2024
    Explanation:

    Molar Heat Capacity at Constant Volume (Cv)
    - The molar heat capacity at constant volume (Cv) is a measure of the amount of heat required to raise the temperature of one mole of a substance by 1 Kelvin while keeping the volume constant.

    Given Information
    - The molar heat capacity at constant volume of a colorless gas is 25 J mol&nda    ... more

    The element NaCl and Kr crystallizes in a cubic structure. While NaCl is a solid at room temperature, Kr is a gas? The reason for this is:
    • a)
      NaCl has covalent bonding and Kr has metallic bonding.
    • b)
      NaCl has ionic bonding and Kr has covalent bonding.
    • c)
      NaCl has ionic bonding and Kr has Vander Waals interactions.
    • d)
      NaCl has ionic bonding and Kr has hydrogen bonding.
    Correct answer is option 'C'. Can you explain this answer?

    Sravya Mehta answered  •  Sep 16, 2023
    Explanation:

    1. Ionic Bonding in NaCl:
    NaCl (sodium chloride) is an ionic compound where sodium (Na) atom loses an electron to form a cation (Na+) and chlorine (Cl) atom gains an electron to form an anion (Cl-). The opposite charges of Na+ and Cl- attract each other, resulting in the formation of an ionic bond. The strong electrostatic attraction between the cations a    ... more

    Sn2+ + 2e– → Sn,    E0 = – 0.14 V
    Sn4+ + 2e- → Sn2+, E0 = + 0.13 V
    Which of the following is true?
    • a)
      Sn2+ is unstable and disproportionates to Sn4+ and Sn
    • b)
      Sn2+ is stable and disproportionat ion reaction is not spontaneous
    • c)
      Sn4+ is easily reduced to Sn
    • d)
      None of these
    Correct answer is option 'B'. Can you explain this answer?

    Sravya Mehta answered  •  Sep 16, 2023
    The term "SN2" refers to a type of nucleophilic substitution reaction that involves a simultaneous attack by a nucleophile and the departure of a leaving group.

    The "S" stands for substitution, indicating that a new group is replacing the leaving group. The "N" stands for nucleophilic, indicating that the nucleophile (electron-rich species) is involved in the reaction. The "2" represen    ... more

    Suppose x, y, z are positive real number such that x + 2y + 3z = 1. If M is the maximum value of xyz2, then the value of 1/M is _______ .
      Correct answer is '1152'. Can you explain this answer?

      Sravya Mehta answered  •  Sep 16, 2023
      To find the value of 1/M, we need to first find the maximum value of the function xyz^2, given the constraint x + 2y + 3z = 1.

      Constraint:
      Given: x + 2y + 3z = 1

      Objective:
      To find the maximum value of xyz^2.

      Method:
      To solve this problem, we can use the method of Lagrange multipliers. This method allows us to find the maximum or      ... more
      Sravya Mehta asked   •  Aug 17, 2023

      Can I get the details of the seat allocation process for candidates applying through the sponsored category in IITs through IIT JAM Chemistry?

      Shivani Mehta answered
      Seat Allocation Process for Candidates Applying through Sponsored Category in IITs through IIT JAM Chemistry

      Introduction
      The seat allocation process for candidates applying through the sponsored category in IITs through IIT JAM Chemistry involves several steps. Sponsored candidates are those who are employed in a government organization, research and development (R&D      ... more

      Sravya Mehta asked   •  Aug 17, 2023

      Can I download the admit card for IIT JAM Chemistry if my application is still under review?

      Shivani Mehta answered
      Can I download the admit card for IIT JAM Chemistry if my application is still under review?

      To answer your question, let's break down the process of downloading the admit card for IIT JAM Chemistry and understand whether it is possible to do so while your application is under review.

      Application Review Process

      Before discussing the admit card downloa      ... more

      Sravya Mehta asked   •  Aug 14, 2023

      Can I access the IIT JAM Chemistry exam result even if I have lost my admit card or application number?

      Sinjini Singh answered
      Yes, you can access the IIT JAM Chemistry exam result even if you have lost your admit card or application number.

      Step 1: Contact the IIT JAM Conducting Authority

      If you have lost your admit card or application number, the first step is to contact the conducting authority of IIT JAM. You can find their contact details on the official website of IIT JAM.

      ... more

      Sravya Mehta asked a question

      Can you suggest books that offer interactive study tools like flashcards or quizzes to enhance learning for IIT JAM Chemistry?

      Answer this Question
      Sravya Mehta asked a question

      Can I find any study guides or summaries that cover the entire IIT JAM Chemistry syllabus?

      Answer this Question
      Sravya Mehta asked   •  Aug 02, 2023

      What is the total number of questions in the IIT JAM Chemistry paper?

      Soumya Sharma answered
      Total Number of Questions in IIT JAM Chemistry Paper

      The IIT JAM (Joint Admission Test for M.Sc.) is a national-level entrance exam conducted by the Indian Institutes of Technology (IITs) for admission into various postgraduate programs in science. The Chemistry paper of IIT JAM consists of a total of 60 questions, which are divided into three sections: Section A, Section B, and       ... more

      Sravya Mehta asked   •  Aug 02, 2023

      What are the minimum qualifying marks for the IIT JAM Chemistry exam?

      Soumya Sharma answered
      IIT JAM Chemistry Exam: Minimum Qualifying Marks

      The IIT JAM (Joint Admission Test for M.Sc.) is a national-level entrance exam conducted by the Indian Institute of Technology (IIT) for admission to various postgraduate programs in science and technology. The minimum qualifying marks for the IIT JAM Chemistry exam vary each year, depending on factors such as the difficulty level       ... more

      Sravya Mehta asked   •  Dec 07, 2022

      The angle between two bonds in a linear molecule is _______
      • a)
        108°
      • b)
        180°
      • c)
        74.5°
      • d)
        90°
      Correct answer is option 'B'. Can you explain this answer?

      Hema answered
      A linear molecule will have bond angle 180. example : H--Cl

      Sravya Mehta asked   •  Dec 03, 2022

      Those groups which are electron repelling and have lesser electron attracting power than hydrogen show __________
      • a)
        (+E) effect
      • b)
        (-E) effect
      • c)
        (-I) effect
      • d)
        (+I) effect
      Correct answer is option 'D'. Can you explain this answer?

      Anushka Chavan answered
      The correct answer is option 'D' - (I) effect.

      The (I) effect, also known as the inductive effect, refers to the electron-withdrawing or electron-donating ability of a substituent group in a molecule. It occurs due to the polar nature of sigma bonds, where electrons are not equally shared between two atoms. Substituent groups can either withdraw or donate electrons through sigma bonds,       ... more

      Sravya Mehta asked   •  Nov 30, 2022

      The overall order of reaction for –rA = kCA0.7CB1.3 is _______
      • a)
        0
      • b)
        1
      • c)
        2
      • d)
        3
      Correct answer is option 'C'. Can you explain this answer?

      Arnab Pillai answered
      A chemical reaction is determined by the sum of the exponents in the rate equation. The rate equation is an expression that relates the rate of the reaction to the concentrations of the reactants.

      For example, a generic rate equation may be written as:

      Rate = k[A]^m[B]^n

      Where:
      - Rate is the rate of the reaction
      - k is the rate constant
      - [A] and [B      ... more

      Fetching relevant content for you
      © EduRev
      Education Revolution
      Signup to see your scores go up
      within 7 days!
      Takes less than 10 seconds to signup