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All questions of d – and f – Block Elements for JEE Exam
Can you explain the answer of this question below:Which one of the following is a diamagnetic ion?- A:CO2+
- B:Cu2+
- C:Mn2+
- D:Sc3+
The answer is d.
Which one of the following is a diamagnetic ion?
A:
CO2+
B:
Cu2+
C:
Mn2+
D:
Sc3+
|
Learners Habitat answered |
Co+2 = [Ar] 3d7
Cu2+ = [Ar] 3d9
Mn+2 = [Ar] 3d5
Sc+3 = [Ar]
We can see that only Sc+3 has no unpaired electron, so it is a diamagnetic ion.
Cu2+ = [Ar] 3d9
Mn+2 = [Ar] 3d5
Sc+3 = [Ar]
We can see that only Sc+3 has no unpaired electron, so it is a diamagnetic ion.
Which ion will show more paramagnetic behaviour ?- a)Cu+
- b)Fe2+
- c)Ag+
- d)Fe3+
Correct answer is option 'D'. Can you explain this answer?
Which ion will show more paramagnetic behaviour ?
a)
Cu+
b)
Fe2+
c)
Ag+
d)
Fe3+
|
Lavanya Menon answered |
Since the configuration of Fe3+ ion is (argon ) 3d5,which contains maximum number of unpaired electrons, hence more will be paramagnetic behavior.
Which form of silver is colourless?- a)Ag2+
- b)Ag
- c)Ag3+
- d)Ag+
Correct answer is option 'D'. Can you explain this answer?
Which form of silver is colourless?
a)
Ag2+
b)
Ag
c)
Ag3+
d)
Ag+
|
Om Desai answered |
ilver in the form of Ag+ is colourless. For transition metal ions to exhibit color, their metal ions must have incompletely filled (n-1)d orbitals.
Ag+ =4d10,5s0
Ag+ has completely filled d orbitals hence is colourless.
Which among the following is colourless?- a)Sc2+
- b)Zn2+
- c)Ti3+
- d)V3+
Correct answer is option 'B'. Can you explain this answer?
Which among the following is colourless?
a)
Sc2+
b)
Zn2+
c)
Ti3+
d)
V3+
|
Krishna Iyer answered |
Zn2+ has completely filled d-orbitals and there are no vacant d-orbitals for the transition of electrons, hence it is colourless.
The first ionization energy of the d-block elements are?- a)Lesser than p-block elements
- b)Between s and p-block elements
- c)Lesser than s-block elements
- d)Higher than p-block elements
Correct answer is option 'B'. Can you explain this answer?
The first ionization energy of the d-block elements are?
a)
Lesser than p-block elements
b)
Between s and p-block elements
c)
Lesser than s-block elements
d)
Higher than p-block elements
|
Rahul Bansal answered |
The first ionization energy of the d-block elements are between s and p-block elements. Thus they are more electropositive than p-block elements and less electropositive than s-block elements.
Which of the following group of elements are not regarded as transition elements?- a)Sc,Y,La
- b)Cu, Ag, Au
- c)Zn, Cd, Hg
- d)Cr ,Mo,W
Correct answer is option 'C'. Can you explain this answer?
Which of the following group of elements are not regarded as transition elements?
a)
Sc,Y,La
b)
Cu, Ag, Au
c)
Zn, Cd, Hg
d)
Cr ,Mo,W
|
Neha Sharma answered |
Zn, Cd & Hg because the d-orbital of these elements are completely filled. So, they don't show the characteristics of transition elements (i.e. the d-orbital of transition elements is incomplete.
The inner transition elements are the elements in which the added electrons go to:- a)(n-1)d-orbitals
- b)(n-1)d-orbitals and (n-1)f-orbitals
- c)(n-1)d-orbitals and ns orbitals
- d)(n-2)f-orbitals
Correct answer is option 'D'. Can you explain this answer?
The inner transition elements are the elements in which the added electrons go to:
a)
(n-1)d-orbitals
b)
(n-1)d-orbitals and (n-1)f-orbitals
c)
(n-1)d-orbitals and ns orbitals
d)
(n-2)f-orbitals
|
Rohit Shah answered |
Lanthanides and actinides are called inner transition elements because they are a group of elements that are shown as the bottom two rows of the periodic table. ... Lanthanides and actinides belong to the f-block elements, which means that they have filled up their f-orbitals with electrons.
Melting point of d block elements across a period:- a)Increases from left to right
- b)Deceases from left to right
- c)Increases to a maximum at d5 and then decreases with increase of atomic number.
- d)Does not change on moving from left to right.
Correct answer is option 'C'. Can you explain this answer?
Melting point of d block elements across a period:
a)
Increases from left to right
b)
Deceases from left to right
c)
Increases to a maximum at d5 and then decreases with increase of atomic number.
d)
Does not change on moving from left to right.
|
Jayant Mishra answered |
The melting and boiling points first increase, reaches maximum and then steadily decrease across any transition series. ... The low melting points of Zn, Cd, and Hg are due to the absence of unpaired d-electrons in their atoms and thus low metallic bonding.
The second series of transition element starts with:- a)Scandium
- b)Rhodium
- c)Ytterium
- d)Actinium
Correct answer is option 'C'. Can you explain this answer?
The second series of transition element starts with:
a)
Scandium
b)
Rhodium
c)
Ytterium
d)
Actinium
|
Pooja Mehta answered |
The second series includes the elements yttrium (symbol Y, atomic number 39) to cadmium (symbol Cd, atomic number 48)
Which of the following is not an interstitial compound?- a)Mn4N
- b)TiC
- c)Fe3H
- d)FeCl3
Correct answer is option 'D'. Can you explain this answer?
Which of the following is not an interstitial compound?
a)
Mn4N
b)
TiC
c)
Fe3H
d)
FeCl3
|
|
Lavanya Menon answered |
The correct answer is option D
An interstitial compound is a compound that is formed when an atom with a small enough radius sits a hole in a metal lattice
They are usually transitional elements
Eg: Tic, Mn4N, Fe3H, TiH2 etc.
Main Characteristics:-
· High melting points than metals
· They are much harder
· They become chemically inert
· They become less malleable
So, the answer is (a), (b), (c) .
An interstitial compound is a compound that is formed when an atom with a small enough radius sits a hole in a metal lattice
They are usually transitional elements
Eg: Tic, Mn4N, Fe3H, TiH2 etc.
Main Characteristics:-
· High melting points than metals
· They are much harder
· They become chemically inert
· They become less malleable
So, the answer is (a), (b), (c) .
In neutral solution, potassium permanganate forms:- a)Manganese dioxide
- b)Manganous sulphate
- c)Pyrolusite
- d)Potassium manganite
Correct answer is option 'A'. Can you explain this answer?
In neutral solution, potassium permanganate forms:
a)
Manganese dioxide
b)
Manganous sulphate
c)
Pyrolusite
d)
Potassium manganite
|
Prakash answered |
KMno₄ is an oxidising agent (here Mn⁺⁷)in nuetral medium there is a change of 3 in it's oxidation state M⁺⁷-------Mn⁺⁴
The elements which lie between s and p block elements in the long form periodic table are called as:- a)Actinides
- b)d-block elements
- c)Lanthanides
- d)Electropositive elements
Correct answer is option 'B'. Can you explain this answer?
The elements which lie between s and p block elements in the long form periodic table are called as:
a)
Actinides
b)
d-block elements
c)
Lanthanides
d)
Electropositive elements
|
|
Harsh Desai answered |
D-block elements
The long form periodic table consists of four blocks: s, p, d, and f. The s and p blocks are located on the left and right sides of the periodic table, respectively. The d-block elements are located in the middle of the periodic table, between the s and p blocks. These elements are also known as transition elements.
Explanation:
The d-block elements are characterized by the presence of partially filled d-orbitals in their valence shells. These elements are often referred to as transition elements because they exhibit a transition between the highly reactive s-block elements and the relatively inert p-block elements. The d-block elements are known for their unique chemical and physical properties, such as their ability to form complex ions and their high melting and boiling points.
Examples of d-block elements include titanium, iron, copper, and zinc. These elements are widely used in industry and technology due to their unique properties, such as their strength, durability, and conductivity.
In summary, the elements which lie between s and p block elements in the long form periodic table are called d-block elements or transition elements. These elements exhibit unique chemical and physical properties and are widely used in industry and technology.
The long form periodic table consists of four blocks: s, p, d, and f. The s and p blocks are located on the left and right sides of the periodic table, respectively. The d-block elements are located in the middle of the periodic table, between the s and p blocks. These elements are also known as transition elements.
Explanation:
The d-block elements are characterized by the presence of partially filled d-orbitals in their valence shells. These elements are often referred to as transition elements because they exhibit a transition between the highly reactive s-block elements and the relatively inert p-block elements. The d-block elements are known for their unique chemical and physical properties, such as their ability to form complex ions and their high melting and boiling points.
Examples of d-block elements include titanium, iron, copper, and zinc. These elements are widely used in industry and technology due to their unique properties, such as their strength, durability, and conductivity.
In summary, the elements which lie between s and p block elements in the long form periodic table are called d-block elements or transition elements. These elements exhibit unique chemical and physical properties and are widely used in industry and technology.
Transition metals with highest melting point is- a)Cr
- b)W
- c)Hg
- d)Sc
Correct answer is option 'B'. Can you explain this answer?
Transition metals with highest melting point is
a)
Cr
b)
W
c)
Hg
d)
Sc
|
Pragati Choudhury answered |
W belongs to 5d series and also it have lot of unpaired electrons thus it forms strong metallic bonding.
Brass is an alloy of:- a)Copper and molybdenum
- b)Copper and zinc
- c)Copper and tungsten
- d)Copper and tin
Correct answer is option 'B'. Can you explain this answer?
Brass is an alloy of:
a)
Copper and molybdenum
b)
Copper and zinc
c)
Copper and tungsten
d)
Copper and tin
|
Mrprince 007 answered |
Brass is an alloy of copper and zinc
Mohr’s salt is a- a)Acidic salt
- b)Double salt
- c)Basic Acidic salt
- d)Normal salt
Correct answer is option 'B'. Can you explain this answer?
Mohr’s salt is a
a)
Acidic salt
b)
Double salt
c)
Basic Acidic salt
d)
Normal salt
|
Amar Pillai answered |
Mohr salt is an example of double salt. Mohr Salt is
FeSO4 . (NH4)2 SO4.6H2O
Which one of the following is a diamagnetic ion?- a)CO2+
- b)Cu2+
- c)Mn2+
- d)Sc3+
Correct answer is option 'D'. Can you explain this answer?
Which one of the following is a diamagnetic ion?
a)
CO2+
b)
Cu2+
c)
Mn2+
d)
Sc3+
|
|
Ameya Pillai answered |
Co2+ (Z = 27) : [Ar]183d7 (3 unpaired electrons)
Cu2+ (Z = 29) : [Ar]183d9 (1 unpaired electrons)
Mn2+ (Z = 25): [Ar]183d5 (5 unpaired electrons)
Sc3+ (Z = 21): [Ar]183d0 (No unpaired electron)
Sc3+ with no unpaired electron will be diamagnetic
Cu2+ (Z = 29) : [Ar]183d9 (1 unpaired electrons)
Mn2+ (Z = 25): [Ar]183d5 (5 unpaired electrons)
Sc3+ (Z = 21): [Ar]183d0 (No unpaired electron)
Sc3+ with no unpaired electron will be diamagnetic
Ag+ ion is isoelectronic with- a)Zn2+
- b)Cd2+
- c)Pd2+
- d)Cu2+
Correct answer is option 'B'. Can you explain this answer?
Ag+ ion is isoelectronic with
a)
Zn2+
b)
Cd2+
c)
Pd2+
d)
Cu2+
|
Malavika Shah answered |
Ag+ is isoelectronic with Cd2+
When an alkali is added to an orange red solution of dichromate, it forms:- a)Ferrochrome
- b)Chromyl chloride
- c)Chromate
- d)Chromium trioxide
Correct answer is option 'C'. Can you explain this answer?
When an alkali is added to an orange red solution of dichromate, it forms:
a)
Ferrochrome
b)
Chromyl chloride
c)
Chromate
d)
Chromium trioxide
|
Knowledge Hub answered |
The correct answer is C
When an alkali is added to an orange red solution of dichromate it forms chromate.
For example:
K2Cr2O7 + 2KOH ➡ 2K2CrO4 + H2O
When an alkali is added to an orange red solution of dichromate it forms chromate.
For example:
K2Cr2O7 + 2KOH ➡ 2K2CrO4 + H2O
Transition metals and their compounds have paramagnetic properties due to the presence of unpaired electrons in (n - 1)d-orbitals. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of the unpaired electrons (n). It is given as
Magnetic moment = 
Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. This is also due to the presence of unpaired electrons in (n - 1) d-orbitals, d-orbitals splitting and d-d transition of electrons absorbing suitable visible light.Q. Which pair of ions are expected to be diamagnetic?- a)Cu+ and Cu2+
- b)Ag+ and Au+
- c)Ag+ and Au3+
- d)Zn2+ and Cu2+
Correct answer is option 'B'. Can you explain this answer?
Transition metals and their compounds have paramagnetic properties due to the presence of unpaired electrons in (n - 1)d-orbitals. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of the unpaired electrons (n). It is given as
Magnetic moment =
Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. This is also due to the presence of unpaired electrons in (n - 1) d-orbitals, d-orbitals splitting and d-d transition of electrons absorbing suitable visible light.
Magnetic moment =
Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. This is also due to the presence of unpaired electrons in (n - 1) d-orbitals, d-orbitals splitting and d-d transition of electrons absorbing suitable visible light.
Q.
Which pair of ions are expected to be diamagnetic?
a)
Cu+ and Cu2+
b)
Ag+ and Au+
c)
Ag+ and Au3+
d)
Zn2+ and Cu2+
|
Ishani Yadav answered |
Ag+ (d10) and Au+(d10) are diamagnetic due to absence of unpaired number of electrons.
For the four successive transition elements (Cr, Mn, Fe and Co), the stability of + 2 oxidation state will be there in which of the following order?- a)Mn > Cr > Fe > Co
- b)Fe > Mn > Co > Cr
- c)Co > Mn > Fe > Cr
- d)Cr > Mn > Co > Fe
Correct answer is option 'A'. Can you explain this answer?
For the four successive transition elements (Cr, Mn, Fe and Co), the stability of + 2 oxidation state will be there in which of the following order?
a)
Mn > Cr > Fe > Co
b)
Fe > Mn > Co > Cr
c)
Co > Mn > Fe > Cr
d)
Cr > Mn > Co > Fe
|
Mohit Rajpoot answered |
Mn2+ (d5) > Cr2+ (d4) > Fe2+ (d6) > Co2+ (d7) Mn2+ is more stable due to half-filled configuration, i . e . d5.
Which of the following is not the condition for the complex formation?- a)High ionic charge density on metal ion.
- b)Smaller size of transition metal ion.
- c)Absence of vacant d-orbitals.
- d)Availability of vacant d-orbitals.
Correct answer is option 'C'. Can you explain this answer?
Which of the following is not the condition for the complex formation?
a)
High ionic charge density on metal ion.
b)
Smaller size of transition metal ion.
c)
Absence of vacant d-orbitals.
d)
Availability of vacant d-orbitals.
|
|
Krishna Iyer answered |
The correct answer is Option C
Only d orbitals accept the lone pair of electrons during complex formation. Their absence means that the atom will not be able to accept the lone pair of electrons and the complex will not be formed.
Only d orbitals accept the lone pair of electrons during complex formation. Their absence means that the atom will not be able to accept the lone pair of electrons and the complex will not be formed.
Oxidation state of chromium in CrO5 is +x. Here, value of x is
Correct answer is '6'. Can you explain this answer?
Oxidation state of chromium in CrO5 is +x. Here, value of x is
|
Arpita Nair answered |
4 oxygen atoms attached by peroxide linkage. So, their oxidation states are taken as -1.
Now, let the oxidation state of Cr be x.
then x + 4 x (-1) - 2 = 0
x = 6
Now, let the oxidation state of Cr be x.
then x + 4 x (-1) - 2 = 0
x = 6
Comprehension TypeDirection (Q, Nos. 16 and 17) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageTransition metals and their compounds have paramagnetic properties due to the presence of unpaired electrons in (n - 1)d-orbitals. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of the unpaired electrons (n). It is given as
Magnetic moment =
Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. This is also due to the presence of unpaired electrons in (n - 1) d-orbitals, d-orbitals splitting and d-d transition of electrons absorbing suitable visible light.Q. Which of the following exhibit colour due to charge transfer phenomenon, but not due to d-d transition?- a)
- b)
- c)
- d)All of these
Correct answer is option 'D'. Can you explain this answer?
Comprehension Type
Direction (Q, Nos. 16 and 17) This section contains a paragraph, describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).
Passage
Transition metals and their compounds have paramagnetic properties due to the presence of unpaired electrons in (n - 1)d-orbitals. The paramagnetic behaviour is expressed in terms of magnetic moment which is because of the spin of the unpaired electrons (n). It is given as
Magnetic moment =
Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. This is also due to the presence of unpaired electrons in (n - 1) d-orbitals, d-orbitals splitting and d-d transition of electrons absorbing suitable visible light.
Magnetic moment =
Majority of transition metal compounds are coloured both in solid state as well as in aqueous solution. This is also due to the presence of unpaired electrons in (n - 1) d-orbitals, d-orbitals splitting and d-d transition of electrons absorbing suitable visible light.
Q.
Which of the following exhibit colour due to charge transfer phenomenon, but not due to d-d transition?
a)
b)
c)
d)
All of these
|
Srestha Choudhury answered |
In transition metal complexes, a change in electron distribution between the metal and a ligand give rise to charge transfer bonds.
Here, charge transfer may occur from the ligand molecular orbitals to the empty or partially filled metal d-orbitals.
Here, charge transfer may occur from the ligand molecular orbitals to the empty or partially filled metal d-orbitals.
In which of the following pairs both the ions are coloured in aqueous solution? (Atomic number, Sc = 21, Ti = 22, Ni = 28, Cu = 29, Co = 27)- a)Sc3+ and Ti3+
- b)Sc3+ and Co2+
- c)Ni2+ and Cu+
- d)Ni2+ and Ti3+
Correct answer is option 'D'. Can you explain this answer?
In which of the following pairs both the ions are coloured in aqueous solution? (Atomic number, Sc = 21, Ti = 22, Ni = 28, Cu = 29, Co = 27)
a)
Sc3+ and Ti3+
b)
Sc3+ and Co2+
c)
Ni2+ and Cu+
d)
Ni2+ and Ti3+
|
Gauri Sharma answered |
Ni2+ and Ti3+ ions are coloured in aqueous solution because they contain unpaired electrons.
Ions having same colour in aqueous solution are- a)Cu2+ and Fe2+
- b)Ni2+ and Fe2+
- c)Fe3+ and Cr3+
- d)V4+ and Cr2+
Correct answer is option 'B,D'. Can you explain this answer?
Ions having same colour in aqueous solution are
a)
Cu2+ and Fe2+
b)
Ni2+ and Fe2+
c)
Fe3+ and Cr3+
d)
V4+ and Cr2+
|
Sinjini Tiwari answered |
Ni2+ and Fe2+ have green colour and V4+ and Cr2+ have blue colour.
Which of the following metals have only one oxidation state?- a)Co
- b)Sc
- c)Fe
- d)Al
Correct answer is option 'B,D'. Can you explain this answer?
Which of the following metals have only one oxidation state?
a)
Co
b)
Sc
c)
Fe
d)
Al
|
Avantika Dasgupta answered |
Sc,Al has only one oxidation state i.e. +3.
Co,Fe has various oxidation states; most common are +2 and +3.
Number of compounds in which metal has zero oxidation stateWO3,Ni(CO)4, MoO3, Fe(CO)5, Cr(CO)6, [Pt(NH3)2CI2], Co2(CO)8 and Mn2(CO)10
Correct answer is '5'. Can you explain this answer?
Number of compounds in which metal has zero oxidation state
WO3,Ni(CO)4, MoO3, Fe(CO)5, Cr(CO)6, [Pt(NH3)2CI2], Co2(CO)8 and Mn2(CO)10
|
|
Gauri Sharma answered |
In metal carbonyls, metal oxidation state is zero.
Maximum magnetic moment is shown by- a)d6
- b)d8
- c)d5
- d)d7
Correct answer is option 'C'. Can you explain this answer?
Maximum magnetic moment is shown by
a)
d6
b)
d8
c)
d5
d)
d7
|
Dishani Kulkarni answered |
Magnetic moment is maximum for the element having maximum unpaired electrons.
Transition metals with lowest melting point is- a)Zn
- b)Cr
- c)Cd
- d)Hg
Correct answer is option 'A'. Can you explain this answer?
Transition metals with lowest melting point is
a)
Zn
b)
Cr
c)
Cd
d)
Hg
|
|
Abhijeet Sharma answered |
Zinc (Zn) has the lowest melting point in 3d series because of the absence of d-electrons.
Which is called chromic acid?- a)Cr2O3
- b)Cr3O4
- c)CrO
- d)H2CrO4
Correct answer is option 'D'. Can you explain this answer?
Which is called chromic acid?
a)
Cr2O3
b)
Cr3O4
c)
CrO
d)
H2CrO4
|
|
Shraddha Dey answered |
Chromic Acid is a naturally occurring oxide with a formula H2CrO4.
Among the following series of transition metal ions, the one where all metal ions have 3d2 electronic configuration is (Atomic number, Ti = 22, V = 23, Cr = 24, Mn = 25) [AIEEE 2004]- a)Ti3+, V2+, Cr3+, Mn4+
- b)Ti+, V4+, Cr6+, Mn7+
- c)Ti4+, V3+, Cr2+, Mn3+
- d)Ti2+, V3+, Cr4+, Mn5+
Correct answer is option 'D'. Can you explain this answer?
Among the following series of transition metal ions, the one where all metal ions have 3d2 electronic configuration is (Atomic number, Ti = 22, V = 23, Cr = 24, Mn = 25)
[AIEEE 2004]
a)
Ti3+, V2+, Cr3+, Mn4+
b)
Ti+, V4+, Cr6+, Mn7+
c)
Ti4+, V3+, Cr2+, Mn3+
d)
Ti2+, V3+, Cr4+, Mn5+
|
Samridhi Bajaj answered |
Ti2+,V3+,Cr4+ and Mn5+ show 1s22s22p63s23p64s03d2 electronic configuration.
One Integer Value Correct TypeDirection (Q. Nos. 21-24) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).Q. Number of alloys that contain nickel among the following solder, gun metal, German silver, nichrome, monel metal, constanton, bell metal, duralumin, type metal, invar, alnico.
Correct answer is '6'. Can you explain this answer?
One Integer Value Correct Type
Direction (Q. Nos. 21-24) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).
Q.
Number of alloys that contain nickel among the following solder, gun metal, German silver, nichrome, monel metal, constanton, bell metal, duralumin, type metal, invar, alnico.
|
|
Nishtha Bose answered |
German silver (Cu + Zn + Ni), nichrome (Ni 60% + Cr 20% + Fe), monel metal (Cu + Ni 66%), constanton (Cu + Ni), invar (Fe + Ni), alnico (Al + Ni + Co + Cu).
One or More than One Options Correct TypeDirection (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.Q. Which one of the following arrangements represent the correct order of the property stated against it?- a)V2+ < Cr2+ < Mn2+ < Fe2+ : paramagnetic behaviour
- b)Ni2+ < Co2+ < Fe2+ < Mn2+: ionic size
- c)Co3+ < Fe3+ < Cr3+ < Sc3+ : stability in aqueous solution
- d)Sc < Ti < Cr < Mn : number of oxidation state
Correct answer is option 'B,C,D'. Can you explain this answer?
One or More than One Options Correct Type
Direction (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.
Q.
Which one of the following arrangements represent the correct order of the property stated against it?
a)
V2+ < Cr2+ < Mn2+ < Fe2+ : paramagnetic behaviour
b)
Ni2+ < Co2+ < Fe2+ < Mn2+: ionic size
c)
Co3+ < Fe3+ < Cr3+ < Sc3+ : stability in aqueous solution
d)
Sc < Ti < Cr < Mn : number of oxidation state
|
Arshiya Choudhury answered |
Red hot steel rods on suddenly immersing in water become- a)Fibrous
- b)Hard and brittle
- c)Soft and malleable
- d)Tough and ductile
Correct answer is option 'B'. Can you explain this answer?
Red hot steel rods on suddenly immersing in water become
a)
Fibrous
b)
Hard and brittle
c)
Soft and malleable
d)
Tough and ductile
|
Arnab Chavan answered |
Red hot steel rods on suddenly immersing in water become hard and brittle.
Which of the following is not a condition for complex formation?- a)Small atomic size
- b)High nuclear charge
- c)Variable oxidation states
- d)Availability of vacant d orbitals
Correct answer is option 'C'. Can you explain this answer?
Which of the following is not a condition for complex formation?
a)
Small atomic size
b)
High nuclear charge
c)
Variable oxidation states
d)
Availability of vacant d orbitals
|
Tarun Kaushik answered |
Tendency of an element to form complexes does not depend on whether the element shows variable O.S. or not
Which of the following pairs of ions have same paramagnetic moment?- a)Cu2+, Ti3+
- b)Ti3+, Ni2+
- c)Ti4+, Cu2+
- d)Mn2+, Cu2+
Correct answer is option 'A'. Can you explain this answer?
Which of the following pairs of ions have same paramagnetic moment?
a)
Cu2+, Ti3+
b)
Ti3+, Ni2+
c)
Ti4+, Cu2+
d)
Mn2+, Cu2+
|
Tejas Desai answered |
Cu2+, Ti3+ will have same unpaired electrons and hence same paramagnetic moment.
Which of the following is not an alloy?- a)Bronze
- b)Brass
- c)Gold
- d)Steel
Correct answer is option 'C'. Can you explain this answer?
Which of the following is not an alloy?
a)
Bronze
b)
Brass
c)
Gold
d)
Steel
|
|
Neha Sharma answered |
The short answer is no, gold by itself is not an alloy, gold is a pure element. However, due to pure gold’s (24K) softness, it is often alloyed with other base metals to alter its hardness, along with other properties, so that it may be used to make certain products. This is done when making gold jewelry.
Ferrous sulphate on heating gives- a)SO2 and SO3
- b)SO2 and O2
- c)SO2
- d)SO3
Correct answer is option 'A'. Can you explain this answer?
Ferrous sulphate on heating gives
a)
SO2 and SO3
b)
SO2 and O2
c)
SO2
d)
SO3
|
M. Vishnu answered |
On heating, ferrous sulphate crystals lose water and anhydrous ferrous sulphate (FeSO4) is formed. So their colour changes from light green to white. On furtherheating, anhydrous ferrous sulphate decomposes to form ferric oxide (Fe2O3), sulphur dioxide (SO2) and sulphur trioxide (SO3).
Maximum oxidation state is shown by- a)Os
- b)Co
- c)Cr
- d)Mn
Correct answer is option 'A'. Can you explain this answer?
Maximum oxidation state is shown by
a)
Os
b)
Co
c)
Cr
d)
Mn
|
Shreya Gupta answered |
Os shows maximum oxidation state of +8.
Lucas reagent is
- a)ZnCl2 + HCl
- b)MnO2 + H2O
- c)H2SO4 + HCl
- d)NO + H2O
Correct answer is option 'A'. Can you explain this answer?
Lucas reagent is
a)
ZnCl2 + HCl
b)
MnO2 + H2O
c)
H2SO4 + HCl
d)
NO + H2O
|
|
Arshiya Choudhury answered |
Lucas Test is done to distinguish primary secondary and tertiary alcohols. Lucas reagent is ZnCl2 + HCl
+8 oxidation state is/are shown by- a)Fe
- b)Ru
- c)Os
- d)W
Correct answer is option 'B,C'. Can you explain this answer?
+8 oxidation state is/are shown by
a)
Fe
b)
Ru
c)
Os
d)
W
|
|
Nishtha Bose answered |
+8 oxidation state shown by Ru and Os.
The basic character of the transition metal monoxides follows the order (Atomic Nos., Ti = 22, V = 23, Cr = 24, Fe = 26)- a)TiO > VO > CrO > FeO
- b)VO > CrO > TiO > FeO
- c)CrO > VO > FeO > TiO
- d)TiO > FeO > VO > CrO
Correct answer is option 'A'. Can you explain this answer?
The basic character of the transition metal monoxides follows the order (Atomic Nos., Ti = 22, V = 23, Cr = 24, Fe = 26)
a)
TiO > VO > CrO > FeO
b)
VO > CrO > TiO > FeO
c)
CrO > VO > FeO > TiO
d)
TiO > FeO > VO > CrO
|
|
Tarun Kaushik answered |
The order of basic character of the transition metal monoxide is TiO > VO > CrO > FeO because basic character of oxides decreases with increase in atomic number.
The catalytic activity of transition metals and their compounds is mainly due to- a)their magnetic behaviour
- b)their ful-filled d-orbitals
- c)their ability to adopt variable oxidation states
- d)their chemical reactivity
Correct answer is option 'C'. Can you explain this answer?
The catalytic activity of transition metals and their compounds is mainly due to
a)
their magnetic behaviour
b)
their ful-filled d-orbitals
c)
their ability to adopt variable oxidation states
d)
their chemical reactivity
|
|
Nishtha Bose answered |
The variability of oxidation state, a characteristic of transition element arises due to incomplete filling of d-orbitals.
Gun metal is an alloy of- a)Cu and Al
- b)Cu and Sn
- c)Cu,Zn and Sn
- d)Cu,Zn and Ni
Correct answer is option 'C'. Can you explain this answer?
Gun metal is an alloy of
a)
Cu and Al
b)
Cu and Sn
c)
Cu,Zn and Sn
d)
Cu,Zn and Ni
|
|
Harsh Desai answered |
Understanding Gun Metal
Gun metal is a specific type of alloy known for its strength and resistance to corrosion. It is primarily used in manufacturing firearms, marine components, and various engineering applications.
Composition of Gun Metal
- Copper (Cu): The primary element in gun metal, providing strength and durability.
- Zinc (Zn): Added to improve fluidity during casting and enhance the alloy's resistance to corrosion.
- Tin (Sn): Contributes to the alloy's wear resistance and overall toughness.
Properties of Gun Metal
- Corrosion Resistance: The presence of zinc helps protect against oxidation, making gun metal suitable for marine and outdoor applications.
- Machinability: Gun metal can be easily machined, allowing for precise manufacturing of components.
- Strength: The alloy exhibits excellent tensile strength, making it ideal for high-stress applications.
Applications of Gun Metal
- Firearms: Used to manufacture components like barrels, where strength and resistance to wear are critical.
- Marine Hardware: Commonly applied in valves, pumps, and fittings due to its corrosion resistance.
- Engineering Parts: Utilized in various machinery parts that require durability and reliability.
In conclusion, gun metal is an alloy of copper, zinc, and tin (option C), prized for its advantageous properties in numerous industrial applications. Understanding its composition and characteristics can help in selecting the right materials for specific engineering needs.
Gun metal is a specific type of alloy known for its strength and resistance to corrosion. It is primarily used in manufacturing firearms, marine components, and various engineering applications.
Composition of Gun Metal
- Copper (Cu): The primary element in gun metal, providing strength and durability.
- Zinc (Zn): Added to improve fluidity during casting and enhance the alloy's resistance to corrosion.
- Tin (Sn): Contributes to the alloy's wear resistance and overall toughness.
Properties of Gun Metal
- Corrosion Resistance: The presence of zinc helps protect against oxidation, making gun metal suitable for marine and outdoor applications.
- Machinability: Gun metal can be easily machined, allowing for precise manufacturing of components.
- Strength: The alloy exhibits excellent tensile strength, making it ideal for high-stress applications.
Applications of Gun Metal
- Firearms: Used to manufacture components like barrels, where strength and resistance to wear are critical.
- Marine Hardware: Commonly applied in valves, pumps, and fittings due to its corrosion resistance.
- Engineering Parts: Utilized in various machinery parts that require durability and reliability.
In conclusion, gun metal is an alloy of copper, zinc, and tin (option C), prized for its advantageous properties in numerous industrial applications. Understanding its composition and characteristics can help in selecting the right materials for specific engineering needs.
Many copper (I) compounds are unstable in aqueous solution and undergo disproportionation as 2Cu+ → Cu + Cu2+ . This is due to- a)free energy change of reaction is positive
- b)free energy of reaction is negative
- c)second ionisation energy of Cu is higher than first ionisation energy
- d)hydration energy of Cu+ is less than Cu2+
Correct answer is option 'B'. Can you explain this answer?
Many copper (I) compounds are unstable in aqueous solution and undergo disproportionation as 2Cu+ → Cu + Cu2+ . This is due to
a)
free energy change of reaction is positive
b)
free energy of reaction is negative
c)
second ionisation energy of Cu is higher than first ionisation energy
d)
hydration energy of Cu+ is less than Cu2+
|
Anjana Sharma answered |
Cu+ is unstable in aqueous solution than Cu2+ because although 2nd I.E. of copper is large but hydration enthalpy for Cu2+ is much more negative than that for Cu+ and hence, it is more than compensates for the 2nd I.E. of copper. Therefore, many Cu+ compounds are unstable in aqueous solution and undergo disproportionation.
2Cu+ → Cu2+ + Cu
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