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January 1st 1992 was a Wednesday. what day of the week was January 1, 1993?
  • a)
    Friday
  • b)
    Saturday
  • c)
    Thursday
  • d)
    Monday
Correct answer is option 'A'. Can you explain this answer?

Preeti Khanna answered
1992 being a leap year it had two odd days show the first day of the year 1993 was today beyond so Wednesday i.e it was Friday.

Today is Monday. After 61 days, it will be:
  • a)
    Wednesday
  • b)
    Saturday
  • c)
    Tuesday
  • d)
    Thursday
Correct answer is option 'B'. Can you explain this answer?

Arshiya Patel answered
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
∴ After 61 days, it will be Saturday.

What was the day of the week on 17th June, 1998?
  • a)
    Monday
  • b)
    Tuesday
  • c)
    Wednesday
  • d)
    Thursday
Correct answer is option 'C'. Can you explain this answer?

Simran Sarkar answered
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = (5 x 3) ≡ 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan.         Feb.       March       April         May         June
(31     +     28     +     31     +     30     +     31     +     17) = 168 days

Therefore 168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.

What day of the week will 22 Apr 2222 be?
  • a)
    Monday
  • b)
    Tuesday
  • c)
    Wednesday
  • d)
    Thursday
Correct answer is option 'A'. Can you explain this answer?

Aarav Sharma answered
Analysis:
To determine the day of the week for a given date, we can use the concept of the Gregorian calendar, which is the most widely used calendar system today. The Gregorian calendar repeats every 400 years, and each year has either 365 or 366 days.

Step 1: Leap Year Calculation
To determine if a year is a leap year, we need to check if it is divisible by 4 but not divisible by 100, unless it is also divisible by 400.
- In this case, the year is 2222, which is not divisible by 4, so it is not a leap year.

Step 2: Number of Days Calculation
To calculate the number of days between a given date and a reference date, we need to consider the number of days in each year, month, and the additional days for leap years.
- We will use the reference date as 1st January 1900, which was a Monday.

Number of years: We need to calculate the number of years between the reference year and the given year, excluding the given year.
- Number of years = 2222 - 1900 - 1 = 322

Number of leap years: We need to calculate the number of leap years between the reference year and the given year, excluding the given year.
- Number of leap years = (322 / 4) - (322 / 100) + (322 / 400) = 80 - 3 + 0 = 77

Number of non-leap years: We need to calculate the number of non-leap years between the reference year and the given year, excluding the given year.
- Number of non-leap years = 322 - 77 = 245

Number of days in years: We need to calculate the total number of days in the years between the reference year and the given year.
- Number of days in years = (245 * 365) + (77 * 366) = 89525 + 28142 = 117667

Number of days in months: We need to calculate the total number of days in the months of the given year.
- Number of days in months = 31 (January) + 28 (February) + 31 (March) + 22 (April) = 112

Total number of days: We need to calculate the total number of days between the reference date and the given date.
- Total number of days = Number of days in years + Number of days in months = 117667 + 112 = 117779

Step 3: Determining the Day
To determine the day of the week, we can divide the total number of days by 7 and find the remainder.
- Total number of days = 117779
- 117779 divided by 7 = 16825 remainder 4

Conclusion:
Since the reference day was Monday (day 0) and the remainder is 4, we can conclude that 22 Apr 2222 will be a Monday.

What will be the day of the week 15th August, 2010?
  • a)
    Sunday
  • b)
    Monday
  • c)
    Tuesday
  • d)
    Friday
Correct answer is option 'A'. Can you explain this answer?

Sagar Sharma answered
Understanding the Day of the Week Calculation
To determine the day of the week for a specific date, we can use a method called Zeller’s Congruence or simply count the days. Here, we will use a straightforward counting method.
Step-by-Step Calculation
1. Identify the Date:
- Year: 2010
- Month: August (8th Month)
- Day: 15
2. Key Reference Dates:
- We know that January 1, 2000, was a Saturday.
3. Calculate the Days from 2000 to 2010:
- 2000 to 2009: 9 years, including 2 leap years (2000, 2004, 2008).
- Total days = (9 years * 365 days) + (2 leap days) = 3287 days.
4. Days in 2010 until August 15:
- January (31) + February (28) + March (31) + April (30) + May (31) + June (30) + July (31) + August (15) = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31 + 15 = 31 + 28 + 31 + 30 + 31 + 30 + 31

What was the day of the week on 28th May, 2006?
  • a)
    Thursday
  • b)
    Friday
  • c)
    Saturday
  • d)
    Sunday
Correct answer is option 'D'. Can you explain this answer?

Simran Sarkar answered
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) ≡ 6 odd days

Jan.         Feb.       March       April         May
(31     +     28     +     31     +     30     +     28 ) = 148 days

∴ 148 days = (21 weeks + 1 day) ≡ 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 ≡ 0 odd day.
Given day is Sunday.

The calendar for the year 2007 will be the same for the year:
  • a)
    2014
  • b)
    2016
  • c)
    2017
  • d)
    2018
Correct answer is option 'D'. Can you explain this answer?

Aarav Sharma answered
Explanation:

The calendar for any year depends on the number of days in that year and the days of the week on which each year begins. The year 2007 had 365 days starting on Monday.

To determine which year will have the same calendar as 2007, we need to look for a year that also has 365 days and starts on the same day of the week (Monday).

Using a calendar or a simple calculation, we can determine that the year 2018 also has 365 days and starts on a Monday. Therefore, the calendar for the year 2007 will be the same for the year 2018.

In summary, the answer is option D (2018) because it has the same number of days as 2007 and starts on the same day of the week.

HTML Representation:

Explanation:


  • The calendar for any year depends on the number of days in that year and the days of the week on which each year begins.

  • The year 2007 had 365 days starting on Monday.

  • To determine which year will have the same calendar as 2007, we need to look for a year that also has 365 days and starts on the same day of the week (Monday).

  • Using a calendar or a simple calculation, we can determine that the year 2018 also has 365 days and starts on a Monday.

  • Therefore, the calendar for the year 2007 will be the same for the year 2018.

  • In summary, the answer is option D (2018) because it has the same number of days as 2007 and starts on the same day of the week.

January 1, 2008 is Tuesday. What day of the week lies on Jan 1, 2009?
  • a)
    Monday
  • b)
    Wednesday
  • c)
    Thursday
  • d)
    Sunday
Correct answer is option 'C'. Can you explain this answer?

Simran Sarkar answered
The year 2008 is a leap year. So, it has 2 odd days.
1st day of the year 2008 is Tuesday (Given)
So, 1st day of the year 2009 is 2 days beyond Tuesday.
Hence, it will be Thursday.

On what dates of April, 2001 did Wednesday fall?
  • a)
    1st, 8th, 15th, 22nd, 29th
  • b)
     
    2nd, 9th, 16th, 23rd, 30th
  • c)
    3rd, 10th, 17th, 24th
  • d)
     
    4th, 11th, 18th, 25th
Correct answer is option 'D'. Can you explain this answer?

Simran Sarkar answered
We shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April
(31 + 28 + 31 + 1)     = 91 days ≡ 0 odd days.
Total number of odd days = (0 + 0 + 0) = 0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.

On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
  • a)
    Sunday
  • b)
    Thursday
  • c)
    Tuesday
  • d)
    Friday
Correct answer is option 'D'. Can you explain this answer?

Simran Sarkar answered
The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday.
∴ 8th Dec, 2006 is Friday.

If the first day of a year (other than leap year) was Friday, then which was the last day of that year?
  • a)
    Wednesday
  • b)
    Thursday
  • c)
    Friday
  • d)
    Saturday
Correct answer is option 'C'. Can you explain this answer?

Asha Kumar answered
Given that first day of a normal year was Friday
Odd days of the mentioned year = 1 (Since it is an ordinary year)
Hence First day of the next year = (Friday + 1 Odd day) = Saturday
Therefore, last day of the mentioned year = Friday

If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?
  • a)
    Sunday
  • b)
    Saturday
  • c)
    Tuesday
  • d)
    Wednesday
Correct answer is option 'A'. Can you explain this answer?

Asha Kumar answered
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
∴ The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
∴ 6th March, 2004 is Sunday (1 day before to 6th March, 2005).

On 8th Feb, 2005 it was Tuesday. What was the day of the week on 8th Feb, 2004?
  • a)
    Tuesday
  • b)
    Monday
  • c)
    Sunday
  • d)
    Wednesday
Correct answer is option 'C'. Can you explain this answer?

Aarav Sharma answered
Explanation:
To determine the day of the week on February 8th, 2004, we can use a few methods, such as the Zeller's Congruence formula or counting the number of days between the two dates. Let's use the latter method.

Method:
1. Determine the number of days between February 8th, 2004, and February 8th, 2005.
- There are 365 days in a non-leap year.
- So, the number of days between the two dates is 365.

2. Divide the number of days by 7 to find the remainder.
- 365 divided by 7 equals 52 remainder 1.
- This means that February 8th, 2004, is 1 day after a multiple of 7.

3. Use the day of the week for February 8th, 2005, as a reference point.
- Given that February 8th, 2005, is Tuesday, we can count 1 day back to find the day for February 8th, 2004.
- Tuesday minus 1 day equals Monday.

Therefore, the day of the week on February 8th, 2004, was Monday.

January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?
  • a)
    Monday
  • b)
    Tuesday
  • c)
    Wednesday
  • d)
    Sunday
Correct answer is option 'B'. Can you explain this answer?

The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2007 was Monday.
1st day of the year 2008 will be 1 day beyond Monday.
Hence, it will be Tuesday.

The last day of a century cannot be
  • a)
    Monday
  • b)
    Wednesday
  • c)
    Tuesday
  • d)
    Friday
Correct answer is option 'C'. Can you explain this answer?

Arshiya Patel answered
100 years contain 5 odd days.
∴ Last day of 1st century is Friday.
200 years contain (5 x 2) ≡ 3 odd days.
∴ Last day of 2nd century is Wednesday.
300 years contain (5 x 3) = 15 ≡ 1 odd day.
∴ Last day of 3rd century is Monday.
400 years contain 0 odd day.
∴ Last day of 4th century is Sunday.
This cycle is repeated.
∴ Last day of a century cannot be Tuesday or Thursday or Saturday.

It was Thursday on 12th January 2006. What day of the week it will be on January 12th 2007 ?
  • a)
    Wednesday
  • b)
    Thursday
  • c)
    Friday
  • d)
    Saturday
Correct answer is option 'C'. Can you explain this answer?

Arshiya Patel answered
There is exactly 1 year, (365 days) between two dates.
2006 is an ordinary year. It has one odd day.
The day of the week on January 12th 2007 is one day beyond Thursday ⇒ Friday

Today is Monday. After 61 days, it will be:
  • a)
    Tuesday
  • b)
    Wednesday
  • c)
    Thursday
  • d)
    Saturday
Correct answer is option 'D'. Can you explain this answer?

Preeti Khanna answered
Each day of the week is repeated after 7 days. So, after 63 days, it will be on Monday. After 61 days, it will be on Saturday.

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