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All questions of JEE Advanced 2017 for JEE Exam

Among the following, the number of aromatic compound (s) is-

    Correct answer is '5'. Can you explain this answer?

    Telecom Tuners answered

    Cyclooctatetraene ; non aromatic
    Due to nonplanarity of ring the π-electrons are not delocalised.
     
    Cyclopropcnyl anion : Anti aromatic 4π-electrons delocalised.
    Cyclopropenyl cation ; Aromatic 2π-clcctrons delocalised.
    Cyclohexadiene : Non-aromatic.

    Tropylium ion : Arom atic 6π-electrons delocalised.

    Cyclo pentadienyl cation . Anti-aromatic 4π-electrons delocalised.

    Cyclo pentadienyl anion ; Aromatic 6π-electrons delocalised.

    The correct statement(s) for the following addition reactions is(are)
    • a)
      (M and O) and (N and P) are two pairs of diastereomers
    • b)
      Bromination proceeds through trans-addition in both the reactions
    • c)
      O and P are identical molecules
    • d)
      (M and O) and (N and P) are two pairs of enantiomers
    Correct answer is option 'A,B'. Can you explain this answer?

    Anaya Patel answered
     

     
    (ii)  
    (O) and (P) are enantiomers
    Explanation of 4 options : (A) (M) and (O) are distereomers of each other.
    (N) and (P) are distereomers of each other.
    (B) Addition of Br2 on alkene follows non-classical carbocation mechanism. It is anti or trans addition.
    (C) (O) and (P) are enantiomers
    (D) (M) and (N) are identical and (O) and (P) are enantiomers.
     (M and O) are distereomers and (N and P) are distereomers.

    For how many values of p, the circle x2 + y2 + 2x + 4y – p = 0 and the coordinate axes have exactly three common points ?
    • a)
      4
    • b)
      8
    • c)
      2
    • d)
      6
    Correct answer is option 'C'. Can you explain this answer?

    This can be answered without solving...according to question the circle and coordinate axes have 3 poi6in common there are two possibilities for this..first 2 points on X-axis and one point on Y-axis forbthis we get one corresponding value of 'p' and other case is 2 points o Y-axis and one point on X-axis for this we get one corresponding value of p...on total we get two values of p satisfying the given conditions...hope you understood the ideology used here

    Let S = {1, 2, 3,.....,9}. For k = 1,2, ....., 5, let Nk be the number of subsets of S, each containing five elements out of which exactly k are odd. Then N1 + N2 + N3 + N5  =
    • a)
      125
    • b)
      252
    • c)
      210
    • d)
      126
    Correct answer is option 'D'. Can you explain this answer?

    Aryan Rane answered
    N1 + N2 + N3 + N5
    = Total ways – {when no odd}
    Total ways = 9C5 Number of ways when no odd, is zero        (∵ only available even are 2, 4, 6, 8)
    ∴ Ans : 9C5 – zero = 126

    Let [x] be the greatest integer less than or equal to x. Then, at which of the following point(s) the function ƒ(x) = xcos(π(x + [x])) is discontinuous ?
    • a)
      x = -1
    • b)
      x = 0
    • c)
      x = 2
    • d)
      x = 1
    Correct answer is option 'A,C,D'. Can you explain this answer?

    Kritika Rane answered
    Discontinuity of the function (x) = xcos((x - [x]))

    To determine the points of discontinuity for the function (x) = xcos((x - [x])), we need to consider the behavior of the function at various points.

    Understanding the greatest integer function [x]
    The greatest integer function [x] takes a real number x and returns the greatest integer less than or equal to x. For example, [2.5] = 2, [3] = 3, and [-1.7] = -2.

    Discontinuity at x = -1
    We need to evaluate the function (x) = xcos((x - [x])) at x = -1.

    Substituting x = -1 into the function, we get:
    (-1)cos((-1) - [(-1)]))

    Since [-1] = -1, the expression simplifies to:
    (-1)cos((-1) - (-1))
    (-1)cos(0)
    (-1)(1)
    -1

    Therefore, at x = -1, the value of the function is -1. There is no discontinuity at this point.

    Discontinuity at x = 0
    We need to evaluate the function (x) = xcos((x - [x])) at x = 0.

    Substituting x = 0 into the function, we get:
    (0)cos((0) - [(0)]))

    Since [0] = 0, the expression simplifies to:
    (0)cos((0) - 0)
    (0)cos(0)
    0

    Therefore, at x = 0, the value of the function is 0. There is no discontinuity at this point.

    Discontinuity at x = 2
    We need to evaluate the function (x) = xcos((x - [x])) at x = 2.

    Substituting x = 2 into the function, we get:
    (2)cos((2) - [(2)]))

    Since [2] = 2, the expression simplifies to:
    (2)cos((2) - 2)
    (2)cos(0)
    2(1)
    2

    Therefore, at x = 2, the value of the function is 2. There is no discontinuity at this point.

    Discontinuity at x = 1
    We need to evaluate the function (x) = xcos((x - [x])) at x = 1.

    Substituting x = 1 into the function, we get:
    (1)cos((1) - [(1)]))

    Since [1] = 1, the expression simplifies to:
    (1)cos((1) - 1)
    (1)cos(0)
    1(1)
    1

    Therefore, at x = 1, the value of the function is 1. There is no discontinuity at this point.

    Conclusion
    After evaluating the function at x = -1, 0, 2, and 1, we can conclude that there are no points of discontinuity for the function (x) = xcos((x - [x])). The correct answer is option 'A,C,D', which includes all the given options

    Which of the following combination will produce H2 gas ?
    • a)
      Zn metal and NaOH(aq)
    • b)
      Au metal and NaCN(aq) in the presence of air
    • c)
      Cu metal and conc. HNO3
    • d)
      Fe metal and conc. HNO3
    Correct answer is option 'A'. Can you explain this answer?

    Nishanth Verma answered
    (A) Zn + 2NaOH → Na2ZnO2 + H2
    (B) 4Au + 8NaCN + O2 + 2H2O  → 4Na[Au(CN)2] + 4NaOH
    (C) Cu + 4HNO3 →  Cu(NO3)2 + 2NO2 + 2H2O
    (D)  Formation of passive layer of Fe2O3 on the surface of Fe and NO2 gas is evolved.

    How many 3 × 3 matrices M with entries from {0,1,2} are there, for which the sum of the diagonal entries of MTM is 5 ?
    • a)
      198
    • b)
      126
    • c)
      135
    • d)
      162
    Correct answer is option 'A'. Can you explain this answer?

    Harshad Das answered
    Let = 
    ∴ tr(MTM) = a2 + b2 + c2 + d2 + c2 + f+ g2 + h2 + i2 = 5,
    where entries are {0,1,2} Only two cases are possible.
    (I) five entries 1 and other four zero
    9C5 × 1
    (II) One entry is 2, one entry is 1 and others are 0.
    9C2 × 2!
    Total = 126 + 72 = 198.

    Among H2, He+2, Li2, Be2, B2, C2, N2, O-2, the number of diamagnetic species is -( Atomic number) : H =1, He = 2, Li = 3, Be = 4, B = 5, C = 6, N = 7,I = 8, F = 9)
    • a)
      5
    • b)
      6
    • c)
      1
    • d)
      2
    Correct answer is option 'A'. Can you explain this answer?





    If existence of Be2 is considered in atomic form or very weak bonded higher energetic species having zero bond order then it is diamagnetic , then answer will be 6. But if existence of molecular form of Be2 is not considered then magnetic property can't be predicted then answer will be 5

    The equation of the plane passing through the point (1,1,1) and perpendicular to the planes 2x + y – 2z = 5 and 3x – 6y – 2z = 7, is
    • a)
      14x + 2y + 15z = 31
    • b)
      14x + 2y – 15z = 1
    • c)
      –14x + 2y + 15z = 3
    • d)
      14x – 2y + 15z = 27
    Correct answer is option 'A'. Can you explain this answer?

    The normal vector of required plane is parallel to vector

    ∴ The equation of required plane passing through (1, 1, 1) will be
     –14(x – 1) – 2(y – 1) – 15(z – 1) = 0
    ⇒ 14x + 2y + 15z = 31
    ∴ Option (A) is correct

    PARAGRAPH–1
    Consider a simple RC circuit as shown in figure 1.
    Process 1 : In the circuit the switch S is closed at t = 0 and the capacitor is fully charged to voltage V0 (i.e., charging continues for time T >> RC). In the process some dissipation (ED) occurs across the resistance R. The amount of energy finally stored in the fully charged capacitor is EC.
    Process 2 : In a different process the voltage is first set to  and maintained for a charging time T >> RC. Then the voltage is raised to   without discharging the capacitor and again maintained for a time T >> RC. The process is repeated one more time by raising the voltage to V0 and the capacitor is charged to the same final voltage V0 as in Process 1. These two processes are depicted in Figure 2.

    Q. In Process 2, total energy dissipated across the resistance ED is :-
    • a)
    • b)
    • c)
    • d)
    Correct answer is option 'A'. Can you explain this answer?

    For process (1)
    Charge on capacitor =

    energy stored in capacitor =

    work done by battery = 

    Heat loss =
    For process (2)
    Charge on capacitor =

    Extra charge flow through battery =

    Work done by battery :

    Final energy store in capacitor :

    energy store in process 2 :

    Heat loss in process (2) = work done by battery in process (2) – energy store in capacitor process (2)
    For process (3)
    Charge on capacitor = CV0
    extra charge flow through battery : 

    work done by battery in this process :

    find energy store in capacitor :

    energy stored in this process :

    Now total heat loss (ED) : 
    final energy store in capacitor :

    so we can say that ED =

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