All questions of Simple and Compound Interest for Electrical Engineering (EE) Exam
A father left a will of Rs.5 lakhs between his two daughters aged 10 and 15 such that they may get equal amounts when each of them reach the age of 21 years. The original amount of Rs.5 lakhs has been instructed to be invested at 10% p.a. simple interest. How much did the elder daughter get at the time of the will?- a)Rs.2,04,797
- b)Rs.3,05,890
- c)Rs.1,90,00
- d)Rs.4,00,700
- e)Rs.2,46,870
Correct answer is option 'A'. Can you explain this answer?
A father left a will of Rs.5 lakhs between his two daughters aged 10 and 15 such that they may get equal amounts when each of them reach the age of 21 years. The original amount of Rs.5 lakhs has been instructed to be invested at 10% p.a. simple interest. How much did the elder daughter get at the time of the will?
a)
Rs.2,04,797
b)
Rs.3,05,890
c)
Rs.1,90,00
d)
Rs.4,00,700
e)
Rs.2,46,870
|
Akash Pandey answered |
Answer – A.Rs.2,04,797 Explanation : Let Rs.x be the amount that the elder daughter got at the time of the will. Therefore, the younger daughter got (5,00,000 – x).
The elder daughter’s money earns interest for (21 – 15) = 6 years @ 10% p.a simple interest The younger daughter’s money earns interest for (21 – 10) = 11 years @ 10% p.a simple interest.
As the sum of money that each of the daughters get when they are 21 is the same, x + (6*10*x/100)= (5,00,000 – x) +(11*10*[5,00,000-x]/100) 100x+60x = (5,00,000-x)+(55,000,000-110x) 160x =55,500,000-111x 271x = 55,500,000 X = 2,04,797
The elder daughter’s money earns interest for (21 – 15) = 6 years @ 10% p.a simple interest The younger daughter’s money earns interest for (21 – 10) = 11 years @ 10% p.a simple interest.
As the sum of money that each of the daughters get when they are 21 is the same, x + (6*10*x/100)= (5,00,000 – x) +(11*10*[5,00,000-x]/100) 100x+60x = (5,00,000-x)+(55,000,000-110x) 160x =55,500,000-111x 271x = 55,500,000 X = 2,04,797
Raghu lends Rs 50,000 of two of his friends. He gives Rs 30,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is- a)8%
- b)16%
- c)11%
- d)17%
- e)19%
Correct answer is option 'B'. Can you explain this answer?
Raghu lends Rs 50,000 of two of his friends. He gives Rs 30,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is
a)
8%
b)
16%
c)
11%
d)
17%
e)
19%
|
Target Study Academy answered |
Answer –B.16% Explanation : S.I. on Rs 30000 =(30000×6×1)/100 = Rs. 1800 Profit to made on Rs 50000 = 50000×10/100=Rs 5000 S.I.on Rs.20000 = 5000-1800 = Rs.3200 Rate=(S.I.* 100)/(P * T)=(3200×100)/20000 =16% per annum
Shortcut: 6……………………x ………..10…………….
3………………………2
4/(x-10)=2/3 x=16
Shortcut: 6……………………x ………..10…………….
3………………………2
4/(x-10)=2/3 x=16
In how many years will a sum of Rs.15625 at 8% pa compounded semi annually become Rs.17,576?- a)2(1/3)yrs
- b)2yrs
- c)1(1/2)yrs
- d)1yr
Correct answer is option 'C'. Can you explain this answer?
In how many years will a sum of Rs.15625 at 8% pa compounded semi annually become Rs.17,576?
a)
2(1/3)yrs
b)
2yrs
c)
1(1/2)yrs
d)
1yr
|
Cstoppers Instructors answered |
15625*(1+(4/100))2n = 17576
15625*(104/100)2n = 17576
(26/25)2n = 17576/15625 = (26/27)3
2n = 3 N =3/2 = 1(1/2) yrs
15625*(104/100)2n = 17576
(26/25)2n = 17576/15625 = (26/27)3
2n = 3 N =3/2 = 1(1/2) yrs
A person earns an interest of 240 on investing certain amount at Simple interest for 2 years at 5 percent amount. If the rate of interest is compounded annually then how much more interest will be gain by the person at same rate of interest and on the same sum.- a)6
- b)8
- c)12
- d)10
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
A person earns an interest of 240 on investing certain amount at Simple interest for 2 years at 5 percent amount. If the rate of interest is compounded annually then how much more interest will be gain by the person at same rate of interest and on the same sum.
a)
6
b)
8
c)
12
d)
10
e)
None of these
|
Preeti Khanna answered |
240 = P*(5/100)*2, P = 2400
CI = 2400(1+5/100)2 – 2400 = 246
So, 246 – 240 = 6
CI = 2400(1+5/100)2 – 2400 = 246
So, 246 – 240 = 6
A sum of rupees 3200 is compounded annually at the rate of 25 paise per rupee per annum. Find the compound interest payable after 2 years.- a)1200
- b)1600
- c)1800
- d)2000
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A sum of rupees 3200 is compounded annually at the rate of 25 paise per rupee per annum. Find the compound interest payable after 2 years.
a)
1200
b)
1600
c)
1800
d)
2000
e)
None of these
|
Anaya Patel answered |
Rate of interest is 25 paise per rupee per annum.
So for 100 rupees it is 2500 paise i.e. 25 percent
Now, CI = 3200(1+25/100)2 – 3200 = 1800
So for 100 rupees it is 2500 paise i.e. 25 percent
Now, CI = 3200(1+25/100)2 – 3200 = 1800
Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?- a)5%
- b)7%
- c)10%
- d)12%
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Out of Rs. 50,000 that a man has, he lends Rs. 8,000 at 11/2 % per annum simple interest and Rs. 24,000 at 6% per annum simple interest. He lends the remaining money at a certain rate of interest so that he gets total annual interest of Rs. 3,680. The rate of interest per annum, at which the remaining money is lent, is ?
a)
5%
b)
7%
c)
10%
d)
12%
e)
None of the Above
|
Waqil Ali answered |
H
Arun divides Rs 4702 among A, B, and C, so that if the amounts being invested at 4% simple interest, the amounts received after 2, 3 and 4 yrs by A, B, and C respectively is equal. Find the share of B?- a)Rs 1,458
- b)Rs 1,556
- c)Rs 2,358
- d)Rs 1,237
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Arun divides Rs 4702 among A, B, and C, so that if the amounts being invested at 4% simple interest, the amounts received after 2, 3 and 4 yrs by A, B, and C respectively is equal. Find the share of B?
a)
Rs 1,458
b)
Rs 1,556
c)
Rs 2,358
d)
Rs 1,237
e)
None of these
|
|
Anaya Patel answered |
B) Rs 1,556 Explanation: 4702 will be divided in ratio – 1/[100+rt1] : 1/[100+rt2] : 1/[100+rt3] 1/[100+4*2] : 1/[100+4*3] : 1/[100+4*4] 1/108 : 1/112 : 1/116
= 812 : 783 : 756
So B gets 783/(812+783+756) * 4702 = 1566
= 812 : 783 : 756
So B gets 783/(812+783+756) * 4702 = 1566
The compound interest on a certain sum for 2 years is Rs. 786 and S.I. is Rs. 750. If the sum is invested such that the S.I. is Rs. 1296 and the number of years is equal to the rate per cent per annum, Find the rate of interest?- a)4%
- b)5%
- c)6%
- d)8%
- e)2%
Correct answer is option 'C'. Can you explain this answer?
The compound interest on a certain sum for 2 years is Rs. 786 and S.I. is Rs. 750. If the sum is invested such that the S.I. is Rs. 1296 and the number of years is equal to the rate per cent per annum, Find the rate of interest?
a)
4%
b)
5%
c)
6%
d)
8%
e)
2%
|
Vikas Kumar answered |
CI for 2 years = Rs. 786
SI for 2 years = Rs. 750
36/360 * 100 = 10%
P for first year = 3600
P*x*x/100 = 1296
x = 6%
Two equal some of money were invested at an annual rate of 10%, One sum at simple interest and other at compound interest, If the difference between the interest after 2 years was Rs.100, What were the sum invested ?- a)25,000
- b)100000
- c)20,000
- d)10,000
- e)50,000
Correct answer is option 'D'. Can you explain this answer?
Two equal some of money were invested at an annual rate of 10%, One sum at simple interest and other at compound interest, If the difference between the interest after 2 years was Rs.100, What were the sum invested ?
a)
25,000
b)
100000
c)
20,000
d)
10,000
e)
50,000
|
|
Target Study Academy answered |
Correct Answer :- d
Explanation : Assume X = 100
SI = 120
CI = 121
100 mean difference is 1
200 mean difference is 2
Therefore, 10000 mean difference is 100.
Suresh lends 40% of his money at 15% per annum, 50% of the rest at 10% per annum and the rest at 18% per annum rate of interest. What would be the annual rate of interest, if the interest is calculated on the whole sum?- a)18.5%
- b)14.4%
- c)16.5%
- d)19.5%
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Suresh lends 40% of his money at 15% per annum, 50% of the rest at 10% per annum and the rest at 18% per annum rate of interest. What would be the annual rate of interest, if the interest is calculated on the whole sum?
a)
18.5%
b)
14.4%
c)
16.5%
d)
19.5%
e)
None of the Above
|
|
Preeti Khanna answered |
B. 14.4%
Explanation: x – (40/100)*x = 60x/100 40/100 at 15% p.a = 40/100 * 15/100 = 60x/1000 50/100*60x/100 = 30x/100 at 10% p.a = 30x/100 * 10/100 = 30x/1000 Balance amount = x – 40x/100 – 30x/100 = 30x/100 at 18% p.a = 18/100 * 30x/100 = 54x/1000 R = [(144x/1000)/x] * 100 = 14.4%
Explanation: x – (40/100)*x = 60x/100 40/100 at 15% p.a = 40/100 * 15/100 = 60x/1000 50/100*60x/100 = 30x/100 at 10% p.a = 30x/100 * 10/100 = 30x/1000 Balance amount = x – 40x/100 – 30x/100 = 30x/100 at 18% p.a = 18/100 * 30x/100 = 54x/1000 R = [(144x/1000)/x] * 100 = 14.4%
Ravi lent out a part of Rs. 38800 is lent out at 6% per six months. The rest of the amount is lent out at 5% per annum after one year. The ratio of interest after 3 years from the time when first amount was lent is 5:4. Find the second part that was lent out at 5%.- a)28500
- b)30080
- c)20500
- d)28800
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
Ravi lent out a part of Rs. 38800 is lent out at 6% per six months. The rest of the amount is lent out at 5% per annum after one year. The ratio of interest after 3 years from the time when first amount was lent is 5:4. Find the second part that was lent out at 5%.
a)
28500
b)
30080
c)
20500
d)
28800
e)
None of the Above
|
KS Coaching Center answered |
D. 28800
Explanation: First Part = x [x * (0.06)*6] / (388800 – x)*0.05*2 = 5/4 1.44x = 19400 – 0.5x x = 10000 Second Part = 38800 – 10000 = 28800
Explanation: First Part = x [x * (0.06)*6] / (388800 – x)*0.05*2 = 5/4 1.44x = 19400 – 0.5x x = 10000 Second Part = 38800 – 10000 = 28800
A man borrows 10000 rupees at 20 % compound interest for 3 years. If every year he pays 2000 rupees as repayment. How much amount is still left to be paid by the man?- a)5000
- b)7000
- c)9000
- d)10000
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A man borrows 10000 rupees at 20 % compound interest for 3 years. If every year he pays 2000 rupees as repayment. How much amount is still left to be paid by the man?
a)
5000
b)
7000
c)
9000
d)
10000
e)
None of these
|
|
Aisha Gupta answered |
Amount to be paid at the end of three years = 10000*(1+20/100)3 = 17280
Amount paid as instalment by the man = 2000*(1+20/100)2 + 2000*(1+20/100) + 2000 = 7280
So remaining amount = 10000
Amount paid as instalment by the man = 2000*(1+20/100)2 + 2000*(1+20/100) + 2000 = 7280
So remaining amount = 10000
A sum of 3000 becomes 3600 in 3 years at 15 percent per annum. What will be the sum at the same rate after 9 years?- a)5124
- b)5184
- c)5186
- d)5192
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A sum of 3000 becomes 3600 in 3 years at 15 percent per annum. What will be the sum at the same rate after 9 years?
a)
5124
b)
5184
c)
5186
d)
5192
e)
None of these
|
Kavya Saxena answered |
3600 = 3000*(1+15/100)3 (1+15/100)3 = 6/5
Amount = 3000*[(1+15/100)3]3 Amount = 3000*(6/5)3 = 5184
Amount = 3000*[(1+15/100)3]3 Amount = 3000*(6/5)3 = 5184
A certain sum of money at certain rate of interest becomes Rs 3420 after 2 years and at same rate after two and a half years becomes Rs 3525. Find the rate percent per annum.- a)8.5%
- b)8%
- c)7%
- d)10%
- e)11%
Correct answer is option 'C'. Can you explain this answer?
A certain sum of money at certain rate of interest becomes Rs 3420 after 2 years and at same rate after two and a half years becomes Rs 3525. Find the rate percent per annum.
a)
8.5%
b)
8%
c)
7%
d)
10%
e)
11%
|
|
Aarav Sharma answered |
C) 7%
Explanation: Amount after 2.5 yrs = 3525, after 2 yrs = 3420 So SI for half yr = 3525-3420 = 105, so for 1 yr SI = 105*2 = 210 P + 2*SI = 3420
So P = 3420 – 2*210 = 3000 So 3000*r*2/100 = 420
Explanation: Amount after 2.5 yrs = 3525, after 2 yrs = 3420 So SI for half yr = 3525-3420 = 105, so for 1 yr SI = 105*2 = 210 P + 2*SI = 3420
So P = 3420 – 2*210 = 3000 So 3000*r*2/100 = 420
A sum of money becomes Rs 35,280 after 2 years and Rs 37,044 after 3 years when lent on compound interest. Find the principal amount.- a)2800
- b)3000
- c)3200
- d)4000
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A sum of money becomes Rs 35,280 after 2 years and Rs 37,044 after 3 years when lent on compound interest. Find the principal amount.
a)
2800
b)
3000
c)
3200
d)
4000
e)
None of these
|
Faizan Khan answered |
37044 = p*(1 +r/100)3
35280 = p*(1 + r/100)2
Divide both equations to get the value of r and then substitute in any equation to get P
35280 = p*(1 + r/100)2
Divide both equations to get the value of r and then substitute in any equation to get P
The difference between interest received by Vivek and Vimal is Rs.405 on Rs.4500 for 3 years. What is the difference in rate of interest ?- a)1.5%
- b)2%
- c)3%
- d)2.7%
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
The difference between interest received by Vivek and Vimal is Rs.405 on Rs.4500 for 3 years. What is the difference in rate of interest ?
a)
1.5%
b)
2%
c)
3%
d)
2.7%
e)
None of these
|
|
Faizan Khan answered |
4500*3/100(R1-R2) = 405
R1-R2 = 405*100/13500 = 3%
R1-R2 = 405*100/13500 = 3%
A sum of 3000 becomes 3600 in 3 years at 15 percent per annum. What will be the sum at the same rate after 9 years.- a)5124
- b)5184
- c)5186
- d)5192
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A sum of 3000 becomes 3600 in 3 years at 15 percent per annum. What will be the sum at the same rate after 9 years.
a)
5124
b)
5184
c)
5186
d)
5192
e)
None of these
|
|
Aarav Sharma answered |
3600 = 3000*(1+15/100)^ 3
(1+15/100)^ 3 = 6/5
Amount = 3000*[(1+15/100)^ 3]^ 3
Amount = 3000*(6/5)^ 3 = 5184
Hari borrowed some money for one year at 6% per annum simple interest and after 18 months , he again borrowed the same money at a Simple Interest of 24% per annum. In both the cases, he paid Rs.4704. Which of the following could be the amount that was borrowed by Hari in each case if interest is paid half yearly?- a)4000
- b)3000
- c)4400
- d)4200
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
Hari borrowed some money for one year at 6% per annum simple interest and after 18 months , he again borrowed the same money at a Simple Interest of 24% per annum. In both the cases, he paid Rs.4704. Which of the following could be the amount that was borrowed by Hari in each case if interest is paid half yearly?
a)
4000
b)
3000
c)
4400
d)
4200
e)
None of the Above
|
Ravi Singh answered |
D. 4200
Explanation: 12% for 6 months x = Borrowed money Take x =100% 112% of x = 4704 x = 4200
Explanation: 12% for 6 months x = Borrowed money Take x =100% 112% of x = 4704 x = 4200
A man borrows Rs 4000 at 8% compound interest for 3 years. At the end of each year he paid Rs 500. How much amount should he pay at the end of 3rd year to clear the debt?- a)Rs 4254.5
- b)Rs 3465.2
- c)Rs 3485.2
- d)Rs 4345.4
- e)Rs 3915.6
Correct answer is option 'E'. Can you explain this answer?
A man borrows Rs 4000 at 8% compound interest for 3 years. At the end of each year he paid Rs 500. How much amount should he pay at the end of 3rd year to clear the debt?
a)
Rs 4254.5
b)
Rs 3465.2
c)
Rs 3485.2
d)
Rs 4345.4
e)
Rs 3915.6
|
|
Anaya Patel answered |
Amount after 1 yr = 4000[1 + 8/100] = 4320
Paid 500, so P = 4320 – 500 = 3820
Amount after 2nd yr = 3820[1 + 8/100] = 4125.6
So P= 4125.6-500 = 3625.6
Amount after 3rd yr = 3625.6[1 + 8/100] = 3915.6
Paid 500, so P = 4320 – 500 = 3820
Amount after 2nd yr = 3820[1 + 8/100] = 4125.6
So P= 4125.6-500 = 3625.6
Amount after 3rd yr = 3625.6[1 + 8/100] = 3915.6
The CI on a certain sum at 10% pa for 2yrs is Rs.6548. What is SI on the sum of money at 7%pa for 4 yrs(approx) ?- a)8700
- b)8731
- c)8370
- d)8470
Correct answer is option 'B'. Can you explain this answer?
The CI on a certain sum at 10% pa for 2yrs is Rs.6548. What is SI on the sum of money at 7%pa for 4 yrs(approx) ?
a)
8700
b)
8731
c)
8370
d)
8470
|
Bank Exams India answered |
CI = p [{1 + (10/100)}2 – 1] 6548 = p [(110/100)2 – 1] 6548 =p (121 – 100)/100
P = 654800/21 =31,181
SI = 31181*7*4/100 = 8731
P = 654800/21 =31,181
SI = 31181*7*4/100 = 8731
Ajay borrows Rs 1000 at the rate of 12% per annum simple interest and Babu borrows Rs 1050 at the rate of 10% per annum simple interest. In how many years will their amounts of debts be equal?- a)18/5
- b)10/3
- c)22/3
- d)10/5
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Ajay borrows Rs 1000 at the rate of 12% per annum simple interest and Babu borrows Rs 1050 at the rate of 10% per annum simple interest. In how many years will their amounts of debts be equal?
a)
18/5
b)
10/3
c)
22/3
d)
10/5
e)
None of the Above
|
|
Anaya Patel answered |
B. 10/3
Explanation: Let Time = x years Then, [1000+(1000*12*x)/100] = [1050+(1050*10*x)/100] => 1000 + 120x = 1050 + 105x => 15x = 50 ⇒ x = 10/3 years
Explanation: Let Time = x years Then, [1000+(1000*12*x)/100] = [1050+(1050*10*x)/100] => 1000 + 120x = 1050 + 105x => 15x = 50 ⇒ x = 10/3 years
A sum of money is lent at simple interest and compound interest. The ratio between the difference of compound interest and simple interest of 3 years and 2 years is 35 : 11. What is the rate of interest per annum?- a)20 3/4%
- b)17 2/5%
- c)18 2/11%
- d)22 1/5%
- e)24 5/6%
Correct answer is option 'C'. Can you explain this answer?
A sum of money is lent at simple interest and compound interest. The ratio between the difference of compound interest and simple interest of 3 years and 2 years is 35 : 11. What is the rate of interest per annum?
a)
20 3/4%
b)
17 2/5%
c)
18 2/11%
d)
22 1/5%
e)
24 5/6%
|
|
Preeti Khanna answered |
Difference in 3 yrs = Pr2 (300+r)/1003
Difference in 2 yrs = Pr2 /1002
So Pr2 (300+r)/1003 / Pr2 /1002 = 35/11 (300+r)/100 = 35/11
Difference in 2 yrs = Pr2 /1002
So Pr2 (300+r)/1003 / Pr2 /1002 = 35/11 (300+r)/100 = 35/11
At what rate of CI pa will a sum of Rs.1000 becomes Rs.1040.4 in 2yrs ?- a)2%
- b)1%
- c)1.5%
- d)3%
Correct answer is option 'A'. Can you explain this answer?
At what rate of CI pa will a sum of Rs.1000 becomes Rs.1040.4 in 2yrs ?
a)
2%
b)
1%
c)
1.5%
d)
3%
|
|
Preeti Khanna answered |
1000*(1+(R/100))2 = 1040.4
(1+(R/100))2 = 1040.4/1000
(1+(R/100))2 = 10404/10000 = (102/100)2
R = 2%
(1+(R/100))2 = 1040.4/1000
(1+(R/100))2 = 10404/10000 = (102/100)2
R = 2%
P is going to pay Rs.700 to Q, 7 months later at 6% annual simple interest, Q isgoing to pay Rs.550 to P, 12 months later at 8% annual simple interest, if theydecide to settle the debts, who will pay what amount to whom ?- a)A, Rs.149
- b)B,Rs.167
- c)A, Rs.155
- d)B, Rs.197
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
P is going to pay Rs.700 to Q, 7 months later at 6% annual simple interest, Q isgoing to pay Rs.550 to P, 12 months later at 8% annual simple interest, if theydecide to settle the debts, who will pay what amount to whom ?
a)
A, Rs.149
b)
B,Rs.167
c)
A, Rs.155
d)
B, Rs.197
e)
None of these
|
|
Aisha Gupta answered |
Answer – B.B,Rs.167
Explanation :
For P:
P+ (p*6*7/12*100) = 700
1200p+42P = 700*1200
P = 676.33
For Q:
P+ (p*8*12/12*100) = 550
1200P+96P = 550*1200
P =509.26
Q =676-509 = 167
Explanation :
For P:
P+ (p*6*7/12*100) = 700
1200p+42P = 700*1200
P = 676.33
For Q:
P+ (p*8*12/12*100) = 550
1200P+96P = 550*1200
P =509.26
Q =676-509 = 167
The simple interest on a certain sum of money for 4 years at 15 percent per annum is 600. Find the compound interest in the same sum at 10 percent interest for 2 years- a)220
- b)200
- c)210
- d)120
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
The simple interest on a certain sum of money for 4 years at 15 percent per annum is 600. Find the compound interest in the same sum at 10 percent interest for 2 years
a)
220
b)
200
c)
210
d)
120
e)
None of these
|
|
Ravi Singh answered |
600 = p*4*(15/100), P = 1000
CI = 1000(1+10/100)2 – 1000 = 210
CI = 1000(1+10/100)2 – 1000 = 210
Hari took an educational loan from a nationalized bank for his 2 years course of MBA. He took the loan of Rs.5 lakh such that he would be charged at 7% p.a. at CI during his course and at 9% CI after the completion of the course. He returned half of the amount which he had to be paid on the completion of his studies and remaining after 2 years. What is the total amount returned by Hari?- a)Rs. 626255
- b)Rs. 626277
- c)Rs. 616266
- d)Rs. 626288
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
Hari took an educational loan from a nationalized bank for his 2 years course of MBA. He took the loan of Rs.5 lakh such that he would be charged at 7% p.a. at CI during his course and at 9% CI after the completion of the course. He returned half of the amount which he had to be paid on the completion of his studies and remaining after 2 years. What is the total amount returned by Hari?
a)
Rs. 626255
b)
Rs. 626277
c)
Rs. 616266
d)
Rs. 626288
e)
None of these
|
Naroj Boda answered |
5,00,000 * (1.07)² = 572450
Returned amount = 286225
After two years = 286225 * (1.09)² = 340063
Total amount = 286225 + 340063 = 626288
Returned amount = 286225
After two years = 286225 * (1.09)² = 340063
Total amount = 286225 + 340063 = 626288
Tarun invested an amount of Rs. 10000 at the simple interest rate of 8% per annum and another amount at the simple interest rate of 20% per annum. The total interest earned at the end of one year on the total amount invested became 12% per annum. Find the total amount invested.- a)Rs.12,000
- b)Rs.15000
- c)Rs.5,000
- d)Rs.10,000
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Tarun invested an amount of Rs. 10000 at the simple interest rate of 8% per annum and another amount at the simple interest rate of 20% per annum. The total interest earned at the end of one year on the total amount invested became 12% per annum. Find the total amount invested.
a)
Rs.12,000
b)
Rs.15000
c)
Rs.5,000
d)
Rs.10,000
e)
None of these
|
Future Foundation Institute answered |
Answer – B.Rs.15000 Explanation : SI1= 10000*8*1/100 = 800
SI2 = x*20*1/100 = x/5 800+(x/5) = (10000+x)*12*1/100 80000+20x = 1,20,000+12x 8x = 40,000 X = 5000
Total= 10000+5000 = 15000
SI2 = x*20*1/100 = x/5 800+(x/5) = (10000+x)*12*1/100 80000+20x = 1,20,000+12x 8x = 40,000 X = 5000
Total= 10000+5000 = 15000
Vikram lends Rs 30,000 of two of his friends. He gives Rs 15,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is- a)8%
- b)16%
- c)12%
- d)14%
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
Vikram lends Rs 30,000 of two of his friends. He gives Rs 15,000 to the first at 6% p.a. simple interest. He wants to make a profit of 10% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend is
a)
8%
b)
16%
c)
12%
d)
14%
e)
None of the Above
|
|
Alok Verma answered |
D. 14%
Explanation: S.I. on Rs 15000 =(15000×6×1)/100 = Rs. 900 Profit to made on Rs 30000 = 30000×10/100=Rs 3000 S.I.on Rs.15000 = 3000-900 = Rs.2100 Rate=(S.I.* 100)/(P * T)=(2100×100)/15000 =14% per annum
Explanation: S.I. on Rs 15000 =(15000×6×1)/100 = Rs. 900 Profit to made on Rs 30000 = 30000×10/100=Rs 3000 S.I.on Rs.15000 = 3000-900 = Rs.2100 Rate=(S.I.* 100)/(P * T)=(2100×100)/15000 =14% per annum
Priya saves an amount of 500 every year and then lent that amount at an interest of 10 percent compounded annually. Find the amount after 3 years.- a)1820.5
- b)1840.5
- c)1920.5
- d)1940.5
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Priya saves an amount of 500 every year and then lent that amount at an interest of 10 percent compounded annually. Find the amount after 3 years.
a)
1820.5
b)
1840.5
c)
1920.5
d)
1940.5
e)
None of these
|
|
Bank Exams India answered |
Total amount = 500*(1+10/100)3 + 500*(1+10/100)2 + 500*(1+10/100)
= 1820.5
= 1820.5
A sum of Rs. 8400 was taken as loan. This is to be paid in two equal annual installments. If the rate of interest be 20% compounded annually, then the value of each installment is- a)5400
- b)5700
- c)5100
- d)5200
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
A sum of Rs. 8400 was taken as loan. This is to be paid in two equal annual installments. If the rate of interest be 20% compounded annually, then the value of each installment is
a)
5400
b)
5700
c)
5100
d)
5200
e)
None of these
|
Yash Patel answered |
Let value of each installment be X.
X/(1 + 20/100) + X/(1 + 20/100)² = 8400
⇒ X(5/6 + 25/36) = 8400
⇒ X(56/36) = 8400
X = 5400
X/(1 + 20/100) + X/(1 + 20/100)² = 8400
⇒ X(5/6 + 25/36) = 8400
⇒ X(56/36) = 8400
X = 5400
During the first year the population of a village is increased by 5% and the second year it is diminished by 5%. At the end of the second year its population was 31500. What was the population at the beginning of the first year?- a)35500
- b)31578
- c)33500
- d)33000
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
During the first year the population of a village is increased by 5% and the second year it is diminished by 5%. At the end of the second year its population was 31500. What was the population at the beginning of the first year?
a)
35500
b)
31578
c)
33500
d)
33000
e)
None of these
|
|
Preeti Khanna answered |
x * 105/100 * 95/100 = 31500
x = 31500 * 100/105 * 100/95
D = 31578
x = 31500 * 100/105 * 100/95
D = 31578
If 40% increase in an amount in 4 years at SI. What will be the CI of Rs.10,000 after 2 yrs at the same rate ?- a)1000
- b)1100
- c)2000
- d)2100
Correct answer is option 'D'. Can you explain this answer?
If 40% increase in an amount in 4 years at SI. What will be the CI of Rs.10,000 after 2 yrs at the same rate ?
a)
1000
b)
1100
c)
2000
d)
2100
|
|
Bank Exams India answered |
P = 100, SI = 40, T = 4
R = 100*40 / 100*4 = 10%pa
CI = 10,000(110/100)2 = 10000*11*11/100 = 12100
12100 – 10000 = 2100
R = 100*40 / 100*4 = 10%pa
CI = 10,000(110/100)2 = 10000*11*11/100 = 12100
12100 – 10000 = 2100
Venkat and Vidhya have to clear their respective loans by paying 2 equal annual instalments of Rs.30000 each. Venkat pays at 10% pa of SI and Vidhyapays at 10% CI pa. What is the difference in their payments ?- a)200
- b)300
- c)400
- d)500
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
Venkat and Vidhya have to clear their respective loans by paying 2 equal annual instalments of Rs.30000 each. Venkat pays at 10% pa of SI and Vidhyapays at 10% CI pa. What is the difference in their payments ?
a)
200
b)
300
c)
400
d)
500
e)
None of these
|
|
Bank Exams India answered |
D =[(30,000 *110/100*110/100) – 30,000] – 30,000 *10*2/100
=[36300-30000]- 6000
=6300 – 6000
D = 300
=[36300-30000]- 6000
=6300 – 6000
D = 300
A part of 2000 is lent at 6% per annum and rest sum is lent at 8% per annum.If total interest earned after 4 years is 500. Then the sum lent at 8%.- a)250
- b)350
- c)450
- d)550
Correct answer is option 'A'. Can you explain this answer?
A part of 2000 is lent at 6% per annum and rest sum is lent at 8% per annum.If total interest earned after 4 years is 500. Then the sum lent at 8%.
a)
250
b)
350
c)
450
d)
550
|
|
Preeti Khanna answered |
Answer –a) 250 Solution: Let sum lent at 8% is X 500 = X*(8/100)*4 + (2000-X)*(6/100)*4
Mohan invested 20000 rupee in fixed deposit at the rate of 10% simple interest.After every 3 rd year he added interest to principal. Find the interest earned at the end of 6 year.- a)7800
- b)8000
- c)7600
- d)8200.
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Mohan invested 20000 rupee in fixed deposit at the rate of 10% simple interest.After every 3 rd year he added interest to principal. Find the interest earned at the end of 6 year.
a)
7800
b)
8000
c)
7600
d)
8200.
e)
None of these
|
|
Ravi Singh answered |
Answer – a) 7800 Explanation : For the first 3 years SI will be = 20000*10/100*3 = 6000 Now he add 3000 to the principal i.e = 20000+6000 = 26000 Now interest earned at end of 6 year = 26000*10/100*3 = 7800
Poorni and Priyanka have to clear their respective loans by paying 2 equal annual instalments of Rs.20000 each. Poorni pays at 10% pa of SI and Priyanka pays at 10% CI pa. What is the difference in their payments ?- a)200
- b)300
- c)400
- d)500
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Poorni and Priyanka have to clear their respective loans by paying 2 equal annual instalments of Rs.20000 each. Poorni pays at 10% pa of SI and Priyanka pays at 10% CI pa. What is the difference in their payments ?
a)
200
b)
300
c)
400
d)
500
e)
None of these
|
|
Anaya Patel answered |
D =[(20,000 *110/100*110/100) – 20,000] – 20,000 *10*2/100
=[ 24200-20000]-4000
=4200 – 4000
D = 200
=[ 24200-20000]-4000
=4200 – 4000
D = 200
Riya saves an amount of 500 every year and then lent that amount at an interest of 10 percent compounded annually. Find the amount after 3 years.- a)1820.5
- b)1840.5
- c)1920.5
- d)1940.5
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
Riya saves an amount of 500 every year and then lent that amount at an interest of 10 percent compounded annually. Find the amount after 3 years.
a)
1820.5
b)
1840.5
c)
1920.5
d)
1940.5
e)
None of these
|
|
Aarav Sharma answered |
Given:
Riya saves an amount of $500 every year.
Interest rate = 10% compounded annually.
To find:
The amount after 3 years.
Solution:
We can solve this problem using the compound interest formula:
A = P(1 + r/n)^(nt)
Where:
A = Final amount
P = Principal amount (initial savings)
r = Annual interest rate (as a decimal)
n = Number of times interest is compounded per year
t = Number of years
Step 1: Calculate the final amount after 1 year.
P = $500
r = 10% = 0.10
n = 1 (compounded annually)
t = 1 year
A = 500(1 + 0.10/1)^(1*1)
A = 500(1 + 0.10)^1
A = 500(1.10)
A = $550
Step 2: Calculate the final amount after 2 years.
P = $550 (the amount after 1 year)
r = 10% = 0.10
n = 1 (compounded annually)
t = 2 years
A = 550(1 + 0.10/1)^(1*2)
A = 550(1 + 0.10)^2
A = 550(1.10)^2
A = 550(1.21)
A = $665.50
Step 3: Calculate the final amount after 3 years.
P = $665.50 (the amount after 2 years)
r = 10% = 0.10
n = 1 (compounded annually)
t = 3 years
A = 665.50(1 + 0.10/1)^(1*3)
A = 665.50(1 + 0.10)^3
A = 665.50(1.10)^3
A ≈ 665.50(1.331)
A ≈ $885.71
Therefore, the amount after 3 years is approximately $885.71.
Answer:
The correct answer is option A, 1820.5 (as given in the question). However, this answer is incorrect based on the calculations provided above.
Riya saves an amount of $500 every year.
Interest rate = 10% compounded annually.
To find:
The amount after 3 years.
Solution:
We can solve this problem using the compound interest formula:
A = P(1 + r/n)^(nt)
Where:
A = Final amount
P = Principal amount (initial savings)
r = Annual interest rate (as a decimal)
n = Number of times interest is compounded per year
t = Number of years
Step 1: Calculate the final amount after 1 year.
P = $500
r = 10% = 0.10
n = 1 (compounded annually)
t = 1 year
A = 500(1 + 0.10/1)^(1*1)
A = 500(1 + 0.10)^1
A = 500(1.10)
A = $550
Step 2: Calculate the final amount after 2 years.
P = $550 (the amount after 1 year)
r = 10% = 0.10
n = 1 (compounded annually)
t = 2 years
A = 550(1 + 0.10/1)^(1*2)
A = 550(1 + 0.10)^2
A = 550(1.10)^2
A = 550(1.21)
A = $665.50
Step 3: Calculate the final amount after 3 years.
P = $665.50 (the amount after 2 years)
r = 10% = 0.10
n = 1 (compounded annually)
t = 3 years
A = 665.50(1 + 0.10/1)^(1*3)
A = 665.50(1 + 0.10)^3
A = 665.50(1.10)^3
A ≈ 665.50(1.331)
A ≈ $885.71
Therefore, the amount after 3 years is approximately $885.71.
Answer:
The correct answer is option A, 1820.5 (as given in the question). However, this answer is incorrect based on the calculations provided above.
SBI lent Rs. 10,000 to Deepak @7% SI for 10 years. Mean while, the government implemented a scheme due to which interest rate reduced by 2%.By this Deepak paid Rs.16,000 in total. Then after how many years after Deepak took the loan, the government introduced the scheme?- a)3 Years
- b)4 Years
- c)5 years
- d)6 years
- e)Cannot be determined
Correct answer is option 'C'. Can you explain this answer?
SBI lent Rs. 10,000 to Deepak @7% SI for 10 years. Mean while, the government implemented a scheme due to which interest rate reduced by 2%.By this Deepak paid Rs.16,000 in total. Then after how many years after Deepak took the loan, the government introduced the scheme?
a)
3 Years
b)
4 Years
c)
5 years
d)
6 years
e)
Cannot be determined
|
|
Kavya Saxena answered |
Answer – 3. 5 years Explanation : 6000 = 10000(7*x+5*(10-x))/100 x = 5
A sum of money invested for 13 years yields Rs 2500 as simple interest. The interest rate being charged at 4% for first 3 years, 5% for next 4 years and 8% beyond 7 years. What is the principal invested?- a)Rs 3,525
- b)Rs 3,475
- c)Rs 3,125
- d)Rs 2,125
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A sum of money invested for 13 years yields Rs 2500 as simple interest. The interest rate being charged at 4% for first 3 years, 5% for next 4 years and 8% beyond 7 years. What is the principal invested?
a)
Rs 3,525
b)
Rs 3,475
c)
Rs 3,125
d)
Rs 2,125
e)
None of these
|
Nikita Singh answered |
C) Rs 3,125 Explanation: Beyond 7 years is after 7 years for remaining (13-7) = 6 years P = 2500*100/[r1t1+r2t2+r3t3] P = 2500*100/[4*3 + 5*4 + 8*6]
A sum of Rs.7140 is to be divided between Anita and Bala who are respectively 18 and 19 yr old, in such a way that if their shares will be invested at 4% per annum at compound interest, they will receive equal amounts on attaining the age of 21 year. The present share of Anita is- a)4225
- b)4352
- c)3500
- d)4000
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A sum of Rs.7140 is to be divided between Anita and Bala who are respectively 18 and 19 yr old, in such a way that if their shares will be invested at 4% per annum at compound interest, they will receive equal amounts on attaining the age of 21 year. The present share of Anita is
a)
4225
b)
4352
c)
3500
d)
4000
e)
None of these
|
|
Nikita Singh answered |
Amount got by Anita after 3 yr = Amount got by Bala after 2 yr
x*(26/25)³ = (7140 – x)*(26/25)
26/25 = 7140 – x / x
x = 3500
x*(26/25)³ = (7140 – x)*(26/25)
26/25 = 7140 – x / x
x = 3500
Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and another amount at 10% SI per annum. The total interest earned at the end of one year will be same as interest earned when the total amount invested at 6% SI per annum. Find the total amount invested?- a)Rs.12000
- b)Rs.24000
- c)Rs.30000
- d)Rs.36000
- e)None
Correct answer is option 'D'. Can you explain this answer?
Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and another amount at 10% SI per annum. The total interest earned at the end of one year will be same as interest earned when the total amount invested at 6% SI per annum. Find the total amount invested?
a)
Rs.12000
b)
Rs.24000
c)
Rs.30000
d)
Rs.36000
e)
None
|
|
Rhea Reddy answered |
Answer – 4.Rs.36000 Explanation : 24000*4/100 = 960
x*10/100 = 0.1x 960+0.1x = (24000+x)*6/100 x =12000 Total = 24,000+12,000 = 36,000
x*10/100 = 0.1x 960+0.1x = (24000+x)*6/100 x =12000 Total = 24,000+12,000 = 36,000
Amit lent a part of Rs. 15900 to Raju at 6% SI. Rest to Anil at 5% SI. After 4 years he got an amount of Rs 19376 in total. Then what is the amount paid by Anil in total?- a)Rs. 9176
- b)Rs. 9847
- c)Rs. 10200
- d)Rs. 11200
- e)None
Correct answer is option 'C'. Can you explain this answer?
Amit lent a part of Rs. 15900 to Raju at 6% SI. Rest to Anil at 5% SI. After 4 years he got an amount of Rs 19376 in total. Then what is the amount paid by Anil in total?
a)
Rs. 9176
b)
Rs. 9847
c)
Rs. 10200
d)
Rs. 11200
e)
None
|
|
Anjana Sharma answered |
3476 = x*6*4/100 + (15900-x)*5*4/100
x =7400
Anil = 8500+8500*4*5/100 = 10200
A sum of rupees 4420 is to be divided between rakesh and prakash in such a way that after 5 years and 7 years respectively the amount they get is equal. The rate of interest is 10 percent. Find the share of rakesh and prakash- a)2000, 2420
- b)2420, 2000
- c)2480, 2420
- d)2210, 2210
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A sum of rupees 4420 is to be divided between rakesh and prakash in such a way that after 5 years and 7 years respectively the amount they get is equal. The rate of interest is 10 percent. Find the share of rakesh and prakash
a)
2000, 2420
b)
2420, 2000
c)
2480, 2420
d)
2210, 2210
e)
None of these
|
|
Aarav Sharma answered |
Given: Total amount = Rs. 4420, Rate of interest = 10%, Time for Rakesh = 5 years, Time for Prakash = 7 years
Let the share of Rakesh be x. Then, the share of Prakash will be (4420 - x).
Amount received by Rakesh after 5 years = x(1 + 10/100)^5 = 1.61x
Amount received by Prakash after 7 years = (4420 - x)(1 + 10/100)^7 = 1.97(4420 - x)
As per the question, both amounts should be equal. So, we can write:
1.61x = 1.97(4420 - x)
1.61x = 8717.4 - 1.97x
3.58x = 8717.4
x = 2420
Therefore, the share of Rakesh is Rs. 2420 and the share of Prakash is Rs. (4420 - 2420) = Rs. 2000.
Hence, option B is the correct answer.
Let the share of Rakesh be x. Then, the share of Prakash will be (4420 - x).
Amount received by Rakesh after 5 years = x(1 + 10/100)^5 = 1.61x
Amount received by Prakash after 7 years = (4420 - x)(1 + 10/100)^7 = 1.97(4420 - x)
As per the question, both amounts should be equal. So, we can write:
1.61x = 1.97(4420 - x)
1.61x = 8717.4 - 1.97x
3.58x = 8717.4
x = 2420
Therefore, the share of Rakesh is Rs. 2420 and the share of Prakash is Rs. (4420 - 2420) = Rs. 2000.
Hence, option B is the correct answer.
Ravi borrows a sum of Rs.2000 at the beginning of a year. After four months Rs.2600 more is borrowed at a rate of interest double the previous one. At the end of one year, the sum of interest on both the loans is Rs.494. What is the first rate of interest per annum?- a)8.5%
- b)9%
- c)9.5%
- d)12%
- e)None of the Above
Correct answer is option 'C'. Can you explain this answer?
Ravi borrows a sum of Rs.2000 at the beginning of a year. After four months Rs.2600 more is borrowed at a rate of interest double the previous one. At the end of one year, the sum of interest on both the loans is Rs.494. What is the first rate of interest per annum?
a)
8.5%
b)
9%
c)
9.5%
d)
12%
e)
None of the Above
|
|
Nikita Singh answered |
Answer –C.9.5% Explanation : P = 2000
Rate of Interest = x SI = 2000x/100 = 20x P = 2600
Rate of Interest = 2x SI = 5200x/100 = 52x 52x = 494 x = 9.5%
Rate of Interest = x SI = 2000x/100 = 20x P = 2600
Rate of Interest = 2x SI = 5200x/100 = 52x 52x = 494 x = 9.5%
Simple Interest for the sum of Rs.1230 for two year is Rs.10 more than the SI for Rs.1130 for the same duration. Find the Rate of Interest?- a)5%
- b)8%
- c)4%
- d)2%
Correct answer is option 'A'. Can you explain this answer?
Simple Interest for the sum of Rs.1230 for two year is Rs.10 more than the SI for Rs.1130 for the same duration. Find the Rate of Interest?
a)
5%
b)
8%
c)
4%
d)
2%
|
|
Preeti Khanna answered |
A. 5%
Explanation: (1230*2*R)/100 – (1130*2*R)/100 = 10
R=5%
Explanation: (1230*2*R)/100 – (1130*2*R)/100 = 10
R=5%
Rahul invested a sum of money at Simple Interest at a certain rate of interest for three years. Had it been invested at a 4% higher rate, it would have fetched Rs.480 more. Find out the Principal amount that was invested by Rahul?- a)3000
- b)4000
- c)5000
- d)4500
- e)None of the Above
Correct answer is option 'B'. Can you explain this answer?
Rahul invested a sum of money at Simple Interest at a certain rate of interest for three years. Had it been invested at a 4% higher rate, it would have fetched Rs.480 more. Find out the Principal amount that was invested by Rahul?
a)
3000
b)
4000
c)
5000
d)
4500
e)
None of the Above
|
|
Anaya Patel answered |
B. 4000
Explanation: x – Principal Extra amount = 4% for 3 years = 12% of x = 480 x = (480/12)*100 = 4000
Explanation: x – Principal Extra amount = 4% for 3 years = 12% of x = 480 x = (480/12)*100 = 4000
Ajay bought Rs.11,000 from a bank to buy a car at 12% simple Interest. If he paid $ 6,600 as interest while clearing the loan, find the time for which the loan was given.- a)7
- b)3
- c)4
- d)5
- e)6
Correct answer is option 'D'. Can you explain this answer?
Ajay bought Rs.11,000 from a bank to buy a car at 12% simple Interest. If he paid $ 6,600 as interest while clearing the loan, find the time for which the loan was given.
a)
7
b)
3
c)
4
d)
5
e)
6
|
|
Anaya Patel answered |
Answer – D.5 Explanation : T = 6600/11000*0.12
T = 5
T = 5
A sum of money is lent for 2 years at 10% p.a. compound interest. It yields Rs 8.81 more when compounded semi-annually than compounded annually. What is the sum lent?- a)1000
- b)1200
- c)1400
- d)1600
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A sum of money is lent for 2 years at 10% p.a. compound interest. It yields Rs 8.81 more when compounded semi-annually than compounded annually. What is the sum lent?
a)
1000
b)
1200
c)
1400
d)
1600
e)
None of these
|
|
Rajeev Kumar answered |
8.81 = p*(1+5/100)4 – p*(1+10/100)2
If Rs. 7200 amounts to Rs.10368 at compound interest in a certain time , then Rs. 7200 amounts to what in half of the time?- a)8640
- b)8600
- c)8800
- d)8520
- e)None of these
Correct answer is option 'A'. Can you explain this answer?
If Rs. 7200 amounts to Rs.10368 at compound interest in a certain time , then Rs. 7200 amounts to what in half of the time?
a)
8640
b)
8600
c)
8800
d)
8520
e)
None of these
|
|
Ravi Singh answered |
Let rate = R% and time = n year
Then, 10368 =7200(1+R/100)n
⇒ (1+R/100)n = 10368/7200 = 1.44
∴ (1 + R/100)n/2 = √1.44 = 1.2
∴ Required amount for n/2 yr
= 7200(1+ R/100)n/2
= 7200 x 1.2 = Rs. 8640
Then, 10368 =7200(1+R/100)n
⇒ (1+R/100)n = 10368/7200 = 1.44
∴ (1 + R/100)n/2 = √1.44 = 1.2
∴ Required amount for n/2 yr
= 7200(1+ R/100)n/2
= 7200 x 1.2 = Rs. 8640
Chapter doubts & questions for Simple and Compound Interest - RRB JE Mock Test Series Electrical & Electronics Engineering 2025 2025 is part of Electrical Engineering (EE) exam preparation. The chapters have been prepared according to the Electrical Engineering (EE) exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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