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Baishali BajajEduRev Computer Science Engineering (CSE) |
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Baishali Bajaj
EduRev Computer Science Engineering (CSE)
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Top Scoring Tests by Baishali
Physics - 2017 Past Year Paper | 65/100 |
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Model Test Paper, Math, Feb. - 2017 | 61/100 |
Rigid Body Dynamics NAT Level - 2 | 12/20 |
Statistical Physics MSQ | 12/20 |
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Model Test Physics - 2017 | 59/101 |
Discussed Questions
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Athul Menon upvoted • Feb 27, 2025 |
The absorption at λmax 279 nm (ε = 15) in the UV spectrum of acetone is due to:
- a)π-π* transition
- b)σ-σ* transition
- c)n-π* transition
- d)π-σ* transition
Correct answer is option 'C'. Can you explain this answer?
The absorption at λmax 279 nm (ε = 15) in the UV spectrum of acetone is due to:
a)
π-π* transition
b)
σ-σ* transition
c)
n-π* transition
d)
π-σ* transition
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Edurev.iitjam answered |
The type of transition is responsible for a band at λmax = 279 nm in absorption spectrum of acetone. In case of n → π* transitions, the polar solvents form hydrogen bonds with the ground state of polar molecules more readily than with their excited states. Therefore, in polar solvents the energies of electronic transitions are increased.
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Athul Menon upvoted • Feb 11, 2025 |
Which of the following molecules, in pure form, is (are) unstable at room temperature:- a)
- b)
- c)
- d)
Correct answer is option 'B,C'. Can you explain this answer?
Which of the following molecules, in pure form, is (are) unstable at room temperature:
a)
b)
c)
d)
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Asf Institute answered |
Correct Answer :- b,c
Explanation : (B) Cyclobutadiene follows Huckel's criteria for anti-aromaticity [(4n)−π electrons], hence unstable.
(C) Follows Huckel's criteria for anti-aromaticity [(4n)−π electrons], hence, unstable.
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Athul Menon upvoted • Feb 05, 2025 |
In radical chain polymerization, the quantity given by the rate of monomer depletion, divided by the rate of propagating radical formation is called:
- a)Kinetic chain length.
- b)Propagation efficiency.
- c)Propagation rate constant
- d)Polymerization time.
Correct answer is option 'A'. Can you explain this answer?
In radical chain polymerization, the quantity given by the rate of monomer depletion, divided by the rate of propagating radical formation is called:
a)
Kinetic chain length.
b)
Propagation efficiency.
c)
Propagation rate constant
d)
Polymerization time.
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Edurev.iitjam answered |
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Athul Menon upvoted • Feb 01, 2025 |
The correct statement about the Cu–N bond distance in [Cu(NH3)6]2+ is:- a)All the bond distance are equal.
- b)The axial bonds are longer than the equatorial ones.
- c)The equatorial bonds are longer than the axial ones.
- d)All the bond distances are unequal.
Correct answer is option 'B'. Can you explain this answer?
The correct statement about the Cu–N bond distance in [Cu(NH3)6]2+ is:
a)
All the bond distance are equal.
b)
The axial bonds are longer than the equatorial ones.
c)
The equatorial bonds are longer than the axial ones.
d)
All the bond distances are unequal.
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Edurev.iitjam answered |
- In [Cu(NH3)6]2+, there are six NH3 ligands arranged in an octahedral geometry around the central Cu2+ ion.
- The bond distances are different due to the difference in the orientation of the ligands.
- There are two types of bond distances in this complex: axial and equatorial.
- Axial bonds: These are the bonds that are perpendicular to the plane of the equatorial bonds. There are two axial bonds in this complex.
- Equatorial bonds: These are the bonds that lie in the plane of the complex. There are four equatorial bonds in this complex.
- The repulsion between the lone pairs of electrons on the NH3 ligands causes the axial bonds to be longer than the equatorial bonds.
- Therefore, the correct statement is that the axial bonds are longer than the equatorial ones (option B is correct).
- The bond distances are different due to the difference in the orientation of the ligands.
- There are two types of bond distances in this complex: axial and equatorial.
- Axial bonds: These are the bonds that are perpendicular to the plane of the equatorial bonds. There are two axial bonds in this complex.
- Equatorial bonds: These are the bonds that lie in the plane of the complex. There are four equatorial bonds in this complex.
- The repulsion between the lone pairs of electrons on the NH3 ligands causes the axial bonds to be longer than the equatorial bonds.
- Therefore, the correct statement is that the axial bonds are longer than the equatorial ones (option B is correct).
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Athul Menon upvoted • Jan 28, 2025 |
For the reaction in equilibrium, A 
B
Thus, K is- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
For the reaction in equilibrium, A B
Thus, K is
BThus, K is
a)
b)
c)
d)
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Sushil Kumar answered |
From the reaction
-d[A]/dt = d[B] /dt
⇒2.3 × 106 [A] = k [B]
as given in question [B] /[A] = 4 × 108
so [A] / [B] = 1/ 4 ×108
⇒ 2.3 × 106 . [A] /[B] = k
⇒ 2.3 × 106 / 4 × 108 = k
Or k = 5.8 × 10-3 /sec¹
-d[A]/dt = d[B] /dt
⇒2.3 × 106 [A] = k [B]
as given in question [B] /[A] = 4 × 108
so [A] / [B] = 1/ 4 ×108
⇒ 2.3 × 106 . [A] /[B] = k
⇒ 2.3 × 106 / 4 × 108 = k
Or k = 5.8 × 10-3 /sec¹
The northern blot is used for the probing of:- a)RNA identity
- b)RNA size
- c)RNA abundance
- d)All of the above
Correct answer is option 'D'. Can you explain this answer?
The northern blot is used for the probing of:
a)
RNA identity
b)
RNA size
c)
RNA abundance
d)
All of the above
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Athul Menon answered • Jan 24, 2025 |
Overview of Northern Blotting
Northern blotting is a powerful technique used to study RNA. It allows researchers to analyze various aspects of RNA molecules in a sample, making it an essential tool in molecular biology.
Probing for RNA Identity
- Northern blotting enables the identification of specific RNA molecules within a complex mixture.
- By using labeled pro... more
Northern blotting is a powerful technique used to study RNA. It allows researchers to analyze various aspects of RNA molecules in a sample, making it an essential tool in molecular biology.
Probing for RNA Identity
- Northern blotting enables the identification of specific RNA molecules within a complex mixture.
- By using labeled pro... more
For a pure substance, ln P(solid) = –20/T 10 and ln P(liquid) = –15/T 2. Calculate ratio of slope at triple point?
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Athul Menon answered • Dec 15, 2024 |
Understanding the Problem
To calculate the ratio of slopes at the triple point for a pure substance, we need to analyze the given equations for the solid and liquid phases.
Given Equations
- Solid Phase: ln P(solid) = –20/T + 10
- Liquid Phase: ln P(liquid) = –15/T + 2
Identifying the Slopes
The slopes of the equations can be derived from the line... more
To calculate the ratio of slopes at the triple point for a pure substance, we need to analyze the given equations for the solid and liquid phases.
Given Equations
- Solid Phase: ln P(solid) = –20/T + 10
- Liquid Phase: ln P(liquid) = –15/T + 2
Identifying the Slopes
The slopes of the equations can be derived from the line... more
?
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Athul Menon answered • Oct 23, 2024 |
Understanding IIT JAM Geology
IIT JAM (Joint Admission Test for M.Sc.) is a prestigious examination for students wishing to pursue M.Sc. programs at IITs and other renowned institutions. Geology is one of the branches offered, and preparing effectively can significantly enhance your chances of success.
Importance of Past Year Papers
- Familiarity with Exam Pattern... more
IIT JAM (Joint Admission Test for M.Sc.) is a prestigious examination for students wishing to pursue M.Sc. programs at IITs and other renowned institutions. Geology is one of the branches offered, and preparing effectively can significantly enhance your chances of success.
Importance of Past Year Papers
- Familiarity with Exam Pattern... more
?
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Athul Menon answered • Aug 25, 2024 |
Importance of Previous Year Questions
Previous year questions (PYQs) are invaluable resources for exam preparation, especially for competitive exams like IIT JAM, CSIR, and GATE in Chemistry. They help in understanding the exam pattern, frequently asked topics, and the level of difficulty.
Benefits of Solving PYQs
Creating a Topicwise Question Bank
To enhance your preparation, create a topicwise question bank based on previous years’ exams. Here’s how:
Conclusion
Incorporating previous year questions into your study routine is essential for effective preparation for IIT JAM, CSIR, and GATE Chemistry. By creating a structured, topicwise question bank, you not only enhance your grasp of the subject but also significantly improve your chances of performing well in the exams.
Previous year questions (PYQs) are invaluable resources for exam preparation, especially for competitive exams like IIT JAM, CSIR, and GATE in Chemistry. They help in understanding the exam pattern, frequently asked topics, and the level of difficulty.
Benefits of Solving PYQs
- Familiarity with Exam Format: Solv... more
- Topic-Specific Preparation: It allows you to identify important topics and focus your studies accordingly.
- Time Management Skills: Practicing with a timer can help you improve your speed and efficiency during the actual exam.
- Assessment of Knowledge: Regularly attempting these questions can help you gauge your understanding and retention of concepts.
- Confidence Building: Successfully solving past questions boosts confidence and reduces exam anxiety.
Creating a Topicwise Question Bank
To enhance your preparation, create a topicwise question bank based on previous years’ exams. Here’s how:
- Collect PYQs: Gather questions from the last 5-10 years for IIT JAM, CSIR, and GATE Chemistry exams.
- Organize by Topic: Sort the questions into categories such as Physical Chemistry, Organic Chemistry, Inorganic Chemistry, and Analytical Chemistry.
- Identify Patterns: Note which topics are frequently repeated and prioritize these in your study plan.
- Practice Regularly: Dedicate specific times in your study schedule to solve questions from each topic.
- Review Mistakes: After attempting, review incorrect answers to understand your weaknesses.
Conclusion
Incorporating previous year questions into your study routine is essential for effective preparation for IIT JAM, CSIR, and GATE Chemistry. By creating a structured, topicwise question bank, you not only enhance your grasp of the subject but also significantly improve your chances of performing well in the exams.
The main sources of arenes among these are:- a)Petroleum
- b)Biogas and petroleum
- c)Petroleum and natural gas
- d)Natural gas
Correct answer is option 'C'. Can you explain this answer?
The main sources of arenes among these are:
a)
Petroleum
b)
Biogas and petroleum
c)
Petroleum and natural gas
d)
Natural gas
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Athul Menon answered • Jun 21, 2024 |
Sources of Arenes
- Petroleum: Petroleum is a major source of arenes, also known as aromatic hydrocarbons. It is a complex mixture of hydrocarbons that can be refined to obtain different aromatic compounds like benzene, toluene, and xylene.
- Natural Gas: Although natural gas primarily consists of alkanes, it can also contain small amounts of aromatic hydrocarbons li... more
- Petroleum: Petroleum is a major source of arenes, also known as aromatic hydrocarbons. It is a complex mixture of hydrocarbons that can be refined to obtain different aromatic compounds like benzene, toluene, and xylene.
- Natural Gas: Although natural gas primarily consists of alkanes, it can also contain small amounts of aromatic hydrocarbons li... more
In a double stranded DNA, if the sequence 5’AGATCC3’ appears on one strand of DNA, what sequence in the complementary strand?- a)5’AGATCC3’
- b)5’CCTAGA3’
- c)5’GGATCT3’
- d)5’TCTAGG3’
Correct answer is option 'D'. Can you explain this answer?
In a double stranded DNA, if the sequence 5’AGATCC3’ appears on one strand of DNA, what sequence in the complementary strand?
a)
5’AGATCC3’
b)
5’CCTAGA3’
c)
5’GGATCT3’
d)
5’TCTAGG3’
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Athul Menon answered • Jun 21, 2024 |
Complementary Strand Sequence in Double Stranded DNA
DNA is made up of two strands that are complementary to each other, meaning that the sequence of nucleotides in one strand determines the sequence in the other. In a double-stranded DNA molecule, adenine (A) always pairs with thymine (T), and guanine (G) always pairs with cytosine (C).
Given Sequence on One Strand: 5&pr... more
- The sequence on one strand of DNA is 5′AGATCC3′.
- To find the complementary sequence on the other strand, we need to identify the pairing nucleotides for each base.
Pairing Nucleotides:
- A (Adenine) pairs with T (Thymine)
- G (Guanine) pairs with C (Cytosine)
Complementary Sequence:
- The complementary sequence for 5′AGATCC3′ would be:
- A -> T
- G -> C
- A -> T
- T -> A
- C -> G
- C -> G
Final Complementary Strand Sequence:
Therefore, the complementary sequence on the other strand would be 5′TCTAGG3′ (Option D). This sequence follows the base pairing rules where A pairs with T, G pairs with C, and vice versa.
DNA is made up of two strands that are complementary to each other, meaning that the sequence of nucleotides in one strand determines the sequence in the other. In a double-stranded DNA molecule, adenine (A) always pairs with thymine (T), and guanine (G) always pairs with cytosine (C).
Given Sequence on One Strand: 5&pr... more
- The sequence on one strand of DNA is 5′AGATCC3′.
- To find the complementary sequence on the other strand, we need to identify the pairing nucleotides for each base.
Pairing Nucleotides:
- A (Adenine) pairs with T (Thymine)
- G (Guanine) pairs with C (Cytosine)
Complementary Sequence:
- The complementary sequence for 5′AGATCC3′ would be:
- A -> T
- G -> C
- A -> T
- T -> A
- C -> G
- C -> G
Final Complementary Strand Sequence:
Therefore, the complementary sequence on the other strand would be 5′TCTAGG3′ (Option D). This sequence follows the base pairing rules where A pairs with T, G pairs with C, and vice versa.
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Athul Menon asked • Mar 24, 2024 |
Which of the following statements regarding electron-impact mass spectrometry is true?- a)Samples need isotopic labels.
- b)The base peak is formed by loss of one electron from each vaporised molecule by an electron beam.
- c)Compounds must have a functional group to show a mass spectrum.
- d)A meaningful mass spectrum can sometimes be obtained on a very small sample of an impure compound.
Correct answer is option 'D'. Can you explain this answer?
Which of the following statements regarding electron-impact mass spectrometry is true?
a)
Samples need isotopic labels.
b)
The base peak is formed by loss of one electron from each vaporised molecule by an electron beam.
c)
Compounds must have a functional group to show a mass spectrum.
d)
A meaningful mass spectrum can sometimes be obtained on a very small sample of an impure compound.
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Edurev.iitjam answered |
For the electron-impact mass spectrometric method. A mass spectrum records relative abundances of the molecular cation and its fragment cations by their mass-to-charge ratios, m/z. The base peak corresponds to the most abundant cation which is not usually the molecular cation. Mass spectrometric signals of impurities do not normally obscure the significant peaks of the main compound; in fact, mass spectrometry is a useful technique for identifying impurities.
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is - a)1/40
- b)1/20
- c)3/10
- d)3/80
Correct answer is option 'A'. Can you explain this answer?
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is
a)
1/40
b)
1/20
c)
3/10
d)
3/80
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Athul Menon answered • Jan 30, 2024 |
Problem:
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40 b)1/20 c)3/10 d)3/80. The correct answer is option 'A'. Explain this answer.
Solution:
We are given a set of 10 numbers: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. We need to select three numbers ... more
From the set of 10 numbers {1, 2,...,10} three numbers are selected at random without replacement. The probability that the sum of these selected numbers is 9, is a)1/40 b)1/20 c)3/10 d)3/80. The correct answer is option 'A'. Explain this answer.
Solution:
We are given a set of 10 numbers: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. We need to select three numbers ... more
A solution formed by mixing 300 ml of HCL having pH 3 and 700 mL of H2SO4 having pH 2, will have new pH as ________ [Answer upto one place of decimal]
Correct answer is between '2.1,2.2'. Can you explain this answer?
A solution formed by mixing 300 ml of HCL having pH 3 and 700 mL of H2SO4 having pH 2, will have new pH as ________ [Answer upto one place of decimal]
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Athul Menon answered • Jan 30, 2024 |
Given:
- Volume of HCl solution = 300 mL
- pH of HCl solution = 3
- Volume of H2SO4 solution = 700 mL
- pH of H2SO4 solution = 2
To find:
- pH of the solution formed by mixing the two solutions
Solution:
To find the pH of the solution formed by mixing the two solutions, we can use the formula for calculating the pH of a solut... more
- Volume of HCl solution = 300 mL
- pH of HCl solution = 3
- Volume of H2SO4 solution = 700 mL
- pH of H2SO4 solution = 2
To find:
- pH of the solution formed by mixing the two solutions
Solution:
To find the pH of the solution formed by mixing the two solutions, we can use the formula for calculating the pH of a solut... more
A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1 mg-1). [Answer upto two place of decimal]
Correct answer is '0.05'. Can you explain this answer?
A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1 mg-1). [Answer upto two place of decimal]
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Athul Menon answered • Jan 30, 2024 |
Calculating the specific enzyme activity
To calculate the specific enzyme activity, we need to divide the total activity of the enzyme by the protein concentration.
Given data:
- Enzyme solution volume = 20 ml
- Total activity of enzyme = 20 katal
- Protein concentration = 20 mg/ml
Step 1: Convert the enzyme activity to mol/s
The t... more
To calculate the specific enzyme activity, we need to divide the total activity of the enzyme by the protein concentration.
Given data:
- Enzyme solution volume = 20 ml
- Total activity of enzyme = 20 katal
- Protein concentration = 20 mg/ml
Step 1: Convert the enzyme activity to mol/s
The t... more
Select the correct statement regarding [Ph3MeP][AI(BH4)4]
(I) At 298 anion show one signal in 1H NMR
(II) At 298 anion show two signal in 1H NMR
(III) At 298 a quintet is observed in 11B NMR
(IV) At 298 a triplet of triplet is observed in 11B NMR- a)I and III
- b)I and IV
- c)II and IV
- d)II and III
Correct answer is option 'A'. Can you explain this answer?
Select the correct statement regarding [Ph3MeP][AI(BH4)4]
(I) At 298 anion show one signal in 1H NMR
(II) At 298 anion show two signal in 1H NMR
(III) At 298 a quintet is observed in 11B NMR
(IV) At 298 a triplet of triplet is observed in 11B NMR
(I) At 298 anion show one signal in 1H NMR
(II) At 298 anion show two signal in 1H NMR
(III) At 298 a quintet is observed in 11B NMR
(IV) At 298 a triplet of triplet is observed in 11B NMR
a)
I and III
b)
I and IV
c)
II and IV
d)
II and III
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Athul Menon answered • Jan 30, 2024 |
Explanation:
In order to determine the correct statement regarding [Ph3MeP][AI(BH4)4](I), we need to analyze the information given for each option.
I. At 298 anion show one signal in 1H NMR:
This statement suggests that the anion [AI(BH4)4]- would exhibit a single signal in the 1H NMR spectrum at 298 K. This implies that all the protons in the molecule are ... more
In order to determine the correct statement regarding [Ph3MeP][AI(BH4)4](I), we need to analyze the information given for each option.
I. At 298 anion show one signal in 1H NMR:
This statement suggests that the anion [AI(BH4)4]- would exhibit a single signal in the 1H NMR spectrum at 298 K. This implies that all the protons in the molecule are ... more
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Athul Menon asked • Oct 02, 2023 |
The trigonometric Fourier series for the waveform f(t) shown below contains
- a)Only cosine terms and zero value for the dc component
- b)Only cosine terms and a positive value for the dc component
- c)Only cosine terms and a negative value for the dc component
- d)Only sine terms and a negative for the dc component
Correct answer is option 'C'. Can you explain this answer?
The trigonometric Fourier series for the waveform f(t) shown below contains
a)
Only cosine terms and zero value for the dc component
b)
Only cosine terms and a positive value for the dc component
c)
Only cosine terms and a negative value for the dc component
d)
Only sine terms and a negative for the dc component
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Veda Institute answered |
From figure it’s an even function. so only cosine terms are present in the series and for DC value,
So DC take negative value.
So DC take negative value.
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Athul Menon asked • Aug 17, 2023 |
Can I get the details of the seat allocation process for General category candidates in IITs through IIT JAM Chemistry?
|
Shivani Mehta answered |
Seat Allocation Process for General Category Candidates in IITs through IIT JAM Chemistry
Introduction
The Indian Institutes of Technology (IITs) are premier engineering institutions in India, known for their quality education and research. The admission to IITs is highly competitive and is conducted through various entrance examinations, including the Joint Admission... more
Introduction
The Indian Institutes of Technology (IITs) are premier engineering institutions in India, known for their quality education and research. The admission to IITs is highly competitive and is conducted through various entrance examinations, including the Joint Admission... more
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Athul Menon asked • Aug 17, 2023 |
Can I access the IIT JAM Chemistry admit card without my application number or registration ID?
|
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Shivani Mehta answered |
Procedure to access IIT JAM Chemistry admit card without application number or registration ID:
If you have misplaced or forgotten your IIT JAM Chemistry application number or registration ID, you can still access your admit card by following these steps:
1. Visit the official website:
Go to the official website of IIT JAM, which is https://jam.iisc.ac.in.<... more
If you have misplaced or forgotten your IIT JAM Chemistry application number or registration ID, you can still access your admit card by following these steps:
1. Visit the official website:
Go to the official website of IIT JAM, which is https://jam.iisc.ac.in.<... more
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Athul Menon asked • Aug 02, 2023 |
Are there any changes expected in the exam pattern of IIT JAM Chemistry in the upcoming years?
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Soumya Sharma answered |
Current Exam Pattern of IIT JAM Chemistry
The IIT JAM (Joint Admission Test for M.Sc.) Chemistry exam is conducted every year by one of the IITs for admission to various postgraduate programs in chemistry. The current exam pattern of IIT JAM Chemistry is as follows:
1. Mode of Examination: The exam is conducted in online mode (computer-based test).
2.... more
The IIT JAM (Joint Admission Test for M.Sc.) Chemistry exam is conducted every year by one of the IITs for admission to various postgraduate programs in chemistry. The current exam pattern of IIT JAM Chemistry is as follows:
1. Mode of Examination: The exam is conducted in online mode (computer-based test).
2.... more
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Athul Menon asked • Aug 02, 2023 |
What is the application process for IIT JAM Chemistry exam?
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Soumya Sharma answered |
Application Process for IIT JAM Chemistry Exam
The IIT JAM (Joint Admission Test for M.Sc.) is a national-level entrance exam conducted by the Indian Institutes of Technology (IITs) for admission to M.Sc., Joint M.Sc.-Ph.D., M.Sc.-Ph.D. Dual Degree, and other post-bachelor's degree programs at IITs and IISc. Here is a detailed explanation of the application process for the IIT JA... more
The IIT JAM (Joint Admission Test for M.Sc.) is a national-level entrance exam conducted by the Indian Institutes of Technology (IITs) for admission to M.Sc., Joint M.Sc.-Ph.D., M.Sc.-Ph.D. Dual Degree, and other post-bachelor's degree programs at IITs and IISc. Here is a detailed explanation of the application process for the IIT JA... more
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Athul Menon asked • Dec 06, 2022 |
Which type of isomerism exhibits compounds with same chemical formula and bonds but different spatial arrangement?- a)Optical isomerism
- b)Linkage isomerism
- c)Structural isomerism
- d)Solvate isomerism
Correct answer is option 'A'. Can you explain this answer?
Which type of isomerism exhibits compounds with same chemical formula and bonds but different spatial arrangement?
a)
Optical isomerism
b)
Linkage isomerism
c)
Structural isomerism
d)
Solvate isomerism
|
Vivek Khatri answered |
Stereoisomers have the same chemical formula and binds but have different spatial arrangement. Optical isomerism is a type of stereoisomerism.
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