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After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?- a)1400
- b)1300
- c)1200
- d)1100
Correct answer is option 'C'. Can you explain this answer?
After decreasing 24% in the price of an article costs Rs.912. Find the actual cost of an article?
a)
1400
b)
1300
c)
1200
d)
1100
|
Pk Academy answered |
CP* (76/100) = 912
CP= 12 * 100
Hence, the Cost Price is 1200
CP= 12 * 100
Hence, the Cost Price is 1200
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M and N’s salaries together amount to Rs. 2,000. M spends 95% of his salary and N spends 85% of his. If now their savings are the same, what is N’s salary?- a)Rs.1500
- b)Rs.750
- c)Rs.1250
- d)Rs.500
Correct answer is option 'D'. Can you explain this answer?
M and N’s salaries together amount to Rs. 2,000. M spends 95% of his salary and N spends 85% of his. If now their savings are the same, what is N’s salary?
a)
Rs.1500
b)
Rs.750
c)
Rs.1250
d)
Rs.500
|
|
Pk Academy answered |
Let's assume M's salary is x and N's salary is y.
According to the given information, we can form the following equations:
M + N = 2000 (Equation 1) - their salaries together amount to Rs. 2000
M - 0.95M = N - 0.85N (Equation 2) - their savings are the same
Simplifying Equation 2, we get:
0.05M = 0.15N
Dividing both sides by 0.05, we get:
M = 3N (Equation 3)
Substituting Equation 3 into Equation 1, we get:
3N + N = 2000
Combining like terms, we get:
4N = 2000
Dividing both sides by 4, we get:
N = 500
Therefore, N's salary is Rs. 500.
Hence, the correct answer is option A: Rs. 500.
According to the given information, we can form the following equations:
M + N = 2000 (Equation 1) - their salaries together amount to Rs. 2000
M - 0.95M = N - 0.85N (Equation 2) - their savings are the same
Simplifying Equation 2, we get:
0.05M = 0.15N
Dividing both sides by 0.05, we get:
M = 3N (Equation 3)
Substituting Equation 3 into Equation 1, we get:
3N + N = 2000
Combining like terms, we get:
4N = 2000
Dividing both sides by 4, we get:
N = 500
Therefore, N's salary is Rs. 500.
Hence, the correct answer is option A: Rs. 500.
In a class of 45 students, Aravind’s rank from the top is 16th. Basha is 6 ranks below Aravind. What is Basha’s rank from the bottom?- a)23rd
- b)24th
- c)30th
- d)32nd
Correct answer is option 'B'. Can you explain this answer?
In a class of 45 students, Aravind’s rank from the top is 16th. Basha is 6 ranks below Aravind. What is Basha’s rank from the bottom?
a)
23rd
b)
24th
c)
30th
d)
32nd
|
|
Pk Academy answered |
According to the given data
Basha’s rank from bottom = 45 – (16 + 6) + 1 = 24th
Basha’s rank from bottom = 45 – (16 + 6) + 1 = 24th
A Lion starts chasing a Deer. It takes 4 hours to catch the Deer. If the speed of the Lion is 40 kmph. What is the speed of Deer?- a)20 kmph
- b)50 kmph
- c)40 kmph
- d)70 kmph
Correct answer is option 'A'. Can you explain this answer?
A Lion starts chasing a Deer. It takes 4 hours to catch the Deer. If the speed of the Lion is 40 kmph. What is the speed of Deer?
a)
20 kmph
b)
50 kmph
c)
40 kmph
d)
70 kmph
|
Codebreakers answered |
Let us assume that
Deer Speed = x kmph
Then, 4 = 4*x/(40-x)
x = 20 kmph
Deer Speed = x kmph
Then, 4 = 4*x/(40-x)
x = 20 kmph
A trader marks the price at 8 percent higher than the original price. Due to the hike in demand, he again increases the price by 10 percent. How much percent profit he gets.- a)17.8%
- b)18.8%
- c)19.8%
- d)20.8%
Correct answer is option 'B'. Can you explain this answer?
A trader marks the price at 8 percent higher than the original price. Due to the hike in demand, he again increases the price by 10 percent. How much percent profit he gets.
a)
17.8%
b)
18.8%
c)
19.8%
d)
20.8%
|
Kavya Nair answered |
Calculation:
Step 1: Initial price increase
- Let the original price be 100.
- The trader marks the price at 8% higher, so the new price = 100 + 8% of 100 = 100 + 8 = 108.
Step 2: Second price increase
- Due to the hike in demand, the price is increased by 10%.
- The new price after the second increase = 108 + 10% of 108 = 108 + 10.8 = 118.8.
Profit Percentage Calculation:
- Profit percentage = ((Selling Price - Cost Price) / Cost Price) * 100
- Cost Price = 100 (initial price)
- Selling Price = 118.8 (final price after both increases)
- Profit percentage = ((118.8 - 100) / 100) * 100 = 18.8%
Therefore, the trader gets a profit percentage of 18.8%. Option B is the correct answer.
Step 1: Initial price increase
- Let the original price be 100.
- The trader marks the price at 8% higher, so the new price = 100 + 8% of 100 = 100 + 8 = 108.
Step 2: Second price increase
- Due to the hike in demand, the price is increased by 10%.
- The new price after the second increase = 108 + 10% of 108 = 108 + 10.8 = 118.8.
Profit Percentage Calculation:
- Profit percentage = ((Selling Price - Cost Price) / Cost Price) * 100
- Cost Price = 100 (initial price)
- Selling Price = 118.8 (final price after both increases)
- Profit percentage = ((118.8 - 100) / 100) * 100 = 18.8%
Therefore, the trader gets a profit percentage of 18.8%. Option B is the correct answer.
Choose the word which is different from the rest.- a)Scallop
- b)Mussel
- c)Oyster
- d)Clam
Correct answer is option 'A'. Can you explain this answer?
Choose the word which is different from the rest.
a)
Scallop
b)
Mussel
c)
Oyster
d)
Clam
|
|
Pk Academy answered |
All except Scallop live in shells
If the price of an article is increased by 15%, then by how much the household should decrease their consumption so as to keep his expenditure same.- a)11(1/23)%
- b)11(2/23)%
- c)13(1/23) %
- d)13(2/23)%
Correct answer is option 'C'. Can you explain this answer?
If the price of an article is increased by 15%, then by how much the household should decrease their consumption so as to keep his expenditure same.
a)
11(1/23)%
b)
11(2/23)%
c)
13(1/23) %
d)
13(2/23)%
|
|
Pk Academy answered |
By Analyzing the given information
Decrease in expenditure = (15/115)*100 = 13(1/23) %
Decrease in expenditure = (15/115)*100 = 13(1/23) %
Two pipes M and N can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are opened simultaneously, after what time should N be closed so that the tank is full in 6 minutes?- a)1 min
- b)2 min
- c)3 min
- d)4 min
Correct answer is option 'C'. Can you explain this answer?
Two pipes M and N can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are opened simultaneously, after what time should N be closed so that the tank is full in 6 minutes?
a)
1 min
b)
2 min
c)
3 min
d)
4 min
|
|
Pk Academy answered |
Let us assume that after x minutes pipe N is closed
(1/8 + 1/12)*x + (1/8)*(6 -x) = 1
Therefore, x = 3 minutes
(1/8 + 1/12)*x + (1/8)*(6 -x) = 1
Therefore, x = 3 minutes
Ajay invested an amount of Rs.9000 in a fixed deposit scheme for 2 years at CI rate 6% Per Annum. How much amount will Ajay get on maturity of the fixed amount?- a)Rs. 11, 230
- b)Rs. 10, 250
- c)Rs. 10, 112
- d)Rs. 10, 400
Correct answer is option 'C'. Can you explain this answer?
Ajay invested an amount of Rs.9000 in a fixed deposit scheme for 2 years at CI rate 6% Per Annum. How much amount will Ajay get on maturity of the fixed amount?
a)
Rs. 11, 230
b)
Rs. 10, 250
c)
Rs. 10, 112
d)
Rs. 10, 400
|
|
Pk Academy answered |
Amount = 9000*106/100*106/100
= 9000*53/50*53/50
= 10, 112
Therefore, Ajay will get on maturity of a fixed amount is Rs. 10, 112
= 9000*53/50*53/50
= 10, 112
Therefore, Ajay will get on maturity of a fixed amount is Rs. 10, 112
Peace: Chaos:: Creation:?
- a)Build
- b)Manufacture
- c)Destruction
- d)Construction
Correct answer is option 'C'. Can you explain this answer?
Peace: Chaos:: Creation:?
a)
Build
b)
Manufacture
c)
Destruction
d)
Construction
|
|
Pk Academy answered |
As the opposite meaning of peace is chaos
Therefore, the opposite meaning of creation is destruction.
Therefore, the opposite meaning of creation is destruction.
If the side of the square is increased by 30%, then how much % does its area get increased?- a)49%
- b)69%
- c)79%
- d)89%
Correct answer is option 'B'. Can you explain this answer?
If the side of the square is increased by 30%, then how much % does its area get increased?
a)
49%
b)
69%
c)
79%
d)
89%
|
|
Pk Academy answered |
Area of the plot is = 1.3 * 1.3 = 1.69 = 69%
Two Trains of the same length are running in the same direction with speed 50 kmph and 80 kmph. The latter completely cross the man in 18sec. The length of each Train is- a)70 m
- b)75 m
- c)80 m
- d)150 m
Correct answer is option 'B'. Can you explain this answer?
Two Trains of the same length are running in the same direction with speed 50 kmph and 80 kmph. The latter completely cross the man in 18sec. The length of each Train is
a)
70 m
b)
75 m
c)
80 m
d)
150 m
|
|
Codebreakers answered |
80 – 50 = 30
30×(5/18) = 25/3 m/s
Distance covered in 20 sec = 18 ×(25/3) = 150
Therefore, Length of each Train = 150/2 = 75 m
30×(5/18) = 25/3 m/s
Distance covered in 20 sec = 18 ×(25/3) = 150
Therefore, Length of each Train = 150/2 = 75 m
Needle: Thread:: Bike:?- a)Oil
- b)Brake
- c)Key
- d)Petrol
Correct answer is option 'D'. Can you explain this answer?
Needle: Thread:: Bike:?
a)
Oil
b)
Brake
c)
Key
d)
Petrol
|
|
Pk Academy answered |
Second is used to perform the function of first.
If CALM is written as XZON, YEAR may be written as- a)BVIZ
- b)BVZJ
- c)BVZI
- d)BZVI
Correct answer is option 'C'. Can you explain this answer?
If CALM is written as XZON, YEAR may be written as
a)
BVIZ
b)
BVZJ
c)
BVZI
d)
BZVI
|
|
Codebreakers answered |
The concept of Reverse EJOTY is followed.
Or we can also say that the sum of the letter & its respective coded letter is 27.
Y+B=25+2=27, E+V=5+22=27, and so on.
Hence code for YEAR is ‘BVZI’.
Or we can also say that the sum of the letter & its respective coded letter is 27.
Y+B=25+2=27, E+V=5+22=27, and so on.
Hence code for YEAR is ‘BVZI’.
Two taps can separately fill the tank in 10 min and 15 min respectively. They fill the tank in 12 minutes when a third pipe which empties the tank is also opened. What is the time taken by the third pipe to empty the whole tank?- a)12 minutes
- b)14 minutes
- c)15 minutes
- d)20 minutes
Correct answer is option 'A'. Can you explain this answer?
Two taps can separately fill the tank in 10 min and 15 min respectively. They fill the tank in 12 minutes when a third pipe which empties the tank is also opened. What is the time taken by the third pipe to empty the whole tank?
a)
12 minutes
b)
14 minutes
c)
15 minutes
d)
20 minutes
|
|
Pk Academy answered |
1/10 + 1/15 – 1/x = 1/12
After solving the above equation we will get x = 12
After solving the above equation we will get x = 12
Two pipes P and Q can fill a tank in 10 hours and 15 hours respectively while a third pipe R can empty the full tank in 20 hours. All the pipes are opened for 5 hours and then R is closed. Find the time in which the tank is full?- a)5.5 hrs
- b)6.5 hrs
- c)7.5 hrs
- d)8.5 hrs
Correct answer is option 'C'. Can you explain this answer?
Two pipes P and Q can fill a tank in 10 hours and 15 hours respectively while a third pipe R can empty the full tank in 20 hours. All the pipes are opened for 5 hours and then R is closed. Find the time in which the tank is full?
a)
5.5 hrs
b)
6.5 hrs
c)
7.5 hrs
d)
8.5 hrs
|
|
Codebreakers answered |
(1/10 + 1/15 – 1/20)*5 + (1/10 + 1/15)*T = 1.
We will get Time = 2.5 hrs
Therefore, the total time = 5 + 2.5 = 7.5 hrs
We will get Time = 2.5 hrs
Therefore, the total time = 5 + 2.5 = 7.5 hrs
In a horse racing, there are three horses, P, Q, and R. The Payoffs at P is 3: 7, at Q, is 4: 9, at R, is 5: 11. Salman bets Rs. 693 on a horse which would fetch the maximum amount. Luckily his horse has won. Then what is the total amount won by him?- a)Rs.990
- b)Rs.1001
- c)Rs.1008
- d)Rs.1011
Correct answer is option 'C'. Can you explain this answer?
In a horse racing, there are three horses, P, Q, and R. The Payoffs at P is 3: 7, at Q, is 4: 9, at R, is 5: 11. Salman bets Rs. 693 on a horse which would fetch the maximum amount. Luckily his horse has won. Then what is the total amount won by him?
a)
Rs.990
b)
Rs.1001
c)
Rs.1008
d)
Rs.1011
|
|
Pk Academy answered |
If Salman bets on horse P: 693*3/7 = 297
If he bets on horse Q: 693*4/9 = 308
If he bets on horse R: 693*5/11 = 315
Hence, Salman bets on horse R and he wins 315
Total = 693+315 = 1008
If he bets on horse Q: 693*4/9 = 308
If he bets on horse R: 693*5/11 = 315
Hence, Salman bets on horse R and he wins 315
Total = 693+315 = 1008
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