All Exams >
EmSAT Achieve >
Physics for EmSAT Achieve >
All Questions
All questions of Graphs of Motion for EmSAT Achieve Exam
Two stones of different masses are thrown vertically upward with same initial velocity. Which one will rise to a greater height ?- a)Stone of lower mass
- b)Stone of higher mass
- c)Both will rise to the same height
- d)Information given is insufficient
Correct answer is option 'C'. Can you explain this answer?
Two stones of different masses are thrown vertically upward with same initial velocity. Which one will rise to a greater height ?
a)
Stone of lower mass
b)
Stone of higher mass
c)
Both will rise to the same height
d)
Information given is insufficient
|
Sushil Kumar answered |
If we write the equation of motion for both the masses and derive a simple equation to find the maximum vertical height let say H, we get for any particle for some mass m,
H = v2 / 2a
Where a is gravitational acceleration and v is vertical speed. Thus as H does not depend upon m, we get both particles would have equal maximum height.
H = v2 / 2a
Where a is gravitational acceleration and v is vertical speed. Thus as H does not depend upon m, we get both particles would have equal maximum height.
A ball is thrown vertically upward. At the highest point in its path, which of the following statements is correct?- a)The velocity is zero and the acceleration is pointing down
- b)The velocity and acceleration are both zero
- c)The acceleration is zero and the velocity is pointing up
- d)The acceleration is zero and the velocity is pointing down
Correct answer is option 'A'. Can you explain this answer?
A ball is thrown vertically upward. At the highest point in its path, which of the following statements is correct?
a)
The velocity is zero and the acceleration is pointing down
b)
The velocity and acceleration are both zero
c)
The acceleration is zero and the velocity is pointing up
d)
The acceleration is zero and the velocity is pointing down
|
Geetika Shah answered |
Until and unless the velocity of any object comes to zero, any peek in its displacement-time graph can’t be achieved. Which means for the height to be maximised the velocity must become zero. And any time of this motion the acceleration is always a constant downward due to gravity.
In a distance-time graph, if the line is horizontal, then the object is:- a)Accelerating
- b)Speeding up
- c)At rest
- d)Slowing down
Correct answer is option 'C'. Can you explain this answer?
In a distance-time graph, if the line is horizontal, then the object is:
a)
Accelerating
b)
Speeding up
c)
At rest
d)
Slowing down
|
Destroyed answered |
When an object is at rest it will not be able to cover any distance . So for any object at rest the distance -time graph is horizontal to time axis
Rain falls at a speed of 50m/s and a child walks on a straight road from east to west at a speed of 100m/s. To find the direction in which the child should hold the umbrella use- a)resultant speed of child and rain
- b)resultant speed of rain and child
- c)relative speed of rain with respect to child
- d)relative speed of child with respect to rain
Correct answer is option 'C'. Can you explain this answer?
Rain falls at a speed of 50m/s and a child walks on a straight road from east to west at a speed of 100m/s. To find the direction in which the child should hold the umbrella use
a)
resultant speed of child and rain
b)
resultant speed of rain and child
c)
relative speed of rain with respect to child
d)
relative speed of child with respect to rain
|
Rajesh Gupta answered |
The child should hold the umbrella in the direction at which the rain appears to fall on him, which is the direction of relative speed of rain with respect to the child.
The motion of a freely falling body is an example of:- a)uniformly accelerated motion
- b)non uniformly accelerated motion
- c)uniform motion
- d)none of the above
Correct answer is option 'A'. Can you explain this answer?
The motion of a freely falling body is an example of:
a)
uniformly accelerated motion
b)
non uniformly accelerated motion
c)
uniform motion
d)
none of the above
|
Om Desai answered |
A freely falling body observes a constant downwards force of gravity which hence applies a constant downward acceleration upon the body.
The area enclosed by velocity-time graph and the time axis will be equal to the magnitude of- a)displacement
- b)speed
- c)acceleration
- d)distance
Correct answer is option 'A'. Can you explain this answer?
The area enclosed by velocity-time graph and the time axis will be equal to the magnitude of
a)
displacement
b)
speed
c)
acceleration
d)
distance
|
Ishaan Chauhan answered |
Explanation:
Derivation:
Conclusion:
When an object is in motion, its velocity changes with time. The velocity-time graph shows the variation of velocity with time. The area enclosed by the velocity-time graph and the time axis represents the distance travelled by the object in a given time interval.
Derivation:
Let's consider an object moving with a variable velocity v(t) in a straight line. The velocity of the object at any instant t is given by:
v(t) = ds/dt
where s is the displacement of the object at time t. Integrating both sides, we get:
s = ∫v(t) dt
The integral of velocity with respect to time gives the displacement of the object. The area under the velocity-time graph represents the area of the region bounded by the graph, the time axis and the two vertical lines drawn at the beginning and end of the time interval.
Conclusion:
Therefore, the area enclosed by the velocity-time graph and the time axis represents the displacement of the object. Hence, option 'A' is the correct answer.
The slope of the distance-time graph is:- a)Distance
- b)acceleration
- c)Speed
- d)Displacement
Correct answer is option 'C'. Can you explain this answer?
The slope of the distance-time graph is:
a)
Distance
b)
acceleration
c)
Speed
d)
Displacement
|
Sarita Reddy answered |
The gradient of a distance-time graph represents the speed of an object. The velocity of an object is its speed in a particular direction. The slope on a velocity-time graph represents the acceleration of an object. The distance travelled is equal to the area under a velocity-time graph.
A body of mass 1kg and 10kg are dropped simultaneously from the top of a tower. The ratio of the time taken by them to reach the ground is- a)9.8:98
- b)1:1
- c)10:1
- d)1:10
Correct answer is option 'B'. Can you explain this answer?
A body of mass 1kg and 10kg are dropped simultaneously from the top of a tower. The ratio of the time taken by them to reach the ground is
a)
9.8:98
b)
1:1
c)
10:1
d)
1:10
|
Anjana Sharma answered |
1:1, the time taken does not depend on the mass of the falling object.
For a body performing motion with uniform speed, the distance-time graph is:- a)Straight line parallel to y-axis
- b)Straight line inclined to the time axis
- c)Straight line parallel to x-axis
- d)Curved line
Correct answer is 'B'. Can you explain this answer?
For a body performing motion with uniform speed, the distance-time graph is:
a)
Straight line parallel to y-axis
b)
Straight line inclined to the time axis
c)
Straight line parallel to x-axis
d)
Curved line
|
|
Rohit Sharma answered |
For a body moving at uniform speed, the distance time graph is a straight line inclined to the time axis, which may pass through origin or some other point on the y- axis.
As in uniform motion, the distance time graph would be a straight line, because the equal distance is covered in equal units of time.
As in uniform motion, the distance time graph would be a straight line, because the equal distance is covered in equal units of time.
The kinematic equation of motion v = u+at is not applicable if :- a)Displacement is not constant
- b)motion is non-uniform.
- c)acceleration is not constant
- d)velocity is not constant
Correct answer is option 'C'. Can you explain this answer?
The kinematic equation of motion v = u+at is not applicable if :
a)
Displacement is not constant
b)
motion is non-uniform.
c)
acceleration is not constant
d)
velocity is not constant
|
Yash Ghoshal answered |
Explanation:
The kinematic equation of motion v = u + at is one of the four equations of motion which are used to describe the motion of an object under constant acceleration. The equation shows the relationship between the initial velocity (u), acceleration (a), time (t), and final velocity (v) of an object. However, this equation is not applicable if the acceleration is not constant.
Constant acceleration means that the rate of change of velocity is constant. If the acceleration is not constant, then the rate of change of velocity is changing, and the equation v = u + at does not hold true for the entire motion.
For example, if an object is moving in a circular path, its acceleration changes direction at every point, and hence, the acceleration is not constant. In this case, the kinematic equation cannot be used to describe the motion of the object.
Similarly, if an object is thrown vertically upwards, the acceleration of the object changes as it moves upwards and then downwards due to the force of gravity. Hence, the kinematic equation v = u + at cannot be used to describe the entire motion of the object.
Conclusion:
In conclusion, the kinematic equation of motion v = u + at is not applicable if the acceleration is not constant, and the rate of change of velocity is changing. The equation is valid only for objects that are moving under constant acceleration. Hence, before using this equation to solve any problem, it is important to check whether the acceleration is constant or not.
The kinematic equation of motion v = u + at is one of the four equations of motion which are used to describe the motion of an object under constant acceleration. The equation shows the relationship between the initial velocity (u), acceleration (a), time (t), and final velocity (v) of an object. However, this equation is not applicable if the acceleration is not constant.
Constant acceleration means that the rate of change of velocity is constant. If the acceleration is not constant, then the rate of change of velocity is changing, and the equation v = u + at does not hold true for the entire motion.
For example, if an object is moving in a circular path, its acceleration changes direction at every point, and hence, the acceleration is not constant. In this case, the kinematic equation cannot be used to describe the motion of the object.
Similarly, if an object is thrown vertically upwards, the acceleration of the object changes as it moves upwards and then downwards due to the force of gravity. Hence, the kinematic equation v = u + at cannot be used to describe the entire motion of the object.
Conclusion:
In conclusion, the kinematic equation of motion v = u + at is not applicable if the acceleration is not constant, and the rate of change of velocity is changing. The equation is valid only for objects that are moving under constant acceleration. Hence, before using this equation to solve any problem, it is important to check whether the acceleration is constant or not.
What is the slope of distance-time graph when object is at rest?- a)Decreases continuously
- b)Zero
- c)Increases continuously
- d)One
Correct answer is option 'B'. Can you explain this answer?
What is the slope of distance-time graph when object is at rest?
a)
Decreases continuously
b)
Zero
c)
Increases continuously
d)
One
|
Preetam Pyare answered |
Since The Body is at Rest ,It clearly means that The Body hasn't covered any Distance here.So,Distance is equal to zero.So,There is no meaning of having any slope here.. So,The Slope=0 Becoz The Distance at anytime will represent same point in Distance-Time Graph at 0..So,(B)is d correct answer. .
Which of the following quantity does not remain constant during the uniform circular motion?- a)linear momentum
- b)speed
- c)angular velocity
- d)angular acceleration
Correct answer is option 'A'. Can you explain this answer?
Which of the following quantity does not remain constant during the uniform circular motion?
a)
linear momentum
b)
speed
c)
angular velocity
d)
angular acceleration
|
|
Geetika Shah answered |
- Linear momentum is not constant but angular momentum is
- Speed has to be constant for “uniform” circular motion
- For obvious reasons ω is constant
- And the same goes for α
The area under a velocity-time graph is represented by the unit:- a)m
- b)m-1
- c)m3
- d)m2
Correct answer is option 'A'. Can you explain this answer?
The area under a velocity-time graph is represented by the unit:
a)
m
b)
m-1
c)
m3
d)
m2
|
Jyoti Kapoor answered |
The area under the velocity-time graph gives the distance (magnitude of displacement) which has the unit: metre (m)
A uniform force of (3 i + j) N acts on a particle of mass 2 kg. Hence the particle is displaced from position (2 i + k) m to position ( 4 i + 3 j - k) m. The work done by the force on the particle is,- a)9 J
- b)6 J
- c)13 J
- d)15 J
Correct answer is option 'A'. Can you explain this answer?
A uniform force of (3 i + j) N acts on a particle of mass 2 kg. Hence the particle is displaced from position (2 i + k) m to position ( 4 i + 3 j - k) m. The work done by the force on the particle is,
a)
9 J
b)
6 J
c)
13 J
d)
15 J
|
Ishan Ghosh answered |
Uniform force acting = 3i + j N
Displacement done = (4-2)i + 3j + (-1-1)k
= 2i + 3j -2k
Thus total work done = F.s (dot product here)
We get W = 3 x 2 + 1 x 3 + 0 x -2
= 9J
Displacement done = (4-2)i + 3j + (-1-1)k
= 2i + 3j -2k
Thus total work done = F.s (dot product here)
We get W = 3 x 2 + 1 x 3 + 0 x -2
= 9J
In a velocity-time graph, which variable is plotted on the Y-axis?- a)Velocity
- b)Speed
- c)Time
- d)Distance
Correct answer is option 'A'. Can you explain this answer?
In a velocity-time graph, which variable is plotted on the Y-axis?
a)
Velocity
b)
Speed
c)
Time
d)
Distance
|
EduRev Class 9 answered |
- In a velocity-time graph:
- The Y-axis represents Velocity.
- The X-axis represents Time.
- Thus, the variable plotted on the Y-axis is Velocity.
- The Y-axis represents Velocity.
- The X-axis represents Time.
- Thus, the variable plotted on the Y-axis is Velocity.
The angular velocity (in rad/s) of a body rotating at N r.p.m. is- a)π N/60
- b)2 π N/60
- c)π N/120
- d)π N/180
Correct answer is option 'B'. Can you explain this answer?
The angular velocity (in rad/s) of a body rotating at N r.p.m. is
a)
π N/60
b)
2 π N/60
c)
π N/120
d)
π N/180
|
|
Shreya Gupta answered |
Angular velocity is defined as the rate of change of angular displacement with respect to time. It is usually expressed by a Greek letter ω (omega).
Mathematically, angular velocity,
ω =dθ/dt
If a body is rotating at the rate of N r.p.m. (revolutions per minute), then its angular velocity,
ω = 2πΝ / 60 rad/s
On the distance-time graph, the Y-axis should be labeled as:
- a)Distance
- b)Displacement
- c)Speed
- d)Time
Correct answer is option 'A'. Can you explain this answer?
On the distance-time graph, the Y-axis should be labeled as:
a)
Distance
b)
Displacement
c)
Speed
d)
Time
|
Let's Tute answered |
Independent variables are plotted along X-axis and Dependent variables are plotted along Y-axis. In the distance-time graph, time is independent and distance is a dependent variables. Y-axis is Distance
Topic in NCERT: DISTANCE-TIME GRAPHS
Line in NCERT: "In this graph, time is taken along the x-axis and distance is taken along the y-axis."
Chapter doubts & questions for Graphs of Motion - Physics for EmSAT Achieve 2025 is part of EmSAT Achieve exam preparation. The chapters have been prepared according to the EmSAT Achieve exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for EmSAT Achieve 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of Graphs of Motion - Physics for EmSAT Achieve in English & Hindi are available as part of EmSAT Achieve exam.
Download more important topics, notes, lectures and mock test series for EmSAT Achieve Exam by signing up for free.
Physics for EmSAT Achieve
208 videos|329 docs|212 tests
|
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup