All Exams >
RRB NTPC/ASM/CA/TA >
Mathematics for RRB NTPC / ASM >
All Questions
All questions of Compound & Simple Interest for RRB NTPC/ASM/CA/TA Exam
Find the sum of money when increases 1/10 of itself every year amount to Rs. 600 in 5 years.- a)Rs. 380
- b)Rs. 280
- c)Rs. 480
- d)None
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
Find the sum of money when increases 1/10 of itself every year amount to Rs. 600 in 5 years.
a)
Rs. 380
b)
Rs. 280
c)
Rs. 480
d)
None
e)
All of the above
|
Ishani Rane answered |
This is an example of an exponential growth problem. Exponential growth can be modeled by the equation P = a(r)t, where a is the initial amount, t is the time that has passed, P is the amount after time t, and r is the rate of growth.
For your problem, t = 5 years and P = 600. The money increases by 1/10 = 10% each year, so each year, the amount of money is 110% of the previous year. That's a rate of growth of r = 1.1. So:
600 = a(1.1)5
600 = 1.61051a
372.55 = a
The sum was initially Rs. 372.55.
Can you explain the answer of this question below:A sum of money amounts to Rs.9800 after 5 years and Rs.12005 after 8 years at the same rate of simple interest. The rate of interest per annum is- A:15%
- B:12%
- C:8%
- D:5%
The answer is B.
|
Arya Roy answered |
We can get SI of 3 years = 12005 - 9800 = 2205
SI for 5 years = (2205/3)*5 = 3675 [so that we can get principal amount after deducting SI]
Principal = 12005 - 3675 = 6125
So Rate = (100*3675)/(6125*5) = 12%
If the simple interest on a certain sum of money after 25/8 years is 1/4 of the principal, what is the rate of interest per annum?
- a)6%
- b)4%
- c)8%
- d)12%
Correct answer is option 'C'. Can you explain this answer?
If the simple interest on a certain sum of money after 25/8 years is 1/4 of the principal, what is the rate of interest per annum?
a)
6%
b)
4%
c)
8%
d)
12%
|
Rahul Mehta answered |
Take P=x
given T=25/8
& I=1/4x
w.k.t I=PTR/100
1/4x =x*25/8*R/100
R = 8%
given T=25/8
& I=1/4x
w.k.t I=PTR/100
1/4x =x*25/8*R/100
R = 8%
Find the Compound Interest on Rs. 12500 at 8% per annum for 9 months compounded quarterly.
- a)Rs.1020
- b)Rs. 1428
- c)Rs. 510
- d)765.1
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
Find the Compound Interest on Rs. 12500 at 8% per annum for 9 months compounded quarterly.
a)
Rs.1020
b)
Rs. 1428
c)
Rs. 510
d)
765.1
e)
All of the above
|
Aryan Khanna answered |
The correct is D as
n=9 months
=3 quaterly
A=12500×(1+2/100)^3
=12500×51/50×51/50×51/50
=Rs.13265.1
CI=A−P
=13265.1−12500
=Rs.765.1
n=9 months
=3 quaterly
A=12500×(1+2/100)^3
=12500×51/50×51/50×51/50
=Rs.13265.1
CI=A−P
=13265.1−12500
=Rs.765.1
A sum of money at simple interest amounts to Rs. 815 in 3 years and to Rs. 854 in 4 years. The sum is :- a)Rs. 700
- b)Rs. 690
- c)Rs. 650
- d)Rs. 698
Correct answer is option 'D'. Can you explain this answer?
a)
Rs. 700
b)
Rs. 690
c)
Rs. 650
d)
Rs. 698
|
Dhruv Mehra answered |
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 * 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
An automobile financier claims to be lending money at simple interest, but he includes the interest every six months for calculating the principal. If he is charging an interest of 10%, the effective rate of interest becomes:- a)10%
- b)10.25%
- c)10.5%
- d)None of these
Correct answer is option 'B'. Can you explain this answer?
a)
10%
b)
10.25%
c)
10.5%
d)
None of these
|
Master Training Institute answered |
B is the correct option. Solution
6 months interest will be 5%
next 6 months interest will be 5%
percentage effect = 5 + 5 +25/100
= 10.25 Ans
6 months interest will be 5%
next 6 months interest will be 5%
percentage effect = 5 + 5 +25/100
= 10.25 Ans
A sum was put at simple interest at a certain rate for 2 years. Had it been put at 4% higher rate, it would have fetched Rs. 112 more. The sum is:- a)1120
- b)1400
- c)1200
- d)8000
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A sum was put at simple interest at a certain rate for 2 years. Had it been put at 4% higher rate, it would have fetched Rs. 112 more. The sum is:
a)
1120
b)
1400
c)
1200
d)
8000
e)
None of these
|
|
Anaya Patel answered |
The correct answer is C as let principle be p , rate be r , si be x . Also t = 2yrs.
so , x = (p*r*2)/100
x = 2pr/100 _____(1)
If rate = r+4 , si = x+112 then
x+112 = (p*(r+4)*2)/100
x+112 = 2p(r+4)/100
2pr/100+112 = (2pr+8p)/100 (using eq(1))
(2pr+11200)/100 = (2pr+8p)/100
2pr+11200 = 2pr+8p
11200 = 8p
p = 1400
Correct ans is b) 1400
so , x = (p*r*2)/100
x = 2pr/100 _____(1)
If rate = r+4 , si = x+112 then
x+112 = (p*(r+4)*2)/100
x+112 = 2p(r+4)/100
2pr/100+112 = (2pr+8p)/100 (using eq(1))
(2pr+11200)/100 = (2pr+8p)/100
2pr+11200 = 2pr+8p
11200 = 8p
p = 1400
Correct ans is b) 1400
The difference between simple interest and compound on Rs. 900 for one year at 10% per annum reckoned half-yearly is: - a)Rs. 3
- b)Rs. 2.25
- c)Rs. 4.5
- d)Rs. 4
Correct answer is option 'B'. Can you explain this answer?
a)
Rs. 3
b)
Rs. 2.25
c)
Rs. 4.5
d)
Rs. 4
|
Maheshwar Banerjee answered |
Hence Option B is correct
For Complete syllabus of Quant for CAT click on the link given below:
A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is:
- a)Rs. 120
- b)Rs. 121
- c)Rs. 123
- d)Rs. 122
Correct answer is option 'B'. Can you explain this answer?
A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is:
a)
Rs. 120
b)
Rs. 121
c)
Rs. 123
d)
Rs. 122
|
|
Ishani Rane answered |
Simple interest on a certain sum of money for 4 years at 5% per annum is half the compound interest on Rs. 3000 for 2 years at 10% per annum. The sum placed on simple interest is: - a)Rs.1575
- b)Rs. 2200
- c)Rs. 1200
- d)Rs. 1625
Correct answer is option 'A'. Can you explain this answer?
a)
Rs.1575
b)
Rs. 2200
c)
Rs. 1200
d)
Rs. 1625
|
KS Coaching Center answered |
C.I = P[(1 + r/100)n - 1]
C.I = 3000[(1 + 0.10)2 - 1]
= 3000(1.21 - 1)
⇒ 3000 * 0.21
⇒ 630
S.I = 630/2
⇒ 315
As we know that, P = (SI * 100)/(R * T)
⇒ (315 * 100)/(4 * 5)
⇒ 1575
C.I = 3000[(1 + 0.10)2 - 1]
= 3000(1.21 - 1)
⇒ 3000 * 0.21
⇒ 630
S.I = 630/2
⇒ 315
As we know that, P = (SI * 100)/(R * T)
⇒ (315 * 100)/(4 * 5)
⇒ 1575
At what rate percent per annum simple Interestwill a sum of money be 1.1 times in 2 years?
- a)2%
- b)3%
- c)4%
- d)None
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
At what rate percent per annum simple Interestwill a sum of money be 1.1 times in 2 years?
a)
2%
b)
3%
c)
4%
d)
None
e)
All of the above
|
|
Anaya Patel answered |
The correct answer is D as the rate would be 5 % which is not in given options . so the D would be the correct option.
In what time Rs. 2600 amount to Rs. 3055 at the rate of 3 ½ % per annum.- a)2½ years
- b)5 years
- c)3 years
- d)None
- e)All of the above
Correct answer is option 'B'. Can you explain this answer?
In what time Rs. 2600 amount to Rs. 3055 at the rate of 3 ½ % per annum.
a)
2½ years
b)
5 years
c)
3 years
d)
None
e)
All of the above
|
Faizan Khan answered |
The correct option is B.
Principal amount=2600
Rate=3 1/2%pa=7/2
Time = T
SI=3055-2600=455
SI=PRT/100
455=2600×7×T/100×2,
T=5yrs.
Principal amount=2600
Rate=3 1/2%pa=7/2
Time = T
SI=3055-2600=455
SI=PRT/100
455=2600×7×T/100×2,
T=5yrs.
Arun took a loan of Rs. 1400 with simple interest for as many years as the rate of interest. If he paid Rs.686 as interest at the end of the loan period, what was the rate of interest?- a)8%
- b)6%
- c)4%
- d)7%
Correct answer is option 'D'. Can you explain this answer?
a)
8%
b)
6%
c)
4%
d)
7%
|
Meghana Mishra answered |
Simple Interest (SI) = P N R / 100
P is the Principal loan amount = Rs.1400
N is the number of years of deposit
R is the rate of interest
It is given that the loan period is as many years as the rate of interest.
So, N = R
Interest at the end of the loan period (SI ) = Rs.686
So,
686 = 1400 * R * R /100
R^2 = 686*100 /1400
R^2 = 49
R = 7%
A lends Rs. 1500 to B and a certain sum to C at the same time at 8% per annum simple interest. If after 4 years, A altogether receives Rs. 1400 as interest from B and C, then the sum lent to C is A.
- a)Rs.2875
- b)Rs.1885
- c)Rs.2245
- d)Rs.2615
Correct answer is option 'A'. Can you explain this answer?
A lends Rs. 1500 to B and a certain sum to C at the same time at 8% per annum simple interest. If after 4 years, A altogether receives Rs. 1400 as interest from B and C, then the sum lent to C is A.
a)
Rs.2875
b)
Rs.1885
c)
Rs.2245
d)
Rs.2615
|
EduRev SSC CGL answered |
A is the correct option.
Simple interest on the total money lent at
8% FOR 4 YEARS = 1400
Total money lent
= 100/8 × 1400/4 =4375
Therefore, money lent to C
= 4375- 1400 = 2875
Simple interest on the total money lent at
8% FOR 4 YEARS = 1400
Total money lent
= 100/8 × 1400/4 =4375
Therefore, money lent to C
= 4375- 1400 = 2875
A sum of Rs. 14,000 amounts to Rs. 22,400 in 12 years at the rate of simple interest. What is the rate of interest?- a)7%
- b)6%
- c)5%
- d)4%
Correct answer is option 'C'. Can you explain this answer?
a)
7%
b)
6%
c)
5%
d)
4%
|
Nandini Iyer answered |
Simple Interest for 12 years (SI) = (22400 - 14000) = Rs.8400
R = ?
T = 12 years
P = Rs. 14000
R=100 X SI/PT=100 X 8400/14000 X 12
=5%
Can you explain the answer of this question below:Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?- A:Rs. 6400
- B:Rs. 7200
- C:Rs. 6500
- D:Rs. 7500
The answer is A.
A:
Rs. 6400
B:
Rs. 7200
C:
Rs. 6500
D:
Rs. 7500
|
Pallabi Deshpande answered |
Ravi borrowed some money at the rate of 4 pcpa for the first three years, at the rate of 8 pcpa for the next two years and at the rate of 9 pcpa for the period beyond 5 years. If he pays a total simple interest of Rs. 19550 at the end of 7 years, how much money did he borrow?- a)Rs. 39,500
- b)Rs. 42,500
- c)Rs. 41,900
- d)Rs. 43,000
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Ravi borrowed some money at the rate of 4 pcpa for the first three years, at the rate of 8 pcpa for the next two years and at the rate of 9 pcpa for the period beyond 5 years. If he pays a total simple interest of Rs. 19550 at the end of 7 years, how much money did he borrow?
a)
Rs. 39,500
b)
Rs. 42,500
c)
Rs. 41,900
d)
Rs. 43,000
e)
None of these
|
Aspire Academy answered |
The correct answer is B .as f the amount borrowed be Rs.x, then
x×4×6
100
+
x×8×2
100
+
x×9×2
100
x×4×6100+x×8×2100+x×9×2100 = Rs.19550Th
=>
12x100+16x100+18x10012x100+16x100+18x100 = 19550
=> 12x+16x+18x
= 1955000
=> 46x = 1955000
=> x = 19550000
46
1955000046
= Rs.42500
x×4×6
100
+
x×8×2
100
+
x×9×2
100
x×4×6100+x×8×2100+x×9×2100 = Rs.19550Th
=>
12x100+16x100+18x10012x100+16x100+18x100 = 19550
=> 12x+16x+18x
= 1955000
=> 46x = 1955000
=> x = 19550000
46
1955000046
= Rs.42500
A sum was put at simple interest at a certain rate for 5 years. had it been put at 5% higher rate, it would have fetched Rs. 500 more. What is the sum?- a)Rs. 2000
- b)Rs. 2400
- c)Rs. 2500
- d)Rs. 3200
- e)Rs. 4400
Correct answer is option 'A'. Can you explain this answer?
A sum was put at simple interest at a certain rate for 5 years. had it been put at 5% higher rate, it would have fetched Rs. 500 more. What is the sum?
a)
Rs. 2000
b)
Rs. 2400
c)
Rs. 2500
d)
Rs. 3200
e)
Rs. 4400
|
Shanaya Sharma answered |
For first case , let principle be p , rate be r , si be x . Also t = 5 yrs.
so , x = (p*r*5)/100
x = 5pr/100 _____(1)
If rate = r+5 , si = x+500 then
x+500 = (p*(r+5)*5)/100
x+500 = 5p(r+5)/100
5pr/100+500 = (5pr+25p)/100 (using eq(1))
(5pr+50000)/100 = (5pr+25p)/100
5pr+50000 = 5pr+25p
50000 = 25p
p = 2000
Correct ans is a) 2000
so , x = (p*r*5)/100
x = 5pr/100 _____(1)
If rate = r+5 , si = x+500 then
x+500 = (p*(r+5)*5)/100
x+500 = 5p(r+5)/100
5pr/100+500 = (5pr+25p)/100 (using eq(1))
(5pr+50000)/100 = (5pr+25p)/100
5pr+50000 = 5pr+25p
50000 = 25p
p = 2000
Correct ans is a) 2000
A man took loan from a bank at the rate of 8% p.a. simple interest. After 4 years he had to pay Rs. 6200 interest only for the period. The principal amount borrowed by him was:- a)Rs.17322
- b)Rs.20245
- c)Rs.18230
- d)Rs.19375
Correct answer is option 'D'. Can you explain this answer?
a)
Rs.17322
b)
Rs.20245
c)
Rs.18230
d)
Rs.19375
|
|
Aarav Sharma answered |
Given:
Rate of interest = 8% p.a.
Interest paid after 4 years = Rs. 6200
To find: Principal amount borrowed
Formula: Simple Interest = (P * R * T) / 100
Where,
P = Principal amount
R = Rate of interest
T = Time (in years)
Calculation:
Let the principal amount be P.
Simple Interest for 4 years = Rs. 6200
=> (P * 8 * 4) / 100 = Rs. 6200
=> 32P = 620000
=> P = Rs. 19375
Therefore, the principal amount borrowed was Rs. 19375.
Rate of interest = 8% p.a.
Interest paid after 4 years = Rs. 6200
To find: Principal amount borrowed
Formula: Simple Interest = (P * R * T) / 100
Where,
P = Principal amount
R = Rate of interest
T = Time (in years)
Calculation:
Let the principal amount be P.
Simple Interest for 4 years = Rs. 6200
=> (P * 8 * 4) / 100 = Rs. 6200
=> 32P = 620000
=> P = Rs. 19375
Therefore, the principal amount borrowed was Rs. 19375.
The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is- a)5
- b)4
- c)6
- d)2
Correct answer is option 'B'. Can you explain this answer?
a)
5
b)
4
c)
6
d)
2
|
|
Anaya Patel answered |
P [1 + (r/100)]n > 2P
⇒ P [1 + (20/100)]n > 2P
[1 + (2/10) ]n > 2
[12 / 10]n > 2
[6/5]n > 2
{6/5 * 6/5 * 6/5 * 6/5} > 2
∴ n = 4
⇒ P [1 + (20/100)]n > 2P
[1 + (2/10) ]n > 2
[12 / 10]n > 2
[6/5]n > 2
{6/5 * 6/5 * 6/5 * 6/5} > 2
∴ n = 4
.)In what time Rs. 540 at 5 percent per annum will produce the same Interest as Rs. 1800 in 5 years at 6 percent per annum.- a)10 years
- b)30 years
- c)25 years
- d)None
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
.)In what time Rs. 540 at 5 percent per annum will produce the same Interest as Rs. 1800 in 5 years at 6 percent per annum.
a)
10 years
b)
30 years
c)
25 years
d)
None
e)
All of the above
|
Bank Exams India answered |
Using the simple interest formula I = PRT, we set the interests equal: 540 * 0.05 * T = 1800 * 0.06 * 5. 27T = 540. T = 20 years. Since 20 isn't an option, the answer is D.
The compound interest accrued on an amount of the end of two years @ 12 p.c.p.a. is Rs. 2862/- What is the amount?- a)Rs. 11,250/-
- b)Rs. 12,200/-
- c)Rs. 13,500/-
- d)Rs. 10,000
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
The compound interest accrued on an amount of the end of two years @ 12 p.c.p.a. is Rs. 2862/- What is the amount?
a)
Rs. 11,250/-
b)
Rs. 12,200/-
c)
Rs. 13,500/-
d)
Rs. 10,000
e)
None of these
|
Glance Learning Institute answered |
The correct answer is A as
CI = P((1+R/100)^n - 1)
2862 = P(( 1+12/100)^2-1)
2862 = P((1+144/10000 + 24/100) -1)
2862 = P (144/10000+24/100)
2862 = P (2544/10000)
P = 11,250
CI = P((1+R/100)^n - 1)
2862 = P(( 1+12/100)^2-1)
2862 = P((1+144/10000 + 24/100) -1)
2862 = P (144/10000+24/100)
2862 = P (2544/10000)
P = 11,250
A man had Rs. 5800 a part of which he lent at 4% and rest at 6%. The whole annual interest received was Rs. 292. The money lent at 4% was ……?- a)Rs. 3000
- b)Rs. 2600
- c)Rs. 2700
- d)None
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
A man had Rs. 5800 a part of which he lent at 4% and rest at 6%. The whole annual interest received was Rs. 292. The money lent at 4% was ……?
a)
Rs. 3000
b)
Rs. 2600
c)
Rs. 2700
d)
None
e)
All of the above
|
|
Anaya Patel answered |
The correct option is D as Let the part lent at 4% be x then , rest will be (5800-x) .
(x*4*1)/100 + { (5800-x)*6*1 } / 100 = 292
4x/100 + { 34800 - 6x }/100 = 292
4x + 34800 - 6x = 29200
2x = 5600
x = 2800 so , d is correct option.
(x*4*1)/100 + { (5800-x)*6*1 } / 100 = 292
4x/100 + { 34800 - 6x }/100 = 292
4x + 34800 - 6x = 29200
2x = 5600
x = 2800 so , d is correct option.
What is the difference between the compound interest and the simple interest for the sum Rs. 16000 at 5% p.a. for 2 years?- a)Rs. 80
- b)Rs. 60
- c)Rs. 54
- d)Rs. 40
- e)Rs. 35
Correct answer is option 'A'. Can you explain this answer?
What is the difference between the compound interest and the simple interest for the sum Rs. 16000 at 5% p.a. for 2 years?
a)
Rs. 80
b)
Rs. 60
c)
Rs. 54
d)
Rs. 40
e)
Rs. 35
|
Dia Mehta answered |
Option ( A) 40 is the correct answer.
Explanation:- Given, P = 16000₹
R = 5% , T = 2 years
A = P (1 + R /100) ^n
= 16000 * ( 1+5/100) ^2
= 16000 * ( 105 / 100) ^2
A = 17,640₹
C. I = A- P
= 17,640 - 16,000
= 1,640
S. I = PTR / 100
= 16000 * 2 * 5/ 100
= 1,600
Difference CI - SI ;
= 1640 - 1600
= 40 ₹
What is the sum of amount which gives Rs. 6300 as interest @ 7% per annum of simple interest in 7*1/2years?- a)36000
- b)24000
- c)63000
- d)12000
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
What is the sum of amount which gives Rs. 6300 as interest @ 7% per annum of simple interest in 7*1/2years?
a)
36000
b)
24000
c)
63000
d)
12000
e)
None of these
|
Sachin Salaria answered |
S.I=6300,R=7%,T=7*1/2=15/2 YEARS
Formula
SI= P×R×T/100
6300 =P×7×15/100×2
6300=P×7×3/20×2
6300×40=P×7×3
6300×40/7×3=P
300×40=P
12000= P answer is D
Formula
SI= P×R×T/100
6300 =P×7×15/100×2
6300=P×7×3/20×2
6300×40=P×7×3
6300×40/7×3=P
300×40=P
12000= P answer is D
An amount of money grows upto Rs. 4000 in 2 years and up to Rs. 8000 in 3 years on compound interest. What is the sum?- a)Rs. 1600
- b)Rs. 1000
- c)Rs. 1200
- d)Rs. 2400
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
An amount of money grows upto Rs. 4000 in 2 years and up to Rs. 8000 in 3 years on compound interest. What is the sum?
a)
Rs. 1600
b)
Rs. 1000
c)
Rs. 1200
d)
Rs. 2400
e)
None of these
|
|
Aarav Sharma answered |
Solution:
Let the principal be Rs. x.
Given, the principal amount grows up to Rs. 4000 in 2 years and up to Rs. 8000 in 3 years on compound interest.
Calculation:
Using the formula for compound interest,
Amount after 2 years = x(1 + r/100)²
Amount after 3 years = x(1 + r/100)³
Given, amount after 2 years = Rs. 4000 and amount after 3 years = Rs. 8000
So, we have two equations as below:
x(1 + r/100)² = 4000
x(1 + r/100)³ = 8000
Dividing the second equation by the first equation, we get:
(1 + r/100) = 2
r/100 = 1
r = 100
Substituting the value of r in any of the equations above, we get:
x = 1000
Therefore, the sum is Rs. 1000.
Hence, option (b) is the correct answer.
Let the principal be Rs. x.
Given, the principal amount grows up to Rs. 4000 in 2 years and up to Rs. 8000 in 3 years on compound interest.
Calculation:
Using the formula for compound interest,
Amount after 2 years = x(1 + r/100)²
Amount after 3 years = x(1 + r/100)³
Given, amount after 2 years = Rs. 4000 and amount after 3 years = Rs. 8000
So, we have two equations as below:
x(1 + r/100)² = 4000
x(1 + r/100)³ = 8000
Dividing the second equation by the first equation, we get:
(1 + r/100) = 2
r/100 = 1
r = 100
Substituting the value of r in any of the equations above, we get:
x = 1000
Therefore, the sum is Rs. 1000.
Hence, option (b) is the correct answer.
A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
- a)Rs. 35
- b)Rs. 245
- c)Rs. 350
- d)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
a)
Rs. 35
b)
Rs. 245
c)
Rs. 350
d)
Cannot be determined
|
|
Ishani Rane answered |
We need to know the S.I, principal and time to find the rate. Since the principal is not given, so data is inadequate.
What will be the compound interest on a sum of Rs. 40,000 after 3 years at the rate of 11 p.c.p.a.? - a)Rs. 14705.24
- b)Rs. 14602.25
- c)Rs. 14822.26
- d)Rs. 14322.10
Correct answer is option 'A'. Can you explain this answer?
a)
Rs. 14705.24
b)
Rs. 14602.25
c)
Rs. 14822.26
d)
Rs. 14322.10
|
|
Rhea Reddy answered |
Amount after 3 years = P(1 + R/100)T
=> 40000(1 + 11/100)3
=> 40000(111/100)3
=> 40000[(111*111*111)/(100*100*100)]
=> (4*111*111*111)/100
=> 54705.24
Compound Interest = 54705.24 - 40000
= Rs. 14705.24
=> 40000(1 + 11/100)3
=> 40000(111/100)3
=> 40000[(111*111*111)/(100*100*100)]
=> (4*111*111*111)/100
=> 54705.24
Compound Interest = 54705.24 - 40000
= Rs. 14705.24
A man buys a land and gives for it 20 times the annual rent. Find the rate of Interest he gets for his money.- a)10%
- b)3%
- c)4%
- d)None.
- e)All of the above
Correct answer is option 'D'. Can you explain this answer?
A man buys a land and gives for it 20 times the annual rent. Find the rate of Interest he gets for his money.
a)
10%
b)
3%
c)
4%
d)
None.
e)
All of the above
|
|
Nikita Singh answered |
Let annual rent is 1 Rs. so buys the land at 20 Rs. So by investing Rs.20 he is getting Rs.1 as interest. so on Rs.100 he gets Rs.5. So rate%=5%. Hence option D is the answer.
A sum of money triples itself in 3 years at a simple interest. In how many years will it multiply five times?
- a)5 years
- b)8 years
- c)4 years
- d)6 years
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A sum of money triples itself in 3 years at a simple interest. In how many years will it multiply five times?
a)
5 years
b)
8 years
c)
4 years
d)
6 years
e)
None of these
|
|
Kavya Saxena answered |
The correct option is Option B.
For 3 yrs
SI = P*R*T/100
3P-P = P*R*3/100
2P = 3P*R/100
R = 200/3
Money will become 5 times
5P - P = (P*200/3*T)/100
4P = (2/3P)T
T = 6
Money will become five times in 6 years
A lent 180 to B for 10 years and 200 to C for 2 years at Simple interest, the rate of interest being same in both the cases. He received Rs. 220 as total interest. Find the rate%.
- a)5%
- b)10%
- c)8%
- d)None
- e)All of the above
Correct answer is option 'B'. Can you explain this answer?
A lent 180 to B for 10 years and 200 to C for 2 years at Simple interest, the rate of interest being same in both the cases. He received Rs. 220 as total interest. Find the rate%.
a)
5%
b)
10%
c)
8%
d)
None
e)
All of the above
|
Melvin Joe answered |
T. S. I=220
S.I (B) +S. I(C) =(180*10*R+200*2*R)/100=220
2200R=22000
R=22000/2200
R=10%
S.I (B) +S. I(C) =(180*10*R+200*2*R)/100=220
2200R=22000
R=22000/2200
R=10%
A man had Rs.3000 a part of which he lent at 4% p.a and rest at 5% p.a. The whole annual interest received was Rs. 130. The money he lent at 4% was
- a)Rs. 2000
- b)Rs. 1000
- c)Rs. 800
- d)None
- e)All of the above
Correct answer is option 'A'. Can you explain this answer?
A man had Rs.3000 a part of which he lent at 4% p.a and rest at 5% p.a. The whole annual interest received was Rs. 130. The money he lent at 4% was
a)
Rs. 2000
b)
Rs. 1000
c)
Rs. 800
d)
None
e)
All of the above
|
|
Melvin Joe answered |
3000=1st part(x) +2nd part(3000-x)_assumed.
S.I 1+S.I 2=130
[X*4+(3000-X)*5]/100=130
4X+15000-5X=13000
X=15000-13000
X=2000
S.I 1+S.I 2=130
[X*4+(3000-X)*5]/100=130
4X+15000-5X=13000
X=15000-13000
X=2000
Arun invested an amount of Rs. 2000 in a fixed deposit scheme for 2 years at compound interest rate 4 p.c.p.a. How much amount will Arun get on maturity of the fixed deposit?
- a)2034.2
- b)2163.2
- c)2232.4
- d)2412.0
Correct answer is option 'B'. Can you explain this answer?
Arun invested an amount of Rs. 2000 in a fixed deposit scheme for 2 years at compound interest rate 4 p.c.p.a. How much amount will Arun get on maturity of the fixed deposit?
a)
2034.2
b)
2163.2
c)
2232.4
d)
2412.0
|
Monica A answered |
20,000*(104/100)² = 21632...(principle + Interest = Amount)...since it is fixed deposit, we receive amount after maturity
The simple interest accrued on an amount of Rs. 22,500/- at the end of four years is Rs. 10,800/-. What would be the compound interest accrued on the same amount at the same rate at the end of two years?- a)Rs. 16908/-
- b)Rs. 5724/-
- c)Rs. 28224/-
- d)Rs. 8586/-
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
The simple interest accrued on an amount of Rs. 22,500/- at the end of four years is Rs. 10,800/-. What would be the compound interest accrued on the same amount at the same rate at the end of two years?
a)
Rs. 16908/-
b)
Rs. 5724/-
c)
Rs. 28224/-
d)
Rs. 8586/-
e)
None of these
|
Jyoti Reddy answered |
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 60, what is the compound interest on the same at the same rate and for the same time?
- a)Rs. 63.5
- b)Rs. 62
- c)Rs. 61.5
- d)Rs. 64
Correct answer is option 'C'. Can you explain this answer?
If the simple interest on a sum of money for 2 years at 5% per annum is Rs. 60, what is the compound interest on the same at the same rate and for the same time?
a)
Rs. 63.5
b)
Rs. 62
c)
Rs. 61.5
d)
Rs. 64
|
Venky Dhawan answered |
Since SI = 60
SI = P×R×T/ 100
which is P = 60×100/2×5 = 200
P = 600
CI= 600(1+5/100)^2
= 600(21/20)^2
= 600(1.025) = 661.5 which is amount
so sum = 600-661 = 61.5(C)
SI = P×R×T/ 100
which is P = 60×100/2×5 = 200
P = 600
CI= 600(1+5/100)^2
= 600(21/20)^2
= 600(1.025) = 661.5 which is amount
so sum = 600-661 = 61.5(C)
The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is: - a)6.07%
- b)6.08%
- c)6.06%
- d)6.09%
Correct answer is option 'D'. Can you explain this answer?
a)
6.07%
b)
6.08%
c)
6.06%
d)
6.09%
|
Krithika Sengupta answered |
Amount of Rs. 100 for 1 year
when compounded half-yearly = Rs.[100*(1+3/100)^2]=Rs.106.09
Effective rate=(106.09-100)%=6.09%
The simple interest accrued on a sum of certain principal is Rs. 6500/- in eight years at the rate of 13 p.c.p.a. What would be the compound interest accrued on that principal at the rate of 8 p.c.p.a. in 2 years?- a)Rs. 1040/-
- b)Rs. 1020/-
- c)Rs. 1060/-
- d)Rs. 1200/-
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
The simple interest accrued on a sum of certain principal is Rs. 6500/- in eight years at the rate of 13 p.c.p.a. What would be the compound interest accrued on that principal at the rate of 8 p.c.p.a. in 2 years?
a)
Rs. 1040/-
b)
Rs. 1020/-
c)
Rs. 1060/-
d)
Rs. 1200/-
e)
None of these
|
|
Anaya Patel answered |
The corect option is A by using compound formulae the amount comes to be 1040.
Find the rate of Simple Interest when a sum of money treble itself in 25 years.- a)4%
- b)10%
- c)8%
- d)None
- e)All of the above
Correct answer is option 'C'. Can you explain this answer?
Find the rate of Simple Interest when a sum of money treble itself in 25 years.
a)
4%
b)
10%
c)
8%
d)
None
e)
All of the above
|
|
Aarav Sharma answered |
Given, the sum of money trebles itself in 25 years.
Let the principal amount be P.
Formula:
Simple Interest = (P * R * T) / 100
where P is the principal amount, R is the rate of interest, and T is the time period.
Calculation:
After 25 years, the sum becomes 3P.
Using the formula of Simple Interest,
3P = P + (P * R * 25) / 100
2P = (P * R * 25) / 100
R = (2P * 100) / (P * 25)
R = 8%
Therefore, the rate of Simple Interest is 8%. Hence, option C is the correct answer.
Let the principal amount be P.
Formula:
Simple Interest = (P * R * T) / 100
where P is the principal amount, R is the rate of interest, and T is the time period.
Calculation:
After 25 years, the sum becomes 3P.
Using the formula of Simple Interest,
3P = P + (P * R * 25) / 100
2P = (P * R * 25) / 100
R = (2P * 100) / (P * 25)
R = 8%
Therefore, the rate of Simple Interest is 8%. Hence, option C is the correct answer.
The Simple Interest on a certain sum of money for two years is Rs. 40 and the CI on same sum at same rate for same time is Rs. 40.50. Find the sum.- a)Rs. 1600
- b)Rs. 800
- c)Rs. 600
- d)None
- e)All of the above
Correct answer is option 'B'. Can you explain this answer?
The Simple Interest on a certain sum of money for two years is Rs. 40 and the CI on same sum at same rate for same time is Rs. 40.50. Find the sum.
a)
Rs. 1600
b)
Rs. 800
c)
Rs. 600
d)
None
e)
All of the above
|
Krishan Kumar answered |
1. Calculate Simple Interest (SI): SI formula: SI = P × R × T / 100. Given SI for two years is Rs.40. Thus, 40 = P × R × 2 / 100 => P × R = 2000 ...(1) 2. Calculate Compound Interest (CI): CI formula: A = P(1 + R / 100)2. CI for two years is Rs.40.50, so A = P + 40.50. Thus, CI = A - P = 40.50. Therefore, P[(1 + R / 100)2 - 1] = 40.50 ...(2) 3. Substitute R from equation (1) into equation (2): From (1), R = 2000 / P. Substitute into CI formula: P(1 + 20 / P)2 - P = 40.50. Simplify: P(1 + 40 / P + 400 / P2) - P = 40.50. This leads to 40 + 400 / P = 40.50. Therefore, 400 / P = 0.50 => P = 400 / 0.50 = 800. 4. Conclusion: The principal sum is Rs.800.
The compound interest on Rs. 30,000 at 7% per annum is Rs. 4347. The period (in years) is: - a)1
- b)2
- c)3
- d)3.5
Correct answer is option 'B'. Can you explain this answer?
a)
1
b)
2
c)
3
d)
3.5
|
Raghavendra Sharma answered |
Amount = Rs. (30000 + 4347) = Rs. 34347.
Let the time be n years.
Then, 30000 (1 + 7/100)^n = 34347
= (107/100)^n = 34347/30000 = 11449/10000 = (107/100)^2
n = 2 years.
Chapter doubts & questions for Compound & Simple Interest - Mathematics for RRB NTPC / ASM 2025 is part of RRB NTPC/ASM/CA/TA exam preparation. The chapters have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for RRB NTPC/ASM/CA/TA 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of Compound & Simple Interest - Mathematics for RRB NTPC / ASM in English & Hindi are available as part of RRB NTPC/ASM/CA/TA exam.
Download more important topics, notes, lectures and mock test series for RRB NTPC/ASM/CA/TA Exam by signing up for free.
Mathematics for RRB NTPC / ASM
146 videos|96 docs|98 tests
|
Signup to see your scores go up within 7 days!
Study with 1000+ FREE Docs, Videos & Tests
10M+ students study on EduRev
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup