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All questions of Magnetic Circuits & Core Losses for Electrical Engineering (EE) Exam
What is the strength of magnetic field known as ________- a)Flux
- b)Density
- c)Magnetic strength
- d)Magnetic flux density
Correct answer is option 'D'. Can you explain this answer?
What is the strength of magnetic field known as ________
a)
Flux
b)
Density
c)
Magnetic strength
d)
Magnetic flux density
|
Sahil Datta answered |
Strength of magnetic filed is also known as magnetic flux density. It is the amount of magnetic flux lines crossing through unit area.
The total number of magnetic field lines passing through an area is termed as?- a)Voltage
- b)EMF
- c)Magnetic flux
- d)Magnetic flux density
Correct answer is option 'B'. Can you explain this answer?
The total number of magnetic field lines passing through an area is termed as?
a)
Voltage
b)
EMF
c)
Magnetic flux
d)
Magnetic flux density
|
Bijoy Kapoor answered |
The number of magnetic flux lines per unit area is the magnetic flux, because flux is the number of field lines per unit area.
The magnetic field strength of a solenoid can be increased by inserting which of the following materials as the core?- a)Copper
- b)Silver
- c)Iron
- d)Aluminium
Correct answer is option 'C'. Can you explain this answer?
The magnetic field strength of a solenoid can be increased by inserting which of the following materials as the core?
a)
Copper
b)
Silver
c)
Iron
d)
Aluminium
|
Aditya Deshmukh answered |
Strength of the magnetic field can be increased by:
- increasing the current in the coil.
- increasing the number of coils in the solenoid; and.
- using a soft iron core within the solenoid.
Lines of magnetic flux which are parallel and in the same direction __________ each other.- a)Attract
- b)Repel
- c)Intersect
- d)Cancel
Correct answer is option 'B'. Can you explain this answer?
Lines of magnetic flux which are parallel and in the same direction __________ each other.
a)
Attract
b)
Repel
c)
Intersect
d)
Cancel
|
Sanya Agarwal answered |
Lines of magnetic flux which are parallel to each other and in the same direction repel each other because they tend to act as like poles and like poles repel each other.
If a conductor 0.2m long moves with a velocity of 0.3m/s in a magnetic field of 5T, calculate the emf induced.- a)0.3V
- b)0.03V
- c)30V
- d)3V
Correct answer is option 'A'. Can you explain this answer?
If a conductor 0.2m long moves with a velocity of 0.3m/s in a magnetic field of 5T, calculate the emf induced.
a)
0.3V
b)
0.03V
c)
30V
d)
3V
|
|
Sanvi Kapoor answered |
The formula for induced emf is: emf=Blv. Substituting the values of B, l and v from the question, we get emf=0.3V.
The relation between the direction of current and the direction of magnetic field is?- a)Same direction
- b)Opposite direction
- c)Perpendicular
- d)Unrelated
Correct answer is option 'C'. Can you explain this answer?
The relation between the direction of current and the direction of magnetic field is?
a)
Same direction
b)
Opposite direction
c)
Perpendicular
d)
Unrelated
|
Ravi Singh answered |
When a conductor carries a certain value of current, the force developed in the conductor, the current in the conductor and the magnetic field in the conductor are mutually perpendicular to each other.
When the length of the conductor in the current carrying conductor increases, what happens to the force in the conductor which is at right angles to the magnetic field?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'A'. Can you explain this answer?
When the length of the conductor in the current carrying conductor increases, what happens to the force in the conductor which is at right angles to the magnetic field?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
|
Engineering Essentials. answered |
F=BLVsin¢
When the current in the current carrying conductor increases, what happens to the force in the conductor which is at right angles to the magnetic field?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'A'. Can you explain this answer?
When the current in the current carrying conductor increases, what happens to the force in the conductor which is at right angles to the magnetic field?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
|
Yash Patel answered |
The force at right angles to the magnetic field of a current carrying conductor increases when the current increases because it is directly proportional to the force.
Magnetic field lines ___________ at the south pole.- a)Emerge
- b)Converge
- c)Neither emerge nor converge
- d)Either emerge or converge
Correct answer is option 'B'. Can you explain this answer?
Magnetic field lines ___________ at the south pole.
a)
Emerge
b)
Converge
c)
Neither emerge nor converge
d)
Either emerge or converge
|
|
Rhea Reddy answered |
Magnetic field lines converge at the south pole. Field lines seem to converge at the south pole because they end at the south pole.
An E.M.F. can be induced by _________- a)Change in magnetic field
- b)Change in the area of cross section
- c)Change in angle between magnetic field and area
- d)Change in magnetic field, area and angle
Correct answer is option 'D'. Can you explain this answer?
An E.M.F. can be induced by _________
a)
Change in magnetic field
b)
Change in the area of cross section
c)
Change in angle between magnetic field and area
d)
Change in magnetic field, area and angle
|
Pallavi Nair answered |
It is the dot product of magnetic field vector and area vector.
emf=BAcos(theta), hence if either of the three, that is, magnetic field, area or angle changes, thee emf will change.
emf=BAcos(theta), hence if either of the three, that is, magnetic field, area or angle changes, thee emf will change.
The relation between the direction of force and the direction of magnetic field is __________- a)Same direction
- b)Opposite direction
- c)Perpendicular
- d)Unrelated
Correct answer is option 'C'. Can you explain this answer?
The relation between the direction of force and the direction of magnetic field is __________
a)
Same direction
b)
Opposite direction
c)
Perpendicular
d)
Unrelated
|
|
Ravi Singh answered |
When a conductor carries a certain value of current, the force developed in the conductor, the current in the conductor and the magnetic field in the conductor are mutually perpendicular to each other.
What happens to the magnetic field in the solenoid when the length of the solenoid increases?- a)Increases
- b)Decreases
- c)Remains constant
- d)Becomes zero
Correct answer is option 'B'. Can you explain this answer?
What happens to the magnetic field in the solenoid when the length of the solenoid increases?
a)
Increases
b)
Decreases
c)
Remains constant
d)
Becomes zero
|
|
Sanya Agarwal answered |
The magnetic field of a solenoid is inversely proportional to the length. Hence as the length increases, the magnetic field decreases.
Find the strength of magnetic field in a conductor 0.5m long moving with a velocity of 10m/s, inducing an emf of 20V.- a)1T
- b)2T
- c)3T
- d)4T
Correct answer is option 'D'. Can you explain this answer?
Find the strength of magnetic field in a conductor 0.5m long moving with a velocity of 10m/s, inducing an emf of 20V.
a)
1T
b)
2T
c)
3T
d)
4T
|
|
Sanvi Kapoor answered |
The formula for induced emf is: emf=Blv. Substituting the values of l, emf and v from the question, we get B=4T.
When a charged particle moves at right angles to the magnetic field, the variable quantity is?- a)Momentum
- b)Speed
- c)Energy
- d)Moment of inertia
Correct answer is option 'A'. Can you explain this answer?
When a charged particle moves at right angles to the magnetic field, the variable quantity is?
a)
Momentum
b)
Speed
c)
Energy
d)
Moment of inertia
|
|
Parth Ghoshal answered |
When a charged particle moves perpendicular to the field, its speed remains the same whereas its velocity keeps on changing. Momentum is the product of the mass of the particle and the velocity if the particle, hence since velocity varies, momentum also varies.
What is the formula for magnetic field due to a solenoid?- a)μnI
- b)μn2
- c)μNI
- d)μN2I2
Correct answer is option 'A'. Can you explain this answer?
What is the formula for magnetic field due to a solenoid?
a)
μnI
b)
μn2
c)
μNI
d)
μN2I2
|
|
Sanvi Kapoor answered |
The magnetic field due to a solenoid is:
B= μnI, where μ is the permeability, n is the number of turns per unit length and I is the current in the solenoid.
B= μnI, where μ is the permeability, n is the number of turns per unit length and I is the current in the solenoid.
A ring having a cross-sectional area of 500 mm2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the flux density of the ring.- a)1.6T
- b)2.6T
- c)3.6T
- d)4.6T
Correct answer is option 'A'. Can you explain this answer?
A ring having a cross-sectional area of 500 mm2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the flux density of the ring.
a)
1.6T
b)
2.6T
c)
3.6T
d)
4.6T
|
|
Aman Jain answered |
From the given question:
Flux density= 800*10-6/500*106=1.6 Wb/m2.
Flux density= 800*10-6/500*106=1.6 Wb/m2.
North pole induces __________- a)Clockwise current
- b)Anti-clockwise current
- c)Zero current
- d)Infinite current
Correct answer is option 'B'. Can you explain this answer?
North pole induces __________
a)
Clockwise current
b)
Anti-clockwise current
c)
Zero current
d)
Infinite current
|
|
Ravi Singh answered |
A north pole will always induce an anti-clockwise current whereas a south pole will always induce a clockwise current due to electromagnetic theory.
Magnetic field exists along which of the following?- a)Moving charges
- b)Stationary charges
- c)Copper
- d)Iron
Correct answer is option 'A'. Can you explain this answer?
Magnetic field exists along which of the following?
a)
Moving charges
b)
Stationary charges
c)
Copper
d)
Iron
|
Zoya Sharma answered |
Moving charges have a magnetic field associated with them because they have magnetic flux lines associated with it.
Find the length of a conductor which is moving with a velocity 0.4m/s in a magnetic field of 8T, inducing an emf of 20V.- a)50m
- b)5m
- c)6.25m
- d)0.5m
Correct answer is option 'C'. Can you explain this answer?
Find the length of a conductor which is moving with a velocity 0.4m/s in a magnetic field of 8T, inducing an emf of 20V.
a)
50m
b)
5m
c)
6.25m
d)
0.5m
|
Aman Datta answered |
The formula for induced emf is: emf=Blv. Substituting the values of B, emf and v from the question, we get l=6.25m.
What is MMF?- a)Magnetic Machine Force
- b)Magnetomotive Force
- c)Magnetic Motion Force
- d)Magnetomotion Force
Correct answer is option 'B'. Can you explain this answer?
What is MMF?
a)
Magnetic Machine Force
b)
Magnetomotive Force
c)
Magnetic Motion Force
d)
Magnetomotion Force
|
Anuj Rane answered |
MMF stands for magnetomotive force. It is the sum of the magnetizing forces along a circuit.
What is emf?- a)Force
- b)Voltage
- c)Current
- d)Flux
Correct answer is option 'B'. Can you explain this answer?
What is emf?
a)
Force
b)
Voltage
c)
Current
d)
Flux
|
Mansi Choudhury answered |
Electromotive force is not actually a force. It is basically a voltage. It is the voltage developed by any source of electrical energy.
When the area of cross section of the material increases, what happens to reluctance?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'B'. Can you explain this answer?
When the area of cross section of the material increases, what happens to reluctance?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
|
Sharmila Bajaj answered |
Reluctance is inversely proportional to the area of cross section of the material hence as area increases, reluctance decreases.
The total number of magnetic field lines passing through an area is termed as ________- a)Voltage
- b)EMF
- c)Magnetic flux
- d)Magnetic flux density
Correct answer is option 'B'. Can you explain this answer?
The total number of magnetic field lines passing through an area is termed as ________
a)
Voltage
b)
EMF
c)
Magnetic flux
d)
Magnetic flux density
|
|
Srestha Gupta answered |
The number of magnetic flux lines per unit area is the magnetic flux, because flux is the number of field lines per unit area.
Magnetic Field lines move from _______- a)North to south
- b)South to north
- c)West to east
- d)East to west
Correct answer is option 'A'. Can you explain this answer?
Magnetic Field lines move from _______
a)
North to south
b)
South to north
c)
West to east
d)
East to west
|
|
Rajesh Saha answered |
Magnetic field lines originate at the north pole and terminate at the south pole of the magnet.
Calculate the force between two charges having magnitude 3nC and 2nC separated by a distance of 2micro m.- a)13.5N
- b)13.5kN
- c)1.35N
- d)1.35kN
Correct answer is option 'B'. Can you explain this answer?
Calculate the force between two charges having magnitude 3nC and 2nC separated by a distance of 2micro m.
a)
13.5N
b)
13.5kN
c)
1.35N
d)
1.35kN
|
Gayatri Menon answered |
Given:
- Charge 1 magnitude = 3 nC
- Charge 2 magnitude = 2 nC
- Distance between the charges = 2 µm
To calculate the force between the charges, we can use Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
Coulomb's law equation:
F = (k * q1 * q2) / r^2
where:
- F is the force between the charges
- k is the electrostatic constant (k = 9 * 10^9 Nm^2/C^2)
- q1 is the magnitude of charge 1
- q2 is the magnitude of charge 2
- r is the distance between the charges
Let's substitute the given values into the equation:
F = (9 * 10^9 Nm^2/C^2) * ((3 * 10^-9 C) * (2 * 10^-9 C)) / (2 * 10^-6 m)^2
Simplifying the equation:
F = (9 * 3 * 2 * 10^-18) / 4 * 10^-12
F = 54 * 10^-18 / 4 * 10^-12
F = 13.5 * 10^-6 N
Converting the result to kilonewtons (kN):
F = 13.5 * 10^-6 N = 13.5 * 10^-6 * 10^-3 kN
F = 13.5 * 10^-9 kN
Therefore, the force between the charges is 13.5 kN.
- Charge 1 magnitude = 3 nC
- Charge 2 magnitude = 2 nC
- Distance between the charges = 2 µm
To calculate the force between the charges, we can use Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
Coulomb's law equation:
F = (k * q1 * q2) / r^2
where:
- F is the force between the charges
- k is the electrostatic constant (k = 9 * 10^9 Nm^2/C^2)
- q1 is the magnitude of charge 1
- q2 is the magnitude of charge 2
- r is the distance between the charges
Let's substitute the given values into the equation:
F = (9 * 10^9 Nm^2/C^2) * ((3 * 10^-9 C) * (2 * 10^-9 C)) / (2 * 10^-6 m)^2
Simplifying the equation:
F = (9 * 3 * 2 * 10^-18) / 4 * 10^-12
F = 54 * 10^-18 / 4 * 10^-12
F = 13.5 * 10^-6 N
Converting the result to kilonewtons (kN):
F = 13.5 * 10^-6 N = 13.5 * 10^-6 * 10^-3 kN
F = 13.5 * 10^-9 kN
Therefore, the force between the charges is 13.5 kN.
A ring having a cross-sectional area of 500 mm2, a circumference of and ϕ=800microWb 400 mm has a coil of 200 turns wound around it. Calculate the reluctance.- a)1.68 * 10-4A/Wb
- b)1.68 * 104 A/Wb
- c)1.68 * 106 A/Wb
- d)1.68 * 10-6A/Wb
Correct answer is option 'C'. Can you explain this answer?
A ring having a cross-sectional area of 500 mm2, a circumference of and ϕ=800microWb 400 mm has a coil of 200 turns wound around it. Calculate the reluctance.
a)
1.68 * 10-4A/Wb
b)
1.68 * 104 A/Wb
c)
1.68 * 106 A/Wb
d)
1.68 * 10-6A/Wb
|
|
Sravya Khanna answered |
From the given question:
Flux density= 800*10-6/500*106=1.6 Wb/m2.
Reluctance= 0.4/(380*4*pi*10-7*10-4*5)=1.68 * 106 A/Wb.
Flux density= 800*10-6/500*106=1.6 Wb/m2.
Reluctance= 0.4/(380*4*pi*10-7*10-4*5)=1.68 * 106 A/Wb.
The relation between direction of magnetic flux and direction of motion of the conductor is _______- a)Parallel
- b)Equal
- c)Not related
- d)Perpendicular
Correct answer is option 'D'. Can you explain this answer?
The relation between direction of magnetic flux and direction of motion of the conductor is _______
a)
Parallel
b)
Equal
c)
Not related
d)
Perpendicular
|
|
Hiral Kulkarni answered |
According to Fleming’s right hand rule, the induced emf, the motion of the conductor and the magnetic flux are mutually perpendicular.
Calculate the MMF when the magnetic flux is 5Wb and the reluctance is 3A/Wb.- a)10At
- b)10N
- c)15N
- d)15At
Correct answer is option 'D'. Can you explain this answer?
Calculate the MMF when the magnetic flux is 5Wb and the reluctance is 3A/Wb.
a)
10At
b)
10N
c)
15N
d)
15At
|
|
Raghav Nambiar answered |
We know that:
F=ϕS
Substituting the given values from the question, we get MMF= 15At.
F=ϕS
Substituting the given values from the question, we get MMF= 15At.
As the magnetic field strength increases, reluctance?- a)Increases
- b)Decreases
- c)Remains the same
- d)Becomes zero
Correct answer is option 'A'. Can you explain this answer?
As the magnetic field strength increases, reluctance?
a)
Increases
b)
Decreases
c)
Remains the same
d)
Becomes zero
|
|
Swati Tiwari answered |
Reluctance is directly proportional to the strength of magnetic field, hence as the strength of magnetic field increases, the reluctance increases.
What is the magnetic field outside a solenoid?- a)Infinity
- b)Zero
- c)Double the value of the field inside
- d)Half the value of the field inside
Correct answer is option 'B'. Can you explain this answer?
What is the magnetic field outside a solenoid?
a)
Infinity
b)
Zero
c)
Double the value of the field inside
d)
Half the value of the field inside
|
|
Samridhi Bose answered |
There are no magnetic lines of force outside a solenoid, hence the magnetic field outside a solenoid is zero.
What happens to the magnetic field in the solenoid when the number of turns increases?- a)Increases
- b)Decreases
- c)Remains constant
- d)Becomes zero
Correct answer is option 'A'. Can you explain this answer?
What happens to the magnetic field in the solenoid when the number of turns increases?
a)
Increases
b)
Decreases
c)
Remains constant
d)
Becomes zero
|
|
Yash Patel answered |
The magnetic field of a solenoid is directly proportional to the number of turns in it. Hence as the number of turns increases, the magnetic field also increases.
A ring having a cross-sectional area of 500 mm2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetomotive force.- a)1442At
- b)1342At
- c)1432At
- d)1344At
Correct answer is option 'B'. Can you explain this answer?
A ring having a cross-sectional area of 500 mm2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetomotive force.
a)
1442At
b)
1342At
c)
1432At
d)
1344At
|
|
Abhishek Chauhan answered |
We know that:
F=ϕS
Substituting the given values from the question, we get F= 1342At.
F=ϕS
Substituting the given values from the question, we get F= 1342At.
PMMC instruments can be used as a fluxmeters by _______- a)Using a low resistance shunt
- b)Removing the control spring
- c)Making the control springs having large moment of inertia
- d)Using a high resistance in series
Correct answer is option 'B'. Can you explain this answer?
PMMC instruments can be used as a fluxmeters by _______
a)
Using a low resistance shunt
b)
Removing the control spring
c)
Making the control springs having large moment of inertia
d)
Using a high resistance in series
|
|
Rajesh Verma answered |
A PMMC or a permanent moving magnet coil instrument can be used as a fluxmeter by removing the control spring.
A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.- a)6.7A
- b)7.7A
- c)7.6
- d)6.1A
Correct answer is option 'A'. Can you explain this answer?
A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.
a)
6.7A
b)
7.7A
c)
7.6
d)
6.1A
|
Shivani Saha answered |
We know that:
F=ϕS
Substituting the given values from the question, we get F= 1342At.
The magnetic current is:
I=F/N
Substituting the values from the question, we get I=6.7A.
F=ϕS
Substituting the given values from the question, we get F= 1342At.
The magnetic current is:
I=F/N
Substituting the values from the question, we get I=6.7A.
The ballistic galvanometer is usually lightly damped so that ________- a)It can oscillate
- b)It will remain stable
- c)Amplitude of the first swing is very large
- d)Amplitude of the first swing is very small
Correct answer is option 'C'. Can you explain this answer?
The ballistic galvanometer is usually lightly damped so that ________
a)
It can oscillate
b)
It will remain stable
c)
Amplitude of the first swing is very large
d)
Amplitude of the first swing is very small
|
|
Harshad Singh answered |
The ballistic galvanometer is usually lightly damped so that the amplitude of its first swing is very large.
The ratio of magnetic force to electric force on a charged particle getting undeflected in a field is ______- a)1
- b)0
- c)2
- d)4
Correct answer is option 'A'. Can you explain this answer?
The ratio of magnetic force to electric force on a charged particle getting undeflected in a field is ______
a)
1
b)
0
c)
2
d)
4
|
Nandita Kulkarni answered |
When a charged particle is undeflected in a field, the magnitude of the magnetic force and electric force acting on the particle is the same, hence the ratio is 1.
Calculate the magnetic field strength if the magnetic flux density is 4*piT.- a)10-7/16*pi2A/m
- b)10-7A/m
- c)107A/m
- d)10-7A
Correct answer is option 'C'. Can you explain this answer?
Calculate the magnetic field strength if the magnetic flux density is 4*piT.
a)
10-7/16*pi2A/m
b)
10-7A/m
c)
107A/m
d)
10-7A
|
|
Manoj Chaudhary answered |
We know that:
∫0=B/H
Substituting the value of B from the question, we get H = 107A/m.
∫0=B/H
Substituting the value of B from the question, we get H = 107A/m.
If the intensity of magnetic field is 100T, the length of the conductor is 3m and the current in the conductor is 10A, calculate the magnitude of force perpendicular to the electric field.- a)300N
- b)30N
- c)30kN
- d)3kN
Correct answer is option 'D'. Can you explain this answer?
If the intensity of magnetic field is 100T, the length of the conductor is 3m and the current in the conductor is 10A, calculate the magnitude of force perpendicular to the electric field.
a)
300N
b)
30N
c)
30kN
d)
3kN
|
|
Tarun Chawla answered |
The formula for calculating the value of the force which is perpendicular to the electric field is:
F=Bil
Substituting the values from the question, we get F=3kN.
F=Bil
Substituting the values from the question, we get F=3kN.
Permeability of free space is also known as _________- a)Magnetic constant
- b)Electric constant
- c)Electrostatic constant
- d)Magnetostatic constant
Correct answer is option 'A'. Can you explain this answer?
Permeability of free space is also known as _________
a)
Magnetic constant
b)
Electric constant
c)
Electrostatic constant
d)
Magnetostatic constant
|
Neha Nambiar answered |
The permeability of free space is also known as magnetic constant. The permittivity of free space is the electrostatic constant.
B/H curve shows the relationship between?- a)Magnetic field strength and magnetic flux
- b)Magnetic field strength and magnetic flux density
- c)Current and magnetic flux density
- d)Voltage and magnetic flux density
Correct answer is option 'B'. Can you explain this answer?
B/H curve shows the relationship between?
a)
Magnetic field strength and magnetic flux
b)
Magnetic field strength and magnetic flux density
c)
Current and magnetic flux density
d)
Voltage and magnetic flux density
|
|
Madhurima Das answered |
The B/H curve shows the reaction between magnetic field strength and magnetic flux density.
What is the consequence of motor effect?- a)Current
- b)Voltage
- c)Electromagnetic induction
- d)EMF
Correct answer is option 'C'. Can you explain this answer?
What is the consequence of motor effect?
a)
Current
b)
Voltage
c)
Electromagnetic induction
d)
EMF
|
|
Shail Nambiar answered |
Motor effect is when a current carrying conductor in a magnetic field experiences a force, hence its consequence is electromagnetic induction.
Calculate the magnetic flux density if the magnetic field strength is 2A/m.- a) 4*pi/10-7T
- b)8*pi/10-7T
- c)10*pi/10-7T
- d)12*pi/10-7T
Correct answer is option 'B'. Can you explain this answer?
Calculate the magnetic flux density if the magnetic field strength is 2A/m.
a)
4*pi/10-7T
b)
8*pi/10-7T
c)
10*pi/10-7T
d)
12*pi/10-7T
|
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Sparsh Nambiar answered |
We know that:
∫0=B/H
Substituting the value of H from the question, we get B= 8*pi/10-7T.
∫0=B/H
Substituting the value of H from the question, we get B= 8*pi/10-7T.
The current in a solenoid is 30A, the number of turns per unit length is 500 turns per metre. Calculate the magnetic field if the core is air.- a)18.84T
- b)18.84mT
- c)1.84T
- d)1.84mT
Correct answer is option 'B'. Can you explain this answer?
The current in a solenoid is 30A, the number of turns per unit length is 500 turns per metre. Calculate the magnetic field if the core is air.
a)
18.84T
b)
18.84mT
c)
1.84T
d)
1.84mT
|
|
Nandita Kulkarni answered |
The magnetic field in a solenoid is given by:
B=μnI
Substituting the values in the given values in the equation, B=18.84mT.
B=μnI
Substituting the values in the given values in the equation, B=18.84mT.
Which, among the following qualities, is not affected by the magnetic field?- a)Moving charge
- b)Change in magnetic flux
- c)Current flowing in conductor
- d)Stationary charge
Correct answer is option 'D'. Can you explain this answer?
Which, among the following qualities, is not affected by the magnetic field?
a)
Moving charge
b)
Change in magnetic flux
c)
Current flowing in conductor
d)
Stationary charge
|
|
Sanchita Sharma answered |
A stationary charge is not affected by a magnetic field because stationary charges do not have any velocity. Magnetic field cannot occur in a particle having zero velocity.
A substance whose permeability is less than the permeability of free space is?- a)Diamagnetic
- b)Paramagnetic
- c)Ferromagnetic
- d)Not a magnetic substance
Correct answer is option 'A'. Can you explain this answer?
A substance whose permeability is less than the permeability of free space is?
a)
Diamagnetic
b)
Paramagnetic
c)
Ferromagnetic
d)
Not a magnetic substance
|
|
Gaurav Chauhan answered |
A diamagnetic material creates a magnetic field opposing that of the external magnetic field and it repels the external magnetic field. Hence its permeability is less than that of free space.
According to Faraday’s laws of electromagnetic inductance, an emf is induced in a conductor whenever?- a)The conductor is perpendicular to the magnetic field
- b)Lies in the magnetic field
- c)Cuts magnetic lines of flux
- d)Moves parallel to the magnetic field
Correct answer is option 'C'. Can you explain this answer?
According to Faraday’s laws of electromagnetic inductance, an emf is induced in a conductor whenever?
a)
The conductor is perpendicular to the magnetic field
b)
Lies in the magnetic field
c)
Cuts magnetic lines of flux
d)
Moves parallel to the magnetic field
|
Lavanya Menon answered |
An emf is induced, according to Faraday’s laws of electromagnetic inductance, whenever the conductor in a magnetic field cuts the magnetic lies of flux, varying the flux per unit area, and hence the magnetic field which induces an emf.
Which, among the following, have negative susceptibility?- a)Diamagnetic
- b)Paramagnetic
- c)Ferromagnetic
- d)Not a magnetic substance
Correct answer is option 'A'. Can you explain this answer?
Which, among the following, have negative susceptibility?
a)
Diamagnetic
b)
Paramagnetic
c)
Ferromagnetic
d)
Not a magnetic substance
|
|
Nilanjan Saini answered |
Magnetic susceptibility is the degree of magnetisation of a material in response to the external magnetic field. Diamagnetic substances repel the magnetic field and hence have negative susceptibility.
Magnetic field lines form _________ loops from pole to pole.- a)Open
- b)Closed
- c)Branched
- d)Either closed or branched
Correct answer is option 'B'. Can you explain this answer?
Magnetic field lines form _________ loops from pole to pole.
a)
Open
b)
Closed
c)
Branched
d)
Either closed or branched
|
Kritika Gupta answered |
Magnetic field lines form closed loops from pole to pole. There is no discontinuity in the magnetic flux lines.
According to Fleming’s right hand rule, the middle finger points towards?- a)Current
- b)E.M.F.
- c)Motion of the conductor
- d)Magnetic flux
Correct answer is option 'B'. Can you explain this answer?
According to Fleming’s right hand rule, the middle finger points towards?
a)
Current
b)
E.M.F.
c)
Motion of the conductor
d)
Magnetic flux
|
|
Rajveer Saha answered |
Fleming’s left hand rule stated that if the index finger points towards magnetic flux, the thumb towards the motion of the conductor, then the middle finger points towards the induced emf.
Chapter doubts & questions for Magnetic Circuits & Core Losses - Basic Electrical Technology 2025 is part of Electrical Engineering (EE) exam preparation. The chapters have been prepared according to the Electrical Engineering (EE) exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Electrical Engineering (EE) 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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