All Exams  >   NEET  >   NCERT Based Tests for NEET  >   All Questions

All questions of Wave Optics for NEET Exam

Light of wavelength 500 nm is incident on a slit of width 0.1 mm. The width of the central bright line on the screen is 2m. What is the distance of the screen?​
a)1 m
b)200 m
c)0.75 m
d)0.5 m
Correct answer is option 'B'. Can you explain this answer?

Swara Sharma answered
Beta(central Maxima)=2lambda D(distance of the screen)/d(distance between slits).

beta=2m.

wavelength= 500nm=5×10^-7m.

d=0.1mm=1×10^-4m.

2=2×5×10^-7 D/10^-4.

1=5×10^-3 D .

1/5×10^-3=D .

1000/5=D.

200m=D

Which of the following is not an example of coherent source produced by the division of wavefront?
  • a)
    Fresnel’s biprism
  • b)
    Lloyd’s mirror
  • c)
    Young’s double slit experiment
  • d)
    Interference by thin films
Correct answer is option 'D'. Can you explain this answer?

Suresh Iyer answered
The correct answer is option D
In A,B,C there is a single source (coherent source)while in D there is an interference of thin films whose sources are different ,therefore not coherent.

If the Young’s apparatus is immersed in water, the effect on fringe width will​
  • a)
    remain same
  • b)
    decrease
  • c)
    increase
  • d)
    Cant say because the experiment cannot be carried in any other medium except air
Correct answer is option 'B'. Can you explain this answer?

Kalyan Joshi answered
Effect of Immersing Young's Apparatus in Water on Fringe Width

When the Young's apparatus is immersed in water, the effect on the fringe width can be explained as follows:

1. Refractive Index of Water: Water has a higher refractive index than air. This means that light passing through water will be bent more than in air.

2. Path Difference: Path difference is the difference in the distance traveled by two waves from the source to the point where they interfere with each other. When the apparatus is immersed in water, the path difference between the two waves will change due to the change in refractive index.

3. Decrease in Fringe Width: As the path difference changes, the interference pattern will also change. The fringe width will decrease because the change in the path difference will cause the interference pattern to become more spread out.

4. Explanation: The fringe width is inversely proportional to the square root of the refractive index. Since the refractive index of water is higher than air, the fringe width will decrease when the apparatus is immersed in water.

Conclusion

In conclusion, when the Young's apparatus is immersed in water, the fringe width will decrease due to the change in refractive index, which leads to a change in the path difference and the interference pattern.

A rotating calcite crystal is placed over an ink dot. On seeing through the crystal one finds:
  • a)
    Two stationary dots
  • b)
    Two dots moving along straight lines
  • c)
    One dot rotating about the other
  • d)
    Both dots rotating about a common axis
Correct answer is option 'C'. Can you explain this answer?

Anaya Patel answered
In calcite crystal there is a phenomenon of double refraction. So, we see one dot as a stationary object whereas the other being refracted at a little displaced position seems to be rotating about the first dot.

An unpolarised beam of intensity Io is incident on a polarizer and analyser placed in contact. The angle between the transmission axes of the polarizer and the analyser is θ. What is the intensity of light emerging out of the analyser?​
  • a)
    (I0 cos 2θ)/2
  • b)
    I0 cos2θ
  • c)
    I0 cosθ
  • d)
    I0
Correct answer is option 'A'. Can you explain this answer?

Nikita Singh answered
 Suppose the angle between the transmission axes of the analyser and the polarizer is θ. The completely plane polarized light form the polarizer is incident on the analyser. If E0 is the amplitude of the electric vector transmitted by the polarizer, then intensity I0 of the light incident on the analyser is
I ∞ E02
 
The electric field vector E0 can be resolved into two rectangular components i.e E0 cosθ and E0 sinθ. The analyzer will transmit only the component ( i.e E0 cosθ ) which is parallel to its transmission axis. However, the component E0sinθ will be absorbed by the analyser. Therefore, the intensity I of light transmitted by the analyzer is,
 
I ∞ ( E0 x cosθ )2
 
I / I0 = ( E0 x cosθ )2 / E02 = cos2θ
 
I = I0 x cos2θ
when light passes from polarizer it's intensity becomes half and when passed through analyser it becomes,
I = I0 x cos2θ/2
 

Two coherent sources produce a dark fringe when phase difference between the interfering waves is(n integer)​
  • a)
  • b)
    (2n – 1)π
  • c)
    zero
  • d)
    n
Correct answer is option 'B'. Can you explain this answer?

Shruti Sarkar answered
Dark fringes will be produced when there are destructive interference. The condition for that is the two waves should have a phase difference of an odd integral multiple of π.

A beam of light has a wavelength of 650 nm in vacuum. What is the wavelength of these waves in the liquid whose index of refraction at this wavelength is 1.47?
  • a)
    472nm
  • b)
    442nm
  • c)
    462nm
  • d)
    452nm
Correct answer is option 'B'. Can you explain this answer?

Geetika Shah answered
We know that,
Wavelength of light in a material:
λ= λ0/n
where, λ=wavelength of material, λ0=wavelength of light in vacuum,
n=index of refraction of material.
So, 650x10-9m/1.47=442.177nm.

Diffraction of light gives the information of
  • a)
    Transverse nature
  • b)
    Longitudinal nature
  • c)
    Both transverse and longitudinal
  • d)
    Neither transverse nor longitudina
Correct answer is option 'D'. Can you explain this answer?

Vijay Bansal answered
Transverse and longitudinal waves. Light and other types of electromagnetic radiation are transverse waves. Water waves and S waves (a type of seismic wave) are also transverse waves. In transverse waves, the vibrations are at right angles to the direction of travel.

Diffraction pattern cannot be observed with:
a)one wide slit
b)two narrow slits
c)one narrow slit
d)large number of narrow slits
Correct answer is option 'A'. Can you explain this answer?

Pooja Mehta answered
If one illuminates two parallel slits, the light from the two slits again interferes. Here the interference is a more pronounced pattern with a series of alternating light and dark bands. ... He also proposed (as a thought experiment) that if detectors were placed before each slit, the interference pattern would disappear.

The phenomena diffraction can take place in sound waves.
  • a)
    Yes
  • b)
    No
  • c)
    Only Interference
  • d)
    Under certain conditions only
Correct answer is option 'A'. Can you explain this answer?

Rohan Singh answered
YES, Sound waves, on the other hand, are longitudinal, meaning that they oscillate parallel to the direction of their motion. Since there is no component of a sound wave's oscillation that is perpendicular to its motion, sound waves cannot be polarized

Which of the following undergoes largest diffraction?
  • a)
    Ultraviolet light
  • b)
    Infra red light
  • c)
    Radio waves
  • d)
    Y – rays
Correct answer is option 'C'. Can you explain this answer?

Anjana Sharma answered
Maximum diffraction occurs when size of obstacle is almost equal to wavelength of light wave. Hence maximum diffraction occurs for larger wavelength . As wavelength of radio wave is higher than others, maximum diffraction will occur for it.   

Coherent sources can be created by the division of:
  • a)
    only amplitude
  • b)
    only wave front
  • c)
    only wavelength
  • d)
    both amplitude and wave front
Correct answer is option 'D'. Can you explain this answer?

Divey Sethi answered
Division of wave front where wave front is divided into two or more parts with the help of mirrors, lenses and prisms. The common methods are : Young's double slit arrangement, Fresnel's biprism method, Lloyd’s mirror method etc.
 
Division of amplitude where amplitude of the incoming beam is divided into two or more parts by partial reflection or refraction. These divided parts travel different paths and reunited later to produce interference. E.g. Newton's rings, Michelson’s interferometer etc.
 

When viewed in white light, a soap bubble shows colours because of
  • a)
    Interference
  • b)
    Scattering
  • c)
    Dispersion
  • d)
    Diffraction
Correct answer is option 'A'. Can you explain this answer?

Hansa Sharma answered
When the light is incident on a soap bubble of certain thickness it constructively interferes for wavefronts which are in phase to produce white light and when the wavefronts are out of phase, they undergo destructive interference to produce a series of colors. Thus, interference is the reason.

Shape of the wave front of portion of the wave front of light from a distant star intercepted by the Earth
  • a)
    plane
  • b)
    spherical
  • c)
    hyperboloid
  • d)
    conical
Correct answer is option 'A'. Can you explain this answer?

Aryan Keshri answered
Option A ....Since the light coming from the distance star to the earth will be at Infinity , the rays coming from it will be parallel rays , thus the wavefront will be a plane .

The Brewster’s angle for a transparent medium is 600.The angle of incidence is​
  • a)
    450
  • b)
    900
  • c)
    600
  • d)
    300
Correct answer is option 'C'. Can you explain this answer?

Hansa Sharma answered
Brewster's angle is an angle of incidence at which light with a particular polarization is perfectly transmitted through a transparent dielectric surface, with no reflection. When unpolarized light is incident at this angle, the light that is reflected from the surface is therefore perfectly polarized.
So the angle of incidence would be 60°

The intensity of light transmitted by the analyzer is maximum when
  • a)
    The transmission axes of the analyzer and the polarizer are perpendicular
  • b)
    The reflected ray is fully polarized
  • c)
    The transmission axes of the analyzer and the polarizer are parallel
  • d)
    The reflected ray is partially polarized
Correct answer is option 'C'. Can you explain this answer?

Alfiya I answered
From malu's law, If I0 is intensity of plane polarised light incident on an analyser and (thete) is the angle between axes of polariser and analyser, then intensity of polarised light transmitted from analyser ,I = I0 cos(^2) thete, ie, when (thete)=0, cos(^2) 0=1, then I= I0 ie, the transmission axes of polariser and analyser are paralell.

In a Fresnel’s biprism experiment, the two coherent sources are obtained by:
  • a)
    two slits
  • b)
    reflection
  • c)
    Refraction
  • d)
    Internal reflection
Correct answer is option 'C'. Can you explain this answer?

Om Desai answered
When a light travels from one medium to another then deviation in the path of light known as refraction. And in the prism surrounding medium is air and material medium is glass due to the change of medium refraction will occur in prism.

The change in diffraction pattern of a single slit, when the monochromatic source of light is replaced by a source of white light will be
  • a)
    Diffracted image is not clear
  • b)
    Diffracted image gets dispersed into constituent colours of white light
  • c)
    The image of the slit becomes infinitely wide
  • d)
    Clear colourful fringe pattern
Correct answer is option 'B'. Can you explain this answer?

Dr Manju Sen answered
  • When a source of white light is used instead of a monochromatic source, the diffracted image of the slit gets dispersed into constituent colours of white light.
  • The central maximum will be white and on either side of the central maximum, there will be coloured fringes.

Emission and absorption is best described by,
  • a)
    dual / schizophrenic model
  • b)
    a wave model
  • c)
    None of the above
  • d)
    particle model
Correct answer is option 'D'. Can you explain this answer?

Nandini Iyer answered
Distance between the slits, d=0.28×10−3 m
Distance between the slits and the screen, D=1.4m
Distance between the central fringe and the fourth (n=4) fringe, 
u=1.2×10−2 m
In case of a constructive interference, we have the relation for the distance between the two fringes as:
u=nλD/d
⇒λ=ud/nD=6×10−7m=600nm

In the Young’s double slit experiment, the distance of p th dark fringe from the central maximum is:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?

Neha Sharma answered
Position of the pth dark fringe is at a distance of 
y=(2p−1) (λD/2d)​ from the centre
where 
λ: Wavelength
D: Distance between slits 
d: slit width

In an interference experiment monochromatic light is replaced by white light, we will see:​
  • a)
    uniform darkness on the screen
  • b)
    a few coloured bands and then uniform illumination
  • c)
    equally spaced white and dark bands
  • d)
    uniform illumination on the screen
Correct answer is option 'B'. Can you explain this answer?

Arun Khanna answered
Therefore if monochromatic light in Young's interference experiment is replaced by white light, then the waves of each wavelength form their separate interference patterns. The resultant effect of all these patterns is obtained on the screen. i.e., the waves of all colours reach at mid point M in same phase we will see​.a few coloured bands and then uniform illumination

Phase difference between two coherent sources should be:​
  • a)
    zero
  • b)
    πn rad
  • c)
    π rad
  • d)
    π/2 rad
Correct answer is option 'A'. Can you explain this answer?

Kalyan Joshi answered
Phase difference between two coherent sources should be zero.

Coherent Sources:
Coherent sources are the sources of light that emit light waves of the same frequency and have a constant phase difference with respect to each other. When two coherent sources emit light waves, the waves superimpose to form an interference pattern.

Phase Difference:
The phase difference is the difference in the phase of two waves at a given point in space and time. It is measured in radians or degrees. When two coherent sources emit light waves, the phase difference between them determines the interference pattern.

Explanation:
When two coherent sources emit light waves of the same frequency and zero phase difference, the waves superimpose constructively and form a bright fringe in the interference pattern. If the phase difference between the two sources is not zero, the waves may superimpose destructively, resulting in a dark fringe.

Therefore, to obtain a clear interference pattern, the phase difference between the two sources should be zero. This can be achieved by ensuring that the two sources are of the same frequency and are in phase with each other.

Conclusion:
In conclusion, the phase difference between two coherent sources should be zero to obtain a clear interference pattern. This can be achieved by ensuring that the two sources are of the same frequency and are in phase with each other.

If the light is completely polarized by reflection, then angle between the reflected and refracted light is
  • a)
    π
  • b)
  • c)
    π/2
  • d)
    π/4
Correct answer is option 'C'. Can you explain this answer?

Sant Singh answered
This is in accordance with Brewsters law. When light is incident. When light is incident at Brewsters angle then the refracted and reflected ray are perpendicular to reach other.

Estimate the distance for which ray optics is good approximation for an aperture of 4 mm and wavelength 400 nm.
  • a)
    45 m
  • b)
    50 m
  • c)
    40 m
  • d)
    55 m
Correct answer is option 'C'. Can you explain this answer?

Divey Sethi answered
Here,
Aperture, a = 4 mm = 4 × 10-3 m
Wavelength, λ = 400 nm = 400 × 10-9 m = 4 × 10-7 m 
Ray optics is good approximation upto distances equal to Fresnel's distance (ZF).
Fresnel's distance is given by,

Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.
Assertion : In YDSE, if a thin film is introduced in front of the upper slit, then the fringe pattern shifts in the downward direction.
Reason : In YDSE if the slit widths are unequal, the minima will be completely dark.
  • a)
    If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
  • b)
    If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
  • c)
    If the Assertion is correct but Reason is incorrect.
  • d)
    If both the Assertion and Reason are incorrect.
Correct answer is option 'D'. Can you explain this answer?

Srishti Chavan answered
Assertion: In YDSE, if a thin film is introduced in front of the upper slit, then the fringe pattern shifts in the downward direction.

Reason: In YDSE if the slit widths are unequal, the minima will be completely dark.

The correct answer is option 'D' - both the Assertion and Reason are incorrect.

Explanation:

Assertion: In YDSE, if a thin film is introduced in front of the upper slit, then the fringe pattern shifts in the downward direction.

This assertion is incorrect. When a thin film is introduced in front of the upper slit, it does not cause a shift in the fringe pattern in the downward direction. Instead, it leads to the formation of interference fringes in the form of concentric circles around the central bright fringe. This phenomenon is known as Newton's rings.

Reason: In YDSE if the slit widths are unequal, the minima will be completely dark.

This reason is also incorrect. In a Young's double-slit experiment, when the slit widths are unequal, it does not necessarily result in completely dark minima. The intensity of the minima may vary depending on the relative widths of the slits, but they will not be completely dark. The interference pattern formed by the superposition of the waves from the two slits will still exhibit alternating bright and dark fringes.

Therefore, both the Assertion and Reason are incorrect, leading to the correct answer being option 'D'.

Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.
Assertion : No interference pattern is detected when two coherent sources are infinitely close to each other.
Reason : The fringe width is inversely proportional to the distance between the two sources.
  • a)
    If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
  • b)
    If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
  • c)
    If the Assertion is correct but Reason is incorrect.
  • d)
    If both the Assertion and Reason are incorrect.
Correct answer is option 'A'. Can you explain this answer?

Poulomi Desai answered
Understanding Interference Patterns
Interference patterns arise when two coherent light sources combine their wavefronts. The characteristics of these patterns depend on several factors, including the distance between the sources.
Assertion Explained
- The assertion states that no interference pattern is detected when the two coherent sources are infinitely close to each other.
- This is true because the overlapping waves from two sources that are extremely close become indistinguishable; thus, they cannot create a distinct interference pattern.
Reason Explained
- The reason asserts that the fringe width is inversely proportional to the distance between the two sources.
- This statement is also correct. When the distance between the sources decreases, the fringe width (the distance between bright or dark fringes) increases, leading to a less discernible pattern.
Relationship Between Assertion and Reason
- Both the assertion and reason are accurate.
- The reason helps clarify why the assertion is true: as the sources get closer, the fringe width increases, making the interference pattern less noticeable.
Conclusion
- Therefore, the correct response is option 'A': both Assertion and Reason are correct, and the Reason is a valid explanation for the Assertion.
This understanding of interference patterns is crucial in the study of wave optics and illustrates the relationship between distance and visibility of interference effects.

Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.
Assertion : In Young’s double slit experiment if wavelength of incident monochromatic light is just doubled, the number of bright fringes on the screen will increase.
Reason : Maximum number of bright fringe on the screen is inversely proportional to the wavelength of light used
  • a)
    If both the Assertion and Reason are incorrect.
  • b)
    If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
  • c)
    If the Assertion is correct but Reason is incorrect.
  • d)
    If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion. 
Correct answer is option 'A'. Can you explain this answer?

Upasana Sen answered
Assertion: In Young’s double slit experiment, if the wavelength of incident monochromatic light is doubled, the number of bright fringes on the screen will increase.
Reason: The maximum number of bright fringes on the screen is inversely proportional to the wavelength of light used.

To understand why the correct answer is option 'A', let's break down the Assertion and Reason separately and then see how they relate to each other.

Assertion: In Young’s double slit experiment, if the wavelength of incident monochromatic light is doubled, the number of bright fringes on the screen will increase.

In Young's double-slit experiment, a beam of monochromatic light is passed through two slits, creating an interference pattern on a screen placed behind the slits. The interference pattern consists of alternating bright and dark fringes.

When the wavelength of the incident light is doubled, it means that the light waves are becoming longer. The distance between the bright fringes in the interference pattern is determined by the wavelength of light. A longer wavelength means a larger distance between the fringes.

So, if the wavelength is doubled, the distance between the bright fringes will also double. As a result, the number of bright fringes that can fit on the screen will increase. Therefore, the assertion is correct.

Reason: The maximum number of bright fringes on the screen is inversely proportional to the wavelength of light used.

The reason states that the maximum number of bright fringes on the screen is inversely proportional to the wavelength of light used. In other words, as the wavelength increases, the number of bright fringes decreases.

This reason is correct because the distance between the bright fringes is directly related to the wavelength of light. The formula for calculating the distance between the fringes is given by:

Distance between fringes = (wavelength * distance between slits) / (distance to the screen)

As the wavelength increases, the distance between fringes increases, and therefore, the number of fringes that can fit on the screen decreases. This is because the screen has a limited size, and as the distance between fringes increases, fewer fringes can fit within that limited space.

Therefore, the reason is a correct explanation of the assertion.

Conclusion:

Both the assertion and the reason are correct, and the reason is a correct explanation of the assertion. Hence, the correct answer is option 'A'.

Two sources of light are said to be coherent when both give out light waves of same:​
  • a)
    phase and speed
  • b)
    wave length and constant phase difference
  • c)
    intensity and wavelength
  • d)
    amplitude and phase
Correct answer is option 'B'. Can you explain this answer?

In physics, two wave sources are perfectly coherent if they have a constant phase difference and the same frequency (amplitude may be different).
As c be the speed of light which is constant.
Using, c=νλ
Now same ν gives same λ. for the two light sources.
Example: y1​=A1​sinwt  and y2​=A2​sin(wt+ϕ) where ϕ is constant.

According to Huygens construction relation between old and new wave fronts is
  • a)
    new wave front is parallel to old wave front
  • b)
    new wave front is the forward envelope of the secondary waves
  • c)
    new wave front is perpendicular to old wave front
  • d)
    new wave front is tangential to old wave front
Correct answer is option 'B'. Can you explain this answer?

Roshni Desai answered
The Huygens-Fresnel principle states that every point on a wavefront is a source of wavelets. These wavelets spread out in the forward direction, at the same speed as the source wave. The new wavefront is a line tangent to all of the wavelets.
The correct answer is option B.

Directions : In the following questions, A statement of Assertion(A) is followed by a statement of Reason (R). Mark the correct choice as.
Assertion (A): Diffraction takes place with all types of waves.
Reason (R): Diffraction is perceptible when the wavelength of the wave is comparable to the dimension of the diffracting device.
  • a)
    Both A and R are true and R is the correct explanation of A
  • b)
    Both A and R are true but R is NOT the correct explanation of A
  • c)
    A is true but R is false
  • d)
    A is false and R is true
Correct answer is option 'B'. Can you explain this answer?

Kalyan Chavan answered
Assertion (A): Diffraction takes place with all types of waves.
Reason (R): Diffraction is perceptible when the wavelength of the wave is comparable to the dimension of the diffracting device.

Explanation:
Diffration and its occurrence:
- Diffraction is the bending or spreading of waves as they pass through an opening or around obstacles.
- It occurs with all types of waves, including light waves, sound waves, water waves, and even matter waves such as electrons.
- When a wave encounters an obstacle or passes through an opening, it bends and spreads out, resulting in diffraction.

Wavelength and Diffraction:
- The wavelength of a wave is the distance between two consecutive points in a wave that are in phase.
- Diffraction is perceptible when the wavelength of the wave is comparable to the dimension of the diffracting device.
- In other words, when the size of the opening or obstacle is similar to the wavelength of the wave, significant diffraction occurs.
- The diffraction pattern depends on the ratio of the wavelength of the wave to the size of the opening or obstacle.

Explanation of Assertion and Reason:
- Assertion (A) states that diffraction takes place with all types of waves, which is true.
- Reason (R) states that diffraction is perceptible when the wavelength of the wave is comparable to the dimension of the diffracting device, which is also true.
- The reason provided in (R) correctly explains why diffraction occurs.

Conclusion:
- Both Assertion (A) and Reason (R) are true.
- Reason (R) is the correct explanation of Assertion (A).
- Therefore, the correct answer is option 'B'.

Is light a particle or a wave?
  • a)
    Both particle and wave approaches help us understand different phenomenon
  • b)
    Light is schizophrenic i.e. sometimes it behaves like a particle and other times like a wave.
  • c)
    Light is a set of particles
  • d)
    Light is a set of waves
Correct answer is option 'A'. Can you explain this answer?

Understanding the nature of light:
Light has been a subject of scientific investigation for centuries, and its nature has been a topic of debate among scientists. Initially, scientists believed that light behaves solely like a particle, known as the corpuscular theory of light. However, with the advent of experiments and further research, it became evident that light exhibits characteristics of both particles and waves. This understanding led to the development of the wave-particle duality theory, which states that light can behave as both a particle and a wave, depending on the experimental conditions and the phenomenon under study.

Particle-like behavior of light:
When light interacts with matter, it exhibits certain particle-like characteristics. These characteristics include the ability to transfer energy and momentum in discrete amounts called photons. Photons have no mass but possess energy proportional to their frequency, according to the equation E=hf (where E is energy, h is Planck's constant, and f is the frequency of light). This particle-like behavior is observed in phenomena like the photoelectric effect, where light incident on a metal surface causes the emission of electrons.

Wave-like behavior of light:
On the other hand, light also exhibits wave-like characteristics. When light propagates through space, it shows properties such as diffraction, interference, and polarization. Diffraction refers to the bending of light around obstacles or through narrow openings, similar to how waves bend around objects in water. Interference occurs when two or more light waves superpose, either constructively (resulting in bright regions) or destructively (resulting in dark regions), depending on their relative phase. Polarization refers to the alignment of the electric field vectors of light waves, which can be manipulated using filters.

Complementary nature of particle and wave descriptions:
The wave-particle duality theory suggests that light is neither exclusively a particle nor a wave, but a combination of both. The particle and wave approaches are complementary and help us understand different phenomena associated with light. For instance, the particle nature of light explains phenomena like the photoelectric effect and the emission and absorption of photons, while the wave nature of light explains phenomena like interference and diffraction.

Conclusion:
In conclusion, light is best described as exhibiting both particle-like and wave-like behavior. The particle and wave approaches are essential in understanding different aspects of light and its interaction with matter. While the particle behavior explains discrete energy transfer and certain phenomena, the wave behavior explains properties such as diffraction, interference, and polarization. Therefore, option 'A' is the correct answer as it acknowledges the complementary nature of the particle and wave descriptions of light.

Chapter doubts & questions for Wave Optics - NCERT Based Tests for NEET 2025 is part of NEET exam preparation. The chapters have been prepared according to the NEET exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for NEET 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

Chapter doubts & questions of Wave Optics - NCERT Based Tests for NEET in English & Hindi are available as part of NEET exam. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Top Courses NEET

Related NEET Content