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A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1 mg-1). [Answer upto two place of decimal]
Correct answer is '0.05'. Can you explain this answer?
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A tube contained 20 ml of enzyme solution and the total activity of en...
1 Katal = 1 mol s-1
Specific activity = total enzyme activity per unit mass of protein
Total amount of protem in 20 ml of solution = 20 x 20 = 400 mg
Specific activity = 20/400 = 0.05 mol s-1 mg-1
Specific activity = total enzyme activity per unit mass of protein
Total amount of protem in 20 ml of solution = 20 x 20 = 400 mg
Specific activity = 20/400 = 0.05 mol s-1 mg-1
Most Upvoted Answer
A tube contained 20 ml of enzyme solution and the total activity of en...
Calculating the specific enzyme activity
To calculate the specific enzyme activity, we need to divide the total activity of the enzyme by the protein concentration.
Given data:
- Enzyme solution volume = 20 ml
- Total activity of enzyme = 20 katal
- Protein concentration = 20 mg/ml
Step 1: Convert the enzyme activity to mol/s
The total activity of enzyme is given in katal. To convert it to mol/s, we need to use the definition of katal.
1 katal = 1 mol/s
Therefore, the total activity of enzyme in mol/s is also 20.
Step 2: Calculate the total amount of protein in the tube
To calculate the total amount of protein in the tube, we multiply the protein concentration by the volume of the enzyme solution.
Total amount of protein = Protein concentration x Enzyme solution volume
= 20 mg/ml x 20 ml
= 400 mg
Step 3: Convert the total amount of protein to grams
Since the specific enzyme activity is usually expressed in mol/s per gram of protein, we need to convert the total amount of protein to grams.
Total amount of protein in grams = Total amount of protein in mg / 1000
= 400 mg / 1000
= 0.4 g
Step 4: Calculate the specific enzyme activity
Finally, we can calculate the specific enzyme activity by dividing the total activity of enzyme by the total amount of protein.
Specific enzyme activity = Total activity of enzyme / Total amount of protein
= 20 mol/s / 0.4 g
= 50 mol/s/g
= 0.05 mol/s/mg (after converting grams to milligrams)
Therefore, the specific enzyme activity is 0.05 mol/s/mg.
To calculate the specific enzyme activity, we need to divide the total activity of the enzyme by the protein concentration.
Given data:
- Enzyme solution volume = 20 ml
- Total activity of enzyme = 20 katal
- Protein concentration = 20 mg/ml
Step 1: Convert the enzyme activity to mol/s
The total activity of enzyme is given in katal. To convert it to mol/s, we need to use the definition of katal.
1 katal = 1 mol/s
Therefore, the total activity of enzyme in mol/s is also 20.
Step 2: Calculate the total amount of protein in the tube
To calculate the total amount of protein in the tube, we multiply the protein concentration by the volume of the enzyme solution.
Total amount of protein = Protein concentration x Enzyme solution volume
= 20 mg/ml x 20 ml
= 400 mg
Step 3: Convert the total amount of protein to grams
Since the specific enzyme activity is usually expressed in mol/s per gram of protein, we need to convert the total amount of protein to grams.
Total amount of protein in grams = Total amount of protein in mg / 1000
= 400 mg / 1000
= 0.4 g
Step 4: Calculate the specific enzyme activity
Finally, we can calculate the specific enzyme activity by dividing the total activity of enzyme by the total amount of protein.
Specific enzyme activity = Total activity of enzyme / Total amount of protein
= 20 mol/s / 0.4 g
= 50 mol/s/g
= 0.05 mol/s/mg (after converting grams to milligrams)
Therefore, the specific enzyme activity is 0.05 mol/s/mg.
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A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer?
Question Description
A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer?.
A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer?.
Solutions for A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
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A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer?, a detailed solution for A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer? has been provided alongside types of A tube contained 20 ml of enzyme solution and the total activity of enzyme was observed as 20 katal. The estimation of protein concentration showed that there was 20 mg ml protein present in the tube. The specific enzyme activity will be (mol s-1mg-1). [Answer upto two place of decimal]Correct answer is '0.05'. Can you explain this answer? theory, EduRev gives you an
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