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Electromagnets are made of soft iron because soft iron has [2010]
- a)low retentivity and high coercive force
- b)high retentivity and high coercive force
- c)high retentivity and low coercive force
- d)low retentivity and low coercive force
Correct answer is option 'D'. Can you explain this answer?
Electromagnets are made of soft iron because soft iron has [2010]
a)
low retentivity and high coercive force
b)
high retentivity and high coercive force
c)
high retentivity and low coercive force
d)
low retentivity and low coercive force
|
Sneha Basak answered |
Answer :- d
Solution :-Soft iron is a soft magnetic material. Hence, Electromagnetics are made of soft iron because soft iron has low retentivity and low coercive force or low coercivity.
The work done in turning a magnet of magneticmoment M by an angle of 90° from the meridian,is n times the corresponding work done to turnit through an angle of 60°. The value of n isgiven by [1995]- a)2
- b)1
- c)0.5
- d)0.25
Correct answer is option 'A'. Can you explain this answer?
The work done in turning a magnet of magneticmoment M by an angle of 90° from the meridian,is n times the corresponding work done to turnit through an angle of 60°. The value of n isgiven by [1995]
a)
2
b)
1
c)
0.5
d)
0.25
|
Mihir Yadav answered |
Degrees is given by:
W = MΔθ
where W is the work done, M is the magnetic moment of the magnet, and Δθ is the angle through which the magnet is turned.
If the angle of rotation is 90 degrees, then Δθ = 90 degrees. Therefore, the work done in turning the magnet by 90 degrees is:
W = M × 90
W = 90M
So, the work done is directly proportional to the magnetic moment of the magnet. The larger the magnetic moment, the more work is required to turn the magnet.
W = MΔθ
where W is the work done, M is the magnetic moment of the magnet, and Δθ is the angle through which the magnet is turned.
If the angle of rotation is 90 degrees, then Δθ = 90 degrees. Therefore, the work done in turning the magnet by 90 degrees is:
W = M × 90
W = 90M
So, the work done is directly proportional to the magnetic moment of the magnet. The larger the magnetic moment, the more work is required to turn the magnet.
For protecting a sensitive equipment from theexternal electric arc, it should be [1998]- a)wrapped with insulation around it when acurrent is passing through it
- b)placed inside an iron can
- c)surrounded with fine copper sheet
- d)placed inside an aluminium can
Correct answer is option 'B'. Can you explain this answer?
For protecting a sensitive equipment from theexternal electric arc, it should be [1998]
a)
wrapped with insulation around it when acurrent is passing through it
b)
placed inside an iron can
c)
surrounded with fine copper sheet
d)
placed inside an aluminium can
|
Arnab Iyer answered |
The iron can produces a magnetic screening for the equipment as lines of magnetic force can not enter iron enclosure.
The magnetic moment of a diamagnetic atom is [2010]- a)equal to zero
- b)much greater than one
- c)1
- d)between zero and one
Correct answer is option 'A'. Can you explain this answer?
The magnetic moment of a diamagnetic atom is
[2010]
a)
equal to zero
b)
much greater than one
c)
1
d)
between zero and one
|
Priyanka Iyer answered |
The magnetic moment of a diamagnetic
atom is equal to zero.
atom is equal to zero.
If a diamagnetic substance is brought near northor south pole of a bar magnet, it is [1999]- a)attracted by the poles
- b)repelled by the poles
- c)repelled by north pole and attracted by thesouth pole
- d)attracted by the north pole and repelled bythe south pole
Correct answer is option 'B'. Can you explain this answer?
If a diamagnetic substance is brought near northor south pole of a bar magnet, it is [1999]
a)
attracted by the poles
b)
repelled by the poles
c)
repelled by north pole and attracted by thesouth pole
d)
attracted by the north pole and repelled bythe south pole
|
|
Sneha Basak answered |
Diamagnetic substances do not have any unpaired electron. And they are magnetised in direction opposite to that of magnetic field.
Hence, when they are brought to north or south pole of a bar magnet, they are repelled by poles.
Hence, when they are brought to north or south pole of a bar magnet, they are repelled by poles.
A compass needle which is allowed to move in ahorizontal plane is taken to a geomagnetic pole.It : [2012]- a)will become rigid showing no movement
- b)will stay in any position
- c)will stay in north-south direction only
- d)will stay in east-west direction only
Correct answer is option 'B'. Can you explain this answer?
A compass needle which is allowed to move in ahorizontal plane is taken to a geomagnetic pole.It : [2012]
a)
will become rigid showing no movement
b)
will stay in any position
c)
will stay in north-south direction only
d)
will stay in east-west direction only
|
Srishti Sen answered |
Since magnetic field is in vertical direction and needle is free to totate in horizontal plane only so magnetic force cannot rotate the needle in horizontal plane so needle can stay in any position.
A short bar magnet of magnetic moment 0.4J T–1 is placed in a uniform magnetic field of 0.16 T. Themagnet is in stable equilibrium when the potentialenergy is [2011M]- a)–0.064 J
- b)zero
- c)–0.082 J
- d)0.064 J
Correct answer is option 'A'. Can you explain this answer?
A short bar magnet of magnetic moment 0.4J T–1 is placed in a uniform magnetic field of 0.16 T. Themagnet is in stable equilibrium when the potentialenergy is [2011M]
a)
–0.064 J
b)
zero
c)
–0.082 J
d)
0.064 J
|
|
Snehal Iyer answered |
-1
is placed in a uniform magnetic field of 0.2T. If the magnet is free to rotate, what will be the torque experienced by the magnet?
The torque experienced by the magnet can be calculated using the formula:
τ = m × B × sinθ
where τ is the torque, m is the magnetic moment of the magnet, B is the magnetic field strength, and θ is the angle between the magnetic moment vector and the magnetic field vector.
In this case, the magnetic moment of the magnet is 0.4 J T-1, the magnetic field strength is 0.2 T, and since the magnet is free to rotate, we can assume that the angle between the magnetic moment vector and the magnetic field vector is 90 degrees. Therefore, we can calculate the torque as:
τ = 0.4 J T-1 × 0.2 T × sin 90°
τ = 0.08 J
So, the torque experienced by the magnet is 0.08 J.
is placed in a uniform magnetic field of 0.2T. If the magnet is free to rotate, what will be the torque experienced by the magnet?
The torque experienced by the magnet can be calculated using the formula:
τ = m × B × sinθ
where τ is the torque, m is the magnetic moment of the magnet, B is the magnetic field strength, and θ is the angle between the magnetic moment vector and the magnetic field vector.
In this case, the magnetic moment of the magnet is 0.4 J T-1, the magnetic field strength is 0.2 T, and since the magnet is free to rotate, we can assume that the angle between the magnetic moment vector and the magnetic field vector is 90 degrees. Therefore, we can calculate the torque as:
τ = 0.4 J T-1 × 0.2 T × sin 90°
τ = 0.08 J
So, the torque experienced by the magnet is 0.08 J.
A bar magnet is oscillating in the earth’s magneticfield with a period T. What happens to its periodof motion, if its mass is quadrupled [1994, 03]- a)motion remains simple harmonic with newperiod = T/2
- b)motion remains simple harmonic with newperiod = 2 T
- c)motion remains simple harmonic with newperiod = 4T
- d)motion remains simple harmonic and theperiod stays nearly constant
Correct answer is option 'B'. Can you explain this answer?
A bar magnet is oscillating in the earth’s magneticfield with a period T. What happens to its periodof motion, if its mass is quadrupled [1994, 03]
a)
motion remains simple harmonic with newperiod = T/2
b)
motion remains simple harmonic with newperiod = 2 T
c)
motion remains simple harmonic with newperiod = 4T
d)
motion remains simple harmonic and theperiod stays nearly constant
|
Diya Datta answered |
The time period of a bar magnet in a magnetic field is given by.
Here, I = moment of inertia ∝ m , M = moment of magnet, B = magnetic field.
, so, T becomes twice as mass becomes four timesTwo magnets of magnetic moments M and 2M are placed in a vibration magnetometer, with theidentical poles in the same direction. The timeperiod of vibration is T1. If the magnets areplaced with opposite poles together and vibratewith time period T2, then [2002]- a)T2 is infinite
- b)T2 = T1
- c)T2 > T1
- d)T2 < T1
Correct answer is option 'C'. Can you explain this answer?
Two magnets of magnetic moments M and 2M are placed in a vibration magnetometer, with theidentical poles in the same direction. The timeperiod of vibration is T1. If the magnets areplaced with opposite poles together and vibratewith time period T2, then [2002]
a)
T2 is infinite
b)
T2 = T1
c)
T2 > T1
d)
T2 < T1
|
Shraddha Choudhury answered |
Option c) T2 < t1="" />
Above Curie temperature [2006]- a)a paramagnetic substance becomesdiamagnetic
- b)a diamagnetic substance becomesparamagnetic
- c)a paramagnetic substance becomesferromagnetic
- d)a ferromagnetic substance becomesparamagnetic
Correct answer is option 'D'. Can you explain this answer?
Above Curie temperature [2006]
a)
a paramagnetic substance becomesdiamagnetic
b)
a diamagnetic substance becomesparamagnetic
c)
a paramagnetic substance becomesferromagnetic
d)
a ferromagnetic substance becomesparamagnetic
|
|
Srishti Sen answered |
Above Curie Temperature, a ferromagnetic substance becomes paramagnetic
Curie temperature is the temperature abovewhich [2008]- a)ferromagnetic material becomesparamagnetic material
- b)paramagnetic material becomesdiamagnetic material
- c)paramagnetic material becomesferromagnetic material
- d)ferromagnetic material becomesdiamagnetic material.
Correct answer is option 'A'. Can you explain this answer?
Curie temperature is the temperature abovewhich [2008]
a)
ferromagnetic material becomesparamagnetic material
b)
paramagnetic material becomesdiamagnetic material
c)
paramagnetic material becomesferromagnetic material
d)
ferromagnetic material becomesdiamagnetic material.
|
Shanaya Rane answered |
Curie temperature is the temperature above which ferromagnetic material becomes paramagnetic material.
A bar magnet of length ‘ℓ’ and magnetic dipole moment ‘M’ is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be [NEET 2013]
- a)
- b)
- c)M/2
- d)M
Correct answer is option 'A'. Can you explain this answer?
A bar magnet of length ‘ℓ’ and magnetic dipole moment ‘M’ is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be [NEET 2013]
a)
b)
c)
M/2
d)
M
|
Rhea Sarkar answered |
Magnetic dipole moment
M = m × ℓ M' = m × r
From figure
M = m × ℓ M' = m × r
From figure
A vibration magnetometer placed in magneticmeridian has a small bar magnet. The magnetexecutes oscillations with a time period of 2 secin earth's horizontal magnetic field of 24 microtesla. When a horizontal field of 18microtesla is produced opposite to the earth'sfield by placing a current carrying wire, the newtime period of magnet will be [2010]- a)1 s
- b)2 s
- c)3 s
- d)4 s
Correct answer is option 'D'. Can you explain this answer?
A vibration magnetometer placed in magneticmeridian has a small bar magnet. The magnetexecutes oscillations with a time period of 2 secin earth's horizontal magnetic field of 24 microtesla. When a horizontal field of 18microtesla is produced opposite to the earth'sfield by placing a current carrying wire, the newtime period of magnet will be [2010]
a)
1 s
b)
2 s
c)
3 s
d)
4 s
|
Aashna Mukherjee answered |
Time period of a vibration magnetometer,
A magnetic needle suspended parallel to a magnetic field requires √3 J of work to turn it through 60°. The torque needed to maintain the needle in this position will be : [2012M]- a)2√3 J
- b)3J
- c)√3J
- d)3/2 J
Correct answer is option 'B'. Can you explain this answer?
A magnetic needle suspended parallel to a magnetic field requires √3 J of work to turn it through 60°. The torque needed to maintain the needle in this position will be : [2012M]
a)
2√3 J
b)
3J
c)
√3J
d)
3/2 J
|
|
Diya Datta answered |
According to work energy theorem
From equation (i) and (ii)
A diamagnetic material in a magnetic field moves- a)perpendicular to the field [2003]
- b)from stronger to the weaker parts of the field
- c)from weaker to the stronger parts of the field
- d)in none of the above directions
Correct answer is option 'B'. Can you explain this answer?
A diamagnetic material in a magnetic field moves
a)
perpendicular to the field [2003]
b)
from stronger to the weaker parts of the field
c)
from weaker to the stronger parts of the field
d)
in none of the above directions
|
Arindam Khanna answered |
A diamagnetic material in a magnetic field moves from stronger to the weaker parts of the field.
If the magnetic dipole moment of an atom ofdiamagnetic material, paramagnetic material andferromagnetic material are denoted by μd, μp andμf respectively, then [2005]- a)μd = 0 and μp ≠ 0
- b)μd ≠0 and μp =0
- c)μp = 0 and μf ≠0
- d)μd ≠0 and μf ≠0
Correct answer is option 'A'. Can you explain this answer?
If the magnetic dipole moment of an atom ofdiamagnetic material, paramagnetic material andferromagnetic material are denoted by μd, μp andμf respectively, then [2005]
a)
μd = 0 and μp ≠ 0
b)
μd ≠0 and μp =0
c)
μp = 0 and μf ≠0
d)
μd ≠0 and μf ≠0
|
Rajesh Datta answered |
The magnetic dipole moment of diamagnetic material is zero as each of its pair of electrons
have opposite spins, i.e., μd = 0.
Paramagnetic substances have dipole
moment > 0, i.e. μp ≠ 0, because of excess of electrons in its molecules spinning in the same direction.
Ferro-magnetic substances are very strong magnets and they also have permanent magnetic moment, i.e. μf ≠ 0.
have opposite spins, i.e., μd = 0.
Paramagnetic substances have dipole
moment > 0, i.e. μp ≠ 0, because of excess of electrons in its molecules spinning in the same direction.
Ferro-magnetic substances are very strong magnets and they also have permanent magnetic moment, i.e. μf ≠ 0.
A bar magnet, of magnetic moment 
, is placed in a magnetic field of induction 
. The torque exerted on it is- a)
- b)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
A bar magnet, of magnetic moment , is placed in a magnetic field of induction . The torque exerted on it is
, is placed in a magnetic field of induction . The torque exerted on it isa)
b)
c)
d)
|
Bhargavi Choudhury answered |
We know that when a bar magnet is placed in the magnetic field at an angle θ, then torque acting on the bar magnet (τ)
Note : This torque τ has a tendency to make the axis of the magnet parallel to the direction of the magnetic field.
There are four light–weight–rod samples A,B,C,D separately suspended by threads. A bar magnet is slowly brought near each sample and the following observations are noted [2011]
(i) A is feebly repelled
(ii) B is feebly attracted
(iii) C is strongly attracted
(iv) D remains unaffectedWhich one of the following is true ?- a)B is of a paramagnetic material
- b)C is of a diamagnetic material
- c)D is of a ferromagnetic material
- d)A is of a non–magnetic material
Correct answer is option 'A'. Can you explain this answer?
There are four light–weight–rod samples A,B,C,D separately suspended by threads. A bar magnet is slowly brought near each sample and the following observations are noted [2011]
(i) A is feebly repelled
(ii) B is feebly attracted
(iii) C is strongly attracted
(iv) D remains unaffected
(i) A is feebly repelled
(ii) B is feebly attracted
(iii) C is strongly attracted
(iv) D remains unaffected
Which one of the following is true ?
a)
B is of a paramagnetic material
b)
C is of a diamagnetic material
c)
D is of a ferromagnetic material
d)
A is of a non–magnetic material
|
|
Shanaya Rane answered |
A → diamagnetic
B → paramagnetic
C → Ferromagnetic
D → Non magnetic
B → paramagnetic
C → Ferromagnetic
D → Non magnetic
Nickel shows ferromagnetic property at roomtemperature. If the temperature is increasedbeyond Curie temperature, then it will show [2007]- a)anti ferromagnetism
- b)no magnetic property
- c)diamagnetism
- d)paramagnetism
Correct answer is option 'D'. Can you explain this answer?
Nickel shows ferromagnetic property at roomtemperature. If the temperature is increasedbeyond Curie temperature, then it will show [2007]
a)
anti ferromagnetism
b)
no magnetic property
c)
diamagnetism
d)
paramagnetism
|
Pallabi Reddy answered |
Beyond Curie temperature, ferromagnetic substances behaves like a paramagnetic substance.
A coil in the shape of an equilateral triangle of side l is suspended between the pole pieces of a permanent magnet such that 
is in the plane of the coil. If due to a current i in the triangle a torque τ acts on it, the side l of the triangle is [2005]- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
A coil in the shape of an equilateral triangle of side l is suspended between the pole pieces of a permanent magnet such that is in the plane of the coil. If due to a current i in the triangle a torque τ acts on it, the side l of the triangle is [2005]
is in the plane of the coil. If due to a current i in the triangle a torque τ acts on it, the side l of the triangle is [2005]a)
b)
c)
d)
|
Charvi Shah answered |
τ = MB sinθ
τ = iAB sin90º
τ = iAB sin90º
Current i is flowing in a coil of area A and number of turns N, then magnetic moment of the coil, M
is [2001]- a)NiA
- b)Ni/A
- c)
- d)N2Ai
Correct answer is option 'A'. Can you explain this answer?
Current i is flowing in a coil of area A and number of turns N, then magnetic moment of the coil, M
is [2001]
is [2001]
a)
NiA
b)
Ni/A
c)
d)
N2Ai
|
Shruti Chauhan answered |
Magnetic moment linked with one turn = iA Magnetic moment linked with N turns
= iNA amp-m2. Here, A = Area of current loop.
= iNA amp-m2. Here, A = Area of current loop.
Two identical bar magnets are fixed with their centres at a distance d apart. A stationary charge Q is placed at P in between the gap of the two magnets at a distance D from the centre O as shown in the Figure
The force on the charge Q is- a)directed perpendicular to the plane of paper
- b)zero
- c)directed along OP
- d)directed along PO
Correct answer is option 'B'. Can you explain this answer?
Two identical bar magnets are fixed with their centres at a distance d apart. A stationary charge Q is placed at P in between the gap of the two magnets at a distance D from the centre O as shown in the Figure
The force on the charge Q is
a)
directed perpendicular to the plane of paper
b)
zero
c)
directed along OP
d)
directed along PO
|
Sonal Kulkarni answered |
Force on a charged particle is given by F = qvB. Here v = 0 and also resultant B is zero.
∴ Force = 0
∴ Force = 0
A bar magnet of magnetic moment M is placed atright angles to a magnetic induction B. If a force F is experienced by each pole of the magnet, thelength of the magnet will be [NEET Kar. 2013]- a)F/MB
- b)MB/F
- c)BF/M
- d)MF/B
Correct answer is option 'B'. Can you explain this answer?
A bar magnet of magnetic moment M is placed atright angles to a magnetic induction B. If a force F is experienced by each pole of the magnet, thelength of the magnet will be [NEET Kar. 2013]
a)
F/MB
b)
MB/F
c)
BF/M
d)
MF/B
|
Kajal Bose answered |
FL = MB (= Torque) ⇒L = MB/F
If a diamagnetic substance is brought nearthe north or the south pole of a bar magnet, itis: [2009]- a)repelled by the north pole and attracted bythe south pole
- b)attracted by the north pole and repelled by the south pole
- c)attracted by both the poles
- d)repelled by both the poles
Correct answer is option 'D'. Can you explain this answer?
If a diamagnetic substance is brought nearthe north or the south pole of a bar magnet, itis: [2009]
a)
repelled by the north pole and attracted bythe south pole
b)
attracted by the north pole and repelled by the south pole
c)
attracted by both the poles
d)
repelled by both the poles
|
Surbhi Das answered |
Diamagnetic substances are repelled by
external magnetic fields.
external magnetic fields.
A bar magnet having a magnetic moment of 2× 104 JT–1 is free to rotate in a horizontal plane.A horizontal magnetic field B = 6 × 10–4 T existsin the space. The work done in taking the magnetslowly from a direction parallel to the field to a direction 60° from the field is [2009]- a)12 J
- b)6 J
- c)2 J
- d)0.6 J
Correct answer is option 'B'. Can you explain this answer?
A bar magnet having a magnetic moment of 2× 104 JT–1 is free to rotate in a horizontal plane.A horizontal magnetic field B = 6 × 10–4 T existsin the space. The work done in taking the magnetslowly from a direction parallel to the field to a direction 60° from the field is [2009]
a)
12 J
b)
6 J
c)
2 J
d)
0.6 J
|
Nayanika Dasgupta answered |
Work done
= MB (cos θ1 – cos θ2)
= MB (cos 0° – cos 60°)
= MB (cos θ1 – cos θ2)
= MB (cos 0° – cos 60°)
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