Jaya Sen

EduRev Chemistry

Jaya Sen
EduRev Chemistry
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Discussed Questions
Isha Bose upvoted   •  Feb 16, 2025

The compound that undergoes decarboxylation most readily under mild condition is:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?

Urban Dots answered
Beta keto acids readily undergo thermal decarboxylation. The compound that undergoes decarboxylation most readily under mild condition is 2-oxocyclohexanecarboxylic acid (option B) as it is a beta keto acid. The product obtained is cyclohexanone.
 

Isha Bose upvoted   •  Feb 10, 2025

In the trigonal bipyramidal crystal field, the d orbital with the highest energy is:
  • a)
    dxy
  • b)
  • c)
    dyx
  • d)
Correct answer is option 'D'. Can you explain this answer?

Edurev.iitjam answered

  • The trigonal bipyramidal crystal field splits the d orbitals into different energy levels.

  • The dz2 orbital has the highest energy because it points along the z-axis, which aligns with the axial positions of the trigonal bipyramidal geometry.

  • These axial positions experience more repulsion, increasing the energy of the dz... more orbital.

  • Other orbitals, like dxy and dyx, experience less direct interaction with ligands, leading to lower energy levels.

Isha Bose upvoted   •  Jan 30, 2025

 The relative nucleophilicity in polar, protic, solvents of the following is:
 
  • a)
    I > II > III 
  • b)
    II > III > I 
  • c)
     I > III > II 
  • d)
     III > I > II
     
Correct answer is option 'A'. Can you explain this answer?

Veda Institute answered
Correct Answer :- a
Explanation : In a polar protic solvent (CH3OH), nucleophilicity increases down a column of the periodic table. So S- is more nucleophilic than O-.
For two species with the same attacking atom, the more basic is the more nucleophilic, so CH3CH2O- is more nucleophilic than CH3CO2-
CO2- give identical str resonance hybrids more solvated, very less nucleophilic.

 Hyperconjugation is best described as:
 
  • a)
    Delocalisation of p electrons into a nearby empty orbital
     
  • b)
    Delocalisation of  electrons into a nearby empty orbital
     
  • c)
    The effect of the alkyl groups donating a small amount of electron density inductively into a carbocation.
     
  • d)
     The migration of a carbon or hydrogen from one carbocation to another.
     
Correct answer is option 'B'. Can you explain this answer?

Isha Bose answered  •  Dec 26, 2024
Understanding Hyperconjugation
Hyperconjugation refers to a stabilizing interaction that occurs in organic molecules, primarily involving the overlap of sigma (σ) bonds with adjacent empty or partially filled p orbitals. This phenomenon plays a crucial role in the stability of carbocations, alkenes, and radicals.
Key Features of Hyperconjugation:
- Delocalization of
... more Hyperconjugation primarily involves the delocalization of σ (sigma) electrons from C-H or C-C bonds into a nearby empty p orbital or a π (pi) bond. This delocalization can help stabilize charged or radical intermediates.
- Stabilization of Carbocations: In carbocations, the presence of alkyl groups can donate electron density through hyperconjugation. This reduces the positive charge's intensity, leading to increased stability of the carbocation.
- Not Just Inductive Effect: While inductive effects involve the donation of electron density through sigma bonds, hyperconjugation specifically refers to the overlap of σ-bonds with empty orbitals, thus contributing to overall molecular stability.
Conclusion:
Option B correctly describes hyperconjugation as the delocalization of σ electrons into a nearby empty orbital. This concept is integral to understanding how molecular structure influences stability and reactivity in organic chemistry.

Which one of the following ecosystems would have the maximum number of primary producers per unit area?
  • a)
    Forest
  • b)
    Pond
  • c)
    Desert
  • d)
    Grassland 
Correct answer is option 'B'. Can you explain this answer?

Isha Bose answered  •  Dec 26, 2024
Understanding Primary Producers
Primary producers are organisms that can produce their own food through photosynthesis or chemosynthesis. These include plants, algae, and some bacteria. The density and variety of primary producers can vary significantly across different ecosystems.
Why Ponds Have Maximum Primary Producers
Ponds are unique ecosystems that support a high
... more

A culture of mycobacterium leprae was subjected to alkaline ethanol extraction prior to acid fast staining. The colour of culture of following staining will be ______
  • a)
    Orange
  • b)
    Blue
  • c)
    Light Green
  • d)
    Red
Correct answer is option 'D'. Can you explain this answer?

Isha Bose answered  •  Nov 03, 2024
Understanding Acid-Fast Staining
Acid-fast staining is a crucial technique used to identify mycobacteria, such as Mycobacterium leprae, the causative agent of leprosy. This method exploits the unique cell wall structure of mycobacteria, which contains high amounts of mycolic acid.
Alkaline Ethanol Extraction
- Purpose: Alkaline ethanol extraction is performed to
... more

All of the following molecules would exhibit two distinct singlets in a 1H-NMR spectrum except __________.
  • a)
    2,4-hexadiyne
  • b)
    1,4-dimethylbenzene
  • c)
    methyl-tert-butyl ether
  • d)
    1,2,4,5-tetramethylbenzene
Correct answer is option 'A'. Can you explain this answer?

Isha Bose answered  •  Sep 02, 2024
Understanding 1H-NMR Spectra
1H-NMR (Proton Nuclear Magnetic Resonance) spectroscopy is a powerful technique used to analyze the hydrogen environment in organic molecules. The number of distinct signals (singlets, doublets, etc.) in a spectrum indicates the number of different hydrogen environments.

Analyzing the Molecules
- **2,4-hexadiyne**:
- Structure:
... more

The frequency for pure rotational spectrum in cm-1 for pure rotational in the spectrum of NO molecule due to change in the quantum no from J=1 to J= 2?

Isha Bose answered  •  Jun 23, 2024
Calculation of Frequency for Pure Rotational Spectrum of NO Molecule
The frequency for the pure rotational spectrum of a molecule can be calculated using the formula:
\[ \Delta E = B \times (J+1) - B \times J \]
where:
- \( \Delta E \) is the energy difference between two adjacent rotational levels
- B is the rotational constant of the molecule
- J is the quant
... more

Calculation of Repulsive exponent (compressibility and Bulk modulus)?

Isha Bose answered  •  Jun 23, 2024
Calculation of Repulsive Exponent for Compressibility and Bulk Modulus
Calculating the repulsive exponent is essential in understanding the compressibility and bulk modulus of a material. This exponent is a crucial parameter in the repulsive part of the Lennard-Jones potential, which describes the interaction between particles.

Compressibility
- The repulsive exp
... more

If N/2atoms of X are converted into X + absolving E1, N/2 atoms of X are converted to X-, E2 energy is released then 1.) Ionization potential of X would be2E1/N 2.) Ionization of potential X would be2E1 3.) Electron affinity ... more

Isha Bose answered  •  May 21, 2024
Ionization potential of X
- When N/2 atoms of X are converted into X + absorbing E1, it means that E1 energy is required to remove an electron from X to form X+.
- So, the ionization potential of X would be 2E1/N, as N/2 atoms are involved in this process.

Ionization potential of X
- When N/2 atoms of X are converted into X-, it means that E2 energy is rele
... more

F the work done by a human heart is 0.5 J per beat, with the time period “T” of 0.8 seconds for a beat, the approximate energy (in kcal) required by a human heat to beat in a day is?

Isha Bose answered  •  Feb 10, 2024
Calculation of Work Done

To calculate the energy required by a human heart to beat in a day, we need to first calculate the work done by the heart in one beat. Given that the work done per beat is 0.5 J and the time period for one beat is T = 0.8 seconds, we can use the formula:

Work (W) = Force (F) × Distance (d)

Since the force exerted by the heart
... more

There are 8 identical bags of wheat except 1 bag all others have same weight but one bag is heavier what is the minimum number of weights requited to identify the bag with different weight by conventional balance.
  • a)
    2
  • b)
    3
  • c)
    4
  • d)
    5
Correct answer is option 'B'. Can you explain this answer?

Isha Bose answered  •  Feb 01, 2024
Problem:
There are 8 identical bags of wheat, except one bag, which has a different weight. All the bags look identical, but one bag is heavier than the rest. The task is to determine the bag with the different weight using a conventional balance. What is the minimum number of weights required to identify the bag with the different weight?

Solution:

To solv
... more
Isha Bose asked   •  Aug 17, 2023

Can I get the details of the seat allocation process for differently-abled candidates in IITs through IIT JAM Chemistry?

Shivani Mehta answered
Seat Allocation Process for Differently-Abled Candidates in IITs through IIT JAM Chemistry

Introduction
The Indian Institutes of Technology (IITs) are premier engineering institutions in India that offer admission to various programs through the Joint Admission Test for M.Sc. (JAM). The seat allocation process for differently-abled candidates in IITs through IIT JAM C
... more

Isha Bose asked   •  Aug 17, 2023

Can I get the details of the exam session and date mentioned on the IIT JAM Chemistry admit card?

Shivani Mehta answered
Exam Session and Date on IIT JAM Chemistry Admit Card

The IIT JAM (Joint Admission Test for M.Sc.) is a national-level entrance exam conducted by the Indian Institutes of Technology (IITs) for admission to various postgraduate programs in science. The admit card for the IIT JAM Chemistry exam contains important information regarding the exam session and date. Let's delve into the
... more

Isha Bose asked   •  Aug 14, 2023

Is there any provision to apply for improvement or supplementary exams after checking the IIT JAM Chemistry exam result?

Sinjini Singh answered
Applying for Improvement or Supplementary Exams after Checking IIT JAM Chemistry Exam Result

Introduction

The IIT JAM (Joint Admission Test for M.Sc.) is a national-level entrance exam conducted by the Indian Institutes of Technology (IITs) for admission to various postgraduate programs in science disciplines. The exam is held once a year, and the results are declared within a few weeks after the exam.
... more

Isha Bose asked   •  Aug 02, 2023

Can I qualify for IIT JAM Chemistry if I have taken a break after my 12th grade?

Soumya Sharma answered
Can I qualify for IIT JAM Chemistry if I have taken a break after my 12th grade?

Yes, you can still qualify for IIT JAM Chemistry even if you have taken a break after completing your 12th grade. Here is a detailed explanation of the process and requirements for qualifying for IIT JAM Chemistry after a break:

Eligibility Criteria:

To be eligible for II
... more

Isha Bose asked   •  Mar 07, 2023

The natural semiconductor LH0063C has a slew rate of
  • a)
    1400V/µs
  • b)
    6000V/µs
  • c)
    500V/µs
  • d)
    None of the mentioned
Correct answer is option 'B'. Can you explain this answer?

Chirag Verma answered
National semiconductor LH0063C has a slew rate of 6000V/µs. Generally, the practical op-amp is available with slew rate from 0.1V/µs to well above 1000V/µs.

Isha Bose asked   •  Dec 06, 2022

A coordination complex [MX2L2], has a CN=4 and two unidentate ligands X and L. When the two L ligands are arranged opposite to each other in its geometry, it is called _______ isomer.
  • a)
    trans 
  • b)
    cis
  • c)
    fac
  • d)
    mer
Correct answer is option 'A'. Can you explain this answer?

Partho Gupta answered
Coordination Complex [MX2L2]A coordination complex is a compound in which a central metal ion is surrounded by ligands. In this particular complex, the metal ion is represented by M, and it is surrounded by two X ligands and two L ligands.CN=4The coordination number (CN) of a complex refers to the number of ligands that are directly bonded to the central metal ion. In this case, the CN is 4, which... more

Isha Bose asked   •  Dec 03, 2022

Why in the IR spectrum of Benzoyl chloride, a weak band near 1750 cm-1 is formed?
  • a)
    Inductive effect
  • b)
    Fermi resonance between C = O band and first overtone
  • c)
    Conjugation effect
  • d)
    Hyperconjugation effect
Correct answer is option 'B'. Can you explain this answer?

Rohan Desai answered
The weak band near 1750 cm-1 in the IR spectrum of benzoyl chloride is formed due to Fermi resonance between the C=O band and the first overtone.

Explanation:
IR Spectrum and Benzoyl Chloride:
- The infrared (IR) spectrum is a useful tool in identifying functional groups in organic compounds.
- It shows the absorption of infrared light by the compound as a
... more

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