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Preet
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Top Scoring Tests by Preet
Logic Gates MSQ | 16/20 |
Statistical Physics MSQ | 16/20 |
IIT JAM Mathematics Practice Test- 7 | 35/45 |
IIT JAM Mathematics Practice Test- 10 | 34/44 |
IIT JAM Mathematics Practice Test- 4 | 35/50 |
Crystals – MSQ | 14/20 |
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IIT JAM Mathematics Practice Test- 3 | 35/50 |
Discussed Questions
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Saikat Ghoshal upvoted • Feb 25, 2025 |
Does Le-Chatelier’s principle predict a change of equilibrium concentrations for the following reaction if the gas mixture is compressed:
- a)Yes, backward reaction is favoured
- b)Yes, forward reaction is favoured
- c)No change in equilibrium composition is predicted
- d)No information is obtained about concentration changes
Correct answer is option 'A'. Can you explain this answer?
Does Le-Chatelier’s principle predict a change of equilibrium concentrations for the following reaction if the gas mixture is compressed:
a)
Yes, backward reaction is favoured
b)
Yes, forward reaction is favoured
c)
No change in equilibrium composition is predicted
d)
No information is obtained about concentration changes
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Asf Institute answered |
N2O4(g)⇌2NO2(g)
One mole of N2O4 gives 2 moles of NO2 gas. The pressure of the gas increases. Upon compressing the gaseous mixture, there is a change in an equilibrium concentration & backward reaction is favoured. This is according to Le Chatlier's Principle
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Saikat Ghoshal upvoted • Feb 11, 2025 |
Identify N and M:
- a)6, 6
- b)6, 4
- c)4, 4
- d)3, 3
Correct answer is option 'B'. Can you explain this answer?
Identify N and M:
a)
6, 6
b)
6, 4
c)
4, 4
d)
3, 3
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Pie Academy answered |
The number of isomeric products N is 6 and the number of isomeric products M is 4. They are as shown.
M d, l cannot be separated by fractional distillation.
M d, l cannot be separated by fractional distillation.
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Saikat Ghoshal upvoted • Jan 31, 2025 |
The acidity for the following compounds increases in the order:CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH- a) I < II < III
- b) II < III < I
- c) III < II < I
- d) II < I < III
Correct answer is option 'C'. Can you explain this answer?
The acidity for the following compounds increases in the order:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH
a)
I < II < III
b)
II < III < I
c)
III < II < I
d)
II < I < III
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Edurev.iitjam answered |
a. EWG ( e−− withdrawing groups) increases the acidic strength, whereas EDG ( e−− donating groups) decrease the acidic strength.
b. Nearer is the EWG to the source [(−COOH)group], stronger is the acid, i.e., α− substituted halo acid stronger than β−orγ− substituted halo acid.
Increasing order of acidic strength:
(III)<(II)<(I).
Increasing order of acidic strength:
(III)<(II)<(I).
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Saikat Ghoshal upvoted • Jan 28, 2025 |
Upon application of a weak magnetic field, a line in the microwave absorption spectrum of rigid rotor splits into 3 lines. The quantum number (J) of the rotational energy level from which the transition originates is:
- a)1
- b)0
- c)2
- d)3
Correct answer is option 'A'. Can you explain this answer?
Upon application of a weak magnetic field, a line in the microwave absorption spectrum of rigid rotor splits into 3 lines. The quantum number (J) of the rotational energy level from which the transition originates is:
a)
1
b)
0
c)
2
d)
3
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Edurev.iitjam answered |
J=1
In an examination the percentage of students qualified io the number o f students appeared from school ‘A’ is 70%. In school ‘B’ the number of students appeared is 20% more than the students appeared from school ‘A’ and the number of students qualified from school ;B' is 50% more than the students qualified from school :A\ The percentage of students qualified as compared to the number of students appeared from school :B: i s ____________ %. (Round off to one decimal place)
Correct answer is between '87.0,88.0'. Can you explain this answer?
In an examination the percentage of students qualified io the number o f students appeared from school ‘A’ is 70%. In school ‘B’ the number of students appeared is 20% more than the students appeared from school ‘A’ and the number of students qualified from school ;B' is 50% more than the students qualified from school :A\ The percentage of students qualified as compared to the number of students appeared from school :B: i s ____________ %. (Round off to one decimal place)
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Saikat Ghoshal answered • Dec 31, 2024 |
Understanding the Problem
To solve the problem, we need to determine the percentage of students who qualified from school B compared to the number of students who appeared from school B.
Calculating Students from School A
- Let the number of students who appeared from school A be X.
- The percentage of students who qualified from school A is 70%.
- Therefore... more
To solve the problem, we need to determine the percentage of students who qualified from school B compared to the number of students who appeared from school B.
Calculating Students from School A
- Let the number of students who appeared from school A be X.
- The percentage of students who qualified from school A is 70%.
- Therefore... more
Bag contains 3 red balls and 7 black balls two balls are taken at random without replacement if first ball taken out is red then the probability that II taken out bol is also re d is A)1/10 B)1/15 C)3/10 D)2/21
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Saikat Ghoshal answered • Dec 31, 2024 |
Understanding the Problem
In a bag, we have a total of 10 balls:
- 3 Red Balls
- 7 Black Balls
We are taking 2 balls out without replacement. We want to find the probability that if the first ball drawn is red, the second ball drawn is also red.
Step 1: Determine the Total Balls After the First Draw
- After drawing one red ball, the remaining balls in t... more
In a bag, we have a total of 10 balls:
- 3 Red Balls
- 7 Black Balls
We are taking 2 balls out without replacement. We want to find the probability that if the first ball drawn is red, the second ball drawn is also red.
Step 1: Determine the Total Balls After the First Draw
- After drawing one red ball, the remaining balls in t... more
Chromatography question?
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Saikat Ghoshal answered • Nov 03, 2024 |
Understanding Chromatography
Chromatography is a powerful analytical technique used to separate and analyze components in a mixture. It is widely employed in various fields, including chemistry, biology, and environmental science.
Principle of Chromatography
- Chromatography relies on the differential distribution of compounds between a stationary phase and a mobile ph... more
Chromatography is a powerful analytical technique used to separate and analyze components in a mixture. It is widely employed in various fields, including chemistry, biology, and environmental science.
Principle of Chromatography
- Chromatography relies on the differential distribution of compounds between a stationary phase and a mobile ph... more
Which of the following statements in the context of 1H NMR spectroscopy is true?- a)Arene C-H chemical shift (δ) values are greater than simple alkenes C-H chemical shift values because of the aromatic ring current.
- b)Arene C-H chemical shift (δ) values are smaller than simple alkenes C-H chemical shift values because of the aromatic ring current.
- c)Arene C-H signals are always multiplets.
- d)Arene C-H signals are always singlets.
Correct answer is option 'A'. Can you explain this answer?
Which of the following statements in the context of 1H NMR spectroscopy is true?
a)
Arene C-H chemical shift (δ) values are greater than simple alkenes C-H chemical shift values because of the aromatic ring current.
b)
Arene C-H chemical shift (δ) values are smaller than simple alkenes C-H chemical shift values because of the aromatic ring current.
c)
Arene C-H signals are always multiplets.
d)
Arene C-H signals are always singlets.
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Saikat Ghoshal answered • Sep 03, 2024 |
Understanding Arene C-H Chemical Shifts in 1H NMR Spectroscopy
In the context of 1H NMR spectroscopy, the chemical shifts of hydrogen atoms in aromatic compounds (arenes) differ significantly from those in simple alkenes due to the unique electronic environment created by the aromatic ring.
1. Chemical Shift Values
- Arene C-H chemical shift values (δ) are ... more
In the context of 1H NMR spectroscopy, the chemical shifts of hydrogen atoms in aromatic compounds (arenes) differ significantly from those in simple alkenes due to the unique electronic environment created by the aromatic ring.
1. Chemical Shift Values
- Arene C-H chemical shift values (δ) are ... more
) (1) Aqueous solution of anhydrous CuSO4, is blue while its ammonical solution is deep blue. Explain?
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Saikat Ghoshal answered • Jul 23, 2024 |
Explanation:
Anhydrous CuSO4 Solution:
- Anhydrous CuSO4 is a white crystalline solid.
- When dissolved in water, it forms a blue-colored solution due to the presence of Cu2+ ions.
- The blue color is a result of the absorption of certain wavelengths of light by the Cu2+ ions, leading to the reflection of blue ligh... more
Anhydrous CuSO4 Solution:
- Anhydrous CuSO4 is a white crystalline solid.
- When dissolved in water, it forms a blue-colored solution due to the presence of Cu2+ ions.
- The blue color is a result of the absorption of certain wavelengths of light by the Cu2+ ions, leading to the reflection of blue ligh... more
How many M — M bonds are present in [Cp Mo(CO3)]2?- a)0
- b)1
- c)2
- d)3
Correct answer is option 'A'. Can you explain this answer?
How many M — M bonds are present in [Cp Mo(CO3)]2?
a)
0
b)
1
c)
2
d)
3
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Saikat Ghoshal answered • Jun 27, 2024 |
Explanation:
- Composition of [Cp Mo(CO)3]2:
- The given compound [Cp Mo(CO)3]2 consists of a molybdenum (Mo) atom coordinated to three carbon monoxide (CO) ligands and a cyclopentadienyl (Cp) ligand.
- Cp-Mo Bond:
- The cyclopentadienyl ligand in [Cp Mo(CO)3]2 forms a sigma bond with the molybdenum atom. This is a typical metal-arene bond.
- M-M ... more
- There are no direct M-M bonds present in [Cp Mo(CO)3]2. The molybdenum atom is bonded to the ligands (CO and Cp) through coordination bonds, but there is no bond between two molybdenum atoms in this compound.
- Conclusion:
- Therefore, the correct answer is option 'A' as there are 0 M-M bonds present in [Cp Mo(CO)3]2. The only bonds present are the coordination bonds between molybdenum and the ligands.
- Composition of [Cp Mo(CO)3]2:
- The given compound [Cp Mo(CO)3]2 consists of a molybdenum (Mo) atom coordinated to three carbon monoxide (CO) ligands and a cyclopentadienyl (Cp) ligand.
- Cp-Mo Bond:
- The cyclopentadienyl ligand in [Cp Mo(CO)3]2 forms a sigma bond with the molybdenum atom. This is a typical metal-arene bond.
- M-M ... more
- There are no direct M-M bonds present in [Cp Mo(CO)3]2. The molybdenum atom is bonded to the ligands (CO and Cp) through coordination bonds, but there is no bond between two molybdenum atoms in this compound.
- Conclusion:
- Therefore, the correct answer is option 'A' as there are 0 M-M bonds present in [Cp Mo(CO)3]2. The only bonds present are the coordination bonds between molybdenum and the ligands.
Is Sr, Pb, Sn exhibits only one oxidation number other than 0️⃣ Zero?
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Saikat Ghoshal answered • May 21, 2024 |
- Sr, Pb, and Sn Oxidation Numbers
Sr, Pb, and Sn are elements that exhibit multiple oxidation numbers rather than just one.
Sr (Strontium)
- Strontium typically exhibits an oxidation number of +2. This is the most common oxidation state for strontium in compounds.
Pb (Lead)
- Lead can have multiple oxidation numbers, including +2 and +4. The +2 o... more
Sr, Pb, and Sn are elements that exhibit multiple oxidation numbers rather than just one.
Sr (Strontium)
- Strontium typically exhibits an oxidation number of +2. This is the most common oxidation state for strontium in compounds.
Pb (Lead)
- Lead can have multiple oxidation numbers, including +2 and +4. The +2 o... more
Internal energy(ΔE) is equal to the heat supplied(q) in- a)Adiabatic change
- b)Isochoric change
- c)Isothermal reversible change
- d)Isothermal irreversible change
Correct answer is option 'B'. Can you explain this answer?
Internal energy(ΔE) is equal to the heat supplied(q) in
a)
Adiabatic change
b)
Isochoric change
c)
Isothermal reversible change
d)
Isothermal irreversible change
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Saikat Ghoshal answered • Mar 14, 2024 |
Internal Energy and Heat in Different Processes:
Internal energy (ΔE) is a property of a system that represents the sum of all microscopic forms of energy in the system. Heat supplied (q) is the transfer of thermal energy between systems at different temperatures. The relationship between internal energy and heat supplied varies depending on the process.
In... more
What is the shape the orbital, whose “l” is 1?- a)Spherical
- b)Dumbbell
- c)Double dumbbell
- d)Complex
Correct answer is option 'B'. Can you explain this answer?
What is the shape the orbital, whose “l” is 1?
a)
Spherical
b)
Dumbbell
c)
Double dumbbell
d)
Complex
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Saikat Ghoshal answered • Feb 13, 2024 |
Shape is determined by the angular momentum quantum number, l = 2?
A criminal noticed by a police inspector from a distance of 200 m. After seeing, the police the theif starts running at a speed of 10 km/hour and the police starts chasing at a speed of 11 km/hr. The total distance covered by the inspector when he catches the thief i s ______________ km. (Round off to one decimal place)
Correct answer is between '2.1,2.3'. Can you explain this answer?
A criminal noticed by a police inspector from a distance of 200 m. After seeing, the police the theif starts running at a speed of 10 km/hour and the police starts chasing at a speed of 11 km/hr. The total distance covered by the inspector when he catches the thief i s ______________ km. (Round off to one decimal place)
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Saikat Ghoshal answered • Feb 01, 2024 |
Given data:
Distance between the criminal and the police inspector = 200 m
Speed of the criminal = 10 km/hr
Speed of the police inspector = 11 km/hr
Approach:
To find the total distance covered by the police inspector when he catches the thief, we need to calculate the time taken by the police inspector to catch the thief.
Calculating tim... more
The relative speed of the police inspector with respect to the thief is the difference between their speeds.
Relative speed = Speed of police inspector - Speed of the thief
Relative speed = 11 km/hr - 10 km/hr = 1 km/hr
Now, we can calculate the time taken by the police inspector to cover the initial distance between them.
Time = Distance / Speed
Time = 200 m / 1 km/hr
Converting meters to kilometers, 1 km = 1000 m
Time = 0.2 km / 1 km/hr
Time = 0.2 hr
Calculating distance:
Now that we know the time taken by the police inspector to cover the initial distance, we can calculate the distance covered by the police inspector when he catches the thief.
Distance = Speed x Time
Distance = 11 km/hr x 0.2 hr
Distance = 2.2 km
Answer:
The total distance covered by the police inspector when he catches the thief is 2.2 km.
(rounded off to one decimal place)
Verification:
To verify the answer, we can calculate the time taken by the thief to cover the same distance.
Time = Distance / Speed
Time = 2.2 km / 10 km/hr
Time = 0.22 hr
Now, we can calculate the distance covered by the thief in this time.
Distance = Speed x Time
Distance = 10 km/hr x 0.22 hr
Distance = 2.2 km
As the distance covered by the police inspector and the thief is the same, it confirms that the answer is correct.
Distance between the criminal and the police inspector = 200 m
Speed of the criminal = 10 km/hr
Speed of the police inspector = 11 km/hr
Approach:
To find the total distance covered by the police inspector when he catches the thief, we need to calculate the time taken by the police inspector to catch the thief.
Calculating tim... more
The relative speed of the police inspector with respect to the thief is the difference between their speeds.
Relative speed = Speed of police inspector - Speed of the thief
Relative speed = 11 km/hr - 10 km/hr = 1 km/hr
Now, we can calculate the time taken by the police inspector to cover the initial distance between them.
Time = Distance / Speed
Time = 200 m / 1 km/hr
Converting meters to kilometers, 1 km = 1000 m
Time = 0.2 km / 1 km/hr
Time = 0.2 hr
Calculating distance:
Now that we know the time taken by the police inspector to cover the initial distance, we can calculate the distance covered by the police inspector when he catches the thief.
Distance = Speed x Time
Distance = 11 km/hr x 0.2 hr
Distance = 2.2 km
Answer:
The total distance covered by the police inspector when he catches the thief is 2.2 km.
(rounded off to one decimal place)
Verification:
To verify the answer, we can calculate the time taken by the thief to cover the same distance.
Time = Distance / Speed
Time = 2.2 km / 10 km/hr
Time = 0.22 hr
Now, we can calculate the distance covered by the thief in this time.
Distance = Speed x Time
Distance = 10 km/hr x 0.22 hr
Distance = 2.2 km
As the distance covered by the police inspector and the thief is the same, it confirms that the answer is correct.
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Saikat Ghoshal asked • Sep 29, 2023 |
Which type of radiation has a continuous energy spectrum?- a)Alpha particles
- b)Beta particles
- c)Gamma rays
- d)Neutrons
Correct answer is option 'B'. Can you explain this answer?
a)
Alpha particles
b)
Beta particles
c)
Gamma rays
d)
Neutrons
|
Aashna Shah answered |
Continuous Energy Spectrum of Beta Particles
Beta particles are high-energy electrons or positrons that are emitted during certain types of radioactive decay. They have a continuous energy spectrum, which means that they can have a range of different energies.
Explanation:
When a radioactive nucleus undergoes beta decay, it can emit either an electron... more
Beta particles are high-energy electrons or positrons that are emitted during certain types of radioactive decay. They have a continuous energy spectrum, which means that they can have a range of different energies.
Explanation:
When a radioactive nucleus undergoes beta decay, it can emit either an electron... more
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Saikat Ghoshal asked • Aug 17, 2023 |
Can I access the IIT JAM Chemistry answer key if I have made any changes to my application form after submission?
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Shivani Mehta answered |
Can I access the IIT JAM Chemistry answer key if I have made any changes to my application form after submission?
Yes, you can still access the IIT JAM Chemistry answer key even if you have made changes to your application form after submission. Here's what you need to know:
1. Application Form Changes
- If you have made any changes to your application form... more
Yes, you can still access the IIT JAM Chemistry answer key even if you have made changes to your application form after submission. Here's what you need to know:
1. Application Form Changes
- If you have made any changes to your application form... more
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Saikat Ghoshal asked • Aug 17, 2023 |
Can you recommend some websites or resources that offer concept maps or visual aids for better understanding of IIT JAM Chemistry topics?
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Shivani Mehta answered |
However, I can provide you with some general guidance on finding concept maps or visual aids for better understanding of IIT JAM Chemistry topics.
One platform that offers a wide range of study resources, including concept maps and visual aids, is EduRev. It is a popular online learning platform that provides educational content for various exams, including IIT JAM Chemistry. You can fi... more
One platform that offers a wide range of study resources, including concept maps and visual aids, is EduRev. It is a popular online learning platform that provides educational content for various exams, including IIT JAM Chemistry. You can fi... more
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Saikat Ghoshal asked • Aug 14, 2023 |
Can the cutoff for IIT JAM Chemistry differ for candidates with a Bachelor's degree from distance education?
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Sinjini Singh answered |
Can the cutoff for IIT JAM Chemistry differ for candidates with a Bachelor's degree from distance education?
Yes, the cutoff for IIT JAM Chemistry can differ for candidates with a Bachelor's degree from distance education. The cutoff is the minimum score or rank required to secure admission in the desired program or institute. The cutoff is determined based on various factors such as the number of seats available, the difficulty level of the exam, the number of applicants, and the performance of the candidates.
... more|
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Saikat Ghoshal asked • Aug 07, 2023 |
Can I get negative marks for marking more than one option in multiple-choice questions of IIT JAM Chemistry?
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Tejas Goyal answered |
Can I get negative marks for marking more than one option in multiple-choice questions of IIT JAM Chemistry?
Yes, you can get negative marks for marking more than one option in multiple-choice questions of IIT JAM Chemistry. The examination pattern of IIT JAM Chemistry includes negative marking for incorrect answers. Let's understand the details of negative marking in IIT JAM Che... more
Yes, you can get negative marks for marking more than one option in multiple-choice questions of IIT JAM Chemistry. The examination pattern of IIT JAM Chemistry includes negative marking for incorrect answers. Let's understand the details of negative marking in IIT JAM Che... more
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Saikat Ghoshal asked • Aug 02, 2023 |
How important is solving mock tests and sample papers to qualify for IIT JAM Chemistry?
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Soumya Sharma answered |
Importance of Solving Mock Tests and Sample Papers for IIT JAM Chemistry
Preparing for the IIT JAM Chemistry exam requires thorough knowledge of the subject along with effective time management and exam strategy. Solving mock tests and sample papers play a crucial role in this preparation process. Here's why:
1. Familiarity with Exam Pattern:
- Mock tests a... more
Preparing for the IIT JAM Chemistry exam requires thorough knowledge of the subject along with effective time management and exam strategy. Solving mock tests and sample papers play a crucial role in this preparation process. Here's why:
1. Familiarity with Exam Pattern:
- Mock tests a... more
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Saikat Ghoshal asked • Dec 08, 2022 |
There are seventeen non-metals in the periodic table. Unlike metals in the same period, they have higher:- a)Atomic number
- b)Atomic size
- c)Electropositivity
- d)All of the mentioned
Correct answer is option 'A'. Can you explain this answer?
There are seventeen non-metals in the periodic table. Unlike metals in the same period, they have higher:
a)
Atomic number
b)
Atomic size
c)
Electropositivity
d)
All of the mentioned
|
Vivek Khatri answered |
Non-metals are located at the right end of their respective periods. As we move from left to right in a period or from top to bottom in a group, atomic number increases. Due to increasing charge on the nucleus, atomic size also decreases on moving right in a period. This is also the reason of increasing electronegativity or decreasing electropositivity.
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Saikat Ghoshal asked • Dec 04, 2022 |
What catalyst is used for oxidation of ammonia to produce nitric acid?- a)Palladium hydride
- b)Sodium amalgam
- c)Platinum-Rhodium gauze
- d)Vanadium (V) oxide
Correct answer is option 'C'. Can you explain this answer?
What catalyst is used for oxidation of ammonia to produce nitric acid?
a)
Palladium hydride
b)
Sodium amalgam
c)
Platinum-Rhodium gauze
d)
Vanadium (V) oxide
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Vivek Khatri answered |
Ammonia is oxidized to nitrogen (II) oxide in the presence of Pt/Rh gauze catalyst at a temperature of 500 K and a pressure of 9 bars. The nitrous oxide is then converted to nitrogen dioxide which is further reacted with water to produce nitric acid. The NO formed is recycled.
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Saikat Ghoshal asked • Dec 01, 2022 |
Which of the following statements is correct for alkyl halide?- a)Alkyl halide will always show SN1 mechanism
- b)As branching at carbon increases, E1 mechanism is favoured as compared to SN1 mechanism
- c)In unimolecular reaction, increasing the temperature donot favours E1 mechanism
- d)In most unimolecular reactions of alkyl halide E1 reaction is favoured over SN1 reaction
Correct answer is option 'B'. Can you explain this answer?
Which of the following statements is correct for alkyl halide?
a)
Alkyl halide will always show SN1 mechanism
b)
As branching at carbon increases, E1 mechanism is favoured as compared to SN1 mechanism
c)
In unimolecular reaction, increasing the temperature donot favours E1 mechanism
d)
In most unimolecular reactions of alkyl halide E1 reaction is favoured over SN1 reaction
|
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Vivek Khatri answered |
In most unimolecular reactions of alkyl halide SN1 reaction is favoured over E1 reaction. E1 mechanism is favoured as compared to SN1 mechanism by branching at carbon increases, as more steric hinderence at the attacking site will leads to E1 mechanism.
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