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All questions of Problem on Ages for DSSSB TGT/PGT/PRT Exam

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The ratio between the present ages of Ravi and Vinay is 7:15 respectively. Two years from now Vinay’s age will be twice that of Ravi’s age. What was the difference between their ages 5 years ago.
  • a)
    13 years                   
  • b)
    16 years
  • c)
    11 years                   
  • d)
    18 years
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Dia Mehta answered
The correct option is B.
Let the present age of Ravi be 7x and that of Vinay be 15x.
After 2 yrs , Ravi age = 7x+2
Vinay age = 15x+2.
Acc. to ques,
15x+2 = 2 (7x+2)
15x+2 = 14x+4
 x = 2.
Five yrs ago,
 Ravi age = 7x-5 => 7*2 - 5 = 9 yrs
 Vinay age = 15x - 5 = 15*2 - 5 = 25 yrs.
Difference = 25 - 9 = 16 years

A father said to his son, “At the time of your birth, I was as old as you are at present”. If father’s age is 38 years now the sons age 5 years back was
  • a)
    14 years                   
  • b)
    19 years
  • c)
    33 years                   
  • d)
    38 years
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Prani Garg answered
HERE IS YOUR ANSWER.

Let the present age of son= x
At the time of birth of son,father age = x
So after x yrs i.e. at present age of father= 38
38=x+x
x= 38÷2= 19
So the present age of son is 19
Age of son before 5 yrs= 19-5= 14 yrs.

HOPE IT HELPS.

The average age of a man and his two twin sons is 30 years. The ratio of the ages of father and one of his sons is 5:2. What is the father’s age
  • a)
    50 years                   
  • b)
    30 years
  • c)
    45 years                   
  • d)
    20 years
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Let father's age be M and age of twins be 2x
(M + 2x)/3 = 30
M + 2x = 90------------(1)
M/x = 5/2
2M = 5x---------------(2)
Multiply (1) with 2
We get, 2M + 4x = 180--------------(3)
Putting (2) in (3)
5x+4x = 180 => 9x = 180x = 20. [his children are twins so 2x = 40]Since M + 2x = 90M = 90 -40 = 50years

Two years ago the ratio of ages of A and B was 5:7. Two years hence the ratio of their ages will be 7:9. What is the present age of B.
  • a)
    16 years                   
  • b)
    14.5 years
  • c)
    12 years                   
  • d)
    15 years
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Aarav Sharma answered
Given:
The ratio of ages of A and B two years ago = 5:7
The ratio of their ages two years hence = 7:9

To find: Present age of B

Solution:
Let the present ages of A and B be A and B respectively.
According to the given condition,

(A-2)/(B-2) = 5/7 ----(1)
(A+2)/(B+2) = 7/9 ----(2)

Solving the above equations, we get:

A = 22
B = 28

Therefore, the present age of B is 28 years.

Answer: (a) 16 years

The average age of a man and his son is 54 years. The ratio of their ages is 23: 13. What will be the ratio of their ages after 6 years.
  • a)
    10:7                         
  • b)
    5:3
  • c)
    4:3                           
  • d)
    3:2
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Devil answered
Let the age of a man be 23x.And age of his son 13x. Now ,Average age = (23x + 13 x )/ 2 = 54 = 36 x / 2 = 54 = 18x. = 54 = x. = 54 / 18 = 3.
Present age of man = 23 x = 23 *3 = 69And present age of his son = 13x = 13* 3 = 39Then ,
After 6 years ,Age of a man = 69 + 6 = 75 years.And age of his son = 39 + 6 = 45 years
So, man. : son = 75 : 45 = 5: 3.

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