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All questions of JEE Advanced 2014 for JEE Exam
A horizontal circular platform of radius 0.5 m and mass 0.45 kg is free to rotate about its axis. Two massless spring toy-guns, each carrying a steel ball of mass 0.05 kg are attached to the platform at a distance 0.25 m from the centre on its either sides along its diameter (see figure). Each gun simultaneously fires the balls horizontally and perpendicular to the diameter in opposite directions. After leaving the platform, the balls have horizontal speed of 9 ms–1 with respect to the ground. The rotational speed of the platform in rad s–1 after the balls leave the platform is
Correct answer is '4'. Can you explain this answer?
A horizontal circular platform of radius 0.5 m and mass 0.45 kg is free to rotate about its axis. Two massless spring toy-guns, each carrying a steel ball of mass 0.05 kg are attached to the platform at a distance 0.25 m from the centre on its either sides along its diameter (see figure). Each gun simultaneously fires the balls horizontally and perpendicular to the diameter in opposite directions. After leaving the platform, the balls have horizontal speed of 9 ms–1 with respect to the ground. The rotational speed of the platform in rad s–1 after the balls leave the platform is
|
Preeti Iyer answered |
Since net torque about centre of rotation is zero, so we can apply conservation of angular momentum of the
system about center of disc
system about center of disc
Li = Lf
0 = Iω + 2mv (r/2); comparing magnitude
A planet of radius R = 1/10 x (radius of Earth) has the same mass density as Earth. Scientists dig a well of
depth R/5 on it and lower a wire of the same length and of linear mass density 10-3 kgm-1 into it. If the wire
is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the
radius of Earth = 6 x 106 m and the acceleration due to gravity of Earth is 10 ms-2)- a)96N
- b)108N
- c)120N
- d)150N
Correct answer is option 'B'. Can you explain this answer?
A planet of radius R = 1/10 x (radius of Earth) has the same mass density as Earth. Scientists dig a well of
depth R/5 on it and lower a wire of the same length and of linear mass density 10-3 kgm-1 into it. If the wire
is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the
radius of Earth = 6 x 106 m and the acceleration due to gravity of Earth is 10 ms-2)
depth R/5 on it and lower a wire of the same length and of linear mass density 10-3 kgm-1 into it. If the wire
is not touching anywhere, the force applied at the top of the wire by a person holding it in place is (take the
radius of Earth = 6 x 106 m and the acceleration due to gravity of Earth is 10 ms-2)
a)
96N
b)
108N
c)
120N
d)
150N
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Tejas Verma answered |
Each question, when worked out will result in one integer from 0 to 9 (both inclusive).Q.Let n1 < n2 < n3 < n4 < n5 be positive integers such that n1 + n2 + n3 + n4 + n5 = 20. Then the number of such distinct arrangements (n1, n2, n3, n4, n5) is _________
Correct answer is '7'. Can you explain this answer?
Each question, when worked out will result in one integer from 0 to 9 (both inclusive).
Q.
Let n1 < n2 < n3 < n4 < n5 be positive integers such that n1 + n2 + n3 + n4 + n5 = 20. Then the number of such distinct arrangements (n1, n2, n3, n4, n5) is _________
|
Rohit Jain answered |
When n5 takes value from 10 to 6 the carry forward moves from 0 to 4 which can be arranged in
Schemes 1 and 2 describe sequential transformation of alkynes M and N. Consider only the major products formed in each step for both schemes
Q.The correct statement with respect to product Y is- a)It gives a positive Tollens test and is a functional isomer of X.
- b)It gives a positive Tollens test and is a geometrical isomer of X.
- c)It gives a positive iodoform test and is a functional isomer of X.
- d)It gives a positive iodoform test and is a geometrical isomer of X.
Correct answer is option 'C'. Can you explain this answer?
Schemes 1 and 2 describe sequential transformation of alkynes M and N. Consider only the major products formed in each step for both schemes
Q.
The correct statement with respect to product Y is
a)
It gives a positive Tollens test and is a functional isomer of X.
b)
It gives a positive Tollens test and is a geometrical isomer of X.
c)
It gives a positive iodoform test and is a functional isomer of X.
d)
It gives a positive iodoform test and is a geometrical isomer of X.
|
|
Tejas Verma answered |
Four charges Q1, Q2, Q3 and Q4 of same magnitude are fixed along the x axis at x = -2a, -a, +a and +2a,
respectively. A positive charge q is placed on the positive y axis at a distance b > 0. Four options of the
signs of these charges are given in List I. The direction of the forces on the charge q is given in List II.
Match List I with List II and select the correct answer using the code given below the lists.
- a)P-3, Q-1, R-4, S-2
- b)P-4, Q-2, R-3, S-1
- c)P-3, Q-1, R-2, S-4
- d)P-4, Q-2, R-1, S-3
Correct answer is option 'A'. Can you explain this answer?
Four charges Q1, Q2, Q3 and Q4 of same magnitude are fixed along the x axis at x = -2a, -a, +a and +2a,
respectively. A positive charge q is placed on the positive y axis at a distance b > 0. Four options of the
signs of these charges are given in List I. The direction of the forces on the charge q is given in List II.
Match List I with List II and select the correct answer using the code given below the lists.
respectively. A positive charge q is placed on the positive y axis at a distance b > 0. Four options of the
signs of these charges are given in List I. The direction of the forces on the charge q is given in List II.
Match List I with List II and select the correct answer using the code given below the lists.
a)
P-3, Q-1, R-4, S-2
b)
P-4, Q-2, R-3, S-1
c)
P-3, Q-1, R-2, S-4
d)
P-4, Q-2, R-1, S-3
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|
Tejas Verma answered |
P: By Q1 and Q4, Q3 and Q2 F is in +y
Q: By Q1 and Q4, Q2 and Q3 F is in +ve x.
R: By Q1 and Q4, F is in +ve y
By Q2 and Q3, F is in –ve y
But later has more magnitude, since its closer to
(0, b). Therefore net force is in – y
S: By Q1 and Q4, F is in +ve x and by Q2 and Q3, F is
in –x, but later is more in magnitude, since its
closer to (0, b). Therefore net force is in –ve x.
Q: By Q1 and Q4, Q2 and Q3 F is in +ve x.
R: By Q1 and Q4, F is in +ve y
By Q2 and Q3, F is in –ve y
But later has more magnitude, since its closer to
(0, b). Therefore net force is in – y
S: By Q1 and Q4, F is in +ve x and by Q2 and Q3, F is
in –x, but later is more in magnitude, since its
closer to (0, b). Therefore net force is in –ve x.
In the figure a container is shown to have a movable (without friction) piston on top. The container and
the piston are all made of perfectly insulating material allowing no heat transfer between outside and
inside the container. The container is divided into two compartments by a rigid partition made of a
thermally conducting material that allows slow transfer of heat. The lower compartment of the container is filled with 2 moles of an ideal monatomic gas at 700 K and the upper compartment is filled with 2 moles of an ideal diatomic gas at 400 K. The heat capacities per mole of an ideal monatomic gas are 
and those for an ideal diatomic gas are 
Q.Now consider the partition to be free to move without friction so that the pressure of gases in both
compartments is the same. Then total work done by the gases till the time they achieve equilibrium will be- a)250 R
- b)200 R
- c)100 R
- d)–100 R
Correct answer is option 'D'. Can you explain this answer?
In the figure a container is shown to have a movable (without friction) piston on top. The container and
the piston are all made of perfectly insulating material allowing no heat transfer between outside and
inside the container. The container is divided into two compartments by a rigid partition made of a
thermally conducting material that allows slow transfer of heat. The lower compartment of the container is filled with 2 moles of an ideal monatomic gas at 700 K and the upper compartment is filled with 2 moles of an ideal diatomic gas at 400 K. The heat capacities per mole of an ideal monatomic gas are and those for an ideal diatomic gas are
the piston are all made of perfectly insulating material allowing no heat transfer between outside and
inside the container. The container is divided into two compartments by a rigid partition made of a
thermally conducting material that allows slow transfer of heat. The lower compartment of the container is filled with 2 moles of an ideal monatomic gas at 700 K and the upper compartment is filled with 2 moles of an ideal diatomic gas at 400 K. The heat capacities per mole of an ideal monatomic gas are
and those for an ideal diatomic gas are Q.
Now consider the partition to be free to move without friction so that the pressure of gases in both
compartments is the same. Then total work done by the gases till the time they achieve equilibrium will be
compartments is the same. Then total work done by the gases till the time they achieve equilibrium will be
a)
250 R
b)
200 R
c)
100 R
d)
–100 R
|
Krishna Iyer answered |
Heat given by lower compartment = 
Heat obtained by upper compartment =
By equating (i) and (ii)
5(700 -T) = 7(T - 400)
3000 – 5T = 7T– 2800
6300 = 12 T
T = 525K
Work done by lower gas = nRΔT = – 350 R
Work done by upper gas = nRΔT = +250 R
Net work done - 100 R
5(700 -T) = 7(T - 400)
3000 – 5T = 7T– 2800
6300 = 12 T
T = 525K
Work done by lower gas = nRΔT = – 350 RWork done by upper gas = nRΔT = +250 R
Net work done - 100 R
MX2 dissociates in M2+ and X- ions in an aqueous solution, with a degree of dissociation (α) of 0.5. The
ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of
freezing point in the absence of ionic dissociation is
Correct answer is '2'. Can you explain this answer?
MX2 dissociates in M2+ and X- ions in an aqueous solution, with a degree of dissociation (α) of 0.5. The
ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of
freezing point in the absence of ionic dissociation is
ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of
freezing point in the absence of ionic dissociation is
|
|
Tejas Verma answered |
Let E1 (r), E2 (r) and E3 (r) be the respective electric fields at a distance r from a point charge Q, an
infinitely long wire with constant linear charge density λ, and an infinite plane with uniform surface charge
density σ. If E1(r0 ) = E2 (r0 ) = E3 (r0 ) at a given distance r0, then- a)
- b)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
Let E1 (r), E2 (r) and E3 (r) be the respective electric fields at a distance r from a point charge Q, an
infinitely long wire with constant linear charge density λ, and an infinite plane with uniform surface charge
density σ. If E1(r0 ) = E2 (r0 ) = E3 (r0 ) at a given distance r0, then
infinitely long wire with constant linear charge density λ, and an infinite plane with uniform surface charge
density σ. If E1(r0 ) = E2 (r0 ) = E3 (r0 ) at a given distance r0, then
a)
b)
c)
d)
|
Shreya Gupta answered |
A thermodynamic system is taken from an initial state i with internal energy Ui = 100 J to the final state f
along two different paths iaf and ibf, as schematically shown in the figure. The work done by the system
along the paths af, ib and bf are Waf = 200 J, Wib = 50 J and Wbf = 100 J respectively. The heat supplied to
the system along the path iaf, ib and bf are iaf ib Q , Q and Qbf respectively. If the internal energy of the
system in the state b is Ub = 200 J and Qiaf = 500 J, the ratio Qbf / Qib is
Correct answer is '2'. Can you explain this answer?
A thermodynamic system is taken from an initial state i with internal energy Ui = 100 J to the final state f
along two different paths iaf and ibf, as schematically shown in the figure. The work done by the system
along the paths af, ib and bf are Waf = 200 J, Wib = 50 J and Wbf = 100 J respectively. The heat supplied to
the system along the path iaf, ib and bf are iaf ib Q , Q and Qbf respectively. If the internal energy of the
system in the state b is Ub = 200 J and Qiaf = 500 J, the ratio Qbf / Qib is
along two different paths iaf and ibf, as schematically shown in the figure. The work done by the system
along the paths af, ib and bf are Waf = 200 J, Wib = 50 J and Wbf = 100 J respectively. The heat supplied to
the system along the path iaf, ib and bf are iaf ib Q , Q and Qbf respectively. If the internal energy of the
system in the state b is Ub = 200 J and Qiaf = 500 J, the ratio Qbf / Qib is
|
Lavanya Menon answered |
Ub = 200 J, Ui =100 J
Process iaf
Process iaf
An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarized in the scheme given below.
Q.Reagent S is- a)K4 [Fe (CN)6]
- b)Na2HPO4
- c)K2CrO4
- d)KOH
Correct answer is option 'D'. Can you explain this answer?
An aqueous solution of metal ion M1 reacts separately with reagents Q and R in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion M2 always forms tetrahedral complexes with these reagents. Aqueous solution of M2 on reaction with reagent S gives white precipitate which dissolves in excess of S. The reactions are summarized in the scheme given below.
Q.
Reagent S is
a)
K4 [Fe (CN)6]
b)
Na2HPO4
c)
K2CrO4
d)
KOH
|
Advait Singh answered |
The total number of distinct naturally occurring amino acids obtained by complete acidic hydrolysis of the
peptide shown below is
Correct answer is '1'. Can you explain this answer?
The total number of distinct naturally occurring amino acids obtained by complete acidic hydrolysis of the
peptide shown below is
peptide shown below is
|
|
Ananya Das answered |
This peptide on complete hydrolysis produced 4 distinct amino acids which are given below:
Airplanes A and B are flying with constant velocity in the same vertical plane at angles 300 and 600 with
respect to the horizontal respectively as shown in the figure. The speed of A is 100√3 ms-1. At time t = 0
s, an observer in A finds B at a distance of 500 m. This observer sees B moving with a constant velocity
perpendicular to the line of motion of A. If at t = t0, A just escapes being hit by B, t0 in seconds is
Correct answer is '5'. Can you explain this answer?
Airplanes A and B are flying with constant velocity in the same vertical plane at angles 300 and 600 with
respect to the horizontal respectively as shown in the figure. The speed of A is 100√3 ms-1. At time t = 0
s, an observer in A finds B at a distance of 500 m. This observer sees B moving with a constant velocity
perpendicular to the line of motion of A. If at t = t0, A just escapes being hit by B, t0 in seconds is
respect to the horizontal respectively as shown in the figure. The speed of A is 100√3 ms-1. At time t = 0
s, an observer in A finds B at a distance of 500 m. This observer sees B moving with a constant velocity
perpendicular to the line of motion of A. If at t = t0, A just escapes being hit by B, t0 in seconds is
|
Veda Institute answered |
The relative velocity of B with respect to A is perpendicular to line of motion of A.
A rocket is moving in a gravity free space with a constant acceleration of 2 ms–2 along + x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in + x direction with a speed of 0.3 ms–1 relative to the rocket. At the same time, another ball is thrown in +x direction with a speed of 0.2 ms–1 from its right end relative to the rocket. The time in seconds when the two balls hit each other is
Correct answer is '2'. Can you explain this answer?
A rocket is moving in a gravity free space with a constant acceleration of 2 ms–2 along + x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in + x direction with a speed of 0.3 ms–1 relative to the rocket. At the same time, another ball is thrown in +x direction with a speed of 0.2 ms–1 from its right end relative to the rocket. The time in seconds when the two balls hit each other is
|
|
Tejas Verma answered |
Maximum displacement of the left ball from the left wall of the chamber is 2.25 cm, so the right ball has to travel almost the whole length of the chamber (4m) to hit the left ball. So the time taken by the right ball is
1.9 sec (approximately 2 sec)
1.9 sec (approximately 2 sec)
For 
the equation sinx + 2sin2x - sin3x = 3 has- a)infinitely many solutions
- b)three solutions
- c)one solution
- d)no solution
Correct answer is option 'D'. Can you explain this answer?
For the equation sinx + 2sin2x - sin3x = 3 has
the equation sinx + 2sin2x - sin3x = 3 hasa)
infinitely many solutions
b)
three solutions
c)
one solution
d)
no solution
|
|
Tejas Verma answered |
which is not possible at same time
Hence, no solution
Hence, no solution
For the identification of β-naphthol using dye test, it is necessary to use- a)dichloromethane solution of β-naphthol
- b)acidic solution of β-naphthol.
- c)neutral solution of β-naphthol.
- d)alkaline solution of β-naphthol
Correct answer is option 'D'. Can you explain this answer?
For the identification of β-naphthol using dye test, it is necessary to use
a)
dichloromethane solution of β-naphthol
b)
acidic solution of β-naphthol.
c)
neutral solution of β-naphthol.
d)
alkaline solution of β-naphthol
|
Siddharth Ghosh answered |
A person, several methods can be used, including:
1. Visual identification: This involves looking at the physical appearance of the person and comparing it to a known photograph or description. This method is commonly used by law enforcement agencies when searching for suspects.
2. Biometric identification: Biometric technologies such as fingerprint scanning, iris scanning, or facial recognition can be used to identify a person based on their unique physical characteristics. These methods are often used for security purposes, such as accessing a smartphone or entering a secure facility.
3. Personal identification documents: Official documents such as driver's licenses, passports, or ID cards contain personal information and a photograph, which can be used to verify a person's identity. These documents are commonly used in various contexts, such as airport security or when opening a bank account.
4. DNA testing: In certain cases, DNA testing can be used to identify a person by comparing their DNA sample with a known sample, such as from a crime scene or a family member. This method is often used in forensic investigations or to establish biological relationships.
It is important to note that the accuracy and reliability of these identification methods can vary, and some methods may require specialized equipment or expertise. Additionally, privacy and ethical considerations should be taken into account when applying these methods.
1. Visual identification: This involves looking at the physical appearance of the person and comparing it to a known photograph or description. This method is commonly used by law enforcement agencies when searching for suspects.
2. Biometric identification: Biometric technologies such as fingerprint scanning, iris scanning, or facial recognition can be used to identify a person based on their unique physical characteristics. These methods are often used for security purposes, such as accessing a smartphone or entering a secure facility.
3. Personal identification documents: Official documents such as driver's licenses, passports, or ID cards contain personal information and a photograph, which can be used to verify a person's identity. These documents are commonly used in various contexts, such as airport security or when opening a bank account.
4. DNA testing: In certain cases, DNA testing can be used to identify a person by comparing their DNA sample with a known sample, such as from a crime scene or a family member. This method is often used in forensic investigations or to establish biological relationships.
It is important to note that the accuracy and reliability of these identification methods can vary, and some methods may require specialized equipment or expertise. Additionally, privacy and ethical considerations should be taken into account when applying these methods.
Consider all possible isomeric ketones, including stereoisomers of MW = 100. All these isomers are
independently reacted with NaBH4 (NOTE: stereoisomers are also reacted separately). The total number of
ketones that give a racemic product(s) is/are
Correct answer is '5'. Can you explain this answer?
Consider all possible isomeric ketones, including stereoisomers of MW = 100. All these isomers are
independently reacted with NaBH4 (NOTE: stereoisomers are also reacted separately). The total number of
ketones that give a racemic product(s) is/are
independently reacted with NaBH4 (NOTE: stereoisomers are also reacted separately). The total number of
ketones that give a racemic product(s) is/are
|
|
Devansh Kulkarni answered |
Introduction:
In this question, we are given a set of isomeric ketones with a molecular weight of 100. We need to determine the number of ketones that will produce a racemic product when reacted with NaBH4.
Understanding the concept:
When a ketone is reacted with NaBH4, it undergoes reduction to form an alcohol. The reduction of a ketone by NaBH4 is a stereospecific process, meaning that the configuration of the product is determined by the configuration of the starting ketone.
Determining the number of ketones that give a racemic product:
To determine the number of ketones that give a racemic product, we need to consider the presence of a chiral center in the ketone molecule. A chiral center is a carbon atom bonded to four different groups.
Case 1: Ketones with no chiral centers:
If a ketone has no chiral centers, it will not produce a racemic product. This is because there is no possibility for the product to have different configurations.
Case 2: Ketones with one chiral center:
If a ketone has one chiral center, it can exist as a pair of enantiomers. When reacted with NaBH4, each enantiomer will produce the corresponding enantiomeric alcohol. Therefore, in this case, the ketone will give a racemic product.
Case 3: Ketones with two chiral centers:
If a ketone has two chiral centers, it can exist as a pair of diastereomers. When reacted with NaBH4, each diastereomer will produce a mixture of enantiomeric alcohols. Therefore, in this case, the ketone will give a racemic product.
Case 4: Ketones with more than two chiral centers:
If a ketone has more than two chiral centers, it can exist as a pair of diastereomers. However, in this case, the diastereomers will not be mirror images of each other, and the reaction with NaBH4 will not produce a racemic product.
Conclusion:
In summary, the ketones that give a racemic product when reacted with NaBH4 are those with one or two chiral centers. Therefore, out of all the possible isomeric ketones with a molecular weight of 100, there are 5 ketones that will produce a racemic product.
In this question, we are given a set of isomeric ketones with a molecular weight of 100. We need to determine the number of ketones that will produce a racemic product when reacted with NaBH4.
Understanding the concept:
When a ketone is reacted with NaBH4, it undergoes reduction to form an alcohol. The reduction of a ketone by NaBH4 is a stereospecific process, meaning that the configuration of the product is determined by the configuration of the starting ketone.
Determining the number of ketones that give a racemic product:
To determine the number of ketones that give a racemic product, we need to consider the presence of a chiral center in the ketone molecule. A chiral center is a carbon atom bonded to four different groups.
Case 1: Ketones with no chiral centers:
If a ketone has no chiral centers, it will not produce a racemic product. This is because there is no possibility for the product to have different configurations.
Case 2: Ketones with one chiral center:
If a ketone has one chiral center, it can exist as a pair of enantiomers. When reacted with NaBH4, each enantiomer will produce the corresponding enantiomeric alcohol. Therefore, in this case, the ketone will give a racemic product.
Case 3: Ketones with two chiral centers:
If a ketone has two chiral centers, it can exist as a pair of diastereomers. When reacted with NaBH4, each diastereomer will produce a mixture of enantiomeric alcohols. Therefore, in this case, the ketone will give a racemic product.
Case 4: Ketones with more than two chiral centers:
If a ketone has more than two chiral centers, it can exist as a pair of diastereomers. However, in this case, the diastereomers will not be mirror images of each other, and the reaction with NaBH4 will not produce a racemic product.
Conclusion:
In summary, the ketones that give a racemic product when reacted with NaBH4 are those with one or two chiral centers. Therefore, out of all the possible isomeric ketones with a molecular weight of 100, there are 5 ketones that will produce a racemic product.
Consider an elliptically shaped rail PQ in the vertical plane with OP = 3 m and OQ = 4 m. A block of mass 1 kg is pulled along the rail from P to Q with a force of 18 N, which is always parallel to line PQ (see the figure given). Assuming no frictional losses, the kinetic energy of the block when it reaches Q is (n×10) Joules. The
value of n is (take acceleration due to gravity = 10 ms–2)
Correct answer is '5'. Can you explain this answer?
Consider an elliptically shaped rail PQ in the vertical plane with OP = 3 m and OQ = 4 m. A block of mass 1 kg is pulled along the rail from P to Q with a force of 18 N, which is always parallel to line PQ (see the figure given). Assuming no frictional losses, the kinetic energy of the block when it reaches Q is (n×10) Joules. The
value of n is (take acceleration due to gravity = 10 ms–2)
value of n is (take acceleration due to gravity = 10 ms–2)
|
|
Ananya Das answered |
Let n 
2 be an integer. Take n distinct points on a circle and join each pair of points by a line segment.
Colour the line segment joining every pair of adjacent points by blue and the rest by red. If the number of
red and blue line segments are equal, then the value of n is _________
Correct answer is '5'. Can you explain this answer?
Let n 2 be an integer. Take n distinct points on a circle and join each pair of points by a line segment.
Colour the line segment joining every pair of adjacent points by blue and the rest by red. If the number of
red and blue line segments are equal, then the value of n is _________
2 be an integer. Take n distinct points on a circle and join each pair of points by a line segment.Colour the line segment joining every pair of adjacent points by blue and the rest by red. If the number of
red and blue line segments are equal, then the value of n is _________
|
|
Veda Institute answered |
Let a, r, s, t be non-zero real numbers. Let P(at2, 2at), Q, R(ar2, 2ar) and S(as2, 2as) be distinct points on the parabola y2 = 4ax. Suppose that PQ is the focal chord and lines QR and PK are parallel, where K is the point (2a, 0).Q.If st = 1, then the tangent at P and the normal at S to the parabola meet at a point whose ordinate is- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
Let a, r, s, t be non-zero real numbers. Let P(at2, 2at), Q, R(ar2, 2ar) and S(as2, 2as) be distinct points on the parabola y2 = 4ax. Suppose that PQ is the focal chord and lines QR and PK are parallel, where K is the point (2a, 0).
Q.
If st = 1, then the tangent at P and the normal at S to the parabola meet at a point whose ordinate is
a)
b)
c)
d)
|
Nandini Iyer answered |
A block of mass m1 = 1 kg another mass m2 = 2kg, are placed together (see figure) on an inclined plane
with angle of inclination θ. Various values of θ are given in List I. The coefficient of friction between the
block m1 and the plane is always zero. The coefficient of static and dynamic friction between the block m2
and the plane are equal to μ = 0.3. In List II expressions for the friction on the block m2 are given. Match
the correct expression of the friction in List II with the angles given in List I, and choose the correct option.
The acceleration due to gravity is denoted by g.
[Useful information: tan (5.5o) ≈ 0.1; tan (11.5o) ≈ 0.2; tan (16.5o) ≈ 0.3]
- a)P-1, Q-1, R-1, S-3
- b)P-2, Q-2, R-2, S-3
- c)P-2, Q-2, R-2, S-4
- d)P-2, Q-2, R-3, S-3
Correct answer is option 'D'. Can you explain this answer?
A block of mass m1 = 1 kg another mass m2 = 2kg, are placed together (see figure) on an inclined plane
with angle of inclination θ. Various values of θ are given in List I. The coefficient of friction between the
block m1 and the plane is always zero. The coefficient of static and dynamic friction between the block m2
and the plane are equal to μ = 0.3. In List II expressions for the friction on the block m2 are given. Match
the correct expression of the friction in List II with the angles given in List I, and choose the correct option.
The acceleration due to gravity is denoted by g.
[Useful information: tan (5.5o) ≈ 0.1; tan (11.5o) ≈ 0.2; tan (16.5o) ≈ 0.3]
with angle of inclination θ. Various values of θ are given in List I. The coefficient of friction between the
block m1 and the plane is always zero. The coefficient of static and dynamic friction between the block m2
and the plane are equal to μ = 0.3. In List II expressions for the friction on the block m2 are given. Match
the correct expression of the friction in List II with the angles given in List I, and choose the correct option.
The acceleration due to gravity is denoted by g.
[Useful information: tan (5.5o) ≈ 0.1; tan (11.5o) ≈ 0.2; tan (16.5o) ≈ 0.3]
a)
P-1, Q-1, R-1, S-3
b)
P-2, Q-2, R-2, S-3
c)
P-2, Q-2, R-2, S-4
d)
P-2, Q-2, R-3, S-3
|
Pioneer Academy answered |
Hydrogen bonding plays a central role in the following phenomena:- a)Ice floats in water
- b)Higher Lewis basicity of primary amines than tertiary amines in aqueous solutions.
- c)Formic acid is more acidic than acetic acid.
- d)Dimerisation of acetic acid in benzene.
Correct answer is option 'A,B,D'. Can you explain this answer?
Hydrogen bonding plays a central role in the following phenomena:
a)
Ice floats in water
b)
Higher Lewis basicity of primary amines than tertiary amines in aqueous solutions.
c)
Formic acid is more acidic than acetic acid.
d)
Dimerisation of acetic acid in benzene.
|
|
Ananya Das answered |
(A) Ice has cage-like structure in which each water molecule is surrounded by four other water molecules tetrahedrally through hydrogen boding, due to this density of ice is less than water and it floats in
water.
water.
The cation (I) more stabilized through hydrogen boding than cation (II) . So, R–NH2 is better base than (R)3N in aqueous solution.
(C) HCOOH is stronger acid than CH3COOH due to inductive effect and not due to hydrogen bonding.
(D) Acetic acid dimerizes in benzene through intermolecular hydrogen bonding.
Box 1 contains three cards bearing numbers 1, 2, 3 ; box 2 contains five cards bearing numbers 1, 2, 3, 4, 5 ; and box 3 contains seven cards bearing numbers 1, 2, 3, 4, 5, 6, 7. A card is drawn from each of the boxes. Let xi be the number on the card drawn from the ith box, i = 1, 2, 3.Q.The probability that x1 , x2 , x3 are in an arithmetic progression, is- a)9/105
- b)10/105
- c)11/105
- d)7/105
Correct answer is option 'C'. Can you explain this answer?
Box 1 contains three cards bearing numbers 1, 2, 3 ; box 2 contains five cards bearing numbers 1, 2, 3, 4, 5 ; and box 3 contains seven cards bearing numbers 1, 2, 3, 4, 5, 6, 7. A card is drawn from each of the boxes. Let xi be the number on the card drawn from the ith box, i = 1, 2, 3.
Q.
The probability that x1 , x2 , x3 are in an arithmetic progression, is
a)
9/105
b)
10/105
c)
11/105
d)
7/105
|
Hansa Sharma answered |
Here 2x2 = x1 + x3
x1 + x3 = even
Hence number of favourable ways =
x1 + x3 = evenHence number of favourable ways =
To find the distance d over which a signal can be seen clearly in foggy conditions, a railways engineer uses
dimensional analysis and assumes that the distance depends on the mass density ρ of the fog, intensity
(power/area) S of the light from the signal and its frequency f. The engineer finds that d is proportional to
S1/n. The value of n is
Correct answer is '3'. Can you explain this answer?
To find the distance d over which a signal can be seen clearly in foggy conditions, a railways engineer uses
dimensional analysis and assumes that the distance depends on the mass density ρ of the fog, intensity
(power/area) S of the light from the signal and its frequency f. The engineer finds that d is proportional to
S1/n. The value of n is
dimensional analysis and assumes that the distance depends on the mass density ρ of the fog, intensity
(power/area) S of the light from the signal and its frequency f. The engineer finds that d is proportional to
S1/n. The value of n is
|
Raghav Bansal answered |
The correct statement(s) for orthoboric acid is/are- a)It behaves as a weak acid in water due to self ionization.
- b)Acidity of its aqueous solution increases upon addition of ethylene glycol
- c)It has a three dimensional structure due to hydrogen bonding
- d)It is a weak electrolyte in water.
Correct answer is option 'B,D'. Can you explain this answer?
The correct statement(s) for orthoboric acid is/are
a)
It behaves as a weak acid in water due to self ionization.
b)
Acidity of its aqueous solution increases upon addition of ethylene glycol
c)
It has a three dimensional structure due to hydrogen bonding
d)
It is a weak electrolyte in water.
|
Maitri Das answered |
(A) H3BO3 is a weak monobasic Lewis acid.
(B) Equilibrium (i) is shifted in forward direction by the addition of syn-diols like ethylene glycol which forms a stable complex with 
(C) It has a planar sheet like structure due to hydrogen bonding.
(D) H3BO3 is a weak electrolyte in water.
(D) H3BO3 is a weak electrolyte in water.
Four combinations of two thin lenses are given in List I. The radius of curvature of all curved surfaces is r
and the refractive index of all the lenses is 1.5. Match lens combinations in List I with their focal length in
List II and select the correct answer using the code given below the lists.
- a)P-1, Q-2, R-3, S-4
- b)P-2, Q-4, R-3, S-1
- c)P-4, Q-1, R-2, S-3
- d)P-2, Q-1, R-3, S-4
Correct answer is option 'B'. Can you explain this answer?
Four combinations of two thin lenses are given in List I. The radius of curvature of all curved surfaces is r
and the refractive index of all the lenses is 1.5. Match lens combinations in List I with their focal length in
List II and select the correct answer using the code given below the lists.
and the refractive index of all the lenses is 1.5. Match lens combinations in List I with their focal length in
List II and select the correct answer using the code given below the lists.
a)
P-1, Q-2, R-3, S-4
b)
P-2, Q-4, R-3, S-1
c)
P-4, Q-1, R-2, S-3
d)
P-2, Q-1, R-3, S-4
|
|
Tejas Verma answered |
Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed u
between the wires in the same plane at a distance X1 from one of the wires. When the wires carry current of
magnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,
if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1 =3 the value of R1/ R2 is
Correct answer is '3'. Can you explain this answer?
Two parallel wires in the plane of the paper are distance X0 apart. A point charge is moving with speed u
between the wires in the same plane at a distance X1 from one of the wires. When the wires carry current of
magnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,
if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1 =3 the value of R1/ R2 is
between the wires in the same plane at a distance X1 from one of the wires. When the wires carry current of
magnitude I in the same direction, the radius of curvature of the path of the point charge is R1. In contrast,
if the currents I in the two wires have directions opposite to each other, the radius of curvature of the path is R2. id X0/X1 =3 the value of R1/ R2 is
|
|
Anjali Sharma answered |
An ideal gas in a thermally insulated vessel at internal pressure = P1, volume = V1 and absolute
temperature = T1 expands irreversibly against zero external pressure, as shown in the diagram. The final
internal pressure, volume and absolute temperature of the gas are P2, V2 and T2, respectively. For this
expansion,
- a)q = 0
- b)T2 = T1
- c)P2V2 = P1V1
- d)
Correct answer is option 'A,B,C'. Can you explain this answer?
An ideal gas in a thermally insulated vessel at internal pressure = P1, volume = V1 and absolute
temperature = T1 expands irreversibly against zero external pressure, as shown in the diagram. The final
internal pressure, volume and absolute temperature of the gas are P2, V2 and T2, respectively. For this
expansion,
temperature = T1 expands irreversibly against zero external pressure, as shown in the diagram. The final
internal pressure, volume and absolute temperature of the gas are P2, V2 and T2, respectively. For this
expansion,
a)
q = 0
b)
T2 = T1
c)
P2V2 = P1V1
d)
|
Neha Joshi answered |
Since container is thermally insulated. So, q = 0, and it is a case of free expansion therefore W = 0 and
ΔE = 0
So, T1 = T2
Also, P1V1 = P2V2
So, T1 = T2
Also, P1V1 = P2V2
Coefficient of x11 in the expansion of (1 + x2)4 (1 + x3)7 (1 + x4)12 is- a)1051
- b)1106
- c)1113
- d)1120
Correct answer is option 'C'. Can you explain this answer?
Coefficient of x11 in the expansion of (1 + x2)4 (1 + x3)7 (1 + x4)12 is
a)
1051
b)
1106
c)
1113
d)
1120
|
|
Rajiv Reddy answered |
2x1 + 3x2 + 4x3 = 11
Possibilities are (0, 1, 2); (1, 3, 0); (2, 1, 1); (4, 1, 0).
Required coefficients
Possibilities are (0, 1, 2); (1, 3, 0); (2, 1, 1); (4, 1, 0).
Required coefficients
The quadratic equation p(x) = 0 with real coefficients has purely imaginary roots. Then the equation
p(p(x)) = 0 has- a)only purely imaginary roots
- b)all real roots
- c)two real and two purely imaginary roots
- d)neither real nor purely imaginary roots
Correct answer is option 'D'. Can you explain this answer?
The quadratic equation p(x) = 0 with real coefficients has purely imaginary roots. Then the equation
p(p(x)) = 0 has
p(p(x)) = 0 has
a)
only purely imaginary roots
b)
all real roots
c)
two real and two purely imaginary roots
d)
neither real nor purely imaginary roots
|
|
Nandini Iyer answered |
Hence real or purely imaginary number can not satisfy P(P(x)) = 0.
A light source, which emits two wavelengths λ1 = 400 nm and λ2 = 600 nm, is used in a Young’s double
slit experiment. If recorded fringe widths for λ1 and λ2 are β1 and β2 and the number of fringes for them
within a distance y on one side of the central maximum are m1 and m2, respectively, then- a)β2 > β1
- b)m1 > m2
- c)From the central maximum, 3rd maximum of λ2 overlaps with 5th minimum of λ
- d)The angular separation of fringes for λ1 is greater than λ2
Correct answer is option 'A,B,C'. Can you explain this answer?
A light source, which emits two wavelengths λ1 = 400 nm and λ2 = 600 nm, is used in a Young’s double
slit experiment. If recorded fringe widths for λ1 and λ2 are β1 and β2 and the number of fringes for them
within a distance y on one side of the central maximum are m1 and m2, respectively, then
slit experiment. If recorded fringe widths for λ1 and λ2 are β1 and β2 and the number of fringes for them
within a distance y on one side of the central maximum are m1 and m2, respectively, then
a)
β2 > β1
b)
m1 > m2
c)
From the central maximum, 3rd maximum of λ2 overlaps with 5th minimum of λ
d)
The angular separation of fringes for λ1 is greater than λ2
|
|
Sarita Yadav answered |
A parallel plate capacitor has a dielectric slab of dielectric constant K between its plates that
covers 1/3 of the area of its plates, as shown in the figure. The total capacitance of the
capacitor is C while that of the portion with dielectric in between is C1. When the capacitor is
charged, the plate area covered by the dielectric gets charge Q1 and the rest of the area gets
charge Q2. The electric field in the dielectric is E1 and that in the other portion is E2. Choose
the correct option/options, ignoring edge effects.
- a)
- b)
- c)
- d)
Correct answer is option 'A,D'. Can you explain this answer?
A parallel plate capacitor has a dielectric slab of dielectric constant K between its plates that
covers 1/3 of the area of its plates, as shown in the figure. The total capacitance of the
capacitor is C while that of the portion with dielectric in between is C1. When the capacitor is
charged, the plate area covered by the dielectric gets charge Q1 and the rest of the area gets
charge Q2. The electric field in the dielectric is E1 and that in the other portion is E2. Choose
the correct option/options, ignoring edge effects.
covers 1/3 of the area of its plates, as shown in the figure. The total capacitance of the
capacitor is C while that of the portion with dielectric in between is C1. When the capacitor is
charged, the plate area covered by the dielectric gets charge Q1 and the rest of the area gets
charge Q2. The electric field in the dielectric is E1 and that in the other portion is E2. Choose
the correct option/options, ignoring edge effects.
a)
b)
c)
d)
|
|
Ananya Das answered |
As E = V/d
E1/E2 = 1 (both parts have common potential difference)
Assume C0 be the capacitance without dielectric for whole capacitor.
E1/E2 = 1 (both parts have common potential difference)
Assume C0 be the capacitance without dielectric for whole capacitor.
Q. No. 11 - 20 carry 3 Marks eachEach question, when worked out will result in one integer from 0 to 9 (both inclusive).Q.During Searle’s experiment, zero of the Vernier scale lies between 3.20 x 10-2 m and 3.25 x 10-2 m of the
main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions.
When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between 3.20 x
10-2 m and 3.25 x10-2 m of the main scale but now the 45th division of Vernier scale coincides with one of
the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is 8 x 10-7
m2. The least count of the Vernier scale is 1.0 x 10-5 m. The maximum percentage error in the Young’s
modulus of the wire is
Correct answer is '4'. Can you explain this answer?
Q. No. 11 - 20 carry 3 Marks each
Each question, when worked out will result in one integer from 0 to 9 (both inclusive).
Q.
During Searle’s experiment, zero of the Vernier scale lies between 3.20 x 10-2 m and 3.25 x 10-2 m of the
main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions.
When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between 3.20 x
10-2 m and 3.25 x10-2 m of the main scale but now the 45th division of Vernier scale coincides with one of
the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is 8 x 10-7
m2. The least count of the Vernier scale is 1.0 x 10-5 m. The maximum percentage error in the Young’s
modulus of the wire is
main scale. The 20th division of the Vernier scale exactly coincides with one of the main scale divisions.
When an additional load of 2 kg is applied to the wire, the zero of the Vernier scale still lies between 3.20 x
10-2 m and 3.25 x10-2 m of the main scale but now the 45th division of Vernier scale coincides with one of
the main scale divisions. The length of the thin metallic wire is 2 m and its cross-sectional area is 8 x 10-7
m2. The least count of the Vernier scale is 1.0 x 10-5 m. The maximum percentage error in the Young’s
modulus of the wire is
|
|
Tejas Verma answered |
change in lengths = 25(LC)and the maximum permissible error in elongation is one LC
Let M be a 2 x 2 symmetric matrix with integer entries. Then M is invertible if- a)the first column of M is the transpose of the second row of M
- b)the second row of M is the transpose of the first column of M
- c)M is a diagonal matrix with non-zero entries in the main diagonal
- d)the product of entries in the main diagonal of M is not the square of an integer
Correct answer is option 'C,D'. Can you explain this answer?
Let M be a 2 x 2 symmetric matrix with integer entries. Then M is invertible if
a)
the first column of M is the transpose of the second row of M
b)
the second row of M is the transpose of the first column of M
c)
M is a diagonal matrix with non-zero entries in the main diagonal
d)
the product of entries in the main diagonal of M is not the square of an integer
|
|
Ananya Das answered |
X and Y are two volatile liquids with molar weights of 10 g mol-1 and 40 g mol-1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first observed at a distance d cm from the plug soaked in X.Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.
Q.The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is
due to- a)larger mean free path for X as compared to that of Y.
- b)larger mean free path for Y as compared to that of X.
- c)increased collision frequency of Y with the inert gas as compared to that of X with the inert gas.
- d)increased collision frequency of X with the inert gas as compared to that of Y with the inert gas
Correct answer is option 'D'. Can you explain this answer?
X and Y are two volatile liquids with molar weights of 10 g mol-1 and 40 g mol-1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first observed at a distance d cm from the plug soaked in X.Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.
Q.
The experimental value of d is found to be smaller than the estimate obtained using Graham’s law. This is
due to
due to
a)
larger mean free path for X as compared to that of Y.
b)
larger mean free path for Y as compared to that of X.
c)
increased collision frequency of Y with the inert gas as compared to that of X with the inert gas.
d)
increased collision frequency of X with the inert gas as compared to that of Y with the inert gas
|
|
Advait Singh answered |
As the collision frequency increases then molecular speed decreases than the expected.
SECTION – 3 : Matching List Type (Only One Option Correct)Q. No 57- 60 carry 3 marks each and 1 as negative marking for incorrect answerThis section contains four questions, each having two matching list. Choices for the correct combination of elements from List-I and List-II are given as options (A), (B), (C) and (D), out of which ONE is correct.Q.Match the following
A- a)A
- b)B
- c)C
- d)D
Correct answer is option 'D'. Can you explain this answer?
SECTION – 3 : Matching List Type (Only One Option Correct)
Q. No 57- 60 carry 3 marks each and 1 as negative marking for incorrect answer
This section contains four questions, each having two matching list. Choices for the correct combination of elements from List-I and List-II are given as options (A), (B), (C) and (D), out of which ONE is correct.
Q.
Match the following
Aa)
A
b)
B
c)
C
d)
D
|
|
Rajiv Reddy answered |
Q. No 41- 50 carry 3 marks each and 1 as negative marking for incorrect answerThis section contains 10 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE option is correct.Q.Three boys and two girls stand in a queue. The probability, that the number of boys ahead of every girl is at
least one more than the number of girls ahead of her, is- a)1/2
- b)1/3
- c)2/3
- d)3/4
Correct answer is option 'A'. Can you explain this answer?
Q. No 41- 50 carry 3 marks each and 1 as negative marking for incorrect answer
This section contains 10 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE option is correct.
Q.
Three boys and two girls stand in a queue. The probability, that the number of boys ahead of every girl is at
least one more than the number of girls ahead of her, is
least one more than the number of girls ahead of her, is
a)
1/2
b)
1/3
c)
2/3
d)
3/4
|
|
Lavanya Menon answered |
Either a girl will start the sequence or will be at second position and will not acquire the last position as
well.
well.
satisfying
Chapter doubts & questions for JEE Advanced 2014 - National Level Test Series for JEE Advanced 2025 2025 is part of JEE exam preparation. The chapters have been prepared according to the JEE exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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