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Mainak SinghEduRev UGC NET |
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Mainak Singh
EduRev UGC NET
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Top Scoring Tests by Mainak
Test: Gaseous State - 2 | 47/60 |
Test: Periodic Properties- 1 | 35/46 |
Test: Periodic Properties- 3 | 44/60 |
Test: Colligative Properties - 2 | 44/60 |
Test: Thermodynamics And Thermochemistry - 1 | 29/40 |
Test: GOC, Aromaticity, Acidity & Basicity - 1 | 27/40 |
Test: Thermodynamics And Thermochemistry - 3 | 37/60 |
Test: Reaction Intermediate Level - 2 | 37/60 |
Test: Stereochemistry Level - 2 | 36/60 |
Test: Reaction Intermediate Level - 1 | 20/34 |
Rated 5 
by Mainak
by Mainak | Fajan's Rule, Types of Interactions & Dipole Moment Doc | 6 pages |  |
 | Cyclopropane and Cyclobutane Video | 08:42 min | |
 | Entropy & its Physical Significance Doc | 4 pages | |
 | Reversible Reactions & Equilibrium Doc | 1 page | |
 | Electronic Effects: Inductive, Hyperconjugation & Resonance Doc | 10 pages | |
 | Aromaticity - General Organic Chemistry Doc | 5 pages | |
Discussed Questions
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Mainak Singh upvoted • Jun 26, 2021 |
Oxidation number of Co in [Co(NO)(CO)3] is:- a)1
- b)2
- c)3
- d)–1
Correct answer is option 'D'. Can you explain this answer?
Oxidation number of Co in [Co(NO)(CO)3] is:
a)
1
b)
2
c)
3
d)
–1
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Srijan Sengupta answered |
Here can be a confusion that whether NO exists as NO+ or NO- .....CO is a π acid ligand so it accepts electron density from metal centre and so due to presence of 3 CO the metal centre is in somewhat oxidised state ....so NO releases one electron and causes one electron reduction of metal centre and NO exists as NO+ in this complex.....so coordination no. of Co is -1
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Mainak Singh upvoted • Jan 31, 2021 |
MnS has NaCl (Rocksalt) structure with the unit cell parameter a=4.43 Å. The Mn-S distance in MnS is:... more
MnS has NaCl (Rocksalt) structure with the unit cell parameter a=4.43 Å. The Mn-S distance in MnS is:
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Study Sesh answered |
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Mainak Singh upvoted • Jan 25, 2021 |
The values of observed and calculated molecular weights of silver nitrate are 92.64 and 170 respectively. The degree of dissociation of silver nitrate is:- a)60%
- b)83.5%
- c)46.7%
- d)60.23%
Correct answer is 'B'. Can you explain this answer?
The values of observed and calculated molecular weights of silver nitrate are 92.64 and 170 respectively. The degree of dissociation of silver nitrate is:
a)
60%
b)
83.5%
c)
46.7%
d)
60.23%
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Mayank Pandey answered |
First of all we have to calculate the value of vant hoff factor so that we can further find the value of dissociation constant.
HERE, formula used to calculate (i) is
i = normal or calculated molecular mass / observed molecular mass
therefore, i = 92.6/170 = 1.835
also AgNO3 dissociates to give two ions. Therefore, n = 2.
now for dissociation constant (i) = 1-(n-1)a
by putting all values we get a = 1.835 - 1 = 0.835 x 100 = 83.5%
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Mainak Singh upvoted • Jan 13, 2021 |
The solubility of a specific non–volatile salt is 4 g in 100 g of water at 25°C. If 2.0 g, 4.0 g and 6.0 g of the salt added of 100 g of water at 25°C, in system X, Y, and Z. The vapour pressure would be in the order:- a)X < Y < Z
- b)X > Y > Z
- c)Z > X = Y
- d)X > Y = Z
Correct answer is option 'D'. Can you explain this answer?
The solubility of a specific non–volatile salt is 4 g in 100 g of water at 25°C. If 2.0 g, 4.0 g and 6.0 g of the salt added of 100 g of water at 25°C, in system X, Y, and Z. The vapour pressure would be in the order:
a)
X < Y < Z
b)
X > Y > Z
c)
Z > X = Y
d)
X > Y = Z
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Aditya Deshmukh answered |
Solution X is unsaturated so vapour pressure will be more, solution Y & Z are saturated so vapour pressure of Y = vapour pressure of Z and 2 gm of solute would be present in form of solid in system Z.
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Mainak Singh upvoted • Jan 10, 2021 |
The number of S–S bonds in H2S5O6 is
Correct answer is '4'. Can you explain this answer?
The number of S–S bonds in H2S5O6 is
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Neeraj Chandra answered |
Hybridization and shape of N(SiH3)3 is:- a)Sp3, tetrahedral
- b)sp2, planar
- c)sp3, planar
- d)sp2, angular
Correct answer is option 'B'. Can you explain this answer?
Hybridization and shape of N(SiH3)3 is:
a)
Sp3, tetrahedral
b)
sp2, planar
c)
sp3, planar
d)
sp2, angular
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Mainak Singh answered • Aug 10, 2020 |
Hybridisation will be SP2 and the shape will be angular due to lp-bp repulsion
Which of the fo llowing plots represent(s) the Arrhenius rate equation, k=Ae–Ea/RT with 
and 
... more
Which of the fo llowing plots represent(s) the Arrhenius rate equation, k=Ae–Ea/RT with and
and |
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Mainak Singh answered • Jul 30, 2020 |
I think it will be option 2
P2 coverts into P4 due to:- a)Weak pπ - pπ bonding
- b)Strong pπ - pπ bonding
- c)Strong pπ - dπ bonding
- d)Weak sigma bonding
Correct answer is option 'A'. Can you explain this answer?
P2 coverts into P4 due to:
a)
Weak pπ - pπ bonding
b)
Strong pπ - pπ bonding
c)
Strong pπ - dπ bonding
d)
Weak sigma bonding
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Mainak Singh answered • Nov 06, 2019 |
It think it will be a
bcoz due to weak pπ-pπ bonding .it prefer to form sigma bond
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Mainak Singh asked • Aug 24, 2019 |
What is ortho effect ?
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Soumya Sengupta answered |
Ortho effect refers mainly to the set of steric effects and some bonding interactions along with polar effects caused by the various substituents which are in a given molecule altering its chemical properties and physical properties. In a general sense the ortho effect is associated with substitued benzene compounds.
There are three main ortho effects in substituted benzene compounds:
- Ortho effect in substituted benzoic acid (first ortho effect) – Ortho-substituted benzoic acids are stronger acids than their meta and para isomers, regardless of the nature of the substituent
- Ortho effect in substituted aniline (second ortho effect/SIP effect)- Ortho-substituted anilines are weaker bases than their meta and para isomers, regardless of the nature of the substituent
- Ortho effect in electrophilc aromatic substitution of disubstitued benzene compounds (third ortho effect)- It refers to the set of steric effects which determines the regioselectivity of an incoming electrophile in disubstituted benzene compounds where a meta-directing group is meta to an ortho–para-directing group.
- Ortho effect in substituted benzoic acid (first ortho effect) – Ortho-substituted benzoic acids are stronger acids than their meta and para isomers, regardless of the nature of the substituent
- Ortho effect in substituted aniline (second ortho effect/SIP effect)- Ortho-substituted anilines are weaker bases than their meta and para isomers, regardless of the nature of the substituent
- Ortho effect in electrophilc aromatic substitution of disubstitued benzene compounds (third ortho effect)- It refers to the set of steric effects which determines the regioselectivity of an incoming electrophile in disubstituted benzene compounds where a meta-directing group is meta to an ortho–para-directing group.
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