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Q. .
  • a)
    C
  • b)
    B
  • c)
    A
  • d)
    D
Correct answer is option 'A'. Can you explain this answer?
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Q. .a)Cb)Bc)Ad)DCorrect answer is option 'A'. Can you explain this ans...
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Q. .a)Cb)Bc)Ad)DCorrect answer is option 'A'. Can you explain this ans...
Given:
Principal amount (P) = Rs. 5000
Time (t) = 11/2 years
Rate of interest (R) = 4% per annum

We need to find the difference in compound interest when compounded yearly and half-yearly.

Formula:
Compound Interest (CI) = P[1 + R/n]^(nt)
where n is the number of times the interest is compounded per year.

Calculation:
For yearly compounding:
n = 1
t = 11/2 years
CI = P[1 + R/n]^(nt)
CI = 5000[1 + 4/100]^1.5
CI = 5000[1.04]^1.5
CI = 5000[1.061216]
CI = Rs. 5306.08

For half-yearly compounding:
n = 2
t = 11/2 years
CI = P[1 + R/n]^(nt)
CI = 5000[1 + 4/100]^3
CI = 5000[1.02]^3
CI = 5000[1.061208]
CI = Rs. 5304.04

Difference in compound interest = Rs. (5306.08 - 5304.04) = Rs. 2.04

Therefore, the difference in compound interest when compounded yearly and half-yearly is Rs. 2.04.
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Q. .a)Cb)Bc)Ad)DCorrect answer is option 'A'. Can you explain this answer?
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