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All questions of Elementary Statistics for Mechanical Engineering Exam
Class mark of a particular class is 9.5 and the class size is 6, then the class interval is- a)15.5-27.5
- b)12.5-18.5
- c)3.5-15.5
- d)6.5-12.5
Correct answer is option 'D'. Can you explain this answer?
Class mark of a particular class is 9.5 and the class size is 6, then the class interval is
a)
15.5-27.5
b)
12.5-18.5
c)
3.5-15.5
d)
6.5-12.5
|
Anita Menon answered |
Class mark = 9.5
=> Upper limit + Lower limit / 2 = 9.5
=> u + l = 19 -------(1)
Class mark = 6
=> u - l = 6 --------(2)
On adding equation 1 and 2, we get
2u = 25
=> u = 12.5
l = 6.5
Class interval is ( 6.5 - 12.5)
Primary data is gathered through- a)original source of information.
- b)information on website.
- c)second hand information.
- d)annual company reports.
Correct answer is option 'A'. Can you explain this answer?
Primary data is gathered through
a)
original source of information.
b)
information on website.
c)
second hand information.
d)
annual company reports.
|
Bhargavi Chopra answered |
A primary data source is an original data source, that is, one in which the data are collected firsthand by the researcher for a specific research purpose or project. Primary data collection is quite expensive and time consuming compared to secondary
Value that divides the series into hundred equal parts is called- a)percentile.
- b)quartiles.
- c)deciles.
- d)octiles.
Correct answer is option 'A'. Can you explain this answer?
Value that divides the series into hundred equal parts is called
a)
percentile.
b)
quartiles.
c)
deciles.
d)
octiles.
|
Kiran Mehta answered |
Values that divide the series into hundred equal parts are called percentiles. In percentile, we get 99 dividing positions denoted by P1, P2,……..,P99.
Orderly arrangement of data according to magnitude is called- a)raw series.
- b)individual series.
- c)original series.
- d)listed series.
Correct answer is option 'B'. Can you explain this answer?
Orderly arrangement of data according to magnitude is called
a)
raw series.
b)
individual series.
c)
original series.
d)
listed series.
|
Ishan Choudhury answered |
When the raw data is presented individually in the form of a series, it is called an individual series.
In simple words, individual series is the arrangement of raw data individually. It gives numeric values for a specific situation.
In an individual series items are shown separately. So organisation on the basis of magnitude is individual series.
One of the sides of a frequency polygon is
- a)either of the coordinate axes
- b)the x-axis
- c)neither of the coordinate axes
- d)the y-axis
Correct answer is option 'B'. Can you explain this answer?
One of the sides of a frequency polygon is
a)
either of the coordinate axes
b)
the x-axis
c)
neither of the coordinate axes
d)
the y-axis
|
Learners World answered |
The x-axis is one of the sides of a frequency polygon. The x-axis represents the values of the variable being measured.
After collection of data, the next step is- a)presentation of data.
- b)classification of data.
- c)selection of data.
- d)categorising of data.
Correct answer is option 'B'. Can you explain this answer?
After collection of data, the next step is
a)
presentation of data.
b)
classification of data.
c)
selection of data.
d)
categorising of data.
|
Naina Sharma answered |
Classification is the process of arranging data into different groups or classes.
► Classification of data is done after collection of data.
The data obtained from the records of an organisation is called- a)primary data.
- b)secondary data.
- c)external data.
- d)internal data.
Correct answer is option 'A'. Can you explain this answer?
The data obtained from the records of an organisation is called
a)
primary data.
b)
secondary data.
c)
external data.
d)
internal data.
|
|
Aryan Khanna answered |
Primary data is data that is collected by a researcher from first-hand sources, using methods like surveys, interviews, or experiments. It is collected with the research project in mind, directly from primary sources.
Secondary data is the data that has already been collected through primary sources and made readily available for researchers to use for their own research. A researcher may have collected the data for a particular project, then made it available to be used by another researcher.
So it is a secondary data.
So it is a secondary data.
Data collected from the original source of information is called- a)primary data.
- b)secondary data.
- c)published data.
- d)used data.
Correct answer is option 'A'. Can you explain this answer?
Data collected from the original source of information is called
a)
primary data.
b)
secondary data.
c)
published data.
d)
used data.
|
|
Arun Yadav answered |
These are collected from the very source of information. They are collected for the first time from the original source of information.
The population divided into several homogeneous groups is called
a)Deliberate samplingb)Systematic samplingc)Stratified samplingd)Convenience samplingCorrect answer is option 'C'. Can you explain this answer?
|
|
Kiran Mehta answered |
The correct option is Option C.
Stratified random sampling involves dividing the entire population into homogeneous groups called strata.
Which of the following is not a measure of central tendency?- a)Mean
- b)Median
- c)Standard deviation
- d)Mode
Correct answer is option 'C'. Can you explain this answer?
Which of the following is not a measure of central tendency?
a)
Mean
b)
Median
c)
Standard deviation
d)
Mode
|
Om Desai answered |
► Standard deviation is the measure of how spread out the numbers of a data are.
► Mean is the average.
► Median is the middle number, when data is arranged in numerical order.
► Mode is the data item the appears most frequently.
Mean, median and mode are all measures of central tendencies.
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is- a)15
- b)40
- c)25
- d)35
Correct answer is option 'D'. Can you explain this answer?
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
a)
15
b)
40
c)
25
d)
35
|
Vikas Kapoor answered |
Let x and y be the upper and lower class limit of frequency distribution.
Given, width of the class = 5
⇒ x-y= 5 …(i)
Also, given lower class (y) = 10 On putting y = 10 in Eq. (i), we get
x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15.
Hence, the upper class limit of the highest class
=(Number of continuous classes x Class width + Lower class limit of the lowest class)
= 5 x 5+10 = 25+10=35
Hence,’the upper class limit of the highest class is 35.
Alternate Method
After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.
Thus, the highest class is 30-35,
Hence, the upper limit of this class is 35.
Given, width of the class = 5
⇒ x-y= 5 …(i)
Also, given lower class (y) = 10 On putting y = 10 in Eq. (i), we get
x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15.
Hence, the upper class limit of the highest class
=(Number of continuous classes x Class width + Lower class limit of the lowest class)
= 5 x 5+10 = 25+10=35
Hence,’the upper class limit of the highest class is 35.
Alternate Method
After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.
Thus, the highest class is 30-35,
Hence, the upper limit of this class is 35.
Class mark of a particular class is 9.5 and the class size is 6, then the class interval is- a)3.5-15.5
- b)12.5-18.5
- c)15.5-27.5
- d)6.5-12.5
Correct answer is option 'D'. Can you explain this answer?
Class mark of a particular class is 9.5 and the class size is 6, then the class interval is
a)
3.5-15.5
b)
12.5-18.5
c)
15.5-27.5
d)
6.5-12.5
|
Gayatri Choudhary answered |
To determine the class interval, we need to know the range of the data and the number of class intervals.
In this case, the class mark is given as 9.5 and the class size is 6. The class mark represents the midpoint of the class interval, which means that the lower limit of the class interval is 9.5 - 0.5 = 9 and the upper limit is 9.5 + 0.5 = 10.
Let's calculate the range of the data:
Range = Upper Limit - Lower Limit
Range = 10 - 9
Range = 1
Since the range is 1 and there are 6 class intervals, we can divide the range by the number of class intervals to determine the class interval size:
Class Interval Size = Range / Number of Class Intervals
Class Interval Size = 1 / 6
Class Interval Size = 0.1667
Now, we can determine the class intervals:
First Class Interval: 9 - 9.1667
Second Class Interval: 9.1667 - 9.3333
Third Class Interval: 9.3333 - 9.5
Fourth Class Interval: 9.5 - 9.6667
Fifth Class Interval: 9.6667 - 9.8333
Sixth Class Interval: 9.8333 - 10
As we can see, the class interval that includes the class mark of 9.5 is 9.5 - 9.6667. Therefore, the correct answer is option D) 6.5-12.5.
It is important to note that the other options given are incorrect because they do not include the class mark of 9.5 within the range of the class intervals.
In this case, the class mark is given as 9.5 and the class size is 6. The class mark represents the midpoint of the class interval, which means that the lower limit of the class interval is 9.5 - 0.5 = 9 and the upper limit is 9.5 + 0.5 = 10.
Let's calculate the range of the data:
Range = Upper Limit - Lower Limit
Range = 10 - 9
Range = 1
Since the range is 1 and there are 6 class intervals, we can divide the range by the number of class intervals to determine the class interval size:
Class Interval Size = Range / Number of Class Intervals
Class Interval Size = 1 / 6
Class Interval Size = 0.1667
Now, we can determine the class intervals:
First Class Interval: 9 - 9.1667
Second Class Interval: 9.1667 - 9.3333
Third Class Interval: 9.3333 - 9.5
Fourth Class Interval: 9.5 - 9.6667
Fifth Class Interval: 9.6667 - 9.8333
Sixth Class Interval: 9.8333 - 10
As we can see, the class interval that includes the class mark of 9.5 is 9.5 - 9.6667. Therefore, the correct answer is option D) 6.5-12.5.
It is important to note that the other options given are incorrect because they do not include the class mark of 9.5 within the range of the class intervals.
Dividing population into several homogeneous groups for data collection is called- a)deliberate sampling.
- b)stratified sampling.
- c)systematic sampling.
- d)convenience sampling.
Correct answer is option 'C'. Can you explain this answer?
Dividing population into several homogeneous groups for data collection is called
a)
deliberate sampling.
b)
stratified sampling.
c)
systematic sampling.
d)
convenience sampling.
|
|
Ishan Choudhury answered |
The population is divided into homogeneous groups on the basis of their characteristics. It is called systematic sampling.
In an examination, ten students scored the following marks: 60, 58, 90, 51, 47, 81, 70, 95, 87, 99. The range of this data is- a)60
- b)51
- c)61
- d)52
Correct answer is option 'D'. Can you explain this answer?
In an examination, ten students scored the following marks: 60, 58, 90, 51, 47, 81, 70, 95, 87, 99. The range of this data is
a)
60
b)
51
c)
61
d)
52
|
Ishaan Mukherjee answered |
Given data: 60, 58, 90, 51, 47, 81, 70, 95, 87, 99
Range = difference between the highest and the lowest value in the data
To find the range, we need to first arrange the data in ascending or descending order.
Arranging the data in ascending order:
47, 51, 58, 60, 70, 81, 87, 90, 95, 99
Range = highest value - lowest value
Range = 99 - 47
Range = 52
Therefore, the correct answer is option 'D' (52).
Range = difference between the highest and the lowest value in the data
To find the range, we need to first arrange the data in ascending or descending order.
Arranging the data in ascending order:
47, 51, 58, 60, 70, 81, 87, 90, 95, 99
Range = highest value - lowest value
Range = 99 - 47
Range = 52
Therefore, the correct answer is option 'D' (52).
The mean of five observations is 15. If the mean of first three observations is 14 and that of last three is 17, then the third observation is- a)29
- b)31
- c)32
- d)18
Correct answer is option 'D'. Can you explain this answer?
The mean of five observations is 15. If the mean of first three observations is 14 and that of last three is 17, then the third observation is
a)
29
b)
31
c)
32
d)
18
|
|
Naina Sharma answered |
⇒ It is given that Mean of 5 observations is 15.
∴ The sum of observations =15×5=75.
∴ It is given that mean of the first 3 observations is 14.
∴ The sum of first three observations =14×3=42.
⇒ Given that mean of the last 3 observations is 17.
∴ The sum of the last three observations =17×3=51
∴ The third observation =(42+51)−75
=93−75
=93−75
=18
On the basis of presence and absence of an attribute, data are classified into- a)one fold classification.
- b)two fold classification.
- c)three fold classification.
- d)four fold classification.
Correct answer is option 'B'. Can you explain this answer?
On the basis of presence and absence of an attribute, data are classified into
a)
one fold classification.
b)
two fold classification.
c)
three fold classification.
d)
four fold classification.
|
Sunil Chahar answered |
When on the basis presence and absence of an attribute, the data are classified into two classes, one possessing that attribute and the other not possessing that attribute, it is called two-fold classification.
Arithmetic mean is of- a)two types.
- b)three types.
- c)four types.
- d)five types.
Correct answer is option 'A'. Can you explain this answer?
Arithmetic mean is of
a)
two types.
b)
three types.
c)
four types.
d)
five types.
|
Tejas Verma answered |
Arithmetic mean is of two types:
- Simple arithmetic mean
- Weighted mean.
Data can be represented in
- a)one way.
- b)two ways.
- c)four ways.
- d)three ways.
Correct answer is option 'D'. Can you explain this answer?
Data can be represented in
a)
one way.
b)
two ways.
c)
four ways.
d)
three ways.
|
|
Pranjli Dixit answered |
Two ways
first as primary data
and second as secondary data
first as primary data
and second as secondary data
A set of data consists of six numbers: 7, 8, 8, 9, 9 and x. The difference between the modes when x = 9 and x = 8 is- a)1
- b)4
- c)3
- d)2
Correct answer is option 'A'. Can you explain this answer?
A set of data consists of six numbers: 7, 8, 8, 9, 9 and x. The difference between the modes when x = 9 and x = 8 is
a)
1
b)
4
c)
3
d)
2
|
Dhwani Shah answered |
**Solution:**
To find the difference between the modes when x = 9 and x = 8, we need to determine the modes for both scenarios and then calculate the difference between them.
Given data set: 7, 8, 8, 9, 9, x
**When x = 9:**
In this case, the data set becomes: 7, 8, 8, 9, 9, 9
The modes are the numbers that appear most frequently in the data set. In this case, the modes are 8 and 9, as they both appear twice.
**When x = 8:**
In this case, the data set becomes: 7, 8, 8, 9, 9, 8
The modes are the numbers that appear most frequently in the data set. In this case, the modes are 8 and 9, as they both appear twice.
Therefore, the modes are the same for both scenarios: 8 and 9.
**Calculating the difference between the modes:**
To calculate the difference between the modes, we subtract the smaller mode from the larger mode.
In this case, the smaller mode is 8 and the larger mode is 9.
Difference = 9 - 8 = 1
Therefore, the difference between the modes when x = 9 and x = 8 is 1.
Hence, the correct answer is option A.
To find the difference between the modes when x = 9 and x = 8, we need to determine the modes for both scenarios and then calculate the difference between them.
Given data set: 7, 8, 8, 9, 9, x
**When x = 9:**
In this case, the data set becomes: 7, 8, 8, 9, 9, 9
The modes are the numbers that appear most frequently in the data set. In this case, the modes are 8 and 9, as they both appear twice.
**When x = 8:**
In this case, the data set becomes: 7, 8, 8, 9, 9, 8
The modes are the numbers that appear most frequently in the data set. In this case, the modes are 8 and 9, as they both appear twice.
Therefore, the modes are the same for both scenarios: 8 and 9.
**Calculating the difference between the modes:**
To calculate the difference between the modes, we subtract the smaller mode from the larger mode.
In this case, the smaller mode is 8 and the larger mode is 9.
Difference = 9 - 8 = 1
Therefore, the difference between the modes when x = 9 and x = 8 is 1.
Hence, the correct answer is option A.
To analyse the election results, the data is collected from a newspapers. The data thus collected is known as- a)secondary data
- b)raw data
- c)grouped data
- d)primary data
Correct answer is option 'A'. Can you explain this answer?
To analyse the election results, the data is collected from a newspapers. The data thus collected is known as
a)
secondary data
b)
raw data
c)
grouped data
d)
primary data
|
Shweta Arya Arya answered |
Correct answer is option ‘ A ' because secondary data means data collected by someone else earlier like newspaper
In a bar graph, 0.25 cm length of a bar represents 100 people. Then, the length of bar which represents 2000 people is- a)4 cm
- b)4.5 cm
- c)5 cm
- d)3.5 cm
Correct answer is option 'C'. Can you explain this answer?
In a bar graph, 0.25 cm length of a bar represents 100 people. Then, the length of bar which represents 2000 people is
a)
4 cm
b)
4.5 cm
c)
5 cm
d)
3.5 cm
|
|
Vikram Khanna answered |
To find the length of a bar that represents 2000 people in a bar graph, you can use the following steps:
Identify the scale of the bar graph: In this case, the scale of the bar graph is 0.25 cm per 100 people.
Calculate the number of units on the scale: To find the number of units on the scale, you can divide the number of people by the number of people per unit. In this case, you would divide 2000 people by 100 people/unit = 20 units.
Multiply the number of units by the length of each unit: To find the length of the bar, you can multiply the number of units by the length of each unit. In this case, the length of the bar would be 20 units * 0.25 cm/unit = 5 cm.
Therefore, the length of a bar that represents 2000 people in this bar graph is 5 cm. The correct answer is option (c).
Each given interval is called a- a)frequency.
- b)series.
- c)class.
- d)distribution.
Correct answer is option 'C'. Can you explain this answer?
Each given interval is called a
a)
frequency.
b)
series.
c)
class.
d)
distribution.
|
Poonam Reddy answered |
Difference between upper and lower class limit is called class interval.
For example, 0-10, 10-20, 20-30 etc.
The quantitative character of an item is shown by- a)attributes.
- b)variables.
- c)figures.
- d)tables.
Correct answer is option 'B'. Can you explain this answer?
The quantitative character of an item is shown by
a)
attributes.
b)
variables.
c)
figures.
d)
tables.
|
|
Poonam Reddy answered |
Heights and weights of individuals are variables as they can be measured in numerical terms. Thus, variables are used when changing characterstics are numerically measured.
The mean of six numbers is 23. If one of the numbers is excluded, the mean of the remaining numbers becomes 20. The excluded number is- a)38
- b)37
- c)36
- d)39
Correct answer is option 'A'. Can you explain this answer?
The mean of six numbers is 23. If one of the numbers is excluded, the mean of the remaining numbers becomes 20. The excluded number is
a)
38
b)
37
c)
36
d)
39
|
|
Soumya Tiwari answered |
To solve this problem, we need to use the concept of the mean and how it is affected by adding or removing numbers from a set of data. Let's break down the given information and solve the problem step by step.
Given Information:
- The mean of six numbers is 23.
- If one of the numbers is excluded, the mean of the remaining numbers becomes 20.
Step 1: Find the sum of the six numbers
Since the mean is the sum of all numbers divided by the total count, we can find the sum of the six numbers by multiplying the mean (23) by the count (6).
Sum of the six numbers = Mean * Count = 23 * 6 = 138
Step 2: Find the sum of the five remaining numbers
If the mean of the remaining five numbers is 20, we can find the sum of those numbers by multiplying the mean (20) by the count (5).
Sum of the five remaining numbers = Mean * Count = 20 * 5 = 100
Step 3: Find the excluded number
To find the excluded number, we need to subtract the sum of the five remaining numbers from the sum of the six numbers.
Excluded number = Sum of the six numbers - Sum of the five remaining numbers = 138 - 100 = 38
Conclusion:
The excluded number is 38 (option A) based on the given information and calculations above.
Given Information:
- The mean of six numbers is 23.
- If one of the numbers is excluded, the mean of the remaining numbers becomes 20.
Step 1: Find the sum of the six numbers
Since the mean is the sum of all numbers divided by the total count, we can find the sum of the six numbers by multiplying the mean (23) by the count (6).
Sum of the six numbers = Mean * Count = 23 * 6 = 138
Step 2: Find the sum of the five remaining numbers
If the mean of the remaining five numbers is 20, we can find the sum of those numbers by multiplying the mean (20) by the count (5).
Sum of the five remaining numbers = Mean * Count = 20 * 5 = 100
Step 3: Find the excluded number
To find the excluded number, we need to subtract the sum of the five remaining numbers from the sum of the six numbers.
Excluded number = Sum of the six numbers - Sum of the five remaining numbers = 138 - 100 = 38
Conclusion:
The excluded number is 38 (option A) based on the given information and calculations above.
In a frequency distribution, the mid-value of a class is 60.5 and the width of the class is 10. The lower limit of the class is- a)55.5
- b)56.5
- c)62.5
- d)65.5
Correct answer is option 'A'. Can you explain this answer?
In a frequency distribution, the mid-value of a class is 60.5 and the width of the class is 10. The lower limit of the class is
a)
55.5
b)
56.5
c)
62.5
d)
65.5
|
|
Arpita Rane answered |
To find the lower limit of the class, we can subtract half of the width of the class from the mid-value of the class.
Given information:
Mid-value of the class = 60.5
Width of the class = 10
Finding the lower limit of the class:
Lower limit of the class = Mid-value of the class - (Width of the class / 2)
Substituting the given values:
Lower limit of the class = 60.5 - (10 / 2)
Simplifying the expression:
Lower limit of the class = 60.5 - 5
Therefore, the lower limit of the class is 55.5.
So, the correct answer is option 'A' (55.5).
Given information:
Mid-value of the class = 60.5
Width of the class = 10
Finding the lower limit of the class:
Lower limit of the class = Mid-value of the class - (Width of the class / 2)
Substituting the given values:
Lower limit of the class = 60.5 - (10 / 2)
Simplifying the expression:
Lower limit of the class = 60.5 - 5
Therefore, the lower limit of the class is 55.5.
So, the correct answer is option 'A' (55.5).
In case the interviewer is unable to contact a person, it is called- a)sampling bias.
- b)non-response error.
- c)non-sampling error.
- d)error of calculation.
Correct answer is option 'B'. Can you explain this answer?
In case the interviewer is unable to contact a person, it is called
a)
sampling bias.
b)
non-response error.
c)
non-sampling error.
d)
error of calculation.
|
Puja Das answered |
Non-response errors occur when the respondent refuses to respond or the person refuses to provide information.
A student collects information about the number of school going children in a locality consisting of a hundred households. The data collected by him is- a)Arrayed data
- b)Grouped data
- c)Primary data
- d)Secondary data
Correct answer is option 'C'. Can you explain this answer?
A student collects information about the number of school going children in a locality consisting of a hundred households. The data collected by him is
a)
Arrayed data
b)
Grouped data
c)
Primary data
d)
Secondary data
|
|
Rajdeep Majumdar answered |
Primary Data in Statistics
Primary data is the data that is collected firsthand by the researcher himself for a specific research purpose. It is original data that has not been processed or analyzed by anyone else. The researcher collects primary data by conducting surveys, experiments, observations, or interviews.
Explanation:
In the given scenario, a student collects information about the number of school going children in a locality consisting of a hundred households. This information is collected by the student himself for a specific research purpose, making it primary data. The data is collected through surveys or interviews conducted by the student.
Option C is the correct answer as it refers to primary data. Option A, arrayed data, refers to data that is arranged in a specific sequence or order. Option B, grouped data, refers to data that is organized into groups or categories for analysis. Option D, secondary data, refers to data that has already been collected and processed by someone else for a different research purpose.
Primary data is the data that is collected firsthand by the researcher himself for a specific research purpose. It is original data that has not been processed or analyzed by anyone else. The researcher collects primary data by conducting surveys, experiments, observations, or interviews.
Explanation:
In the given scenario, a student collects information about the number of school going children in a locality consisting of a hundred households. This information is collected by the student himself for a specific research purpose, making it primary data. The data is collected through surveys or interviews conducted by the student.
Option C is the correct answer as it refers to primary data. Option A, arrayed data, refers to data that is arranged in a specific sequence or order. Option B, grouped data, refers to data that is organized into groups or categories for analysis. Option D, secondary data, refers to data that has already been collected and processed by someone else for a different research purpose.
The subject that helps in analysing economic problems and formulating policies to solve them is- a)Physics.
- b)Chemistry
- c)Mathematics.
- d)Statistics.
Correct answer is option 'D'. Can you explain this answer?
The subject that helps in analysing economic problems and formulating policies to solve them is
a)
Physics.
b)
Chemistry
c)
Mathematics.
d)
Statistics.
|
|
Nimmi answered |
Statistics is the subject which deals with analysing economic problem and formulating policies using quantitative data.
There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be – 3.5. The mean of the given number is- a)47.5
- b)52.5
- c)56.5
- d)49.5
Correct answer is option 'C'. Can you explain this answer?
There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be – 3.5. The mean of the given number is
a)
47.5
b)
52.5
c)
56.5
d)
49.5
|
Hansa Sharma answered |
Total numbers =50
Mean of numbers after subtracting 53 from each =3.5
Sum of numbers after subtracting 53 from each =3.5×50=175
Sum of the original numbers =175+53×50=2825
Mean of the original numbers =2825/50=56.5
Mean of numbers after subtracting 53 from each =3.5
Sum of numbers after subtracting 53 from each =3.5×50=175
Sum of the original numbers =175+53×50=2825
Mean of the original numbers =2825/50=56.5
A data is such that its maximum value is 75 and range is 20, then the minimum value is- a)20
- b)55
- c)75
- d)95
Correct answer is option 'B'. Can you explain this answer?
A data is such that its maximum value is 75 and range is 20, then the minimum value is
a)
20
b)
55
c)
75
d)
95
|
|
Aditya Shah answered |
Let minimum value be x ,
So,
75 - x = 20
x = 75 - 20
x = 55
So,
75 - x = 20
x = 75 - 20
x = 55
In a bar graph, 0.25 cm length of a bar represents 100 people. Then, the length of bar which represents 2000 people is- a)5 cm
- b)4 cm
- c)4.5 cm
- d)3.5 cm
Correct answer is option 'A'. Can you explain this answer?
In a bar graph, 0.25 cm length of a bar represents 100 people. Then, the length of bar which represents 2000 people is
a)
5 cm
b)
4 cm
c)
4.5 cm
d)
3.5 cm
|
Charvi Tiwari answered |
Given, 0.25 cm represents 100 people.
To find the length of the bar that represents 2000 people, we need to use the concept of proportionality.
Let x be the length of the bar that represents 2000 people.
We know that,
0.25 cm represents 100 people
So,
x cm represents 2000 people
Using the concept of proportionality, we can write:
0.25/100 = x/2000
Simplifying the above equation, we get:
x = (0.25 x 2000)/100
x = 5 cm
Therefore, the length of the bar that represents 2000 people is 5 cm.
Hence, the correct option is (a) 5 cm.
To find the length of the bar that represents 2000 people, we need to use the concept of proportionality.
Let x be the length of the bar that represents 2000 people.
We know that,
0.25 cm represents 100 people
So,
x cm represents 2000 people
Using the concept of proportionality, we can write:
0.25/100 = x/2000
Simplifying the above equation, we get:
x = (0.25 x 2000)/100
x = 5 cm
Therefore, the length of the bar that represents 2000 people is 5 cm.
Hence, the correct option is (a) 5 cm.
The mathematical average is also called- a)median.
- b)mode.
- c)mean.
- d)quartile.
Correct answer is option 'C'. Can you explain this answer?
The mathematical average is also called
a)
median.
b)
mode.
c)
mean.
d)
quartile.
|
|
Tejas Verma answered |
► Mean is a mathematical average.
The arithmetic mean or mean is defined as the sum of values of a group of items divided by the number of items. It is denoted by mean.
More than one attribute are present simultaneously in case of- a)qualitative classification.
- b)quantitative classification.
- c)manifold classification.
- d)chronological classification.
Correct answer is option 'C'. Can you explain this answer?
More than one attribute are present simultaneously in case of
a)
qualitative classification.
b)
quantitative classification.
c)
manifold classification.
d)
chronological classification.
|
|
Vikas Kapoor answered |
In manifold classification, two or more attributes are considered simultaneously. When more attributes are involved, the data would be classified into several classes and subclasses depending on the number of attributes.
For example, the population in a country can be classified in terms of gender as male and female.
For example, the population in a country can be classified in terms of gender as male and female.
The correct option is Option C
Classification of data is the grouping of raw data under different- a)headings
- b)rows
- c)columns
- d)tables
Correct answer is option 'A'. Can you explain this answer?
Classification of data is the grouping of raw data under different
a)
headings
b)
rows
c)
columns
d)
tables
|
|
Vikas Kapoor answered |
Classification is concerned with the division of the data into various groups and sub groups.
► Data is classified into groups of different headings.
The mean of first four prime numbers is- a)4
- b)4.5
- c)3.75
- d)4.25
Correct answer is option 'D'. Can you explain this answer?
The mean of first four prime numbers is
a)
4
b)
4.5
c)
3.75
d)
4.25
|
|
Sarthak Satav answered |
First four prime number 2,3,5,7
mean = sum of all observation/Number of observation
= 2+3+5+7 / 4
= 17/4
= 4.25
so option D is correct
mean = sum of all observation/Number of observation
= 2+3+5+7 / 4
= 17/4
= 4.25
so option D is correct
In a grouped frequency distribution, the class intervals are 0-10, 10-20, 20-30, .., then the class width is- a)10
- b)15
- c)20
- d)30
Correct answer is option 'A'. Can you explain this answer?
In a grouped frequency distribution, the class intervals are 0-10, 10-20, 20-30, .., then the class width is
a)
10
b)
15
c)
20
d)
30
|
Sara Nair answered |
Explanation:
A grouped frequency distribution is a tabular representation of data that is divided into intervals or classes, and each class represents a range of values. In this case, the class intervals are 0-10, 10-20, 20-30, and so on.
The class width is the difference between the upper and lower class limits of a class interval. In this case, the lower class limit of the first interval is 0 and the upper class limit is 10. Therefore, the class width is:
Upper class limit - Lower class limit = 10 - 0 = 10
Hence, the correct answer is option A) 10.
A grouped frequency distribution is a tabular representation of data that is divided into intervals or classes, and each class represents a range of values. In this case, the class intervals are 0-10, 10-20, 20-30, and so on.
The class width is the difference between the upper and lower class limits of a class interval. In this case, the lower class limit of the first interval is 0 and the upper class limit is 10. Therefore, the class width is:
Upper class limit - Lower class limit = 10 - 0 = 10
Hence, the correct answer is option A) 10.
Find the value of ‘n’ if the mean of the set of the numbers 8, 5, n, 10, 15, 21 is given as 11.- a)5
- b)7
- c)4
- d)6
Correct answer is option 'B'. Can you explain this answer?
Find the value of ‘n’ if the mean of the set of the numbers 8, 5, n, 10, 15, 21 is given as 11.
a)
5
b)
7
c)
4
d)
6
|
Rohini Desai answered |
Concept:
The mean (or average) of a number of observations is the sum of the values of all the observations divided by the total number of observations. It is denoted by the symbol
, read as ‘x bar’.
The mean (or average) of a number of observations is the sum of the values of all the observations divided by the total number of observations. It is denoted by the symbol
, read as ‘x bar’.Calculation:
Given set of number is 8, 5, n, 10, 15, 21.
Given set of number is 8, 5, n, 10, 15, 21.
Arranging of data in the given series is required while computing- a)mean.
- b)median.
- c)mode.
- d)quartile.
Correct answer is option 'B'. Can you explain this answer?
Arranging of data in the given series is required while computing
a)
mean.
b)
median.
c)
mode.
d)
quartile.
|
Jatin Singh answered |
Calculation of median requires arranging of data in ascending or descending order before calculating mean. It can also be located graphically.
Find the value ‘p + q’, if mean of set of numbers 3, 6, 7, 14, p, 34, 26, q, 12 is given as 22.- a)96
- b)88
- c)76
- d)75
Correct answer is option 'A'. Can you explain this answer?
Find the value ‘p + q’, if mean of set of numbers 3, 6, 7, 14, p, 34, 26, q, 12 is given as 22.
a)
96
b)
88
c)
76
d)
75
|
|
Rohini Desai answered |
Concept:
The mean (or average) of a number of observations is the sum of the values of all the observations divided by the total number of observations. It is denoted by the symbol, read as ‘x bar’.
The mean (or average) of a number of observations is the sum of the values of all the observations divided by the total number of observations. It is denoted by the symbol, read as ‘x bar’.
Calculation:
Given data 3, 6, 7, 14, p, 34, 26, q and 12.
Mean
∴ p + q = 96
Given data 3, 6, 7, 14, p, 34, 26, q and 12.
Mean
∴ p + q = 96
What is the mean of first 99 natural numbers ?- a)100
- b)50.5
- c)50
- d)99
Correct answer is option 'C'. Can you explain this answer?
What is the mean of first 99 natural numbers ?
a)
100
b)
50.5
c)
50
d)
99
|
|
Rohini Desai answered |
Concept:
Suppose there are ‘n’ observations {x1,x2,x3,…,xn}
Sum of the first n natural numbers
Suppose there are ‘n’ observations {x1,x2,x3,…,xn}
Sum of the first n natural numbers
Calculation:
To find: Mean of the first 99 natural numbers
As we know, Sum of first n natural numbers
Now, Mean
To find: Mean of the first 99 natural numbers
As we know, Sum of first n natural numbers
Now, Mean
If the mode of the following data is 7, then the value of k in the data set 3, 8, 6, 7, 1, 6, 10, 6, 7, 2k + 5, 9, 7, and 13 is:- a)3
- b)7
- c)4
- d)1
Correct answer is option 'D'. Can you explain this answer?
If the mode of the following data is 7, then the value of k in the data set 3, 8, 6, 7, 1, 6, 10, 6, 7, 2k + 5, 9, 7, and 13 is:
a)
3
b)
7
c)
4
d)
1
|
|
Rohini Desai answered |
Concept:
Mode is the value that occurs most often in the data set of values.
Mode is the value that occurs most often in the data set of values.
Calculation:
Given data values are 3, 8, 6, 7, 1, 6, 10, 6, 7, 2k + 5, 9, 7, and 13
In the above data set, values 6, and 7 have occurred more times i.e., 3 times
But given that mode is 7.
So, 7 should occur more times than 6.
Hence the variable 2k + 5 must be 7
⇒ 2k + 5 = 7
⇒ 2k = 2
∴ k = 1
Given data values are 3, 8, 6, 7, 1, 6, 10, 6, 7, 2k + 5, 9, 7, and 13
In the above data set, values 6, and 7 have occurred more times i.e., 3 times
But given that mode is 7.
So, 7 should occur more times than 6.
Hence the variable 2k + 5 must be 7
⇒ 2k + 5 = 7
⇒ 2k = 2
∴ k = 1
A sample which is capable of providing reasonably accurate information about the population at a much lower cost and shorter time is known as- a)sample unit
- b)sample frame
- c)random sample
- d)representative sample
Correct answer is option 'D'. Can you explain this answer?
A sample which is capable of providing reasonably accurate information about the population at a much lower cost and shorter time is known as
a)
sample unit
b)
sample frame
c)
random sample
d)
representative sample
|
Sushil Ku answered |
A good sample is one which is smaller than the population and is capable of providing reasonable accurate information about the population at a much lower cost and in shorter span of time. This kind of a sample is also known as representative sample.
Temporal classification is done on the basis of- a)place.
- b)time.
- c)quality.
- d)quantity.
Correct answer is option 'B'. Can you explain this answer?
Temporal classification is done on the basis of
a)
place.
b)
time.
c)
quality.
d)
quantity.
|
Chan singh answered |
When classification is done on the basis of time, the classification is known as temporal classification. Time may be in hours, days, weeks, months, years etc.
In an examination, ten students scored the following marks: 60, 58, 90, 51, 47, 81, 70, 95, 87, 99. The range of this data is- a)52
- b)51
- c)81
- d)60
Correct answer is option 'A'. Can you explain this answer?
In an examination, ten students scored the following marks: 60, 58, 90, 51, 47, 81, 70, 95, 87, 99. The range of this data is
a)
52
b)
51
c)
81
d)
60
|
Sandeep Saini answered |
The range of this data is the difference between the highest and lowest scores. In this case, the highest score is 99 and the lowest score is 47, so the range is 99-47=52. Therefore, the correct answer is (a) 52.
Out of sixteen observations arranged in an ascending order, the 8th and 9th observations are 25 and 27. Then, the median is- a)26
- b)27
- c)25
- d)26.5
Correct answer is option 'A'. Can you explain this answer?
Out of sixteen observations arranged in an ascending order, the 8th and 9th observations are 25 and 27. Then, the median is
a)
26
b)
27
c)
25
d)
26.5
|
|
Pranjal Gupta answered |
To find the median, we need to determine the middle value of the observations. In this case, we have 16 observations arranged in ascending order.
Given that the 8th observation is 25 and the 9th observation is 27, we can see that these two values are consecutive. This means that there are 7 observations before the 8th observation (including the 8th observation itself) and 6 observations after the 9th observation (including the 9th observation itself).
Since there are an even number of observations (16), the median will be the average of the two middle values. In this case, the two middle values are the 8th and 9th observations, which are 25 and 27.
To find the average, we add the two values together and divide by 2:
(25 + 27) / 2 = 52 / 2 = 26.
Therefore, the median of the given observations is 26.
Hence, the correct answer is option A) 26.
Given that the 8th observation is 25 and the 9th observation is 27, we can see that these two values are consecutive. This means that there are 7 observations before the 8th observation (including the 8th observation itself) and 6 observations after the 9th observation (including the 9th observation itself).
Since there are an even number of observations (16), the median will be the average of the two middle values. In this case, the two middle values are the 8th and 9th observations, which are 25 and 27.
To find the average, we add the two values together and divide by 2:
(25 + 27) / 2 = 52 / 2 = 26.
Therefore, the median of the given observations is 26.
Hence, the correct answer is option A) 26.
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is- a)15
- b)35
- c)25
- d)40
Correct answer is option 'B'. Can you explain this answer?
The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
a)
15
b)
35
c)
25
d)
40
|
|
Nikhita Patel answered |
To solve this problem, we need to understand the concept of class limits and how they relate to the width of each class.
Class limits are the minimum and maximum values within a class interval. The lower class limit is the smallest value within a class, while the upper class limit is the largest value within a class.
Given that the width of each class is 5, it means that the difference between the upper class limit and the lower class limit is 5. Therefore, if we know the lower class limit of the lowest class, we can determine the upper class limit of the highest class.
Let's consider the given information:
- Width of each class: 5
- Lower class limit of the lowest class: 10
To find the upper class limit of the highest class, we need to determine the difference between the lower class limit of the highest class and the width of each class.
Let's denote the lower class limit of the highest class as "L" and find its value:
L = Lower class limit of the lowest class + (Number of classes - 1) × Width of each class
Number of classes can be calculated using the formula:
Number of classes = (Range of data) / (Width of each class)
The range of data is the difference between the maximum and minimum values in the dataset. However, since we don't have this information, we cannot directly calculate the number of classes.
However, we do know that the lower class limit of the lowest class is 10. Therefore, we can make an assumption that the minimum value in the dataset is 10. This assumption allows us to calculate the number of classes:
Number of classes = (Range of data) / (Width of each class)
= (Maximum value - Minimum value) / (Width of each class)
= (L - 10) / 5
Since we know that the width of each class is 5, we can rearrange the equation to solve for L:
L = 10 + (Number of classes - 1) × Width of each class
= 10 + (((L - 10) / 5) - 1) × 5
Simplifying the equation:
L = 10 + (L - 10) - 5
L = L - 10 - 5 + 10
L = L - 5
At this point, we can see that L is equal to the upper class limit of the highest class. Therefore, the answer is option B) 35.
Class limits are the minimum and maximum values within a class interval. The lower class limit is the smallest value within a class, while the upper class limit is the largest value within a class.
Given that the width of each class is 5, it means that the difference between the upper class limit and the lower class limit is 5. Therefore, if we know the lower class limit of the lowest class, we can determine the upper class limit of the highest class.
Let's consider the given information:
- Width of each class: 5
- Lower class limit of the lowest class: 10
To find the upper class limit of the highest class, we need to determine the difference between the lower class limit of the highest class and the width of each class.
Let's denote the lower class limit of the highest class as "L" and find its value:
L = Lower class limit of the lowest class + (Number of classes - 1) × Width of each class
Number of classes can be calculated using the formula:
Number of classes = (Range of data) / (Width of each class)
The range of data is the difference between the maximum and minimum values in the dataset. However, since we don't have this information, we cannot directly calculate the number of classes.
However, we do know that the lower class limit of the lowest class is 10. Therefore, we can make an assumption that the minimum value in the dataset is 10. This assumption allows us to calculate the number of classes:
Number of classes = (Range of data) / (Width of each class)
= (Maximum value - Minimum value) / (Width of each class)
= (L - 10) / 5
Since we know that the width of each class is 5, we can rearrange the equation to solve for L:
L = 10 + (Number of classes - 1) × Width of each class
= 10 + (((L - 10) / 5) - 1) × 5
Simplifying the equation:
L = 10 + (L - 10) - 5
L = L - 10 - 5 + 10
L = L - 5
At this point, we can see that L is equal to the upper class limit of the highest class. Therefore, the answer is option B) 35.
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