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The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class is
  • a)
    15
  • b)
    35
  • c)
    25
  • d)
    40
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The width of each of five continuous classes in a frequency distributi...
To solve this problem, we need to understand the concept of class limits and how they relate to the width of each class.

Class limits are the minimum and maximum values within a class interval. The lower class limit is the smallest value within a class, while the upper class limit is the largest value within a class.

Given that the width of each class is 5, it means that the difference between the upper class limit and the lower class limit is 5. Therefore, if we know the lower class limit of the lowest class, we can determine the upper class limit of the highest class.

Let's consider the given information:

- Width of each class: 5
- Lower class limit of the lowest class: 10

To find the upper class limit of the highest class, we need to determine the difference between the lower class limit of the highest class and the width of each class.

Let's denote the lower class limit of the highest class as "L" and find its value:

L = Lower class limit of the lowest class + (Number of classes - 1) × Width of each class

Number of classes can be calculated using the formula:

Number of classes = (Range of data) / (Width of each class)

The range of data is the difference between the maximum and minimum values in the dataset. However, since we don't have this information, we cannot directly calculate the number of classes.

However, we do know that the lower class limit of the lowest class is 10. Therefore, we can make an assumption that the minimum value in the dataset is 10. This assumption allows us to calculate the number of classes:

Number of classes = (Range of data) / (Width of each class)
= (Maximum value - Minimum value) / (Width of each class)
= (L - 10) / 5

Since we know that the width of each class is 5, we can rearrange the equation to solve for L:

L = 10 + (Number of classes - 1) × Width of each class
= 10 + (((L - 10) / 5) - 1) × 5

Simplifying the equation:

L = 10 + (L - 10) - 5
L = L - 10 - 5 + 10
L = L - 5

At this point, we can see that L is equal to the upper class limit of the highest class. Therefore, the answer is option B) 35.
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Community Answer
The width of each of five continuous classes in a frequency distributi...
According to the question the lower limit of the lowest class is 10, the class width is 5 and there are 5 continuous classes. So the class intervals are :

10 - 15
15 - 20
20 - 25
25 - 30
30 - 35

The highest class is 30 - 35. So, its upper limit is 35. Hence, the answer B is correct.
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The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class isa)15b)35c)25d)40Correct answer is option 'B'. Can you explain this answer?
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