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All questions of Chapter 10 - Vectors for JEE Exam

The area of triangle whose adjacent sides are is :
  • a)
    √70/2 sq. units
  • b)
    9√2 /2 sq. units
  • c)
    3√3 /2 sq. units
  • d)
    2√3 /2 sq. units
Correct answer is option 'A'. Can you explain this answer?

Suresh Iyer answered
Area of triangle = ½(a * b)
a = (1, 0, -2)   b = (2, 3, 1)
= i(0 + 6) + j(-4 - 1) + k(3 - 0)
= 6i - 5j + 3k
|a * b| = (36 + 25 + 9)½
|a * b| = (70)½
Area of triangle = ½(a * b)
= [(70)½]/2

A vector of magnitude 14 units, which is parallel to the vector
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?

EduRev JEE answered
Given vector = i + 2j - 3k
Magnitude = √12 + 22 + (-3)2 = √14
Unit vector in direction of resultant = (i + 2j - 3k) / √14
Vector of magnitude 14​ unit in direction of resultant,
⇒ 14[ (i + 2j - 3k) / √14 ]
⇒ √14(i + 2j - 3k)

The value of  is:
  • a)
    0
  • b)
    3
  • c)
    1/3
  • d)
    1
Correct answer is option 'B'. Can you explain this answer?

Sahil Soni answered
Cross multiply in maths take place in cycle like i》j》k i×j=k j×k=i k×i=j but j×i=-k k×j=-i i×k=-j and dotmultiply takes place as i.i=1j.j=1K.K=1BUTI.J=0J.K=0k.i=0so the correct answer is b

The points with position vectors  are collinear vectors, Value of a =​
  • a)
    -20
  • b)
    20
  • c)
    -40
  • d)
    40
Correct answer is option 'C'. Can you explain this answer?

Om Desai answered
Position vector A = 60i+3j
Position vector B = 40i-8j
Position vector C = aj-52j
Now, find vector AB and BC
AB = -20i-11j
BC= (a-40)i-44j
To be collinear,  angle between the vector AB and BC made by the given position vectors should be 0 or 180 degree.
That’s why the cross product of  the vectors should be zero
ABXBC=(-20i-11j)X(a-40)i-44j
0i+0j+(880+11(a-40))=0
a-40= -80
a=-40
Therefore, a should be -40 to be the given positions vectors collinear.

The unit vector in the direction of , where A and B are the points (2, – 3, 7) and (1, 3, – 4) is:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?

Sushil Kumar answered
Given, Point A (2,-3,7)
Point B (1,3,-4)
Let vector in the direction of AB be C.
∴ C = B - A
⇒ (1,3,-4) - (2,-3,7)
⇒ ( 1-2 , 3+3 , -4-7 )
⇒ (-1,6,-11)
⇒ -1i + 6j -11k
Magnitude of vector C
|C| = √(-1)2 + 62 + (-11)2
⇒ √1+36+121
⇒ √158
Unit vector = (Vector)/(Magnitude of vector)
Unit vector C = (C vector)/(Magnitude of C vector)  = (-1i + 6j -11k)/√158

If  and , then the value of scalars x and y are:
  • a)
    x = 1 and y = -2
  • b)
    x = -2 and y = 1
  • c)
    x = 2 and y = -1
  • d)
    x = 2 and y = 1
Correct answer is option 'C'. Can you explain this answer?

Sushil Kumar answered
Given, a = i + 2j
b = -2i + j
c = 4i +3j
Also, c = xa +yb
Now putting the values in above equation,
4i + 3j  = x(i + 2j) + y(-2i +j)
⇒ xi + 2xj - 2yi + yj
⇒ (x-2y)i + (2x+y)j
We get,
x - 2y = 4
2x + y = 3
After solving,            
x = 2
y = -1

In the triangle ABC, which statement is not true?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?

sanju sura answered
Ab + bc > ac ...it is property of a triangle .... that sum of two sides is greater than the third side ... so I think it is no possible that ab +bc -ca =0...but I'm not understanding the logic behind the question.......😊

If a and b are the position vectors of two points A and B and C is a point on AB produced such that AC = 3AB, then position vector of C will be​
  • a)
    3b – 2a
  • b)
    3a – b
  • c)
    3a – 2b
  • d)
    3b – a
Correct answer is option 'A'. Can you explain this answer?

Anuj Datta answered
Given information:

- Position vector of point A: a
- Position vector of point B: b
- Point C is on line AB produced such that AC = 3AB

To find:

- Position vector of point C

Solution:

Step 1: Find the vector AB

The vector AB is given by:

AB = b - a

Step 2: Find the vector AC

Since AC = 3AB, we can write:

AC = 3(b - a)

Step 3: Find the position vector of C

The position vector of C can be obtained by adding the vector AC to the position vector of A:

C = A + AC

Substituting the values of A and AC, we get:

C = a + 3(b - a)

Simplifying, we get:

C = 3b - 2a

Therefore, the position vector of point C is 3b - 2a.

Answer: Option A (3b - 2a)

If the magnitude of the position vector is 7, the value of x is:​
  • a)
    ±1
  • b)
    ±5
  • c)
    ±3
  • d)
    ±2
Correct answer is option 'C'. Can you explain this answer?

Aryan Khanna answered

|a| = (x2 + 22 + (2x)2)1/2
7 = (x2 + 22 + (2x)2)1/2
⇒ 49 = x2 + 22 + 4x2
⇒ 49 = 4 + 5x2
⇒ 5x2 = 45
⇒ x2 = 9
x = ±3

If  are two vectors, such that , then = ……​
  • a)
    3
  • b)
    √7
  • c)
    √5
  • d)
    √3
Correct answer is option 'D'. Can you explain this answer?

Neha Sharma answered
 |a - b|2 = |a|2 + |b|2 - 2|a||b|
|a - b|2  = (3)2 + (2)2 - 2(5)
|a - b|2  = 9 + 4 - 10
|a - b|2  = 3 
|a - b|   = (3)½.

What is the additive identity of a vector?​
  • a)
    zero vector
  • b)
    Negative of the vector
  • c)
    unit vector
  • d)
    The vector itself
Correct answer is option 'A'. Can you explain this answer?

Nandini Iyer answered
In the Additive Identity of vectors, the additive identity is zero vector 0.
For any vector V additive identity is defined as,
0 + V = V and V + 0 = V

If  are unit vectors along X-axis, Y-axis and Z-axis respectively, then
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?

As per the rules i×i=0 and i×k=-j and also j=-1 so -1×-1=1.So (A)is correct answer because i×j = k is correct.

For any two vectors a and b​, we always have
  • a)
    |a – b| ≥ |a| – |b|
  • b)
    |a + b| ≤ |a| + |b|
  • c)
    |a + b| ≤ |a| – |b|
  • d)
    |a – b| = |a + b|
Correct answer is option 'B'. Can you explain this answer?

Nandini Iyer answered
|a + b|2 = |a|2 + |b|2 + 2|a||b|.cosθ
|a|2 + |b|2 = |a|2 + |b|2 + 2|a| + |b|  ∵ −1 ⩽ cosθ ⩽ 1
⇒ 2|a||b|.cosθ ⩽ 2|a||b|
So, |a + b|2 ⩽ (|a| + |b|
)2

⇒ |a + b| ≤ |a| + |b|
This is also known as Triangle Inequality of vectors.

The vector joining the points A(2, – 3, 1) and B(1, – 2, – 5) directed from B to A is:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?

Siddhant Kumar answered
The vector goes from B to A means that its initial coordinates is at B and final at A.
so the vector BA will be [ (2-1)i + (-3+2) j + (1+5)k ] = i-j+6k.

If  , then
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?

Lavanya Menon answered
a = 2i + 3j - 6k
|a| = √4+9+36 = √49 = 7
b = 6i - 2j + 3k
|b| = √36+4+9 = √49 = 7
|a| = |b|
Hence, option A is correct.

इनमें से कौन-सा क्षेत्र प्रागैतिहासिक शैल कला चित्रों की मेजबानी के लिए प्रसिद्ध हैं?
1. मध्य प्रदेश की विंध्य पर्वतमाला
2. उत्तर प्रदेश का कैमूरियन विस्तार
उपरोक्त में से कौन सा/से सही हैं?
  • a)
    केवल 1
  • b)
    केवल 2
  • c)
    दोनों 1 और 2
  • d)
    इनमे से कोई भी नहीं
Correct answer is option 'C'. Can you explain this answer?

Amit Sharma answered
  • मध्य प्रदेश के विंध्य पर्वतमाला और उत्तर प्रदेश में उनके कैमूरियन विस्तार से सबसे समृद्ध चित्रों की सूचना मिली है। ये पर्वत श्रृंखलाएं पुरापाषाण और मध्यपाषाणकालीन अवशेषों से परिपूर्ण हैं। 9000 ईसा पूर्व में पाषाण युग की संस्कृति में एक मध्यवर्ती चरण शुरू हुआ, जिसे मेसोलिथिक युग कहा जाता है।
  • मध्य प्रदेश, उत्तर प्रदेश, आंध्र प्रदेश, कामतका और बिहार के कई जिलों की गुफाओं में शैल चित्रों के अवशेष हैं।
  • उत्तराखंड में कुमाऊं की पहाड़ियां भी शैल चित्रों के लिए जानी जाती हैं।

Two or more vectors having the same initial point are called​
  • a)
    co-terminus vectors.
  • b)
    zero vectors
  • c)
    co-initial vectors
  • d)
    unit vectors
Correct answer is option 'C'. Can you explain this answer?

Naina Bansal answered
Two or more vectors having the same initial point are called coinitial vector. Two or more vectors are said to be collinear,if they are parallel to the same line,irrespective of their magnitudes and directions.

A point from a vector starts is called …… and where it ends is called its ……​
  • a)
    terminal point, end point.
  • b)
    initial point, terminal point
  • c)
    Origin, end point
  • d)
    initial point, end point
Correct answer is option 'B'. Can you explain this answer?

Gauri Rane answered
A vector is a specific quantity drawn as a line segment with an arrowhead at one end. It has an initial point, where it begins, and a terminal point, where it ends. A vector is defined by its magnitude, or the length of the line, and its direction, indicated by an arrowhead at the terminal point.

  • a)
    collinear
  • b)
    equal
  • c)
    not equal and not collinear
  • d)
     none of these
Correct answer is option 'A'. Can you explain this answer?

Akshay Sharma answered
 collinear vectors , because they are parallel in direction and having the same magnitude.

Chapter doubts & questions for Chapter 10 - Vectors - Mathematics CUET UG Mock Test Series 2025 2025 is part of JEE exam preparation. The chapters have been prepared according to the JEE exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

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