All questions of Ratio and Proportion for Mechanical Engineering Exam

Section A and section B of 7th class in a school contains total 285 students.Which of the following can be a ratio of the ratio of the number of boys and number of girls in the class?
  • a)
    6 : 5
  • b)
    10 : 9
  • c)
    11 : 9
  • d)
    13 : 12
  • e)
    Cannot be determined
Correct answer is option 'B'. Can you explain this answer?

B) 10 : 9
Explanation: The number of boys and girls cannot be in decimal values, so the denominator should completely divide number of students (285).
Check each option: 6+5 = 11, and 11 does not divide 285 completely. 10+9 = 19, and only 19 divides 285 completely among all.

A, B and C divide Rs 4200 among themselves in the ratio 7 : 8 : 6. If Rs 200 is added to each of their shares, what is the new ratio in which they will receive the money?
  • a)
    9 : 8 : 7
  • b)
    8 : 9 : 7
  • c)
    8 : 9 : 8
  • d)
    9 : 10 : 8
  • e)
    7 : 9 : 8
Correct answer is option 'B'. Can you explain this answer?

Alok Verma answered
B) 8 : 9 : 7
Explanation: A gets = [7/(7+8+6)] * 4200 = 1400 B gets = [8/(7+8+6)] * 4200 = 1600 C gets = [6/(7+8+6)] * 4200 = 1200 Rs 200 added to each share, so new ratio = 1400+200 : 1600+200 : 1200+200
1600 : 1800 : 1400

One year ago the ratio between rahul salary and rohit salary is 4:5. The ratio between their individual salary of the last year and current year is 2:3 and 3:5 respectively. If the total current salary of rahul and rohit is 4300. Then find the current salary of rahul.
  • a)
    1200
  • b)
    1800
  • c)
    1600
  • d)
    2000
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Faizan Khan answered
Answer – B.1800 Explanation : 4x and 5x is the last year salry of rahul and rohit respectively Rahul last year to rahul current year = 2/3 Rohit last year to rohit current year = 3/5 Current of rahul + current of rohit = 4300 (3/2)*4x + (5/3)*5x = 4300.
X = 300.
So rahul current salary  = 3/2 * 4* 300 = 1800

A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively?.
  • a)
    216, 144, 27
  • b)
    108, 144, 216
  • c)
    27, 72, 216
  • d)
    120, 35, 108
  • e)
    102, 150, 210
Correct answer is option 'B'. Can you explain this answer?

Kavya Saxena answered
B) 108, 144, 216
Explanation: 25 paise = 25/100 Rs, 50 paise = 50/100 Rs So value ratio of these coins become = 3*(25/100) : 4*(50/100) : 6*(1) = 3/4 : 2 : 6 = 3 : 8 : 24
So 25 paise coins value= [3/(3+8+24)] * 315 = Rs 27, so coins = 27 * (100/25) = 108
Similarly find others.

Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys?
  • a)
    62.5%
  • b)
    54.8%
  • c)
    52.6%
  • d)
    55.8%
  • e)
    53.5%
Correct answer is option 'B'. Can you explain this answer?

B) 54.8%
Explanation: Total students in both = 6x+11x = 17x Boys in class 4 = (60/100)*6x = 360x/100 Boys in class 5 = (52/100)*11x = 572x/100 So total boys = 360x/100 + 572x/100 = 932x/100 = 9.32x % of boys = [9.32x/17x] * 100

Rs 650 was divided among 3 children in the ratio 2 : 4 : 7. Had it been divided in the ratio 1/2 : 1/4 : 1/7, who would have gained the most and by how much?
  • a)
    C, Rs 246
  • b)
    C, Rs 264
  • c)
    B, Rs 18
  • d)
    A, Rs 246
  • e)
    A, Rs 264
Correct answer is option 'E'. Can you explain this answer?

Anaya Patel answered
E) A, Rs 264 Explanation: New ratio = 1/2 : 1/4 : 1/7 = 14 : 7 : 4 So both ratio suggests that C has not gained any money, rather he has lose the money.
For both ratio find the shares of A and B With ratio 2 : 4 : 7, A gets = [2/(2+4+7)] * 650 = 100, B gets = [4/(2+4+7)] * 650 = 200
With ratio 14 : 7 : 4, A gets = [14/(14+7+4)] * 650 = 364, B gets = [7/(14+7+4)] * 650 = 182
B has also lose the money, A gain the money and = 364 – 100 = 264

A 50 litre of mixture contains milk and water in the ratio 2:3. How much milk must be added to the mixture so that it contains milk and water in the proportion of 3:2.
  • a)
    20
  • b)
    25
  • c)
    30
  • d)
    35
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Aarav Sharma answered
Given:
- A 50 liter mixture of milk and water in the ratio 2:3
- We need to add milk to the mixture so that it contains milk and water in the proportion of 3:2

To solve this problem, we can use the following steps:

Step 1: Find the amount of milk and water in the original mixture
- Let the amount of milk in the mixture be 2x liters
- Then the amount of water in the mixture will be 3x liters
- Total amount of mixture = 2x + 3x = 5x liters
- We know that the ratio of milk and water in the mixture is 2:3
- So, (2x/5x) = 2/3 => x = (2/3)*5 = 10/3 liters
- Amount of milk in the original mixture = 2x = 2*(10/3) = 20/3 liters
- Amount of water in the original mixture = 3x = 3*(10/3) = 10 liters

Step 2: Find the amount of milk and water in the final mixture
- Let the amount of milk to be added be y liters
- Total amount of milk in the final mixture = (20/3 + y) liters
- Total amount of water in the final mixture = 10 liters

Step 3: Set up the equation for the proportion of milk and water in the final mixture
- We need the final mixture to have milk and water in the proportion of 3:2
- So, (20/3 + y)/10 = 3/2
- Solving for y, we get:
- y = 25/3 liters

Therefore, we need to add 25/3 liters of milk to the mixture so that it contains milk and water in the proportion of 3:2.
Option (B) is the correct answer.

Equal quantities of 3 mixtures of milk and water are mixed in the ratio 1:3, 2:3 and 3:4.The ratio of water and milk in the new mixture is
  • a)
    45:76
  • b)
    151:269
  • c)
    123:154
  • d)
    145:245
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Answer – B.151:269 Explanation : Milk = 1/4 : 2/5 :3/7 = 35/140 :56/140 : 60/140
Quantity of milk in new mix = 35+56+60 = 151 Quantity of water in new mix = 140*3 = 420-151 = 269 M:W = 151:269

An employer reduces the number of his employees in the ratio of 7:4 and increases their wages in the ratio 3:5. State whether his bill of total wages increases or decreases and in what ratio.
  • a)
    increases 20:21
  • b)
    decreases 21:20
  • c)
    increases 21:22
  • d)
    decreases 22:21
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Aarav Sharma answered
Given data:
- The number of employees is reduced in the ratio 7:4.
- The wages are increased in the ratio 3:5.

Let's assume that the employer had 7x employees and was paying each employee 5y wages.

After the reduction in the number of employees, the new number of employees will be 4x. But the wages have been increased in the ratio 3:5. Therefore, the new wage will be (5y * 5)/(3) = 25y/3.

So, the total bill of wages before the reduction = 7x * 5y = 35xy
And, the total bill of wages after the reduction = 4x * (25y/3) = (100xy/3)

Now, let's simplify the two bills of wages and see how they compare:

(100/3)xy - 35xy = (65/3)xy

So, the bill of total wages has decreased by (65/3)xy.

We can write this as a ratio of the two bills of wages:

New bill : Old bill = (100/3)xy : 35xy
= 100:105
= 20:21

Therefore, the correct option is (b) decreases 21:20.

An amount of money is to be distributed among P, Q and R in the ratio of 7:4:5 respectively. If the total share of P and R is 4 times the share of Q, what is definitely Q’s share?
  • a)
    2000
  • b)
    4000
  • c)
    6000
  • d)
    Data inadequate
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?


The given ratio is:
A : B : C = 3 : 5 : 7
Let the common factor be x. Thus, the production units will be:
A = 3x
B = 5x
C = 7x
We are also given that the total production is 30,000 units. So:
3x + 5x + 7x = 30,000
15x = 30,000
x = 2,000
Now, substitute x = 2,000 into the expressions for each product:
A's production = 3 × 2,000 = 6,000 units
B's production = 5 × 2,000 = 10,000 units
C's production = 7 × 2,000 = 14,000 units
So, the production for A, B, and C is:
A = 6,000 units
B = 10,000 units
C = 14,000 units
Final Answer:
Initial production:
A = 6,000 units, B = 10,000 units, C = 14,000 units
 

If the ratio of the first to second is 2:3 and that of the second to the third is 5: 8, then which of the following is true,
  • a)
    Sum = 98; A = 48
  • b)
    Sum = 147; B = 30
  • c)
    Sum = 147; C = 45
  • d)
    Sum = 98; B = 30
  • e)
    Sum = 98; C = 72
Correct answer is option 'D'. Can you explain this answer?

Aarav Sharma answered
Given ratios:
- First to second = 2:3
- Second to third = 5:8

Finding the values:
Let the first, second, and third values be 2x, 3x, and 8y respectively.

Using the first ratio:
2x/3x = 2/3
Thus, x = 3/2

Using the second ratio:
3x/8y = 5/8
Thus, y = 9/10

Finding the sum:
2x + 3x + 8y = 5x + 8y

Substituting the values of x and y:
5(3/2) + 8(9/10) = 7.5 + 7.2 = 14.7

Thus, the sum is 14.7.

Checking the options:
a) Sum = 98; A = 48
Does not match the calculated sum.

b) Sum = 147; B = 30
Does not match any of the calculated values.

c) Sum = 147; C = 45
Does not match any of the calculated values.

d) Sum = 98; B = 30
Matches the calculated value of second (3x) which is 30.

e) Sum = 98; C = 72
Does not match any of the calculated values.

Thus, option 'D' is the correct answer.

A company reduces his employee in the ratio 14 : 12 and increases their wages in the ratio 16:18, Determine whether the bill of wages increases or not and in what ratio.
  • a)
    Decreases, 28: 27
  • b)
    Increases, 27:28
  • c)
    Decreases, 29:28
  • d)
    Increases, 28:29
  • e)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Preeti Khanna answered
Answer – a) Decreases, 28: 27 Explanation : Let initial employee be 14a and final employee be 12a similarly initial wage is 16b and final wage be 18b Total initial wage = 14a * 16b = 224ab, total final wage = 12a* 18b = 216ab So clearly wages decreases and ratio = 224ab: 216ab = 28:27

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