All questions of Problem on Ages for Computer Science Engineering (CSE) Exam
The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is- a)5:2
- b)7:3
- c)9:2
- d)13:4
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is
a)
5:2
b)
7:3
c)
9:2
d)
13:4
e)
None of these
 | Future Foundation Institute answered |
The correct option ia B.
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20
∴ Required ratio
= (3x + 10) : (x + 10)
= 70 : 30
= 7 : 3
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20
∴ Required ratio
= (3x + 10) : (x + 10)
= 70 : 30
= 7 : 3
The ratio between the present ages of Ravi and Vinay is 7:15 respectively. Two years from now Vinay’s age will be twice that of Ravi’s age. What was the difference between their ages 5 years ago.- a)13 years
- b)16 years
- c)11 years
- d)18 years
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The ratio between the present ages of Ravi and Vinay is 7:15 respectively. Two years from now Vinay’s age will be twice that of Ravi’s age. What was the difference between their ages 5 years ago.
a)
13 years
b)
16 years
c)
11 years
d)
18 years
e)
None of these
 | Aspire Academy answered |
The correct option is B.
Let the present age of Ravi be 7x and that of Vinay be 15x.
After 2 yrs , Ravi age = 7x+2
Vinay age = 15x+2.
Acc. to ques,
15x+2 = 2 (7x+2)
15x+2 = 14x+4
x = 2.
Five yrs ago,
Ravi age = 7x-5 => 7*2 - 5 = 9 yrs
Vinay age = 15x - 5 = 15*2 - 5 = 25 yrs.
Difference = 25 - 9 = 16 years
Let the present age of Ravi be 7x and that of Vinay be 15x.
After 2 yrs , Ravi age = 7x+2
Vinay age = 15x+2.
Acc. to ques,
15x+2 = 2 (7x+2)
15x+2 = 14x+4
x = 2.
Five yrs ago,
Ravi age = 7x-5 => 7*2 - 5 = 9 yrs
Vinay age = 15x - 5 = 15*2 - 5 = 25 yrs.
Difference = 25 - 9 = 16 years
The ratio between the present ages of P and Q is 6:7. If Q is four years older than P, what will be the ratio of the ages of P and Q after 4 years?- a)3:4
- b)3:5
- c)4:3
- d)Data inadequate
- e)None of these
Correct answer is option 'E'. Can you explain this answer?
The ratio between the present ages of P and Q is 6:7. If Q is four years older than P, what will be the ratio of the ages of P and Q after 4 years?
a)
3:4
b)
3:5
c)
4:3
d)
Data inadequate
e)
None of these
 | Aishwarya Rajput answered |
P:Q = 6:7 i.e P/Q = 6/7 => 7P = 6Q--------1
Given that Q = P + 4 (put in 1)
7P = 6(P + 4)
So, P = 24 and Q = P+4 i.e 28years
After 4 years, P+4 i.e 24+4= 28yrs
And Q = 28 +4 = 32years
The ratio we get is 7:8
The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?- a)12 years
- b)24 years
- c)C is elder than A
- d)Data inadequate
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A?
a)
12 years
b)
24 years
c)
C is elder than A
d)
Data inadequate
e)
None of these
 | Glance Learning Institute answered |
The correct option is A.
Given that A+B = 12 + B + C
⇒ A – C = 12 + B – B = 12
⇒ C is younger than A by 12 years
Given that A+B = 12 + B + C
⇒ A – C = 12 + B – B = 12
⇒ C is younger than A by 12 years
Ayesha’s father was 38 year of age when she was born. Her mother was 36 years old when her brother, four years younger to her, was born, What was the age of Ayesha’s father and mother respectively when her brother was born.- a)32 years, 23 years
- b)32 years, 29 years
- c)35 years, 29 years
- d)35 years, 33 years
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
Ayesha’s father was 38 year of age when she was born. Her mother was 36 years old when her brother, four years younger to her, was born, What was the age of Ayesha’s father and mother respectively when her brother was born.
a)
32 years, 23 years
b)
32 years, 29 years
c)
35 years, 29 years
d)
35 years, 33 years
e)
None of these
 | Dia Mehta answered |
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 36) years = 6 years.In a family the average age of the father and mother is 38 years, whereas the average age of father, mother and only daughter is 28 years. The age of daughters is- a)5 years
- b)6 years
- c)8 years
- d)10 years
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
In a family the average age of the father and mother is 38 years, whereas the average age of father, mother and only daughter is 28 years. The age of daughters is
a)
5 years
b)
6 years
c)
8 years
d)
10 years
e)
None of these
 | Anaya Patel answered |
The correct option is C.
Let father's age be x, mother's age be y and daughter's age be z.
(x+y)/2 = 38
x+y = 76
(x+y+z)/3 = 28
(76+z)/3 = 28
76+z = 84
z = 8 years
Let father's age be x, mother's age be y and daughter's age be z.
(x+y)/2 = 38
x+y = 76
(x+y+z)/3 = 28
(76+z)/3 = 28
76+z = 84
z = 8 years
The average age of a man and his son is 54 years. The ratio of their ages is 23: 13. What will be the ratio of their ages after 6 years.- a)10:7
- b)5:3
- c)4:3
- d)3:2
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The average age of a man and his son is 54 years. The ratio of their ages is 23: 13. What will be the ratio of their ages after 6 years.
a)
10:7
b)
5:3
c)
4:3
d)
3:2
e)
None of these
 | Vertex Academy answered |
To find the ratio of their ages after 6 years:
- Let the current ages be 23x and 13x.
avg age =sum/2
sum = avg age x 2
sum = 54x2 =108
- Their sum is 36x (23x + 13x = 36x), and this equals 108 years.
- So, 36x = 108 years, thus x = 3.
- After 6 years, their ages will be 23(3) + 6 = 75 and 13(3) + 6 = 45.
- The ratio of their ages after 6 years is 75:45, which simplifies to 5:3.
- This simplifies further to 5:3, which is the correct answer (Option B).
- Let the current ages be 23x and 13x.
avg age =sum/2
sum = avg age x 2
sum = 54x2 =108
- Their sum is 36x (23x + 13x = 36x), and this equals 108 years.
- So, 36x = 108 years, thus x = 3.
- After 6 years, their ages will be 23(3) + 6 = 75 and 13(3) + 6 = 45.
- The ratio of their ages after 6 years is 75:45, which simplifies to 5:3.
- This simplifies further to 5:3, which is the correct answer (Option B).
If 6 years are subtracted from the present age of Gagan and the remainder is divided by 18,then the present age of his grandson Anup is obtained. If Anup is 2 years younger to Madan whose age is 5 years,then what is Gagan's present age?- a)48 years
- b)60 years
- c)84 years
- d)96 years
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
If 6 years are subtracted from the present age of Gagan and the remainder is divided by 18,then the present age of his grandson Anup is obtained. If Anup is 2 years younger to Madan whose age is 5 years,then what is Gagan's present age?
a)
48 years
b)
60 years
c)
84 years
d)
96 years
e)
None of these
| | Anaya Patel answered |
The correct option is B.
Let gagan's age be "x".
anup's age = (x-6)/18
madan's age=5 therefore anup's age =3
btp,
(x-6)/18=3
so x=60
Let gagan's age be "x".
anup's age = (x-6)/18
madan's age=5 therefore anup's age =3
btp,
(x-6)/18=3
so x=60
The ratio between the present age of Radha and Seema is 5:4. Four years ago Seema’s age was 24 years. What will be the age of Radha after 5 years.- a)39 years
- b)40 years
- c)32 years
- d)35 years
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The ratio between the present age of Radha and Seema is 5:4. Four years ago Seema’s age was 24 years. What will be the age of Radha after 5 years.
a)
39 years
b)
40 years
c)
32 years
d)
35 years
e)
None of these
 | Anannya Reddy answered |
Radha and seema present age =5x, 4x
4years ago seema age =24
so 4x-4=24
4x=28
x=7 so present age of radha=35 seema =28
so 5years after =35+5=40 so B is the answer
4years ago seema age =24
so 4x-4=24
4x=28
x=7 so present age of radha=35 seema =28
so 5years after =35+5=40 so B is the answer
The ratio between the present ages of Radha and Seema is 5:7. After 8 years Radha’s age will be 28 years. What was Seema’s age 5 years ago.- a)21 years
- b)24 years
- c)28 years
- d)22 years
- e)None of these
Correct answer is option 'E'. Can you explain this answer?
The ratio between the present ages of Radha and Seema is 5:7. After 8 years Radha’s age will be 28 years. What was Seema’s age 5 years ago.
a)
21 years
b)
24 years
c)
28 years
d)
22 years
e)
None of these
| | Anaya Patel answered |
The correct option is E.
Let the present age of Radha be 5x So 8 yrs back , i.e, at present she is 20.
this means 5x = 20 => x = 4
Then Seema 's age = 7x = 7*4 = 28yrs.
Five yrs ago , her age was 28 - 5 = 23yrs.
Let the present age of Radha be 5x So 8 yrs back , i.e, at present she is 20.
this means 5x = 20 => x = 4
Then Seema 's age = 7x = 7*4 = 28yrs.
Five yrs ago , her age was 28 - 5 = 23yrs.
Two years ago the ratio of ages of A and B was 5:7. Two years hence the ratio of their ages will be 7:9. What is the present age of B.- a)16 years
- b)14.5 years
- c)12 years
- d)15 years
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Two years ago the ratio of ages of A and B was 5:7. Two years hence the ratio of their ages will be 7:9. What is the present age of B.
a)
16 years
b)
14.5 years
c)
12 years
d)
15 years
e)
None of these
| | Glance Learning Institute answered |
Let x,y be present ages of A,B.
x-2/y-2=5/7 implies 7x-5y=4 -(1)
x+2/y+2=7/9 implies 9x-7y=-4. (2)
(1) * 7 - (2) * 5 gives x=12
7(12) - 5y = 4
84 - 5y = 4
80 = 5y
16 = y
substitute and get y which would be 16
x-2/y-2=5/7 implies 7x-5y=4 -(1)
x+2/y+2=7/9 implies 9x-7y=-4. (2)
(1) * 7 - (2) * 5 gives x=12
7(12) - 5y = 4
84 - 5y = 4
80 = 5y
16 = y
substitute and get y which would be 16
On Teacher’s Day, 4800 sweets were to be equally distributed among a certain number of children. But on that particular day 100 children were absent. Hence, each child got four sweets extra. How many children were originally supposed to be there?- a)300
- b)400
- c)540
- d) 500
- e)None of these .
Correct answer is option 'B'. Can you explain this answer?
On Teacher’s Day, 4800 sweets were to be equally distributed among a certain number of children. But on that particular day 100 children were absent. Hence, each child got four sweets extra. How many children were originally supposed to be there?
a)
300
b)
400
c)
540
d)
500
e)
None of these .
 | Tanvi Dey answered |
Let the original number of children be x.
∴ 4800/x-100 - 4800/x = 4
=> 4800((x-x+100)/(x(x-100))) = 4
=> x(x-100) = 1200 * 100
=> x(x-100) = 400(400-100)
=> x = 400
The average age of a man and his two twin sons is 30 years. The ratio of the ages of father and one of his sons is 5:2. What is the father’s age- a)50 years
- b)30 years
- c)45 years
- d)20 years
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
The average age of a man and his two twin sons is 30 years. The ratio of the ages of father and one of his sons is 5:2. What is the father’s age
a)
50 years
b)
30 years
c)
45 years
d)
20 years
e)
None of these
| | Aishwarya Rajput answered |
Let father's age be M and age of twins be 2x
(M + 2x)/3 = 30
M + 2x = 90------------(1)
M/x = 5/2
2M = 5x---------------(2)
Multiply (1) with 2
We get, 2M + 4x = 180--------------(3)
Putting (2) in (3)
5x+4x = 180 => 9x = 180x = 20. [his children are twins so 2x = 40]Since M + 2x = 90M = 90 -40 = 50years
(M + 2x)/3 = 30
M + 2x = 90------------(1)
M/x = 5/2
2M = 5x---------------(2)
Multiply (1) with 2
We get, 2M + 4x = 180--------------(3)
Putting (2) in (3)
5x+4x = 180 => 9x = 180x = 20. [his children are twins so 2x = 40]Since M + 2x = 90M = 90 -40 = 50years
A father said to his son, “At the time of your birth, I was as old as you are at present”. If father’s age is 38 years now the sons age 5 years back was- a)14 years
- b)19 years
- c)33 years
- d)38 years
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
A father said to his son, “At the time of your birth, I was as old as you are at present”. If father’s age is 38 years now the sons age 5 years back was
a)
14 years
b)
19 years
c)
33 years
d)
38 years
e)
None of these
| | Prani Garg answered |
HERE IS YOUR ANSWER.
Let the present age of son= x
At the time of birth of son,father age = x
So after x yrs i.e. at present age of father= 38
38=x+x
x= 38÷2= 19
So the present age of son is 19
Age of son before 5 yrs= 19-5= 14 yrs.
HOPE IT HELPS.
Let the present age of son= x
At the time of birth of son,father age = x
So after x yrs i.e. at present age of father= 38
38=x+x
x= 38÷2= 19
So the present age of son is 19
Age of son before 5 yrs= 19-5= 14 yrs.
HOPE IT HELPS.
Present age of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. Wat is X’s present age?- a)35
- b)42
- c)49
- d)Cannot be determined
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Present age of X and Y are in the ratio 5:6 respectively. Seven years hence this ratio will become 6:7 respectively. Wat is X’s present age?
a)
35
b)
42
c)
49
d)
Cannot be determined
e)
None of these
 | Shivu D B answered |
Let
X present age is 5a---(1)
Y present age is 6a
After 7 years
5a+7/6a+7=6/7
cross multiply
So
7(5a+7)=6(6a+7)
35a+49=36a+42
a=7--(2)
substitute (2) in (1)
X present age is 5(7)= 35
X present age is 5a---(1)
Y present age is 6a
After 7 years
5a+7/6a+7=6/7
cross multiply
So
7(5a+7)=6(6a+7)
35a+49=36a+42
a=7--(2)
substitute (2) in (1)
X present age is 5(7)= 35
The difference between the ages of two persons is 10 years. Fifteen years ago, the elder one was twice as old as the younger one. The present age of elder person is?- a)25 years
- b)35 years
- c)45 years
- d)55 years
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The difference between the ages of two persons is 10 years. Fifteen years ago, the elder one was twice as old as the younger one. The present age of elder person is?
a)
25 years
b)
35 years
c)
45 years
d)
55 years
e)
None of these
| | Aishwarya Rajput answered |
Let the elder person be 'A' and younger be 'B'. A - B = 10. A = 10 +B. 15 years ago,A -15 = 2(B-15) 10 + B - 15 = 2(B - 15). B -5 = 2B - 30. B = 25 A = B + 10 Therefore, A = 35
At present Tarun is twice the age of Vishal and half of Tanvi’s age. After four years Tarun will be 1.5 times Vishal’s age and Tanvi will be 2.5 times Vishal’s age. What is Tanvi’s present age?- a)12 years
- b)8 years
- c)20 years
- d)16 years
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
At present Tarun is twice the age of Vishal and half of Tanvi’s age. After four years Tarun will be 1.5 times Vishal’s age and Tanvi will be 2.5 times Vishal’s age. What is Tanvi’s present age?
a)
12 years
b)
8 years
c)
20 years
d)
16 years
e)
None of these
 | Kavya Sharma answered |
Vishal's present age = x years
Tarun's present age = 2x years
Tanvi's present age = 4x years
After 4 years.
Tarun's age = 1.5 * Vishal's age
=> 2x + 4 = 1.5(x+4)
=> 2x - 1.5x = 2
=>0.5x = 2 => x = 2/0.5 = 4
Tanvi's present age = 16 years.
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